Ok, what I am trying to do is make a javascript loop of images, but first I have to get a list of the images. In javascript there is no way to directly grab this text file... http://www.ssd.noaa.gov/goes/east/tatl/txtfiles/ft_names.txt but it can be done eaisly in php, I am currently gettung the txt file using php, but the javascript cannot read the variable. How can I make javascript be able to read this variable. Here is what I have...
<?php
$file = "http://www.ssd.noaa.gov/goes/east/tatl/txtfiles/ft_names.txt"; //Path to your *.txt file
$contents = file($file);
$string = implode($contents);
echo $string;
?>
<script type="text/javascript">
function prnt() {
var whatever = "<?= $string ?>";
alert(whatever);
}
</script>
You can use echo or print to write to the page in PHP.
var whatever = "<?php echo $string; ?>";
Although, if the file has line breaks in it, you will need to remove those.
Make it a bit more interesting: go ahead and split the fields and use JSON encoding. It should read directly in javascript without needing to call JSON.parse() on the client.
<?php
$lines = file_get_contents('http://...');
$lines = explode("\n",trim($lines));
foreach ($lines as &$line) {
$line = preg_split('/,? /',$line);
}
$js = json_encode($lines);
?>
<!DOCTYPE HTML>
<html lang="en-US">
<head>
<meta charset="UTF-8">
<title></title>
</head>
<body>
<script type="text/javascript">
var dar = <?php echo $js; ?>;
</script>
</body>
</html>
You should also consider using a local proxy to cache the results of that file if you plan to run this frequently and especially if you are going to serve it up on a public web server somewhere. Store the file locally as "noaa_data.txt" and have a second script on a cron job (12 hours or something):
<?php
file_put_contents("/var/www/noaa_data.txt",file_get_contents("http://www.ssd.noaa.gov/goes/east/tatl/txtfiles/ft_names.txt"));
?>
Related
I need to display html source code form other php file.
I have two file
code.php
index.php (I hope I can convert the code.php to html source code.)
code.php:
<!DOCTYPE html> <html> <body> <?php $color = "red"; echo $color; ?> </body> </html>
index.php (I hope I can convert the code.php to html source code.)
$php_to_html = file_get_contents("code.php");
$html_encoded = htmlentities($php_to_html);
echo $html_encoded;
but when i run the index.php file, the result is
<!DOCTYPE html> <html> <body> <?php $color = "red"; echo $color; ?> </body> </html>
but I hope I can see the result is
<!DOCTYPE html> <html> <body> red </body> </html>
any idea how can i do this ,thanks!!!
You want to execute the PHP, so include it and capture the output:
ob_start();
include("code.php");
$php_to_html = ob_get_clean();
$html_encoded = htmlentities($php_to_html);
echo $html_encoded;
If you want the HTML to be rendered as HTML then don't use htmlentities().
Optionally (not the best way) but you can execute it by retrieving from the URL:
$php_to_html = file_get_contents("http://www.example.com/code.php");
$html_encoded = htmlentities($php_to_html);
echo $html_encoded;
Buffer output and include it:
ob_start();
include_once('code.php');
$html = ob_get_clean();
By using output buffering, any output is not sent to the browser, but instead kept in memory. This allows you to run the code, and get the output as a variable. ob_get_clean() flushes the buffer (in this case into our $html variable), and then stops buffering, allowing you to continue as normal. :-)
I am trying to send the information as a mail to the admin
Below is the mail code and I am reading this using file_get_contents() in another file.
<!doctype html>
<?php
require_once("mysqlconnect.php");
session_start();
?>
<html>
<head>
<link rel="stylesheet" href="css/mail.css">
</head>
<body>
<table border="2">
<?php
$q="select * from profile where mobile=2147483647";
$result=mysqli_query($conn,$q);
while($row = mysqli_fetch_assoc($result))
{
foreach($row as $key=>$value)
{
if($key=="Email")
echo"<tr><th>$key</th><td><a href='mailto:$value; target='_blank'>$value</td></tr>";
else
echo"<tr><th>".str_replace('_',' ',$key)."</th> <td>$value</td></tr>";
}
}
?>
</table>
</body>
</html>
<?php
session_destroy();
?>
The result of this code in the mail is the PHP code itself..
$value) { if($key=="Email") echo"
$key $value
"; else echo"
".str_replace('_',' ',$key)." $value
"; } } ?>
file_get_contents returns the content of a file as string. It does not executes the code inside it.
To use the HTML from a php file you can use php's buffer.
Like this:
ob_start();
include('file_path_here');
$HTML = ob_get_clean();
This will store the output of the file in the $HTML variable.
file_get_contents literally reads in a file as a string. If you're reading in a PHP file using that method, it'll literally return the code, which is what you're getting.
If you want to send HTML as an e-mail, use something like a template system (sitecrafting.com/blog/top-5-php-template-engines) or build a string and pass it onto the mail() function.
PHP documentation: file_get_contents
I'm trying to figure out how to update my live data, I found some examples on Google of Ajax but I can't seem to get them to work.
The part that contains and places the live data in a paragraph is :
$file = "Data.txt";
$data = file($file);
$line = $data[count($data)-1];
for($i=1;$i<6;$i++){
switch ($line) {
case $i:
echo "<p class ='bus".$i."'> <img id='bus' src = 'bus.png'> </p>";
break;
}
}
This is the full html file
<!DOCTYPE>
<html>
<head>
<title>Bus</title>
<link rel="stylesheet" href="stijlenbestand.css">
</head>
<body>
<?php
//aanmaken 5 bushaltes
echo '<figure>';
for($i=1;$i<6;$i++){
echo "<img src = 'bushalte.png'>";
}
echo '</figure>';
//laatste lijn van tekstbestand.
$file = "Data.txt";
$data = file($file);
$line = $data[count($data)-1];
for($i=1;$i<6;$i++){
switch ($line) {
case $i:
echo "<p class ='bus".$i."'> <img id='bus' src = 'bus.png'> </p>";
break;
}
}
?>
</body>
</html>
For a live update you need two parts.
First is the part where your page is and the second part is where your data comes from.
Php is a very static language. Once your script is finished it won't do anything anymore.
For a "live-website" you need Javascript.
if you want to use jQuery i would recommend you to use the jQuery.post() function.
jQuery Code in your Website:
$.post( "test.php", { name: "John", time: "2pm" })
.done(function( data ) {
alert( "Data Loaded: " + data );
});
Your test.php
if(isset($_POST['name'])) {
//Do Some Stuff
$a = 'var a';
echo json_encode($a);
}
This is not ajax. Ajax means having frontend code fetching new information on the background. This information then gets appended to the DOM. (Usually the information is transfered as JSON encoded data but lets keep that out of scope.)
For this you need two files:
A frontend file (for instance static index.html with some content)
A backend file providing the data
The frontend file would run some JavaScript then requests the backend file
The backend file responds and returns some output
The javascript adds output to the DOM.
There are many ways of doing this and I don't have the te time to explain all of it here but you might want to have a look at: http://www.w3schools.com/jquery/jquery_ajax_intro.asp
This provides a simple example based on jQuery.
Probably i didnt explain very well, i updated the code to turn more easy to see what i want.
I need to load a external html file in that "div external_page....", i thing that the best way is to load a file in the php file(External PHP content), tell me if im wrong :)
This is the demo: http://vasplus.info/demos/load_and_refresh_div_every_10_seconds/index.php
(UPDATE)
<script language="javascript" src="js/jquery_1.5.2.js"></script>
<div id="external_page_content_displayer">External page contents will be here</div>
<!-- EXTERNAL PHP CONTENTS-->
<?php
srand((float) microtime() * 10005224);
$lines = file('ajax/rssatom/rss-atom.html');
$This_Page_Content = array($lines,
"teste","teste","teste");
$This_Page_Content_Rand_Keys = array_rand($This_Page_Content, 2);
$This_Page_Content_Displayer = $This_Page_Content[$This_Page_Content_Rand_Keys[0]] . "\n";
echo strip_tags($This_Page_Content_Displayer);
?>
<!-- LOAD FUNCTION-->
<script>
function Load_external_content()
{
$('#external_page_content_displayer').load('external_content.php').hide().fadeIn(3000);
}
setInterval('Load_external_content()', 10000);
</script>
Regards
You can try with this:
$lines = file('ajax/rssatom/rss-atom.html');
I currently have a php file that I'm using as a template but I need it to read in data from another php file that I'm using for the page content. I'm doing it this way to save on code and time, however it doesn't appear to be working. I have done a test with shorter amounts of code but it still isn't working. they are both .php files.
Code -
<html>
<head>
<title></title>
</head>
<body>
<?php
$temp = 'test-2.php';
$file = fopen($temp, 'r');
$cont = fread($file, filesize($temp));
print $cont;
fclose($file);
?>
</body>
test-2.php
<?php
echo 'hello world';
?>
just use <?php include('test-2.php'); ?> surely that'll do what you want?