My tags are showing in the inner foreach loop in the right order.
I would like to comma separate them but am not sure how.
Is there a better way to display my tags without using the second foreach loop?
$people = array();
while($row = mysqli_fetch_array($rs, MYSQLI_ASSOC)){
if(!isset($people[$row["id"]])){
$people[$row["id"]]["id"] = $row["id"];
$people[$row["id"]]["tag"] = $row["tag"];
$people[$row["id"]]["tags"] = array();
}
array_push($people[$row["id"]]["tags"], array("id"=>$row["tags_id"],"tag_name"=>$row["tag"]));
}
foreach($people as $pid=>$p){
echo "(#{$p['id']}) ";
foreach($p["tags"] as $tid=>$t){
echo "<a href='#'>{$t['tag_name']}</a> ";
}
echo "<br><br>";
}
You don't need to use array_push, since you're only adding one element to the array. You can save the overhead of calling a function by using the syntax:
$people[ $row["id"] ]["tags"][] = array(...);
My answer depends on the necessity of the variables saved from the database. In your supplied code, you're only using the id and tag values from the database in the nested foreach loops. If this is this case, then you can simplify your arrays so you can use implode() on a new tags array. I have not tested this since I do not have your database schema, but I believe it will work.
<?php
$people = array();
$tags = array();
while( ($row = mysqli_fetch_array( $rs, MYSQLI_ASSOC)))
{
if( !isset( $people[$row['id']]))
{
$people[ $row['id'] ] = array( 'id' => $row['id'], 'tag' => $row['tag']);
$tags[ $row['id'] ] = array();
}
$tags[ $row['id'] ][] = $row['tag'];
}
foreach( $people as $pid => $p)
{
echo "(#{$p['id']}) ";
echo '' . implode( '', $tags[ $p['id'] ]) . '';
echo '<br /><br />';
}
Related
The following code returns the field names of a result set. I also want it to return the values. How can I do this?
while ($row = mysqli_fetch_assoc($result)) {
foreach( $row as $field => $name) {
echo $field."<br>";
}
}
If we assume that your array looks like this:
$row["first_name"] = "John";
$row["last_name"] = "Doe";
$row["username"] = "john.doe";
Using this code:
while ($row = mysqli_fetch_assoc($result)) {
foreach( $row as $field => $value) {
echo "{$field} - {$value}<br>";
}
}
You will get an output like this:
first_name - John
last_name - Doe
username - john.doe
When you iterate through an array, using => operator, you are iterating in a "key-value" pair style. Every iteration holds the key and value as you can see.
Take a look at foreach for more information.
you are getting the value in $name variable
foreach( $row as $field => $name) {
echo $field . " = " . $name . "<br>";
}
I am trying to generate sql statement dynamically with loops but i am not getting any idea on how to do it with html name array.
assuming $name and $message are post arrays ... and assuming length of both will be equal,
following is a method i tried;
<?php
$name = array('name1','name2' );
$mess= array('message1','message2' );
$values = array($name,$mess);
foreach ($values as $key){
foreach ($key as $value){
echo $value.",";
}
}
?>
output is =
name1,name2,message1,message2,
but i want output as =
(name1,message1),(name2,message2),
Edit : I have acess to $values only and I will not be able to determine how many values are going to join in $values ..
like it can be
$values=array($name,$message,$phone);
and the result i want will be
(name1,message1,phone1),(name2,message2,phone2)
My solutions is
Step 1: Loop your $values this will gonna loop every index of your array like $name
foreach($name as $index => $value) {
// do something
}
Step 2: Inside your loop values start with ( which mean wrap your detail in (
echo "(";
Step 3: loop parent array
foreach($values as $key => $arr) {
// do something
}
Step 4: Inside the loop of your parent array display each data according to your index
echo $values[$key][$index];
$key represents the index of your parent array while $index represents the index of your child array like $name
this loop will create data like
(name1,message1,phone1)
and I just add this
if ($key < sizeof(array_keys($values))-1) {
echo ",";
}
to avoid adding , after the last loop
This code will dynamically display array you put inside $values
So your code would be like this
$name = array('name1','name2','name3','name4' );
$mess= array('message1','message2','message3','message4' );
$phone= array('phone1','phone2','phone3','phone4' );
$married= array('yes','no','yes','yes' );
$values = array($name,$mess,$phone);
foreach($name as $index => $value) {
echo "(";
foreach($values as $key => $arr) {
echo $values[$key][$index];
if ($key < sizeof(array_keys($values))-1) {
echo ",";
}
}
echo "),";
}
Demo
or this
$name = array('name1','name2','name3','name4' );
$mess= array('message1','message2','message3','message4' );
$phone= array('phone1','phone2','phone3','phone4' );
$values = array($name,$mess,$phone);
foreach($name as $index => $value) {
$join = array();
foreach($values as $key => $arr) {
$join[] = $values[$key][$index];
}
echo "(".implode(",",$join)."),";
}
Demo
$name = array('name1','name2' );
$mess = array('message1','message2' );
foreach ($names as $k => $v){
echo "(".$v.",".$mess[$k]."),";
}
Try this, you not need two foreach loop, only use foreach loop and pass key to other array and get value
$name = array('name1','name2' );
$mess= array('message1','message2' );
$values = array($name,$mess);
foreach ($name as $keys => $vals)
{
echo "(".$vals.",".$mess[$keys]."),";
}
DEMO
You can use arrap_map() function in order to join two array. Here is reference http://php.net/manual/en/function.array-map.php
<?php
$name = array('name1','name2' );
$mess= array('message1','message2' );
$value = array_map(null, $name, $mess);
print_r($value);
?>
I would like to echo my results from a database and have them look like an array. They don't necessarily have to be an array but look like one. i.e. When i echo my result,
i would want my final result to look like
[10,200,235,390,290,250,250]
When i try the code below:
$query_rg = mysqli_query($link, "SELECT column FROM `table`");
$row_rg = mysqli_fetch_assoc($query_rg);
echo '[';
while ($row = mysqli_fetch_assoc($query_rg)) {
$list = $row['column'];
$listwithcoma = "$list,";
echo ltrim($listwithcoma,',');
}
echo ']'
The result is :
[10,200,235,390,290,250,250,]
You are doing it wrong. ltrim($listwithcoma,',') has no effect.
ltrim — Strip whitespace (or other characters) from the beginning of a string
You can try a simple way with implode.
$list = array();
while ($row = mysqli_fetch_assoc($query_rg)) {
$list[] = $row['column'];
}
echo '[' . implode(',', $list) . ']';
Just use GROUP_CONCAT in query as
$query_rg = mysqli_query($link, "SELECT GROUP_CONCAT(`column` SEPARATOR ', ') as data
FROM `table`");
$row_rg = mysqli_fetch_assoc($query_rg);
print_r($row_rg['data']);
Try like this
$list = array(); //define a array.
while ($row = mysqli_fetch_assoc($query_rg)) {
$list[] = $row['column']; //store column value in array.
}
$lists = "[".implode(",",$list)."]";
echo $lists; //will echo your results.
You should be using rtrim() function instead, that too outside the loop.
$listwithcoma = '';
echo '[';
while ($row = mysqli_fetch_assoc($query_rg)) {
$list = $row['column'];
$listwithcoma .= "$list,";
// echo ltrim($listwithcoma,','); Remove this
}
echo rtrim($listwithcoma,','); // Add this
echo ']';
Hi all Im trying to query a database and store the results ($searchResults[]) as an array :
<?php
if(isset($_POST['indexSearchSubmit']))
{
foreach($_POST['industryList'] as $selected)
{
$_POST['industryList'] = $selected;
$locationListResults = $_POST['locationList'];
$results = mysqli_query($con,"SELECT * FROM currentListings
WHERE location = '$locationListResults' AND industry = '$selected'");
$searchResults = array();
while($row = mysqli_fetch_array($results))
{
$searchResults[] = $row['industry'];
$searchResults[] = $row['location'];
$searchResults[] = $row['title'];
$searchResults[] = $row['description'];
}
}
mysqli_close($con);
}
?>
the problem im getting is when I try to echo the result:
<?php
echo $searchResults[0];
?>
its only bringing back 1 result not displaying all the results in the arrray as i want it to.
Could anybody please point out what it is im doing wrong.
Any help would be greatly appreciated
Do like this
<?php
print_r($searchResults); // Prints all array elements
?>
Alternatively, you can make use of a for loop to echo all elements too..
foreach($searchResults as $k=>$v)
{
echo $v;
echo "<br>";
}
Your code puts your data into 1D array. You probably want sth else so instead of this:
$searchResults[] = $row['industry'];
$searchResults[] = $row['location'];
$searchResults[] = $row['title'];
$searchResults[] = $row['description'];
do this:
$tmp = array();
$tmp['industry'] = $row['industry'];
$tmp['location'] = $row['location'];
$tmp['title'] = $row['title'];
$tmp['description'] = $row['description'];
$searchResults[] = $tmp;
or just this (thanks to Barmar):
$searchResults[] = $row;
This way you store your data as 2D array. So every row you obtain remains in one subarray.
To print the row (which is now in 2D array) iterate over subarrayw:
foreach($one_of_searchResult_rows as $k => $v)
{
// do whatever you need with $k and $v
}
I think you want a 2d array. Try this code snippet :
$searchResults = array();
while($row = mysqli_fetch_array($results))
{
array_push($searchResults,$row);
}
This should push each row as an associative array in every cell of your final searchResuts array. You could then access the values like:
echo $searchResults[0]['industry']; //and so on
echo $searchResults[0]; //Should print out the first match/row of the sql result
Lets make it simple :
$serach_result=mysqli_fetch_all ($result,MYSQLI_NUM);
//you should use print_r while trying to print an array
print_r($search_result[0]);
Reference : mysqli_fetch_all
Hy every one I have this problem with an array I start like this...
$name = array($_POST['names']);
$nameId = array();
$query = mysql_query("SELECT id FROM types WHERE find_in_set (name, '$name')");
while($row = mysql_fetch_assoc($query)){
$nameId[] = array('ids' => $row['id'] );
}
which gives me arrays like this..
$name:
array('0'=>'name1,name2,name3')
$names:
array('0'=>array('ids'=>'61'), '1'=>array('ids'=>'6'), '2'=>array('ids'=>'1'))
how can I bring this in an string/form like this..
array('0'=>'61,6,1')
The idea is to save the ids to the Database.
Or is the a better more efficent way to get names from a form compare them with a database and get the ids back to save them to the Database?
many thanks in advance.
Change your assignment to this:
$nameId[] = $row['id'];
$name = array(name1,name2,name3);
$nameId = array();
$query = mysql_query("SELECT id FROM types WHERE find_in_set (name, '$name')");
while($row = mysql_fetch_assoc($query)){
//below line changed
$nameId[] = $row['id'] ;
}
$string = implode(',',$nameId);
Try this :
$array = array(0=>array(0=>'61'),1=>array(0=>'6'),2=>array(0=>'1'));
$result = implode(",",call_user_func_array('array_merge', $array));
Please note : Here all are numeric keys, so change your code to :
$nameId[] = array($row['id'] ); , remove key 'ids' from here
Output :
61,6,1
Thats what I think
$nameId[] = $row['id'];
$stringId = implode(',',$name);
Use following function that will loop through array and find ids key and merge it into other array and after that when you calling this function it will impload it.
function CustomFindJoinArray( $needly, $array )
{
$results = array();
foreach ( $array as $key => $value )
{
if ( is_array( $value ) )
{
$results = array_merge($results, foo( $needly, $value ));
}
else if ( $key == $needly )
{
$results[] = $value;
}
}
return $results;
}
echo implode( ",", CustomFindJoinArray( "ids", $your_array ) );
where $your_array will be array('0'=>array('ids'=>'61'), '1'=>array('ids'=>'6'), '2'=>array('ids'=>'1'))
OR More simple
foreach ($your_array as $key => $ids) {
$newArray[] = $array[$key]["ids"];
}
$string = implode(',', $newArray);
$ids = array();
foreach($nameId as $curr) {
$ids[] = $curr['ids'];
}
$str = "(".implode(",",$ids).")";