I have always sucked at complex arrays there must be something in my brain preventing me from ever understanding them. I will try to make this example really simple so we will not go off topic. I use this code to use numbers to represent each file name:
$mod_nums = array('1' => $input_zip_path . '01_mod_1.0.2.zip',
'2' => $input_zip_path . '02_mod_1.0.1.zip',
);
So when I use $mod_nums['01'] it will display the path to that file. I have an array from the script that put these $mod_nums values into an array like so:
$files_to_zip = array(
$mod_nums['1'],
$mod_nums['2']
);
That worked fine. Now I wanted to add a $_POST value so that I can enter numbers like 1,2 and other numbers that I add to the $mod_nums array later like 1,3,6,12 for example. So I used an explode for those posted values:
$explode_mods = explode(",", trim($_POST['mods']));
Now for the big question that is racking my brain and spent hours on and cannot get it to work.... I need for $files_to_zip to still be in an array and display the posted values of $mod_nums. So it would be like:
$files_to_zip = array( HAVE $_POSTED VALUES IN HERE );
I hope that makes sense. I need $files_to_zip to remain in array format, grab the file path to the zip files from the $mod_nums array, and display it all correctly so it would dynamically output:
$files_to_zip = array('01_mod_1.0.2.zip', '02_mod_1.0.1.zip');
so posted numbers will appear in an array format for the $files_to_zip variable. Make sense? In short I need an array to have dynamic values. Thanks :)
EDIT
Phew I figured it out myself from memory when I worked on something similar many years ago. This looks tough but it isn't. I had to use a foreach and assign the variable into an array like so:
$blah = array();
foreach ($explode_mods as $value)
{
$blah[] = $mod_nums[$value];
}
then I just assigned $files_to_zip to $blah:
$files_to_zip = $blah;
works perfectly :) I just forgot how to dynamically assign values into an array.
// filenames array
$mod_nums = array('1' => $input_zip_path . '01_mod_1.0.2.zip',
'2' => $input_zip_path . '02_mod_1.0.1.zip',
);
// mod_num keys
$explode_mods = explode(',', trim($_POST['mods']));
// array to hold filenames
$files_to_zip = array();
// loop over all the mod_num keys submitted via POST
foreach($explode_mods as $key){
// save the filename to the corresponding array
$files_to_zip[] = $mod_nums[$key];
}
maybe i havn't understood you right, but won't this just be a simple foreach-loop to add the entrys to $files_to_zip like this:
$explode_mods = explode(",", trim($_POST['mods']));
foreach($explode_mods as $k){
$files_to_zip[] = $mod_nums[$k];
}
Related
I'm a beginner in PHP. I have a text file like this:
Name-Id-Number
Abid-01-80
Sakib-02-76
I can take the data as an array but unable to take it as an associative array. I want to do the following things:
Take the data as an associative array in PHP.
Search Number using ID.
Find out the total of Numbers
I believe I understand what you want, and it's fairly simple. First you need to read the file into a php array. That can be done with something like this:
$filedata = file($filename, FILE_IGNORE_NEW_LINES);
Now build your desired array using a foreach() loop, explode and standard array assignment. Your search requirement is unclear, but in this example, I make the associated array element into an array that is also an associative array with keys for 'id' and 'num'.
As you create the new array, you can compute your sum, as demonstrated.
<?php
$filedata = array('Abid-01-80', 'Sakib-02-76');
$lineArray = array();
$numTotal = 0;
foreach ($filedata as $line) {
$values = explode('-', $line);
$numTotal += $values[2];
$lineArray[$values[0]] = array('id' => $values[1], 'num' => $values[2]);
}
echo "Total: $numTotal\n\n";
var_dump($lineArray);
You can see this code demonstrated here
Updated response:
Keep in mind that notices are not errors. They are notifiying you that your code could be cleaner, but are typically suppressed in production.
The undefined variable notices are coming because you are using:
$var += $var without having initialized $var previously. Note that you were inconsistent in this practice. For example you initialized $numTotal, so you didn't get a notice when you used the same approach to increment it.
Simply add just below $numTotal = 0:
$count = 0;
$countEighty = 0;
Your other notices are occurring most likely due to a blank line or string in your input that does not follow the pattern expected. When explode is executed it is not returning an array with 3 elements, so when you try and reference $values = explode('-', $line); you need to make sure that $line is not an empty string before you process it. You could also add a sanity check like:
enter code hereif (count($values) === 3) { // It's ok to process
Alright, So I'm redoing my question so people can understand what I'm trying to do.
Search.php
<?php
$getItems = file_get_contents('Items.json');
if(isset($_GET['searchVal'])){
$getItems2 = json_decode($getItems, true);
$data2 = array("items" => array(array()));
foreach($getItems2['items'] as $data){
if(strpos($data['name'], $_GET['searchVal'])){
$data2 = array("items" => array(array($data)));
}
}
echo json_encode($data2,JSON_UNESCAPED_SLASHES);
} else{
echo $getItems;
}
Problem: Doesn't get all items which have that name, gets only one.
Search is done, now I have to fix somehow to get all items which match the name. How could I do that?
You have the following inside a loop:
$data2 = array(...)
...and then you reference $data2 outside the loop.
Of course, it will only contain the last entry, because that line is overwriting $data2 with new data each time the loop iterates.
If you want to keep all the records from the loop, use
$data2[] = array(...)
instead.
[EDIT]
Further guessing as to what you actually want your JSON to look like, I guess you want all the records to be in the items array?
So in that case, let's rewrite your $data2 line, as follows:
$data2['items'][] = array($data);
This will add all the data arrays to your items array in $data2. I will note that your array structure is really convoluted -- too many nested arrays, which makes it difficult to be sure I'm giving you the answer you want even now, but hopefully if it isn't exactly right, it will show you the direction you need to go.
You'll also want to have an additional line at the top of your code to initialise $data2, like this:
$data2 = array('items'=>array());
This should be somewhere at the top of the code, before $data2 is used, and outside of the loop.
I know this should be very simple, but boy I'm making a mess of it... would be great if someone could point me in the right direction.
I've got an array which looks like this:
print_r($request_attributes['length']);
Array
(
[0] => 28.00000
[1] => 18.00000
)
and am trying to modify like so:
if(is_array($request_attributes['length'])) {
$request_attributes['length'] = $request_attributes['length'][0];
print($request_attributes['length']);
$request_attributes['length'] = $request_attributes['length'][1];
print($request_attributes['length']);
}
which gives the correct output in the first update, but the second item outputs an '8'. I've tried the above in both a for and foreach which results in similar output for both this and the other two arrays ( width(8) and height(0) - they should result in 18.00000 and 13.00000 respectively ). So I guess I really have two questions:
1. How do I update this(these) element(s)?
2. Where are the funny outputs actually coming from?
If anyone can help, I'd really appreciated it.
Just have a look at this. Your problem is, that you override you variable and in the second step $request_attributes['length'] is a string. Just define another var for your values.
$request_attributes['length'] = [
28.000,
18.000
];
$attributes = array();
if (is_array($request_attributes['length'])) {
foreach ($request_attributes['length'] as $value) {
$attributes[] = $value;
}
}
As you see $attributes will contain all values of your $request_attributes['length'] array and will not be overwritten.
Define araay as below
$val=array([0]=>"18.000",[1]=>13.000)
then use
if(is_array($request_attributes['length'])) {
$request_attributes['length'] = $val;
print_r($request_attributes['length']);
$request_attributes['length'] = $val;
print_r($request_attributes['length']);
}
Previously your array doesnt have any name.
Your print will only return Just array not the values
use
print_r($request_attributes['length']) ;
instead
This question already has answers here:
How to modify an array's values by a foreach loop?
(2 answers)
Closed 8 years ago.
This is driving me nuts. I've searched for solutions but can't figure out what's wrong.
The situation... I have an SQL query running in WordPress, as follows:
SELECT distinct guid
FROM $wpdb->posts
WHERE post_status = 'inherit'
AND guid is not null
Dead simple. It returns a single column which contains a list of all the attachment media files currently stored on the system (well, not all of them, but it'll do as an explanation).
In a WP plugin function, I run the query:
$media_library_files = $wpdb->get_col($get_all_media,0);
That returns an array (I don't want an object) with values like:
[0] => http://mysitename.com/wp-content/uploads/2013/05/thumb_littlefile_blah.jpg
Then I want to process each one so that there's just the filename left. The problem is that, when I run a str_replace or pretty much any other string function on the contents, it doesn't work. For example:
$horrid_bit = 'http://mysitename.com/wp-content/uploads/2013/05/';
foreach($media_library_files as $item) {
$item = str_replace($horrid_bit,'',$item);
}
When I print_r the array after that, there's no visible change - every line is exactly the same as it was before.
I've tried using a (string) to cast $item, I've tried defining variables to do that, then working the str_replace on them, I've tried... loads of different things.
I have a feeling I'm missing something really simple, but I just can't see it. Is it because the column is varchar in the original table? Or something else?
Any help appreciated. Thanks!
PHP is not my 'native languague', but it seems like you're not modifying the values in the array. Did you try to put the modified string items (=minus the path) in a new array and use that one?
$horrid_bit = 'http://mysitename.com/wp-content/uploads/2013/05/';
$new_array = array();
foreach($media_library_files as $item) {
$new_item = str_replace($horrid_bit,'',$item);
$new_array.push($new_item);
}
//...use the items in the $new_array
Also, you might wanna just read the whole path string as an array (split on '/')and take the last element to get to the file.
$horrid_bit = 'http://mysitename.com/wp-content/uploads/2013/05/';
foreach($media_library_files as $key => $value) {
$media_library_files[$key] = str_replace($horrid_bit,'', $value);
}
But as Michael pointed out if you are not doing it this way for a specific purpose using basename would be better here, so you don't have to worry about the folder changing each month/year.
foreach($media_library_files as $key => $value) {
$media_library_files[$key] = basename($value);
}
You are not actually changing the value of $item in your array, you are instead creating a new variable, which is then overwritten every time your loop iterates.
It's also a good idea to check that the array is not empty before attempting a foreach() loop on it.
Finally, I've replaced str_replace() with basename() (as suggested in the comments under your question by #MichaelBerkowski).
if(!empty($media_library_files)) : foreach($media_library_files as $item) :
$media_library_files[$item] = basename($item);
endforeach;
endif;
str_replace() can handle arrays. No need for your foreach loop.
$horrid_bit = 'http://mysitename.com/wp-content/uploads/2013/05/';
$media_library_files = str_replace( $horrid_bit,'',$media_library_files );
On the other hand, since it seems you want to remove the path and get only the filename:
foreach($media_library_files as $key => $item) {
$media_library_files[$key] = basename($item);
}
This will change all entries to the filename only. The way you have it now you will have to change the $horrid_bit every month since the uploads are organized in year/month/ folders.
I have an array structured like this:
$arrNames = array(
array('first'=>'John', 'last'=>'Smith', 'id'=>'1'),
array('first'=>'John', 'last'=>'Smith', 'id'=>'2'),
array('first'=>'John', 'last'=>'Smith', 'id'=>'3')
)
I need to remove the similar elements where the fist and last name are the same. Normally, I would use array_unique but the elements aren't exactly unique since each one has a unique id. I do not care which id is retained. I just need the array to look like this:
$arrNames = array(
array('first'=>'John', 'last'=>'Smith', 'id'=>'1') // can be any id from the original array
)
Is there a quick way to accomplish this? My first thought is to use something like a bubble sort but I'm wondering if there is a better (faster) way. The resulting array is being added to a drop-down list box and the duplicate entries is confusing some users. I'm using the ID to pull the record back from the DB after it is selected. Therefore, it must be included in the array.
<?php
$arrNames = array(
array('first'=>'John', 'last'=>'Smith', id=>'1'),
array('first'=>'John', 'last'=>'Smith', id=>'2'),
array('first'=>'John', 'last'=>'Smith', id=>'3')
);
$arrFound = array();
foreach ($arrNames as $intKey => $arrPerson) {
$arrPersonNoId = array(
'first' => $arrPerson['first'],
'last' => $arrPerson['last']
);
if (in_array($arrPersonNoId, $arrFound)) {
unset($arrNames[$intKey]);
} else {
$arrFound[] = $arrPersonNoId;
}
}
unset($arrFound, $intKey, $arrPerson, $arrPersonNoId);
print_r($arrNames);
This definitely works, whether it is the best way is up for debate...
Codepad
There is no fast and easy way that I know of, but here is a relatively simple way of doing it assuming that the ids for "similar elements" don't matter (i.e. you just need an ID period).
$final = array();
foreach ($array as $values) {
$final[$values['first'] . $values['last']] = $values;
}
$array = array_values($final);
The last step is not strictly necessary .. only if you want to remove the derived keys.