javascript combo box - php

Question

I have used this function to call the following page depending on the chosen option.
The First IF will direct me to the Monthly report while the second IF will direct me to the Daily report
<script type="text/javascript">
function ActionDeterminator()
{
var monthly = document.myform.duration.options[0].value;
var daily = document.myform.duration.options[1].value;
if (monthly == 0){
document.myform.action = 'month.php';
}
if (daily == 1) {
document.myform.action = 'day.php';
}
}
</script>
I have also another function which will execute a job depending on the option. The first IF will convert my report to excel doc while the second IF will direct me to view page to print.
<script type="text/javascript">
function ActionDeterminator()
{
if(document.myform.group[0].checked == true) {
document.myform.action = 'excel.php';
}
if(document.myform.group[1].checked == true) {
document.myform.action = 'view.php';
}
return true;
}
</script>
The Problem:
the problem is that it does not direct me to the correct page (whether monthly or daily)... it only directs me to view page or exporting to excel. Could anyone teach me the correct way to do this function?
Also, I want to ask the correct javascript for combo box.

Answer 1

What you'll want to do is get all the form elements into an array, loop, and evaluate for checked equals true
For example:
var elems = document.getElementsByName('group');
for (var i=0; i<elems.length; i++) {
if (elems.item(i).checked == true) {
break;
}
}
switch (i) {
case 0:
//action = 'excel.php';
break
//case etc...
}