PDO Problem -> Call to a member function on a non-object - php

I have been turning and twisting this to the best of my non-existing PDO knowledge, but still without any luck.
the code:
function write($id, $data) {
global $dbcon;
$id = mysql_real_escape_string($id);
$data = mysql_real_escape_string($data);
$sql = $dbcon->exec("INSERT INTO `sessions`
(`session_id`, `session_data`,
`session_expire`, `session_agent`,
`session_ip`, `session_referrer`)
VALUES
(\"".$id."\", \"".$data."\",
\"".time()."\",\"".($this->session_encryption($_SERVER['HTTP_USER_AGENT']))."\",
\"".($this->session_encryption($_SERVER['REMOTE_ADDR']))."\", \"".($this->session_encryption((isset($_SERVER['HTTP_REFERER']) ? $_SERVER['HTTP_REFERER'] : str_shuffle('ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789-_^~#&|=+;!,(){}[].?%*#'))))."\")
ON DUPLICATE KEY UPDATE
`session_data` = \"".$data."\",
`session_expire` = \"".time()."\"");
return true;
}
Give me the following error:
Fatal error: Call to a member function exec() on a non-object
on the
$sql = $dbcon->exec(
line.
I have been trying to solve this all evening, but without any luck.
This is my PDO connection script:
require_once(INC_PATH.'/config.php');
$dsn = "$db_type:host=$db_host;port=$db_port;dbname=$db_name;charset=$db_charset";
try{
$dbcon = new PDO($dsn, $db_user, $db_pass);
$dbcon->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
//$dbcon = null; //Close database connection.
}
catch(PDOException $e){
echo $e->getMessage();
}
Hope one of you kind souls out there can help me, I would deeply appreciate it!
Thanks.
UPDATE:
I have a global.php file which looks like this:
//Load database
require_once(INC_PATH.'/database.php');
//Load session handler
require_once(INC_PATH.'/class_sessions.php');
$Sessions = new SessionManager();
session_start();
The database.php is included before the sessions class, and when I view the website, it does not give any errors on this part of the sessions class (which is before the write function:
function read($id) {
global $dbcon;
$data = '';
$id = mysql_real_escape_string($id);
$sql = $dbcon->prepare("SELECT
`session_data`
FROM
`sessions`
WHERE
`session_id` = '".$id."'");
$sql->execute();
$a = $sql->columnCount();
if($a > 0) {
$row = $sql->fetchObject();
$data = $row['session_data'];
}
return $data;
}

Are you sure your connection script is getting executed? Try checking if $dbcon is set. Also, you may be missing global $dbcon within the connection script.
By the way, since you're already using PDO, might I recommend you use placeholders in your query:
$sql = "INSERT INTO `sessions`
(`session_id`, `session_data`, `session_expire`,
`session_agent`, `session_ip`, `session_referrer`)
VALUES
(:session_id, :session_data, :session_expire,
:session_agent, :session_ip, :session_referrer)
ON DUPLICATE KEY UPDATE
`session_data` = :session_data,
`session_expire` = :session_expire";
$params = array(
':session_id' => $id,
':session_data' => $data,
':session_expire' => time(),
':session_agent' => $this->session_encryption($_SERVER['HTTP_USER_AGENT']),
':session_ip', => $this->session_encryption($_SERVER['REMOTE_ADDR']),
':session_referrer' => $this->session_encryption((isset($_SERVER['HTTP_REFERER']) ? $_SERVER['HTTP_REFERER'] : str_shuffle('ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789-_^~#&|=+;!,(){}[].?%*#';
);
$stmt = $dbcon->prepare($sql);
if ($stmt->execute($params) === FALSE) {
// handle error
}

First check that the global object is not being overwritten by another function. I strongly suggest you use Dependency injection instead of globals.
$Sessions = new SessionManager($dbcon);
And inside the Session Management class you can do something like
class SessionManager
{
protected $db;
public function __construct($db) { $this->db = $db; }
public function read($id)
{
$stmt = $this->db->prepare("SELECT session_data
FROM sessions
WHERE session_id = ?");
$stmt->execute(array($id));
return $stmt->fetchColumn();
}
}
And secondly, since you are using PDO, you dont need to call mysql_real_escape_string(), use prepared statements and placeholders :)

Related

What arguments should be passed to PDO::__construct()?

I'm a new in web programming and would ask the advice for code below.
I have the code in class Database. There is it. As you see there's a connect to database with mysqli. And this code work.
function __construct() {
$this->conn = $this->connectDB();
}
function connectDB() {
$conn = mysqli_connect($this->host,$this->user,$this->password,$this->database);
return $conn;
}
function runBaseQuery($query) {
$result = mysqli_query($this->conn,$query);
while($row=mysqli_fetch_assoc($result)) {
$resultset[] = $row;
}
if(!empty($resultset))
return $resultset;
}
function runQuery($query, $param_type, $param_value_array) {
$sql = $this->conn->prepare($query);
$this->bindQueryParams($sql, $param_type, $param_value_array);
$sql->execute();
$result = $sql->get_result();
if ($result->num_rows > 0) {
while($row = $result->fetch_assoc()) {
$resultset[] = $row;
}
}
if(!empty($resultset)) {
return $resultset;
}
}
function bindQueryParams($sql, $param_type, $param_value_array) {
$param_value_reference[] = & $param_type;
for($i=0; $i<count($param_value_array); $i++) {
$param_value_reference[] = & $param_value_array[$i];
}
call_user_func_array(array(
$sql,
'bind_param'
), $param_value_reference);
}
function insert($query, $param_type, $param_value_array) {
$sql = $this->conn->prepare($query);
$this->bindQueryParams($sql, $param_type, $param_value_array);
$sql->execute();
}
function update($query, $param_type, $param_value_array) {
$sql = $this->conn->prepare($query);
$this->bindQueryParams($sql, $param_type, $param_value_array);
$sql->execute();
}
I have to write this class in PDO. I've done it, but something is wrong. I try to connect my Database and get the error
Fatal error: Uncaught TypeError: PDO::__construct() expects parameter 4
class DB {
private $host = "";
private $user = "";
private $password = "";
private $database = "";
private $pdo;
function __construct() {
$this->pdo = $this->connectDB();
}
function connectDB() {
try
{
$pdo = new PDO($this->host,$this->user,$this->password,$this->database);
}
catch (PDOException $e) {
print "Error!: " . $e->getMessage();
}
die();
}
function runBaseQuery($query)
{
$result = $pdo->query($query);
while ($row = $pdo->fetch(PDO::FETCH_ASSOC)) {
$resultset[] = $row;
}
if (!empty($resultset))
return $resultset;
}
function runQuery($query, $param_type, $param_value_array) {
$sql = $pdo->prepare($query);
$pdo->execute($sql, $param_type, $param_value_array);
$result = $pdo->fetchAll(PDO::FETCH_ASSOC);
if ($result->num_rows > 0) {
while ($row = $pdo->fetchAll(PDO::FETCH_ASSOC)) {
$resultset[] = $row;
}
}
if(!empty($resultset)) {
return $resultset;
}
}
function bindQueryParams($sql, $param_type, $param_value_array) {
$param_value_reference[] = & $param_type;
for($i=0; $i<count($param_value_array); $i++) {
$param_value_reference[] = & $param_value_array[$i];
}
call_user_func_array(array(
$sql,
'bind_param'
), $param_value_reference);
}
function insert($query, $param_type, $param_value_array) {
$sql = $pdo->prepare($query);
$pdo->execute($sql, $param_type, $param_value_array);
}
function update($query, $param_type, $param_value_array) {
$sql = $pdo->prepare($query);
$pdo->execute($sql, $param_type, $param_value_array);
}
}
But my the new code don't work. Where is the problem?
Your new class has multiple problems. The one you are asking about can be solved by understanding how to connect properly with PDO and what DSN is. For this I have to refer you to this awesome article https://phpdelusions.net/pdo#dsn
Take this DSN for example:
mysql:host=localhost;dbname=test;port=3306;charset=utf8mb4
driver^ ^ colon ^param=value pair ^semicolon
You start by specifying which DB driver you would like to use: mysql:. After this comes a list of key-value pairs separated by a semicolon. The order should be host, DB name, and charset. You should specify all of these values.
Your DSN is your first argument to PDO::__construct(), the second and third is username and password respectively. The third one is an array of options.
Your options array should contain at least two values. You need to enable error reporting and switch off emulated prepared statements. These are the recommended settings.
Your connection should look at least similar to this:
$options = [
\PDO::ATTR_ERRMODE => \PDO::ERRMODE_EXCEPTION,
\PDO::ATTR_EMULATE_PREPARES => false,
];
$this->pdo = new PDO('mysql:host='.$this->host.';dbname='.$this->database.';charset=utf8mb4', $this->user, $this->password, $options);
However, please take note, that the constructor will be called once, and you do not need to put these values in private properties. They can simply be constants or hardcoded in the constructor. You will never need to reuse this values after opening connection.
Your second main mistake is that you are referring in a lot of places to $pdo, but you should be using $this->pdo.
Other notes:
die(); is going to end your whole script. Do not use it.
Do not catch exceptions, just to print out the error message. It defeats the whole purpose of the exceptions.
The method bindQueryParams() seems completely unnecessary. I would recommend you remove it.
runQuery is riddled with mistakes. $pdo->execute() takes in only one argument, which should be the array of values to be bound. There is no need for param type like in mysqli. The while loop is redundant and incorrect.
num_rows does not exist in PDO, and is not needed at all.
None of these method provide any benefit over just plain PDO.
Conclusion:
The class you have written is completely unnecessary and only makes your code more difficult to understand and maintain. While it might have made more sense with mysqli, PDO is simpler to use and does not need to be wrapped in such class. Please read the article linked at the beginning carefully, it will help you a lot.
The PDO connection does not take a 4th parameter for the database name. The DB name is passed in with the host name. So change:
$pdo = new PDO($this->host,$this->user,$this->password,$this->database);
to:
$pdo = new PDO($this->host . ';dbname=' . $this->database, $this->user, $this->password);
For more information see https://www.php.net/manual/en/pdo.connections.php
Additionally, it is unclear what $this->host contains but for PDO if that is just a host path you need to pass in the driver you are using as well, so you might even need to add
mysql:host=
to the start of this. With mysqli this is not required because the only RDBMS mysqli supports is mysql.
So potentially complete answer:
$pdo = new PDO('mysql:host=' . $this->host . ';dbname=' . $this->database, $this->user, $this->password);

Not able to get return output from PHP class

This is my code in my class
<?php
class PerClass
{
private $sql_connection = null;
private $localAf = '9929292F';
function __construct($env) {
// Nasty globals, sorry
global $_config;
$host = "localhost";
$user = "user";
$pass = "pass";
$db = "kModule";
// Build sql connection
$this->sql_connection = new mysqli($host, $user, $pass, $db);
// Check connection
if ($this->sql_connection->connect_error) {
die("Connection failed: " . $this->sql_connection->connect_error);
}
}
public function getOrders($sSettingsId) {
$query = <<<SQL
SELECT * FROM `scrub_order_log` WHERE `scrub_settings_id` = {$sSettingsId} AND `order_date` BETWEEN (NOW() - INTERVAL (SELECT `c_h_days` FROM `scrub_settings` WHERE `id` = {$sSettingsId}) DAY) AND NOW() ORDER BY `order_date` DESC;
SQL;
$result = $this->sql_connection->query($query);
$resp = null;
while ($row = $result->fetch_assoc()) {
$resp[] = $row;
}
return $resp;
}
}
?>
I am trying to get the output as shown in code below
<?
$details = $PerClass->getOrders('1');
print_r($details);
?>
But unfortunately I am getting following erro
Fatal error: Call to a member function getOrders() on null in /home/domn/public_html/stage/stage_test.php on line 37
Tried different ways but I think I am doing something wrong
The code that calls the getOrders method is missing the object instantiation.
<?
// add this here
$PerClass = new PerClass();
$details = $PerClass->getOrders('1');
print_r($details);
?>
now, because the constructor method of your PerClass expects you to pass in a value as an argument, this is going to result in the following warning:
WARNING Missing argument 1 for PerClass::__construct()
In order to resolve this warning you have two options:
Pass the value of the $env parameter when you instantiate the object i.e. $PerClass = new PerClass('value_to_be_passed'); or
Get rid of the $env argument in your constructor since - from what I can see - it is not used anywhere i.e. from function __construct($env) { ... } to function __construct() { ... }.
See this link for an interested discussion about using global in PHP.

stmt get_result another way

An example of one of my queries...
public function db_query_select($query, $params, $param_types){
$dbc = $this->dbConnect();
if($stmt = $dbc->prepare($query)){
//prepared.
//move the types to the front of the param array
array_unshift($params, $param_types);
//call the bind param function with the parameters passed in by reference
//bind_param only allows by reference.
call_user_func_array(array($stmt, "bind_param"), $this->paramsToRefs($params));
//binded.
//attempt to execute the sql statement.
if ($stmt->execute()){
$result = $stmt->get_result();
$stmt->close();
$dbc->close();
return $result;
}
}
//must have failed...
return NULL;
}
how can I change stmt get_result(); to something that is accepted by shared servers/hosts without the native driver... mysqlnd.
Anyone know? without changing all of my functions that use this database function.
Thanks.
UPDATED:::: Thanks to #your common sense, See Answer.
I believe this is what I was after. Hope it helps anyone that was having the same problem as myself. PDO vs MySQLi, seems simpler... no user call func or anything like that.
DB HANDLER:
private function dbConnect(){
$config = parse_ini_file($_SERVER['DOCUMENT_ROOT'].'/NTConfig.ini');
try {
$dbc = new PDO('mysql:host='.$config['DB_HOST'].';dbname='.$config['DB_DATABASE'].'', $config['DB_USER'], $config['DB_PASSWORD']);
$dbc->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
} catch (PDOException $e) {
echo 'Connection failed: ' . $e->getMessage();
exit;
}
return $dbc;
}
public function db_query_select($query, $params){
$dbc = $this->dbConnect();
if($stmt = $dbc->prepare($query)){
//prepared.
//attempt to execute the sql statement.
if ($stmt->execute($params)){
$result = $stmt->fetch(PDO::FETCH_ASSOC);
print_r($result);
//$stmt->close();
//$dbc->close();
return $result;
}
}
//must have failed...
return NULL;
}
Outside the DBHANDLER
$query = "SELECT error_desc FROM nt_errors WHERE error_code = :ERROR_CODE LIMIT 1";
//array: holds parameters for the query.
$params = array(
':ERROR_CODE' => $code
);
$result = $db->db_query_select($query, $params);
if ($result == NULL){
$errorText = 'ERROR: Failed to retrieve error';
}
else{
//var_dump($result);
$errorText = $result['error_desc'];
PDO is not only much more user friendly than mysqli but also doesn't have any of such a nasty drawbacks. So I strongly suggest to use PDO instead of mysqli.
With DO, the function you're after should be as simple as this
function run($sql, $args = NULL)
{
$pdo = ...;//your means of getting the connection variable
$stmt = $pdo->prepare($sql);
$stmt->execute($args);
return $stmt;
}
After gettin the function's result, you can chain a fetch method to its call, fetchColumn() in your case.
Given your code is mostly procedural, let me suggest you a very simple PDO wrapper I wrote. So the full code would be:
$sql = "SELECT error_desc FROM nt_errors WHERE error_code = ?";
$errorText = DB::run($sql,[$code])->fetchColumn();
if (!$errorText){
$errorText = 'ERROR: Failed to retrieve error';
}
Here DB class is a better replacement of your dbConnect() function, and run() method is a replacement for db_query_select() that actually can be used for any query type, including insert, update or anything.

use a PHP variable from an included file

hi I avec a php file (inc.db.php) which contains my config to connect to my db.
Into this file I have something like
$dbh = new PDO(DSN, USER, PASS);
In a other file I included inc.db.php and in one function I want to use the $dbh variable.
My function is :
function getPassword($utilisateur) {
$uid = addslashes( $utilisateur );
$sql = "SELECT password FROM cc_users WHERE uid='$uid'";
$sth = $dbh->query($sql);
$result = $sth->fetchAll();
if (count($result) == 1) {
return TRUE;
} else {
return FALSE;
}
}
I got an error
PHP Notice: Undefined variable: dbh in /....
How I can do to use the variale included in a external file?
From the PHP Manual:
Any variable used inside a function is by default limited to the local
function scope.
(...)
In PHP global variables must be declared global inside a function if
they are going to be used in that function.
(...)
A second way to access variables from the global scope is to use the
special PHP-defined $GLOBALS array.
You'll avoid the error changing the function to this:
function getPassword($utilisateur) {
global $dbh;
$uid = addslashes( $utilisateur );
$sql = "SELECT password FROM cc_users WHERE uid='$uid'";
$sth = $dbh->query($sql);
$result = $sth->fetchAll();
if (count($result) == 1) {
return TRUE;
} else {
return FALSE;
}
}
But the usage of global variables is considered a bad practice.
Also, using addslashes won't protect your query against SQL injection attacks.
Prepare the SQL statements or use the quote method.

Can't pass mysqli object to class in PHP

So I'm working on a simple user class in php, which has a class variable which contains the mysqli object, however I keep getting the error:
Fatal error: Call to a member function real_escape_string() on a non-object in */classes/user.php on line X
I've checked everything, it should work, but it doesn't. Somehow. This is my code:
namespace bibliotheek;
class user
{
private $mysql;
private $logged_in = false;
private $user_data = null; //ARRAY: user_id, e-mail, password, bevoegdheid, naam, achternaam, adres, postcode, stad
function __construct(\mysqli $mysql, $salt)
{
$this->mysql = $mysql;
}
public function login($email, $pass, $hash = false)
{
$email = $this->mysql->real_escape_string($email);
if($hash == false)
$pass = sha1($this->salt.$pass);
$query = "SELECT *
FROM gebruikers
WHERE gebruikers.email = '$email' AND gebruikers.password = '$pass'";
$result = $this->mysql->query($query);
$user_data = $result->fetch_assoc();
if($user_data == null)
return;
$this->logged_in = true;
$this->user_data = $user_data;
$this->create_cookies($email, $pass);
}
}
And this is how the mysqli object gets passed to the class:
$mysql = new mysqli($cfg['mysql_server'], $cfg['username'], $cfg['password'], $cfg['database']);
$user = new bibliotheek\user($mysql, $cfg['salt']);
the mysql login data is correct, I've made sure of that.
I must be missing something really obvious here, but I just can't see it. Any help is greatly appreciated. Thanks!
And this is how it should be
error_reporting(E_ALL);
$mysql = new mysqli($cfg['mysql_server'], $cfg['username'], $cfg['password'], $cfg['database']);
if ( !$mysql )
{
throw new Exception(mysqli_connect_error()));
}
$user = new bibliotheek\user($mysql, $cfg['salt']);
I'm really f-ing stupid, I compacted my code a bit when I posted it on here and I left out this part:
$this->mysql = $mysql;
$this->mysql = $salt;
Kill me now.

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