PHP Image manipulation moire effect - php

I am making a site where people can upload their own background images. One of the things users really having a problem understanding is image sizes and resolution. If I say 'Make sure your background is at least 1080x1920 pixels (Full HiDef)' I am guessing a good 70% of people will not know what this means or how to do it.
So what I would like to do is enlarge small images in a nicer way than just making them blurry. What I would like to do is something like this:-
http://nanotux.com/plugins/fullscreenr/index.html
where basically every other dot is a black pixel, that way small images will be twice the size when they are stretched to 1080x1920 and generally look better.
Does anyone know of a way to do this with PHP's image functions?
(as an aside does anyone know what this type of effect should be called? Moire? would that be accurate?)
Thanks in advance

If I understood you well, you want to set every second pixel in x and y dimensions to black on the stretched image?
This should do the trick (not tested, I relied on PHP documentation).
$initialImage = ... // handle to the image
$srcWidth = imagesx($initialImage);
$srcHeight = imagesy($initialImage);
$maxX = 1920;
$maxY = 1080;
$newImage = imagecreatetruecolor($max_x, $max_y);
imagecopyresampled ($newImage, $initialImage, 0,0,0,0, $maxX, $maxY, $srcWidth, $srcHeight);
$BLACK = imagecolorallocate($newImage, 0, 0, 0);
for($x=0; $x+=2; $x<$max_x){
for($y=0; $y+=2; $y<$max_y){
imagesetpixel($newImage, $x, $y, $BLACK);
}
}
Documentation: imagesetpixel, imagecolorallocate, imagecopyresampled,
imagecreatetruecolor.
Read PHP documentation and examples there. Remember to use imagecopyresampled instead of imagecopyresized to have better quality.

The most optimal way would be to create a transparent raster (.png) "by hand" (i.e. create it programmatically as in jakub.gieryluk's solution), and overlay that, multiple times if needed, via imagecopy().
Drawing pixel by pixel is painfully slow.

Related

imagecreatefrompng() transparent part of png is black

I am creating a poster using PHP and I want to add figures on the poster.
I use the following code to add them:
$src1 = imagecreatefrompng("m2.png");
$widthsrc=0;
$heightsrc=0;
list($widthsrc, $heightsrc, $typesrc, $attrsrc) = getimagesize("m2.png");
$background = imagecolorallocate($src1, 0, 0, 0);
imagecolortransparent($src1, $background);
imagealphablending($src1, false);
imagesavealpha($src1, true);
imagecopyresampled($my_img,$src1,$line2X1+100*$resize,$line2Y1,0,0,1000*$resize,1000*$resize,$widthsrc,$heightsrc);
The problem is that the places that the figures should be transparent, they are black.
I have already looked at the following posts:
imagecreatefrompng-makes-a-black-background-instead-of-transparent
hp-resizing-png-images-generate-black-background
png-has-black-background
But I haven't been able to create a solution that works for me.
Well that was easy XD Converting comment to answer:
Your mistake was in defining the background colour. You should use this:
$background = imagecolorallocatealpha($src,0,0,0,127);
However, it is probably a good idea to be safe, and avoid using a "transparent" colour that already exists on your image. The "traditional" transparent colour from old sprite-based games is magenta, since it is very unlikely that you'll have straight magenta on your image!
$background = imagecolorallocatealpha($src,255,0,255,127);

Partial black background when watermarking PNG image with GD PHP

I have pieced together a PHP class to perform various image related functions using GD functions of PHP.
It works great for all image types. Rotate, flip, resize, crop and to a lesser extent, watermark.
All but the latter work perfectly. For example after a few changes, rotated PNG images retained their transparency whereas before they were losing that and the background turning black. Common problem, it appears. But all working now.
Where I'm still getting stuck is watermarking a PNG image with another PNG image. It appears to work fine with JPG and other images. This is the code (simplified):
public function writeWatermarkSimple()
{
$watermarkFile = 'watermark.png';
$watermarkImage = imagecreatefrompng($watermarkFile);
imagealphablending($watermarkImage, false);
imagesavealpha($watermarkImage, true);
$imageFile = 'image.png';
$baseImage = imagecreatefrompng($imageFile);
imagealphablending($baseImage, false);
imagesavealpha($baseImage, true);
$marginH = imagesx($baseImage) - imagesx($watermarkImage);
$marginV = imagesy($baseImage) - imagesy($watermarkImage);
$cut = imagecreatetruecolor(imagesx($watermarkImage), imagesy($watermarkImage));
imagecopy($cut, $baseImage, 0, 0, $marginH, $marginV, imagesx($watermarkImage), imagesy($watermarkImage));
imagecopy($cut, $watermarkImage, 0, 0, 0, 0, imagesx($watermarkImage), imagesy($watermarkImage));
imagecopymerge($baseImage, $cut, $marginH, $marginV, 0, 0, imagesx($watermarkImage), imagesy($watermarkImage), 80);
if (!imagepng($baseImage, 'watermarked_image.png'))
{
return false;
}
return true;
}
This has been pieced together with various guides and advice people have given based on a similar issue. Again, working perfectly with JPG images and PNG watermarks, but not PNG & PNG.
Some example images:
http://i.imgur.com/hHRWinj.png - This is the watermark I'm using.
http://i.imgur.com/6sy8Ncs.png - This is the image I'm applying the watermark to.
http://i.imgur.com/ghovYLm.png - This is the end result.
The bit I find interesting is that any part of the watermark that is overlaid on a non-transparent portion of the image is working fine. Just the rest of it has the black background.
This leads me to believe I'm close, and I hope that the expertise of you fine people may lead me to the solution.
Thanks ever so for reading.
So, I'm not giving up on finding the correct answer to do this using GD. However, I was overjoyed to find that what needed up to 30 lines of code with GD can be achieved using much less with ImageMagick:
$image = new Imagick();
$image->readimage($this->_image);
$watermark = new Imagick();
$watermark->readimage($this->_watermark->_getImage());
$watermark->evaluateImage(Imagick::EVALUATE_DIVIDE, 2, Imagick::CHANNEL_ALPHA);
$image->compositeImage($watermark, imagick::COMPOSITE_OVER, $marginH, $marginV);
So this is before (with GD):
http://i.imgur.com/AlS0TcO.png
And after (with ImageMagick and the code above):
http://i.imgur.com/zBxlC3R.png
If anyone has an answer that is purely GD then I'd be immensely grateful.
Ran into some similar issues recently and while this may not exactly solve your problem, these were some useful discoveries that I made.
In my case, I have an original .jpg image and a watermark .png image. The watermark image has a fully transparent background. I wanted to specify the opacity in my script and have it change the watermark opacity before placing it on top of the origina image. Most posts out there regarding PHP watermarking assume that the original watermark .png file already has the solid watermark portion set to the correct opacity rather than changing it via the script.
gd didn't like a 24 bit .png and caused some goofy issues. Switching to 8 bit resolved that with gd. On the other hand, imagick works very well with a 24 bit .png and the final result seems to be better.
For me, using gd worked just fine if I was opening the original watermark .png and using imagecopymerge() to set the watermark transparency. If however I tried to scale the original watermark .png (which has transparent background) first, then I would get similar results as you with black or white background portion of where watermark image is. See How do I resize pngs with transparency in PHP? for a partial solution by filling the new wm image with transparent rectangle first. For me this still produced an opaque white background on the final result no matter what I tried.
I switched to imagick and was using setImageOpacity() to change the transparency of my watermark .png before applying it on top of my original image and I was still getting the same effect with a black background. Finally read in the PHP doc for setImageOpacity() that if the original .png has any transparent pixels and you try to lower the opacity, those pixels become opaque (black) with the new transparency applied. Instead, need to use the evaluateImage() function. This will instead evaluate each pixel's alpha channel only and divide by the specifid number.
I assume the black / white background issue with gd is likely due to similar ways that it treats alpha channels when scaling / combining as compared to imagick and if you want to do it all in gd you just need to find some similar way to evaluate and manipulate the alpha channel per-pixel because the "easy" ways seem to take an already transparent background and make it opaque.
So, the solution:
Assuming you want to apply your watermark at an opacity of 45% and you're using imagick, then instead of this:
$watermark->setImageOpacity(.45);
do this
$watermark->evaluateImage(Imagick::EVALUATE_DIVIDE, (1/.45), Imagick::CHANNEL_ALPHA);
You need to divide 1 by your opacity to get the demoninator by which the function will divide the alpha channel value for each pixel. In this case, 1/.45 = 2.2222, so then the function will divide the alpha channel of each pixel by 2.2222. This means a solid pixel (alpha of 1) would result in 1/2.2222 or .45 alpha or transparency when finished. Any pixels that were already transparent (alpha 0) would stay transparent because 0 divided by anything is always what? Zero!
After you change the watermark transparency then you can use compositeImage() to merge the watermark onto the original image.

Transparency issue with png images

I 've got this image:
i use php5 and gd2 library to achieve a transparent background, but the result is not what i have expected(you need a dark background to see the difference):
and here is my code:
$size = getimagesize($img_url);
$img = imagecreatefrompng($img_url);
$im_tc = imagecreatetruecolor($size[0],$size[1]);
imagecopyresampled($im_tc,$img,0,0,0,0,$size[0],$size[1],$size[0],$size[1]);
imagedestroy($img);
$white = imagecolorallocatealpha($im_tc, 255, 255, 255,127);
imagecolortransparent($im_tc, $white);
imagepng($im_tc,'image.png');
Any help would be appreciated! :)
Your original image doesn't have a transparent background, but you're trying to create one by changing all pure-white pixels to transparent. As the text has a shadow/glow around it, those pixels aren't quite white, and won't become transparent. You have a couple options here:
Use an image editor (GIMP, Photoshop, etc.) and their fine-grained selection tools to perform a smart selection of the "background", then remove that. Photoshop, at least, has extremely useful options available on its magic wand tool to choose threshold, feathering, and more.
Pick more colours to make "transparent." Instead of just white, choose all of the shades of gray, minus the exact colour that ".gr" is set in. This should make all of the shadowed parts of the image transparent as well, although the edges may be less than perfect (i.e.: not feathered, slightly jagged.)

How to rotate an image in GD Image Library while keeping transparency?

I'm making a skin previewer for my site; I need to rotate parts of an image to create a representation of this for my users to see.
The skin is a PNG file, and all parts of it may have transparency or even none at all.
I need to be able to rotate this image while keeping any transparency inside the image transparent, while also having the extended borders (You know, the area that wasn't part of the image before it was rotated) transparent.
All of my attempts have left a black border around the image itself.
Any help?
Cut out the piece of the image you want to rotate
Rotate preserving alpha using something like this http://www.exorithm.com/algorithm/view/rotate_image_alpha
Merge back in preserving alpha using the following:
-
imagesetbrush($destimg, $srcimg);
// x, y are the center of target paste location
imageline($destimg, $x, $y, $x, $y, IMG_COLOR_BRUSHED);
I use that to rotate a PNG and preserve transparency color. Works like a charm. It's "basic GD".
$rotation = 135;
$handle_rotated = imagerotate($handle_not_rotated,$rotation,0);
imagealphablending($handle_rotated, true);
imagesavealpha($handle_rotated, true);
Don't know if it's what you're looking for?
You may want to check here for some uses for libpng (which will need zlib). If you are on linux you can write something in perl. CPAN GD module might be your ticket.

Php Gd rotate image

HEllo,
I am trying to rotate a circular image around the center and then cut off the sides. I see the imagerotate function, but it does not seem to rotate about centre.
Anyone have any suggestions?
Thank you.
Update: Since it is a circle, I want to cut off the edges and keep my circle in the same dimensions.
The documentation says that it does rotate around the center.
Unfortunately it also says that it will scale the image so that it still fits. That means that whatever you do this function will change the size of your internal circular image.
You could (relatively easily) calculate how much scaling down will happen and then prescale the image up appropriately beforehand.
If you have the PHP "ImageMagick" functions available you can use those instead - they apparently don't scale the image.
I faced successfully that problem with the following code
$width_before = imagesx($img1);
$height_before = imagesy($img1);
$img1 = imagerotate($img1, $angle, $mycolor);
//but imagerotate scales, so we clip to the original size
$img2 = #imagecreatetruecolor($width_before, $height_before);
$new_width = imagesx($img1); // whese dimensions are
$new_height = imagesy($img1);// the scaled ones (by imagerotate)
imagecopyresampled(
$img2, $img1,
0, 0,
($new_width-$width_before)/2,
($new_height-$height_before)/2,
$width_before,
$height_before,
$width_before,
$height_before
);
$img1 = $img2;
// now img1 is center rotated and maintains original size
Hope it helps.
Bye
According to the PHP manual imagerotate() page:
The center of rotation is the center
of the image, and the rotated image is
scaled down so that the whole rotated
image fits in the destination image -
the edges are not clipped.
Perhaps the visible center of the image is not the actual center?

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