php if condition - php

I can't find anything wrong with this... This should work right?
function ConfirmedNumber()
{
$rs = mysql_query("CALL ConfirmedNumber('" , $_SESSION['UserID'] . "',#Active)");
while ($row = mysql_fetch_assoc($rs))
{
if ($row['Active'] = 1)
{
return true;
}
}
return false;
}
Assuming the Stored procedure returns a single row with the value '1' in it then I can call the function like this right?
if (ConfirmedNumber())
{
//do some stuff.
}

To expand on my comment:
if ($row['Active'] = 1) should be if ($row['Active'] == 1) to work correctly.
If you want to avoid accidentally doing this in future, you could write your if statements like this:
if (1 == $row['Active'])
This way, you can't accidentally use = as PHP will throw a Fatal Error. You can read more about Comparison Operators at PHP.net
Comment below with the full answer:
The call to the stored proc... line $rs = mysql_query("CALL ConfirmedNumber('" . $_SESSION['UserID'] . "',#Active)"); had a comma instead of the period in the initial post.

you forgot your operator in your IF statement. Change it to this:
if ($row['Active'] == 1)
or even shorter
if ($row['Active'])

it can be something like this
function ConfirmedNumber($id)
{
$rs = mysql_query("CALL ConfirmedNumber('" . $id . "',#Active)");
while ($row = mysql_fetch_assoc($rs))
{
if ($row['Active'] == 1)
{
return true;
}
}
return false;
}
ConfirmedNumber($_SESSION['UserID']);

Related

Working with multiple rows from a MySQL query

Before I begin, I want to point out that I can solve my problem. I've rehearsed enough in PHP to be able to get a workaround to what I'm trying to do. However I want to make it modular; without going too much into detail to further confuse my problem, I will simplify what I am trying to do so that way it does not detract from the purpose of what I'm doing. Keep that in mind.
I am developing a simple CMS to manage a user database and edit their information. It features pagination (which works), and a button to the left that you click to open up a form to edit their information and submit it to the database (which also works).
What does not work is displaying each row from MySQL in a table using a very basic script which I won't get into too much detail on how it works. But it basically does a database query with this:
SELECT * FROM users OFFSET (insert offset here) LIMIT (insert limit here)
Essentially, with pagination, it tells what number to offset, and the limit is how many users to display per page. These are set, defined, and tested to be accurate and they do work. However, I am not too familiar how to handle these results.
Here is an example query on page 2 for this CMS:
SELECT * FROM users OFFSET 10 LIMIT 10
This should return 10 rows, 10 users down in the database. And it does, when I try this command in command prompt, it gives me what I need:
But when I try to handle this data in PHP like this:
<?php
while ($row = $db->query($pagination->get_content(), "row")) {
print_r($row);
}
?>
$db->query method is:
public function query($sql, $type = "assoc") {
$this->last_query = $sql;
$result = mysql_query($sql, $this->connection);
$this->confirm_query($result);
if ($type == "row") {
return mysql_fetch_row($result);
} elseif ($type == "assoc" || true) {
return mysql_fetch_assoc($result);
} elseif ($type == "array") {
return mysql_fetch_array($result);
} elseif ($type == false) {
return $result;
}
}
$pagination->get_content method is:
public function get_content() {
global $db;
$query = $this->base_sql;
if (!isset($_GET["page"])) {
$query .= " LIMIT {$this->default_limit}";
return $query;
} elseif (isset($_GET["page"]) && $_GET["page"] == 1) {
$query .= " LIMIT {$this->default_limit}";
return $query;
} elseif (isset($_GET["page"])) {
$query .= " LIMIT {$this->default_limit}";
$query .= " OFFSET " . (($_GET["page"] * $this->default_limit) - 10);
return $query;
}
}
And my results from the while loop (which should print out each row of the database, no?) gives me the same row everytime, continuously until PHP hits the memory limit/timeout limit.
Forgive me if its something simple. I rarely ever handle database data in this manner. What I want it to do is show the 10 users I requested. Feel free to ask any questions.
AFTER SOME COMMENTS, I'VE DECIDED TO SWITCH TO MYSQLI FUNCTIONS AND IT WORKS
// performs a query, does a number of actions dependant on $type
public function query($sql, $type = false) {
$sql = $this->escape($sql);
if ($result = $this->db->query($sql)) {
if ($type == false) {
return $result;
} elseif ($type == true || "assoc") {
if ($result->num_rows >= 2) {
$array;
$i = 1;
while ($row = $result->fetch_assoc()) {
$array[$i] = $row;
$i++;
}
return $array;
} elseif ($result->num_rows == 1) {
return $result->fetch_assoc();
}
} elseif ($type == "array") {
if ($result->num_rows >= 2) {
$array;
$i = 1;
while ($row = $result->fetch_array()) {
$array[$i] = $row;
$i++;
}
return $array;
} elseif ($result->num_rows == 1) {
return $result->fetch_array();
}
}
} else {
die("There was an error running the query, throwing error: " . $this->db->error);
}
}
Basically, in short, I took my entire database, deleted it, and remade another one based on the OOD mysqli (using the class mysqli) and reformatted it into a class that extends mysqli. A better look at the full script can be found here:
http://pastebin.com/Bc00hESn
And yes, it does what I want it to. It queries multiple rows, and I can handle them however I wish using the very same methods I planned to do them in. Thank you for the help.
I think you should be using mysql_fetch_assoc():
<?php
while ($row = $db->query($pagination->get_content())) {
print_r($row);
}
?>

php while loop running only once

I have a php script for check the availability of some data. I call this script from external jquery. the jquery is running fine. here is my php:
<?php
$avares = checkAva($fi_nm, $tbl_nm, $txtval);
echo $avares;
function checkAva($field, $table, $curval) {
$avres = mysql_query("SELECT " . $field . " FROM " . $table . "") or die("query failed");
while ($a_row = mysql_fetch_array($avres)) {
$dbval = $a_row[$field];
if ($curval == $dbval) {
return "no";
} else {
return "yes";
}
}
}
?>
$curval is the variable coming from external jquery. my problem is that the while loop seems to run only once though there are lot of entries in the DB. I checked it with an integer variable and the while loop seems to run only once. can you help me to solve that?
Look at your code.
while ($a_row = mysql_fetch_array($avres)) {
$dbval = $a_row[$field];
if ($curval == $dbval) {
return "no";
} else {
return "yes";
}
}
you have used return, if its true it returns and false then also returns change those according to your needs. The return statement immediately ends execution of the current function
It will by design as you have a return statement. From what you have said your not actually wanting it to return but to set a variable that at end of execution will return no or yes. I could be wrong on this but hey ho.
<?php
echo checkAva($fi_nm, $tbl_nm, $txtval);
function checkAva($field, $table, $curval) {
$avres = mysql_query("SELECT " . $field . " FROM " . $table) or die("query failed");
$noOrYes = "yes";
while ($a_row = mysql_fetch_array($avres)) {
if($curval == $a_row[$field]) {
$noOrYes = "no";
}
}
return $noOrYes;
}
?>
The possible issue that can cause Loop to iterate once are:
Error in the Variable used for the $query and $result
Same name Variable inside and outside of the Loop
Incorrect placement of Return statement
Invalid Mysql Statement
Directly put the condition in your Query like
function checkAva($field, $table, $curval) {
$avres = mysql_query("SELECT " . $field . " FROM " . $table . "
WHERE `".$field."` = '".$curVal."'");
$res = mysql_fetch_array($avres);
if(is_array($res) && count($res) > 0)
return "Yes";
else
return "No";
}
Instead of getting all the results and checking with each one of the result you directly put a condition to extract the results which satisfies your condition.This will be suggestable if you have many records.
You need to put one of the return outside of the while loop.
For example if you just wanted to check if $curval == $dbval
while ($a_row = mysql_fetch_array($avres)) {
$dbval = $a_row[$field];
//If the condition was met return with a no
if ($curval == $dbval) {
return "no";
}
}
//If the condition was not met return yes
return yes;
That's basically what you need to do so the loop will run until your condition was met or not at all.

Converting mysql_* to mysqli_* issue with mysql_result [duplicate]

I'm porting some old PHP code from mysql to MySQLi, and I've ran into a minor snag.
Is there no equivalent to the old mysql_result() function?
I know mysql_result() is slower than the other functions when you're working with more than 1 row, but a lot of the time I have only 1 result and 1 field. Using it lets me condense 4 lines into 1.
Old code:
if ($r && mysql_num_rows($r))
$blarg = mysql_result($r, 0, 'blah');
Desired code:
if ($r && $r->num_rows)
$blarg = $r->result(0, 'blah');
But there is no such thing. :(
Is there something I'm missing? Or am I going to have to suck it up and make everything:
if ($r && $r->num_rows)
{
$row = $r->fetch_assoc();
$blarg = $row['blah'];
}
The following function fully replicates the mysql_result() function, and returns false when you are out-of-bounds on your request (empty result, no row of that number, no column of that number). It does have the added benefit that, if you don't specify the row, it assumes 0,0 (one less value to be passed). The function allows for the numerical offset of the field or the field name.
function mysqli_result($res,$row=0,$col=0){
$numrows = mysqli_num_rows($res);
if ($numrows && $row <= ($numrows-1) && $row >=0){
mysqli_data_seek($res,$row);
$resrow = (is_numeric($col)) ? mysqli_fetch_row($res) : mysqli_fetch_assoc($res);
if (isset($resrow[$col])){
return $resrow[$col];
}
}
return false;
}
PHP 5.4 now supports function array dereferencing and 7.0 supports a null coalescing operator, which means you can simply do this:
$value = $r->fetch_assoc()['blah'] ?? false;
or even more generic variant where you don't need to supply the column name,
$value = $r->fetch_row()[0] ?? false;
note that you don't even need the if ($r && $r->num_rows) condition.
You can do this by fetching an object instead of an array.
$mysqli->query("SELECT email FROM users WHERE userid = 'foo'")->fetch_object()->email;
function db_result($result,$row,$field) {
if($result->num_rows==0) return 'unknown';
$result->data_seek($row);
$ceva=$result->fetch_assoc();
$rasp=$ceva[$field];
return $rasp;
}
Well, you can always shorten it to something like this:
if ($r && $r->num_rows)
list($blarg) = $r->fetch_row();
But that might be as good as you're going to get.
I suggest you to add this line to Cris' solution in order to be able to get a result by both doing db_result('mytable.myfield) and db_result('myfield') since it is the default behavior of the original mysql_result function.
function db_result($result,$row,$field) {
if($result->num_rows==0) return 'unknown';
$result->data_seek($row);
$ceva=$result->fetch_assoc();
return (isset($ceva[$field])?$ceva[$field]
:(strpos($field,'.')?$ceva[substr($field,strrpos($field,'.')+1)]:''));
}
I use the following function to replace mysql_result()
function mysqli_result($result, $iRow, $field = 0)
{
if(!mysqli_data_seek($result, $iRow))
return false;
if(!($row = mysqli_fetch_array($result)))
return false;
if(!array_key_exists($field, $row))
return false;
return $row[$field];
}
I ended up using a custom function using procedural style:
function mysqli_result($res, $row, $field=0) {
mysqli_data_seek($res, $row);
return mysqli_fetch_array($res)[$field];
}
Reference: https://www.sitepoint.com/community/t/change-mysql-result-to-mysqli/190972/6
You don't need mysql_result() or any similar function.
If you would like to access any column from any row in the result set, the best way is to fetch all into an array using mysqli_fetch_all().
$data = $result->fetch_all(MYSQLI_BOTH);
$var1 = $data[0]['column']; // column from the first row
$var2 = $data[1][2]; // third column from the second row
To prevent access to non-existent values, you can use the null-coalesce operator and provide default value. e.g. $data[1][2] ?? null;.
As of PHP 8.1, mysqli also offers method called fetch_column(). You can use it if you only want to fetch a single value from the result.
$value = $mysqli->query("SELECT email FROM users WHERE userid = 'foo'")->fetch_column(0);
If you select only ONE field in the query and you only expect a single returned data of a selected field, then this works:
function mysqli_datum($result)
{
if ($result->num_rows == 0)
return;
$result->data_seek(0);
$row=$result->fetch_row();
return $row[0];
}
Here's an adaptation of Mario Lurig's answer using a mysqli_result object instead of the procedural version of mysqli.
/**
* Accepts int column index or column name.
*
* #param mysqli_result $result
* #param int $row
* #param int|string $col
* #return bool
*/
function resultMysqli(mysqli_result $result,$row=0,$col=0) {
//PHP7 $row can use "int" type hint in signature
$row = (int)$row; // PHP5 - cast to int
if(!is_numeric($col) ) { // cast to string or int
$col = (string)$col;
} else {
$col = (int)$col;
}
$numrows = $result->num_rows;
if ($numrows && $row <= ($numrows-1) && $row >=0) {
$result->data_seek($row);
$resrow = (is_numeric($col)) ? $result->fetch_row() : $result->fetch_assoc();
if (isset($resrow[$col])){
return $resrow[$col];
}
}
return false;
}
This is a good answer, from http://php.net/manual/es/class.mysqli-result.php
<?php
function mysqli_result($result,$row,$field=0) {
if ($result===false) return false;
if ($row>=mysqli_num_rows($result)) return false;
if (is_string($field) && !(strpos($field,".")===false)) {
$t_field=explode(".",$field);
$field=-1;
$t_fields=mysqli_fetch_fields($result);
for ($id=0;$id<mysqli_num_fields($result);$id++) {
if ($t_fields[$id]->table==$t_field[0] && $t_fields[$id]->name==$t_field[1]) {
$field=$id;
break;
}
}
if ($field==-1) return false;
}
mysqli_data_seek($result,$row);
$line=mysqli_fetch_array($result);
return isset($line[$field])?$line[$field]:false;
}
?>

How to check if results on while($row = mysql_fetch_array in PHP

Im trying to figure out how to handle this is no results are returned, how would I code that?
while($row = mysql_fetch_array($Result))
So like if there a results: print them out
else: show a link
http://ca3.php.net/manual/en/function.mysql-num-rows.php
if(mysql_num_rows($result) > 0) {
while($row = mysql_fetch_array($result)) { ... }
} else {
// show link
}
You can use mysql_num_rows() to tell you how many results are found. Using that with a simple if-statement, and you can determine what action to take.
if (mysql_num_rows($result) > 0) {
// do while loop
} else {
// show link
}
Others suggest using mysql_num_rows() but you should be aware that that function works only if you use a buffered query. If you query using mysql_unbuffered_query(), the number of rows in the result is not available.
I would use a simple flag variable:
$found_row = false;
while ($row = mysql_fetch_array($result)) {
$found_row = true;
. . .
}
if ($found_row == false) {
// show link
}
It may seem redundant to set $found_row to true repeatedly, but assigning a literal value to a variable ought to be an insignificant expense in any language. Certainly it is small compared to fetching and processing an SQL query result.
Use even shorter syntax without insignificant mysql_num_rows to save processor time:
if($result) {
// return db results
} else {
// no result
}
I might have figured it out:
if (!($row = mysql_fetch_array($descResult)))
{
echo "<tr><td>Add Link</td></tr>";
}
This can be done without mysql_num_rows() or an additional (flag) variable
if ( false===($row=mysql_fetch_array($result, MYSQL_ASSOC)) ) {
echo 'no rows in result set';
}
else {
do {
echo $row['X'];
} while ( false===($row=mysql_fetch_array($result, MYSQL_ASSOC)) );
}
but it duplicates the actual fetch command (one in the if-statement and one in the while-clause).

MySQLi equivalent of mysql_result()?

I'm porting some old PHP code from mysql to MySQLi, and I've ran into a minor snag.
Is there no equivalent to the old mysql_result() function?
I know mysql_result() is slower than the other functions when you're working with more than 1 row, but a lot of the time I have only 1 result and 1 field. Using it lets me condense 4 lines into 1.
Old code:
if ($r && mysql_num_rows($r))
$blarg = mysql_result($r, 0, 'blah');
Desired code:
if ($r && $r->num_rows)
$blarg = $r->result(0, 'blah');
But there is no such thing. :(
Is there something I'm missing? Or am I going to have to suck it up and make everything:
if ($r && $r->num_rows)
{
$row = $r->fetch_assoc();
$blarg = $row['blah'];
}
The following function fully replicates the mysql_result() function, and returns false when you are out-of-bounds on your request (empty result, no row of that number, no column of that number). It does have the added benefit that, if you don't specify the row, it assumes 0,0 (one less value to be passed). The function allows for the numerical offset of the field or the field name.
function mysqli_result($res,$row=0,$col=0){
$numrows = mysqli_num_rows($res);
if ($numrows && $row <= ($numrows-1) && $row >=0){
mysqli_data_seek($res,$row);
$resrow = (is_numeric($col)) ? mysqli_fetch_row($res) : mysqli_fetch_assoc($res);
if (isset($resrow[$col])){
return $resrow[$col];
}
}
return false;
}
PHP 5.4 now supports function array dereferencing and 7.0 supports a null coalescing operator, which means you can simply do this:
$value = $r->fetch_assoc()['blah'] ?? false;
or even more generic variant where you don't need to supply the column name,
$value = $r->fetch_row()[0] ?? false;
note that you don't even need the if ($r && $r->num_rows) condition.
You can do this by fetching an object instead of an array.
$mysqli->query("SELECT email FROM users WHERE userid = 'foo'")->fetch_object()->email;
function db_result($result,$row,$field) {
if($result->num_rows==0) return 'unknown';
$result->data_seek($row);
$ceva=$result->fetch_assoc();
$rasp=$ceva[$field];
return $rasp;
}
Well, you can always shorten it to something like this:
if ($r && $r->num_rows)
list($blarg) = $r->fetch_row();
But that might be as good as you're going to get.
I suggest you to add this line to Cris' solution in order to be able to get a result by both doing db_result('mytable.myfield) and db_result('myfield') since it is the default behavior of the original mysql_result function.
function db_result($result,$row,$field) {
if($result->num_rows==0) return 'unknown';
$result->data_seek($row);
$ceva=$result->fetch_assoc();
return (isset($ceva[$field])?$ceva[$field]
:(strpos($field,'.')?$ceva[substr($field,strrpos($field,'.')+1)]:''));
}
I use the following function to replace mysql_result()
function mysqli_result($result, $iRow, $field = 0)
{
if(!mysqli_data_seek($result, $iRow))
return false;
if(!($row = mysqli_fetch_array($result)))
return false;
if(!array_key_exists($field, $row))
return false;
return $row[$field];
}
I ended up using a custom function using procedural style:
function mysqli_result($res, $row, $field=0) {
mysqli_data_seek($res, $row);
return mysqli_fetch_array($res)[$field];
}
Reference: https://www.sitepoint.com/community/t/change-mysql-result-to-mysqli/190972/6
You don't need mysql_result() or any similar function.
If you would like to access any column from any row in the result set, the best way is to fetch all into an array using mysqli_fetch_all().
$data = $result->fetch_all(MYSQLI_BOTH);
$var1 = $data[0]['column']; // column from the first row
$var2 = $data[1][2]; // third column from the second row
To prevent access to non-existent values, you can use the null-coalesce operator and provide default value. e.g. $data[1][2] ?? null;.
As of PHP 8.1, mysqli also offers method called fetch_column(). You can use it if you only want to fetch a single value from the result.
$value = $mysqli->query("SELECT email FROM users WHERE userid = 'foo'")->fetch_column(0);
If you select only ONE field in the query and you only expect a single returned data of a selected field, then this works:
function mysqli_datum($result)
{
if ($result->num_rows == 0)
return;
$result->data_seek(0);
$row=$result->fetch_row();
return $row[0];
}
Here's an adaptation of Mario Lurig's answer using a mysqli_result object instead of the procedural version of mysqli.
/**
* Accepts int column index or column name.
*
* #param mysqli_result $result
* #param int $row
* #param int|string $col
* #return bool
*/
function resultMysqli(mysqli_result $result,$row=0,$col=0) {
//PHP7 $row can use "int" type hint in signature
$row = (int)$row; // PHP5 - cast to int
if(!is_numeric($col) ) { // cast to string or int
$col = (string)$col;
} else {
$col = (int)$col;
}
$numrows = $result->num_rows;
if ($numrows && $row <= ($numrows-1) && $row >=0) {
$result->data_seek($row);
$resrow = (is_numeric($col)) ? $result->fetch_row() : $result->fetch_assoc();
if (isset($resrow[$col])){
return $resrow[$col];
}
}
return false;
}
This is a good answer, from http://php.net/manual/es/class.mysqli-result.php
<?php
function mysqli_result($result,$row,$field=0) {
if ($result===false) return false;
if ($row>=mysqli_num_rows($result)) return false;
if (is_string($field) && !(strpos($field,".")===false)) {
$t_field=explode(".",$field);
$field=-1;
$t_fields=mysqli_fetch_fields($result);
for ($id=0;$id<mysqli_num_fields($result);$id++) {
if ($t_fields[$id]->table==$t_field[0] && $t_fields[$id]->name==$t_field[1]) {
$field=$id;
break;
}
}
if ($field==-1) return false;
}
mysqli_data_seek($result,$row);
$line=mysqli_fetch_array($result);
return isset($line[$field])?$line[$field]:false;
}
?>

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