Php Dynamic Menubar code error - php

Question

I am having a problem with making the links in my bar work properly the database is setup like so my db http://bloodkittens.com/resources/upload/db.png
<?php
error_reporting(E_ALL);
ini_set('display_errors', '1');
mysql_connect("localhost", "dbuser", "******");
mysql_select_db("guild");
// prepare special array with parent-child relations
$menuData = array(
'items' => array(),
'parents' => array()
);
$result = mysql_query("SELECT id_menu id, parentID_menu parentId, label_menu name FROM main_menu` ORDER BY parentID_menu");
while ($menuItem = mysql_fetch_assoc($result))
{
$menuData['items'][$menuItem['id']] = $menuItem;
$menuData['parents'][$menuItem['parentId']][] = $menuItem['id'];
}
// menu builder function, parentId 0 is the root
function buildMenu($parentId, $menuData)
{
$html = '';
$parent='';
if (isset($menuData['parents'][$parentId]))
{
$menuClass= ($parentId==0) ? ' class="navbar" id="navbar"' : '';
$parent= ($parentId==0) ? 0 : 1;
$html = "<ul{$menuClass}>\n";
foreach ($menuData['parents'][$parentId] as $itemId)
{
//subment
$result=mysql_query("select * from main_menu where parentID_menu='$itemId'");
if (mysql_num_rows($result)>(int)0 && $parentId!=0) {
$subm =' class="navbar"';
}else{
$subm ='';
}
//end
$menu = $parentId == 0 ? ' class="menulink"' : ''; //class of main menu
$html .= '<li>' . "<a{$subm}{$menu} href=\"#\" >{$menuData['items'][$itemId]['name']}</a>";
// find childitems recursively
$html .= buildMenu($itemId, $menuData);
$html .= '</li>';
}
$html .= '</ul>';
}
return $html;
}
// output the menu
echo buildMenu(0, $menuData);
?>
How would i make it so that the value link_menu would be the href in the code for each separate entry in the db? rather then \'#\' because the code works completely and i'm very happy how it looks after i apply my css to it but the links aren't working

Answer 1

For work the menu sorting
must be add a new field in the table,
and change this query from
$result = mysql_query("SELECT id_menu id, parentID_menu parentId, label_menu name, link_menu link FROM main_menu ORDER BY parentID_menu");
to :
$result = mysql_query("SELECT id_menu id, parentID_menu parentId, label_menu name, link_menu link FROM main_menu ORDER BY menu_sort");

Answer 2

you never seem to select it
$result = mysql_query("SELECT id_menu id, parentID_menu parentId, label_menu, link_menu, name FROM main_menu ORDER BY parentID_menu");
and then..
$html .= '<li>' . "<a{$subm}{$menu} href=\"{$menuData['items'][$itemId]['link_menu']}\" >{$menuData['items'][$itemId]['name']}</a>";

Answer 3

Instead of href=\"#\" >, use this:
href=\"{$menuData['items'][$itemId]['link_menu']}\" >

Answer 4

the code that i used was in the end like this i think i got it to work by pure luck but regardless i win : )
<?php
error_reporting(E_ALL);
ini_set('display_errors', '1');
mysql_connect("localhost", "BloodKittens", "Zangoshi1");
mysql_select_db("bloodkittens");
// prepare special array with parent-child relations
$menuData = array(
'items' => array(),
'parents' => array(),
'links' => array()
);
$result = mysql_query("SELECT id_menu id, parentID_menu parentId, label_menu name, link_menu link FROM main_menu ORDER BY parentID_menu");
while ($menuItem = mysql_fetch_assoc($result))
{
$menuData['items'][$menuItem['id']] = $menuItem;
$menuData['parents'][$menuItem['parentId']][] = $menuItem['id'];
$menuData['links'] = $menuItem['link'];
}
// menu builder function, parentId 0 is the root
function buildMenu($parentId, $menuData)
{
$html = '';
$parent='';
if (isset($menuData['parents'][$parentId]))
{
$menuClass= ($parentId==0) ? ' class="navbar" id="navbar"' : '';
$parent= ($parentId==0) ? 0 : 1;
$html = "<ul{$menuClass}>\n";
foreach ($menuData['parents'][$parentId] as $itemId)
{
//subment
$result=mysql_query("select * from main_menu where parentID_menu='$itemId'");
if (mysql_num_rows($result)>(int)0 && $parentId!=0) {
$subm =' class="navbar"';
}else{
$subm ='';
}
//end
$menu = $parentId == 0 ? ' class="menulink"' : ''; //class of main menu
$html .= '<li>' . "<a{$subm}{$menu} href=\"{$menuData['items'][$itemId]['link']}\" >{$menuData['items'][$itemId]['name']}</a>";
// find childitems recursively
$html .= buildMenu($itemId, $menuData);
$html .= '</li>';
}
$html .= '</ul>';
}
return $html;
}
// output the menu
echo buildMenu(0, $menuData);
?>