Filtering an array in PHP - php

Question

i have a script which takes data from a database and displays it on a page.
It sorts the rows by an id number, and displays them in that order
heres the script
// get the info from the db
$sql = "SELECT showtime, html FROM showfeed ORDER BY showtime ASC LIMIT $offset, $rowsperpage";
$result = mysql_query($sql, $conn) or trigger_error("SQL", E_USER_ERROR);
// while there are rows to be fetched...
while ($list = mysql_fetch_assoc($result))
{
// echo data
echo $list['html'] . "<hr />";
} // end while
what I want to do is filter that data so that if the ID number of a row is less than a given number than it won't be displayed. And if it is greater than a certain number it will be displayed normally.

Answer 1

Do it in the database query.
SELECT ... WHERE id > $certainNumber ...
If, for whatever reason, you want to do it in PHP:
while ($list = mysql_fetch_assoc($result)) {
if ($list['id'] < $certainNumber) {
continue;
}
...
}

Answer 2

Assuming ID is a field in your table:
$sql = "SELECT id, showtime, html FROM showfeed ORDER BY showtime ASC LIMIT $offset, $rowsperpage";
$result = mysql_query($sql, $conn) or trigger_error("SQL", E_USER_ERROR);
// while there are rows to be fetched...
$targetID = 120;
while ($list = mysql_fetch_assoc($result))
{
// echo data
if ($list['id'] < $targetID) continue;
echo $list['html'] . "<hr />";
} // end while
However, if this would work for you, then probably better to change your query to
$sql = "SELECT showtime, html FROM showfeed WHERE id > 120 ORDER BY showtime ASC LIMIT $offset, $rowsperpage";

Answer 3

Filter sql query (the word "array" is not right here).
you have to filter the query using sql instead of your application
Something like that
SELECT showtime, html FROM showfeed WHERE ID > ?? AND ID < ?? ORDER BY showtime ASC