Using the following code I am attempting to:
Test to see if one of the dynamically assigned field names has been submitted;
Use the "Actionable Code" to process the submitted information.
My problem lies in I am incapable of retrieving the appropriate dynamic variable name. $this->get_field_name('email_to') will output a name variable such as widget-mywidget[3][email_to]; but to access this value via PHP I need it in the form of $_POST['widget-mywidget'][3]['email_to'].
How can I go about solving this dilemma?
OUTPUTTED HTML:
<form id="widget-mywidget-3-osiris_contact" method="post" action="">
<fieldset>
<input type="text" name="widget-mywidget[3][user_name]">
<input type="text" name="widget-mywidget[3][user_email]">
<textarea name="widget-mywidget[3][user_message]"></textarea>
</fieldset>
<fieldset>
<input type="hidden" name="widget-mywidget[3][email_to]" value="">
<input type="hidden" name="widget-mywidget[3][email_subject]" value="">
<button type="submit" name="widget-mywidget[3][email_send]">Send</button>
</fieldset>
</form>
PROCESSING PHP:
if(in_array($this->get_field_name('email_to'), $_POST)){ // <--- Where I need help.
// Actionable Code
}
This is what $this->get_field_name does:
function get_field_name($field_name) {
return 'widget-' . $this->id_base . '[' . $this->number . '][' . $field_name . ']';
}
I suggest that you print_r($_POST) and compare it visually for better debugging...
(Or use a debugger...)
$thing = "widget-mywidget[3][email_to]";
$exp = explode("[", $thing);
$get_it = $_POST['".$exp[0]."[".$exp[1]."[".$exp[2]."'];
Try, if it works.
Related
i have a file 'colecting-data.html' with this code :
<html>
<body>
<form action="collect.php" method="get">
name : <input type="text" name="name">
email : <input type="text" name="email">
telephone: <input type="text" name="telephone">
<input type="submit" value="save">
</form>
</body>
</html>
i when to creat "collect.php" file to collect all the data (name email telephone)
and save then in another file "save.html" inside a table .
it will help me a lot if any one know how to do that .
Very quick & dirty answer, remember to sanitize your inputs.
<?php
//collect.php
$html = "<html><head><title>Test</title></head><body><table>";
foreach($_REQUEST as $k=>$v) {
$html .= "<tr><td>$k</td><td>$v</td></tr>";
}
$html .= "</table></body></html>";
file_put_contents('save.html',$html);
?>
As you can use this to learn, start with the basic way to do this before going for more advanced options...
First off, your form needs to be a POST, not a GET.
<form action="collect.php" method="POST">
This will POST the values to collect.php.
On collect.php, you'll need to collect the values;
<?php
if(isset($_POST['name']) {
// Do Something
;}
if(isset($_POST['email']) {
// Do Something
;}
if(isset($_POST['telephone']) {
// Do Something
;}
?>
From here, you can set the posted values as variables and then do whatever you want with them.
I am creating a web page where the user select a number via a form.
HTML:
<form method="POST" style="font-size: 30px">
<input type="number" id="idname" name = "na" value=168 />
<label for="idname" >Number< /label>
<p><input type = "submit" name = "gesendet" value="Submit" />
<input type = "reset" /> </p>
</form>
using php I want to insert a txt file according to the number, such as 12_.txt or 166_.txt
<?php
$txtfile='"txt/' . $_POST["na"] . '_.txt"';
readfile($txtfile);
?>
The $txtfile string is O.K when "echoing" and the readfile function works with me when I read a file without the $_POST variable, but this simple code is just not working for me !!
Change:
$txtfile='"txt/' . $_POST["na"] . '_.txt"';
To:
$txtfile = 'txt/' . $_POST["na"] . '_.txt';
(Notice the extra double quotes)
I want to pass two variable from POST, one is the text I write and the other one is the result of a query with I already have.But for some reason I am not getting the variable values. Can you help me?
This is my first page:
<form method="post" action="EliminarGrupos.php">
<label for="nomegrupo"><b>Editar nome do grupo 1 :</label</b><br>
<?php
while ($row = mysqli_fetch_array($result66)){
$result = $row['titulogrupo'];
$_POST['nomegrupo'] = $result; //saving first variable
?>
<input type="text" placeholder="<?php echo $result?>" name="grupo1" id="velhas"></td> //saving second variable
<?php } ?>
<input type="submit" name="submit_x" data-inline="true" value="Submeter">
</form>
This is my second page where I want the variables to appear
$variable = $_POST['nomegrupo'];
$variable2 = $_POST['grupo1'];
The placeholder attribute is for display purposes only. You need to set the value attribute to have it sent to the server.
To send a second value, just use a second <input> element. If you don't want it visible, set type attribute to hidden.
In addition, you are expecting an associative array from mysqli_fetch_array() which is not going to happen. Your HTML had a number of errors in it, which I think I've fixed below. You always need to escape output with htmlspecialchars(). You should separate your HTML and your PHP as much as possible.
<?php
$row = mysqli_fetch_assoc($result66);
$titulogrupo = htmlspecialchars($row["titulogrupo"]);
?>
<form method="post" action="EliminarGrupos.php">
<label for="velhas"><b>Editar nome do grupo 1 :</b></label><br/>
<input type="text" placeholder="" name="grupo1" id="velhas"/>
<input type="hidden" name="nomegrupo" value="<?=$titulogrupo?>"/>
<button type="submit" name="submit_x" data-inline="true">Submeter</button>
</form>
You get the $_POST data from the form submission, specfically from the name attributes. This is what gives the $_POST its information, which it retrieves from value, not placeholder, as you have it now.
<input name="grupo1" value="one"> will make $_POST['grupo1'] equal to one.
You also shouldn't set the $_POST variable on page 1 as you are currently doing, and should make the unchanged variable from the database call a hidden field:
Page 1:
<form method="post" action="EliminarGrupos.php">
<label for="nomegrupo"><b>Editar nome do grupo 1 :</label>
<?php
while ($row = mysqli_fetch_array($result66)){
$result = $row['titulogrupo'];
?>
<input type="text" value="<?php echo $result; ?>" name="grupo1" id="grupo1">
<input type="hidden" value="<?php echo $result; ?>" name="titlogrupo" id="titlogrupo">
<?php } ?>
<input type="submit" name="submit_x" data-inline="true" value="Submeter">
</form>
Page 2:
$variable1 = $_POST['titulogrupo']; // $row['titulogrupo']
$variable2 = $_POST['grupo1']; // Form input
Hope this helps! :)
I can't set a variable from a post array.
I have a simple form with a hidden field in it:
<input name="sid" type="hidden" id="sid" value="<?=$sid?>">
This hidden field gets sent off to a second file (exec.php) where I have the following code:
$sid = $_POST['sid'];
For some reason, when trying to set $sid, it gets a NULL value. For haha's, I ran the following:
foreach($_POST as $var => $value)
{
echo $var . ' : ' . $value . "<br>";
}
This provided a correct value of 1938 for sid. I've looked at this for 3 hours and can't find what is happening. I expect something extremely stupid...any thoughts?
Here is the form on enter.php
<form name="form1" method="post" action="exec.php">
<input name="sid" type="hidden" id="sid" value="<? echo($sid); ?>">
<input name="ticket_totals" type="hidden" id="ticket_totals" value="<?=$ticket_totals?>">
<input name="emp" type="hidden" id="emp" value="<?=$emp?>">
<input name="submit" type="submit" id="submit" value="Submit">
<input type="submit" name="submit" id="submit" value="Close">
</form>
Here is the POST output on exec.php:
type : Other
ticket_totals : 0
emp : 105
sid : 1939
submit : Submit
Okay - this was poor syntax on my part but now I'm curious as to why.
I left out quotation marks - the solution is as simple as this:
$sid = $_POST["sid"]
Now it works like a champ.
Any takers on why? I'd guess there is a setting in the php.ini that requires the quotes. Strangely enough, I have other variables called from the POST array that i'm not using quotes for and they're working fine...
Use Console in FireBug to inspect the POST request to see what is the sid value that is being sent.
If the sid value in request is ok, use var_dump($_POST["sid"]); to see the results on the server.
EDIT: it's considered good PHP style to use the quotes when accessing the associative array because quote-less keys are indistinguishable from constants:
define('myVar',3);
echo $array[myVar]; // retrieves $array[3], not $array['myVar'];
Try to echo the $sid instead of the <?=:
// Change that
<input name="sid" type="hidden" id="sid" value="<?=$sid?>">
// With that
<input name="sid" type="hidden" id="sid" value="<?php echo $sid; ?>">
also for the test time try to change the input type from hidden to text in order to be 100% sure the $sid contains a value.
Using quotes for associative array keys is mandatory, and while it may work without them, it's incorrect and erratic behavior is expected.
I had this same problem, trying to use $_POST[sid] as a variable. I'm am thinking that "sid" is a reserved or restricted variable name, because I changed my variable to $_POST[snid] and it worked just fine. This was my code
$sid = $_POST[sid];
$recipient = "($sid) ($_POST[sid])";
if ($_POST[sid] > 0)
{
$recipient = "It Worked";
}
print $recipient;
When I posted "&sid=15", the result was:
() (15)
Unbelievable. Impossible, right? All I did was change from using "sid" as the index to "snid", and it worked no problem.
So, don't ever use $_POST[sid].
I am trying to add commenting like StackOverflow and Facebook uses to a site I'm building. Basically, each parent post will have its own child comments. I plan to implement the front-end with jQuery Ajax but I'm struggling with how to best tackle the PHP back-end.
Since having the same name and ID for each form field would cause validation errors (and then some, probably), I added the parent post's ID to each form field. Fields that will be passed are commentID, commentBody, commentAuthor - with the ID added they will be commentTitle-12, etc.
Since the $_POST array_key will be different each time a new post is processed, I need to trim off the -12 (or whatever the ID may be) from the $_POST key, leaving just commentTitle, commentBody, etc. and its associated value.
Example
$_POST['commentTitle-12']; //how it would be received after submission
$_POST['commentTitle']; //this is what I am aiming for
Many thanks
SOLUTION
Thanks to CFreak-
//Basic example, not actual script
<?php
if (array_key_exists("send", $_POST)) {
$title = $_POST['title'][0];
$body = $_POST['body'][0];
echo $title . ', ' . $body;
}
?>
<html>
<body>
<form name="test" id="test" method="post" action="">
<input type="text" name="title[]"/>
<input type="text" name="body[]"/>
<input type="submit" name="send" id="send"/>
</form>
</body>
</html>
Update 2
Oops, kind of forgot the whole point of it - unique names (although it's been established that 1) this isn't really necessary and 2) probably better, for this application, to do this using jQuery instead)
//Basic example, not actual script
<?php
if (array_key_exists("send", $_POST)) {
$id = $_POST['id'];
$title = $_POST['title'][$id];
$body = $_POST['body'][$id];
echo $title . ', ' . $body;
}
?>
<html>
<body>
<form name="test" id="test" method="post" action="">
<input type="text" name="title[<?php echo $row['id'];?>]"/>
<input type="text" name="body[<?php echo $row['id'];?>]"/>
<input type="hidden" name="id" value="<?php echo $row['id']; //the ID?>"/>
<input type="submit" name="send" id="send"/>
</form>
</body>
</html>
PHP has a little trick to get arrays or even multi-dimensional arrays out of an HTML form. In the HTML name your field like this:
<input type="text" name="commentTitle[12]" value="(whatever default value)" />
(you can use variables or whatever to put in the "12" if that's what you're doing, the key is the [ ] brackets.
Then in PHP you'll get:
$_POST['commentTitle'][12]
You could then just loop through the comments and grabbing each by the index ID.
You can also just leave it as empty square brackets in the HTML:
<input type="text" name="commentTitle[]" value="(whatever default value)" />
That will just make it an indexed array starting at 0, if you don't care what the actual ID value is.
Hope that helps.
You just have to iterate through $_POST and search for matching keys:
function extract_vars_from_post($arr) {
$result = array();
foreach ($arr as $key => $val) {
// $key looks like asdasd-12
if (preg_match('/([a-z]+)-\d+/', $key, $match)) {
$result[$match[1]] = $val;
} else {
$result[$key] = $val;
}
}
return $result;
}
Didn't test the code, though