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Just looking for better solution.I'm retrieving all the records from mysql. Then I will send this data by email. Its working fine. Is there any better solution? thanks
$query = "SELECT * FROM order_details WHERE order_id = '".$data['order_id']."'";
while($row = mysql_fetch_array($result,MYSQL_ASSOC)) {
$message_admin .= "<table style='text-align:center;' border='1' cellspacing='0' cellpadding='7'>
<tr>
<td>Source</td>
<td>".$data['source']."</td>
</tr>
<tr>
<td>Email</td>
<td>".$data['email']."</td>
</tr>
<tr>
<td>Message</td>
<td>".$data['message']."</td>
</tr>
<tr>
<td></td>
<td></td>
</tr>
</table>";
}
You would benefit from: http://us.php.net/manual/en/language.types.string.php#language.types.string.syntax.heredoc
Instead of the complicated string manipulation you are doing now.
You are setting $row, but using $data?
I would take a look at the following to improve your code.
mysql-real-escape-string
SELECT * vs SELECT column
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All i want to do is to output only Agric Department inside the Department columns. How do i go about this. Thanks in advance. This is my code.
<thead>
<tr>
<th>SL</th>
<th>Student Name</th>
<th>Department</th>
<th>Age</th>
<th>Photo</th>
</tr>
</thead>
<tbody>
<?php
$query=mysqli_query($db_con,'SELECT *
FROM `student_info`
ORDER BY `student_info`.`datetime` DESC;');
$i=1;
while ($result = mysqli_fetch_array($query)) { ?>
<tr>
<?php
echo '<td>'.$i.'</td>
<td>'.ucwords($result['name']).'</td>
<td>'.ucwords($result['department']).'</td>
<td>'.ucwords($result['age']).'</td>
<td><img class="rounded-circle avatar-xl" src="../../images/'.$result['photo'].'" ></td>';?>
</tr>
<?php $i++;} ?>
</tbody>
</table>
What am trying to achieve is to display only students in Agric Department
change your query from
SELECT * FROM `student_info` ORDER BY `student_info`.`datetime` DESC
to
SELECT * FROM `student_info` where department = 'Agric' ORDER BY `student_info`.`datetime` DESC
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My table gets populated from my phpmyadmin database in php:
while($row2 = mysqli_fetch_array($result2))
{
$dataRow2 = $dataRow2."
<tr>
<th>Event Name</th>
<th>$row2[1]</th>
<th>Location</th>
<th>$row2[2]</th>
<th>Description</th>
<th>$row2[3]</th>
<th>Date</th>
<th>$row2[4]</th>
<th>Cost</th>
<th>$row2[5]</th>
<th>Email</th>
<th>$row2[6]</th>
</tr>";
}
And is in the HTML as so:
<table>
<?php echo $dataRow2;?>
</table>
I want to make the last th (the email address) clickable, opening a sendto for the user to email the address. How is this achievable?
Assuming the email is $row2[6], you would want to replace it with
<th>$row2[6]</th>
This will change it to a link with the email address still visible in the table.
You can use anchor tag mailto to clickable like the following
while($row2 = mysqli_fetch_array($result2))
{
$dataRow2 = $dataRow2."
<tr>
<th>Event Name</th>
<th>$row2[1]</th>
<th>Location</th>
<th>$row2[2]</th>
<th>Description</th>
<th>$row2[3]</th>
<th>Date</th>
<th>$row2[4]</th>
<th>Cost</th>
<th>$row2[5]</th>
<th>Email</th>
<th><a href='mailto:".$row2[6]."'>$row2[6]</a></th>
</tr>";
}
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I will try my best to explain what I am trying to do. Hopefully you can help me out. I have a database that holds links, these links are displayed in a table. I have the entries output properly in order from Points, but I am trying to add a rank number to the side so it says 1, 2, 3, 4, etc going down the page per entry.
Here is my attempt.
<table width = "1000" style='table-layout:fixed;'>
<tr>
// These are the numbers I need to add
<th>Rank</th>
// All these work fine.
<th>Host</th>
<th>Location</th>
<th>Points</th>
</tr>
<?php while($row1 = mysqli_fetch_array($result1)):;?>
<tr>
<td><?php echo $row1[0]; ?></td>
<td><?php echo $row1[1]; ?></td>
<td><?php echo $row1[2]; ?></td>
</tr>
<?php endwhile; ?>
</table>
Hopefully you understand what I am trying to do, if you need any more information let me know.
Thanks for your time.
you mean? :
<?php $rankId=0; while($row1 = mysqli_fetch_array($result1)){ ?>
<tr>
<td><?=$rankId++ ?></td>
<td><?=$row1[0] ?></td>
<td><?= $row1[1] ?></td>
<td><?=$row1[2] ?></td>
</tr>
<?php } ?>
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I am trying to create table in PHP using array but I am getting parse error in my foreach line. Don't know why its giving me syntax error.
$message = '<table border=1>
<tr>
<th><b>Order Details</b></th>
</tr>
'.foreach ($json_array->request->list as $value) {
$wineId = $value->wineId;
$wineName = $value->wineName;
$noOfDrinks = $value->noOfDrinks;
.'
<tr>
<td>ID</td><td>'.$wineId.'</td>
</tr>
<tr>
<td>Name</td><td>'.$wineName.'</td>
</tr>
<tr>
<td>Quantity</td><td>'.$noOfDrinks.'</td>
</tr>
'. } .'
</table>';
Try this, use string concatenation except php code
$message = '<table border=1>
<tr>
<th><b>Order Details</b></th>
</tr>';
foreach ($json_array->request->list as $value) {
$wineId = $value->wineId;
$wineName = $value->wineName;
$noOfDrinks = $value->noOfDrinks;
$message .= '<tr>
<td>ID</td><td>'.$wineId.'</td>
</tr>
<tr>
<td>Name</td><td>'.$wineName.'</td>
</tr>
<tr>
<td>Quantity</td><td>'.$noOfDrinks.'</td>
</tr>';
}
$message .='</table>';
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I output data from atabase in table.
In result table created with next code:
while($i=$res2->fetch_assoc()) {
$a++;
$t2.='
<tr>
<td>'.$a.'</td>
<td>'.date_format(new DateTime($i['date']),'d.m.Y').'</td>
';
if($valid!='id'){
$t2.='
<td>'.$partner.'</td>
';
}
$t2.='
<td>'.$http_referer.'</td>
</tr>';
}
$t1='
<table class="table table-hover table-bordered">
<thead>
<tr>
<th class="column_th_number">№</th>
<th>Date</th>
';
if($valid!='id'){
$t1.='
<th>Partner</th>
';
}
$t1.='
<th></th>
</tr>
<tr>
<td colspane="2">
</td>
</tr>
</thead>
<tbody>
';
$t3='
</tbody>
</table>
';
echo $t1.$t2.$t3;
but in the result I see that last row was not closed (see image):
Tell me please why last row was not closed?
And how can I make this right?
<td>'.date_format(new DateTime($i['date']),'d.m.Y').'</td>
if($valid!='id'){
replace with
<td>'.date_format(new DateTime($i['date']),'d.m.Y').'</td>'; <--- end the string here
if($valid!='id'){
you missed ';
<td>'.$a.'</td>
<td>'.date_format(new DateTime($i['date']),'d.m.Y').'</td>';
if($valid!='id'){
Thanks ALL.
Error was with colspan(value does not match the number of columns).
Thanks all for help