Find position and get before and after? - php

Question

$x = "P-29042011386693";
$array = "P-28042011135870,P-28042011132333,P-28042011384621,P-29042011386693,P-29042011384190,P-29042011388434,P-29042011382454,P-29042011385512,P-29042011383902";
$array = explode(",", $array);
$count = count($array);
$search = array_search($x, $array);
if (($search > 0) && ($search < $count)){
$before = $array[$search-1];
$after = $array[$search+1];
}elseif ($search == 0){
$before = NULL;
$after = $array[1];
}elseif ($search == $count){
$before = $array[$count-1];
$after = NULL;
}
What is the best way to detect the value before $x and the value after $x, and display $before or $after as blank if there is no result before/after $x?
So if $x was P-29042011383902 - $after would be blank and $before would be P-29042011385512
If $x was P-28042011135870 $before would be blank and $after would be P-28042011132333
Is my code above right?

Answer 1

$search = array_search($x, $array);
if (false === $search) {
throw new Exception('Not found', 404);
}
$before = isset($array[$search - 1]) ? $array[$search - 1] : null;
$after = isset($array[$search + 1]) ? $array[$search + 1] : null;

Answer 2

Something like this?
$eachone = explode (" ,", $row);
6 is $eachone[6]
5 is $eachone[6-1]
If i understood the question, that's it.
With new information:
The example at php.net is this:
$str = "Hello Friend";
$arr1 = str_split($str); and you get an array like this
Array
(
[0] => H[1] => e
[2] => l
[3] => l
[4] => o
[5] =>
[6] => F
[7] => r
[8] => i
[9] => e
[10] => n
[11] => d
)