Msql Inner Join Query Dilemma - Need Joined Auto Increment Value - php

I have two mysql tables that I am querying together and the query works fine. The tables are car and requests
The problem is that i need both the auto increment id's and it only gives me one.
The one it gives me is not the joined tabled.
Here is my query so far
SELECT * FROM `car` INNER JOIN `requests` ON `car`.`make_id` = `requests`.`make_id` WHERE `car`.`user_id` =21
I just need to someway get the auto increment id of the requests table.
As always stack exchange is the best place to come for answers so thanks in advance!

Just specify your query as this and you'll get both but with different names:
SELECT `car`.id AS car_id, `requests`.id AS request_id, *
FROM `car`
INNER JOIN `requests` ON `car`.`make_id` = `requests`.`make_id`
WHERE `car`.`user_id` =21
Note that you will still have an ID column which SHOULD be the requests.id, just diregard it and use car_id and request_id...

When you have to join tables and table contains same name than it creates an ambiguous situation. So always use table name or table alias with column name Like this
SELECT t.column
FROM table as t
OR
SELECT table.column
FROM table

Related

How to change column name while joining the query in mysql

I need to change the column name while joining the MySQL query. I am explaining my code below.
select * from grc_action left join grc_users on grc_action.action_owner=grc_users.user_id
I am giving my table below.
grc_action:
id name action_owner
grc_users:
user_id name
The above is my table structure and as both has same column name i.e-name here I need to change the grc_users table column i.e-name while fetching the record. Please help me to solve this problem.
You can use AS
SELECT table1.name AS exampleName, table2.name AS otherName FROM sometable
You can also use this on tables:
SELECT vltn.id, vltn.name FROM veryLongTableName AS vltn
You dont need to type the AS, you can just do SELECT table1.name exampleName to shorten it, but it increases readbility and maintanability to write it, so I recommend doing it with AS.
You may assign different aliases to the name columns from the two different tables.
select
ga.id,
ga.name as action_name,
ga.action_owner,
gu.user_id,
gu.name as user_name
from grc_action ga
left join grc_users gu
on ga.action_owner = gu.user_id;
Note that I also used table aliases which make the query easier to read. In general, doing SELECT * is undesirable, and it is usually better to explicitly list the columns you want.
select *
from grc_action
left join grc_users on grc_action.action_owner=grc_users.user_id
changed query use this query
select *,grc_users.name as grcuser_name,grc_action.name as grcaction_name
from grc_action
left join grc_users on grc_action.action_owner=grc_users.user_id
Here geting two name like this
grcuser_name ,
grcaction_name

How to get value from one table column when two columns of the same name exist in an sql join

I am currently faced with the problem of trying to get a value when I have joined two tables with columns of the same name eg: table1.date and table2.date (date is different in each table) how would I get the "date" of table 1 in this instance.
I am currently running
while($row = $mysqliquery->fetch_object()) {
is there any way that I could use some form of syntax to retrieve the date from table 1 within the following code
$row->date eg $row->table1.date or something
If not how else would I be able to accomplish this?
Thanks.
You should differentiate between 2 columns with the same name by using an alias for one or both of the 2 columns in the query like this
SELECT a.`date`, b.`date` as b_date
FROM table1 a
JOIN table2 b ON a.id = b.a_id
WHERE some specific criteria
Now when your retrieve the ROW each date has its own unique name i.e.
$row->date;
$row->b_date;
I was thinking more along the lines of this ( ficticious ) pseudo sql
select a.`account_id`, a.`date` as 'account_date', u.`date` as 'signup_date'
from `accounts` a
left outer join `users` u on u.`uid`=a.`uid`
Each table has a column called date but in the sql they are each referenced with a unique alias. You cannot have two columns in the same query with the same name or you'll get errors, so you give them an alias. The tables are also aliased in this code - it really helps simplify things in my opinion... Anyway, just a quick example to illustrate how you might approach this - others may have a different approach from which I might learn new tricks

Searching multiple tables in MySQL database

I have several different tables in my database(mySQL).
Here are the relevant coumns for the tables
table_tournaments
tournamentId
tournamnetName
tournamentStatus
table_tournament_results
tournamentId
playerId
playerName
playerRank
tournamnetParticipants
table_players
playerId
playerName
The tournaments table contains the information about the tournament, the tournament results table shows the results from that table
I want to search the tournaments table by name and then with the returned results get the information from the tournament results table.
SELECT * FROM `tournaments` `WHERE` `tournamentName` LIKE "%Query%"
I'm not sure how to go about this, maybe I need to do something via PHP, any and all help is appreciated.
You can get the results you want with a join operation.
This is an example of an outer join, returning all rows from t that have the string 'foo' appearing as part of tournament_name, along with any matching rows from r.
A relationship between rows in the two tables is established by storing a common value in the tournamentId column of the two tables. The predicate in the ON clause specifies the condition that determines if a row "matches".
SELECT t.tournamentId
, t.tournamentName
, t.tournamentStatus
, r.playerId
, r.playerName
, r.playerRank
FROM table_tournaments t
LEFT
JOIN table_tournament_results r
ON r.tournamentId = t.tournamentId
WHERE t.tournament_name LIKE '%foo%'
ORDER
BY t.tournamentId
, r.playerId
The t and r that appear after the table names are table aliases, we can qualify references to the columns in each table by prefacing the column name with the table alias and a dot. This makes the column reference unambiguous. (In the case of tournamentId, MySQL doesn't know if you are referring to the column in t or r, so we qualify it to make it explicit. We follow this same pattern for all column references. Then, someone reading the statement doesn't need to wonder which table contains the column playerId.
Your Query may be like this
SELECT a.*, b.tournamnetName FROM table_tournament_results a
left join table_tournaments on a.tournamentId=b.tournamentId
WHERE b.tournamnetName LIKE "%Query%"

Get MySQL table.column named records with PHP

For example:
I have the normal column name:
SELECT column FROM....
The way i retrieve it in PHP:
$var = $row["column"];
What i want to know is how to retrieve column records which are named with column and table:
SELECT table.column FROM...
It works the exact same way, it's not going to be prefixed with a table.
so if you do a SELECT table.* FROM ..., and one of the column names is tacos. you can still do $row['tacos'].
Now, if you're doing multiple tables (joins) it can get ambiguous if they have the same names, such as "id". So you can alias them... SELECT table.column as new_name FROM ...
You won't get them returned with table.column. Perhaps use an alias? Could use a delimiter between table / field name part.
SELECT column AS tableName_ColumnName FROM....
It sounds to me like you're trying to select from multiple tables which can be done by using joins:
Lets say you have 3 tables that you need to obtain information from all by a unique ID. You can accomplish this by using a left join:
SELECT a.uniqid, a.testingDate, a.testscore, a.testresults,b.email_addy, b.phone1, c.testlevel as tlevel
FROM Tbl1 a
LEFT JOIN Tbl2 b
ON a.Tbl1 = b.Tbl2
LEFT JOIN Tbl3 c
on a.Tbl1 = c.Tbl3
you can then pull the information just as you always do: $var = $row['testingdate']

Getting SQL result as nested array in PHP

I've a ('courses') table that has a HABTM relationship with ('instructors') table through another table...
I want to get the data of an instructor with all related courses in one query..
Currently, I have the following SQL:
SELECT *
FROM `instructors` AS `instructor`
LEFT JOIN `courses` AS `course`
ON `course`.`id` IN (
SELECT `course_id`
FROM `course_instructors`
WHERE `course_instructors`.`instructor_id` = `instructor`.`id`
)
WHERE `instructor`.`id` = 1
This SQL does what it should be doing, the only "problem" I have is that I get multiple rows for each joined rows.
My question is:
Can I get the result I want in one query? Or do I have to manipulate the data in PHP?
I'm using PHP and MySQL.
Each record of a query result set has the same format: same number of fields, same fields, same order of fields. You cannot change that.
SELECT *
FROM instructors AS instructor
LEFT JOIN
course_instructors
ON
instructor.id= course_instructors.instructor_id
LEFT JOIN
courses
ON
course_instructors.course_id = course.id
WHERE instructor.id = 1
This assumes the PK of course_instructors is (instructor_id,course_id)
Explanation of query:
First join + WHERE make sure you get the relevant instructor
Second join matches ALL the entries from the course_instructor table that belongs to this instructor. If none found, will return one row with NULL in all fields
Last join matches all relevant courses from the entries found from course_instructor If none would will return one record with NULL in all fields.
Again: important to use the right constraints to avoid duplicate data.
That's the nature of relational databases. You need to get the instructor first and then get the related courses. That's how I would do it and that's how I've been doing it. I'm not sure if there is a "hack" to it.

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