PHP - counting problem algorithm - php

Question

I need to get all the combinations and permutations of an array of array of values. See snippet for example:
$a = array(
1,
2
);
$b = array(
'foo',
'bar'
);
$params = array();
$params[] = $a;
$params[] = $b;
// What to do to $params so I can get the following combinations/permutations?
// 1,foo
// 2,foo
// 1,bar
// 2,bar
// foo,1
// bar,1
// foo,2
// bar,2
Keep in mind that the $params can be any size and the items in it can also be any size.

Answer 1

function all($array, $partial, &$result) {
if ($array == array()) {
$result[] = implode(',', $partial);
return;
}
for($i=0; $i<count($array);$i++) {
$e = $array[$i];
$a = $array;
array_splice($a, $i, 1);
foreach($e as $v) {
$p = $partial;
$p[] = $v;
all($a, $p, $result);
}
}
}
Test:
$a = array(1, 2, 3);
$b = array('foo', 'bar');
$c = array('a', 'b');
$params = array($a, $b, $c);
$result = array();
all($params, array(), $result);
print_r($result);
Note: if there is a chance for duplicates (arrays contain the same values) you can check for duplicates before inserting into the $result.

Answer 2

Here is my solution. It should work with any number of associative arrays, even if they contained nested associative arrays.
<?php
$a = array(1,2,3);
$b = array('foo','bar','baz', array('other','other2',array('other3','other4')));
$params = array();
$params[] = $a;
$params[] = $b;
$elements = array();
foreach($params as $param) {
addElement($param,$elements);
}
function addElement($arg,&$result) {
if(!is_array($arg)) {
$result[] = $arg;
} else {
foreach($arg as $argArray) {
addElement($argArray,$result);
}
}
}
for($i=0; $i<count($elements); $i++) {
$curElement = $elements[$i];
for($j=0; $j<count($elements); $j++) {
if($elements[$j] != $curElement) {
$final_results[] = $curElement.','.$elements[$j];
}
}
}
print_r($final_results);
?>
http://codepad.viper-7.com/XEAKFM

Answer 3

Here's a possible solution codepad...
$array = array(
0 => array(
'foo',
'bar'
),
1 => array(
1,
2,
3
),
2 => array(
'x',
'y',
'z'
),
3 => array(
7,
8,
9
)
);
array_permutations($array, $permutations);
print_r($permutations);
public function array_permutations($array, &$permutations, $current_key = 0, $current_subkey = 0)
{
if(!isset($array[$current_key][$current_subkey]))
{
return;
}
$current_val = $array[$current_key][$current_subkey];
foreach($array as $array_key => $row)
{
foreach($row as $row_key => $sub_val)
{
if($array_key === $current_key)
{
if($row_key !== $current_subkey)
{
$permutations[] = $current_val . ', ' . $sub_val;
}
}
else
{
$permutations[] = $current_val . ', ' . $sub_val;
}
}
}
$next_key = ($current_subkey == (count($array[$current_key]) - 1)) ? $current_key + 1 : $current_key;
$next_subkey = ($next_key > $current_key) ? 0 : $current_subkey + 1;
array_permutations($array, $permutations, $next_key, $next_subkey);
}

Answer 4

Try this out, hope this helps
$a = array(
1,
2,
4
);
$b = array(
'foo',
'bar',
'zer'
);
$c = array(
'aaa',
'bbb'
);
$params = array();
$params[] = $a;
$params[] = $b;
$params[] = $c;
$sizeofp = count($params);
for($i=0 ; $i < $sizeofp ; $i++){
foreach ($params[$i] as $paramA) {
for($j=0 ; $j < $sizeofp ; $j++){
if($j == $i){
continue;
}
foreach($params[$j] as $paramB){
echo "\n".$paramA.",".$paramB;
}
}
}
}