I'm trying to use PHP to trim a YouTube URL down to the video ID. It's working, but it's also adding a lot of whitespace to the result. Does anyone know how I'd be able to fix this? Here's the setup:
Located in Wordpress single.php (finds attached YouTube URL from post meta):
<?php
$vidurl = get_post_meta($post->ID, "_videoembed", true );
$youtube_id = getYouTubeIdFromURL($vidurl);
echo $youtube_id;
?>
Here's what's executing the function:
//Get YT Video ID
function getYouTubeIdFromURL($url)
{
$url_string = parse_url($url, PHP_URL_QUERY);
parse_str($url_string, $args);
return isset($args['v']) ? $args['v'] : false;
}
Like I said, the function works fine, but it produces a bunch of white space. Say the video included in the meta is youtube.com/watch?v=1337&feature=player_embedded it'll return
" 1337 "
I appreciate all help in advance! I've had some really nice people help me on this site before.
Are you sure your get_post_meta function isn't returning a bunch of spaces with it? Can you do a var_dump on $vidurl? When I run the function you gave, the output looks just fine (http://www.ideone.com/LRoTd):
<?php
function getYouTubeIdFromURL($url)
{
$url_string = parse_url($url, PHP_URL_QUERY);
parse_str($url_string, $args);
return isset($args['v']) ? $args['v'] : false;
}
$theurl = "youtube.com/watch?v=1337&feature=player_embedded";
$youtubeid = getYouTubeIdFromURL($theurl);
echo "'$youtubeid'";
?>
Output:
'1337'
Related
i'm trying to do something in PHP
I'm trying to get the link of an image -> store it to my DB, but I'd like the user to be able to store text before it, and after it, I've gotten my hands on a similar function for links, but the image part is missing.
As you can see the turnUrlIntoHyperlink does a regex check over the entire arg passed, turning the text that contains it to the url, so users can post something like
Hey check this cool site "https://stackoverflow.com" its dope!
And the entire argument posting to my database.
However i can't seem to get the same function working for the Convert Image, as it simply won't post and removed text before/after it before when i made the attempt.
How would i do this in a correct way, and can i combine these 2 functions in to 1 function?
function convertImg($string) {
return preg_replace('/((https?):\/\/(\S*)\.(jpg|gif|png)(\?(\S*))?(?=\s|$|\pP))/i', '<img src="$1" />', $string);
}
function turnUrlIntoHyperlink($string){
//The Regular Expression filter
$reg_exUrl = "/(?i)\b((?:https?:\/\/|www\d{0,3}[.]|[a-z0-9.\-]+[.][a-z]{2,4}\/)(?:[^\s()<>]+|\(([^\s()<>]+|(\([^\s()<>]+\)))*\))+(?:\(([^\s()<>]+|(\([^\s()<>]+\)))*\)|[^\s`!()\[\]{};:'\".,<>?«»“”‘’]))/";
// Check if there is a url in the text
if(preg_match_all($reg_exUrl, $string, $url)) {
// Loop through all matches
foreach($url[0] as $newLinks){
if(strstr( $newLinks, ":" ) === false){
$link = 'http://'.$newLinks;
}else{
$link = $newLinks;
}
// Create Search and Replace strings
$search = $newLinks;
$replace = ''.$link.'';
$string = str_replace($search, $replace, $string);
}
}
//Return result
return $string;
}
more explained in detail :
When i post a link like https://google.com/ I'd like it to be a href,
But if i post an image like https://image.shutterstock.com/image-photo/duck-on-white-background-260nw-1037486431.jpg , i'd like it to be a img src,
Currently, i'm storing it in my db and echoing it to a little debug panel,
Do you mean that you want to make an <img> inside <a> element?
Your turnUrlIntoHyperlink function have captured the url successfully, so we can just use explode to get string before and after the link.
$exploded = explode($link, $string);
$string_before = $exploded[0];
$string_after = $exploded[1];
Code example:
<?php
function turnUrlIntoHyperlink($string){
//The Regular Expression filter
$reg_exUrl = "/(?i)\b((?:https?:\/\/|www\d{0,3}[.]|[a-z0-9.\-]+[.][a-z]{2,4}\/)(?:[^\s()<>]+|\(([^\s()<>]+|(\([^\s()<>]+\)))*\))+(?:\(([^\s()<>]+|(\([^\s()<>]+\)))*\)|[^\s`!()\[\]{};:'\".,<>?«»“”‘’]))/";
// Check if there is a url in the text
if(preg_match_all($reg_exUrl, $string, $url)) {
// add http protocol if the url does not already contain it
$newLinks = $url[0][0];
if(strstr( $newLinks, ":" ) === false){
$link = 'http://'.$newLinks;
}else{
$link = $newLinks;
}
$exploded = explode($link, $string);
$string_before = $exploded[0];
$string_after = $exploded[1];
return $string_before.'<img src="'.$link.'">'.$string_after;
}
return $string;
}
echo turnUrlIntoHyperlink('Hey check this cool site https://stackoverflow.com/img/myimage.png its dope!');
Output:
Hey check this cool site <img src="https://stackoverflow.com/img/myimage.png"> its dope!
Edit: the question has been edited
Since an image URL is just another kind of link/URL, your logic should go like this pseudocode:
if link is image and link is url
print <img src=link> tag
else if link is url and link is not image
print <a href=link> tag
else
print link
So you can just write a new function to "merge" those two function:
function convertToImgOrHyperlink($string) {
$result = convertImg($string);
if($result != $string) return $result;
$result = turnUrlIntoHyperlink($string);
if($result != $string) return $result;
return $string;
}
echo convertToImgOrHyperlink('Hey check this cool site https://stackoverflow.com/img/myimage.png its dope!');
echo "\r\n\r\n";
echo convertToImgOrHyperlink('Hey check this cool site https://stackoverflow.com/ its dope!');
echo "\r\n\r\n";
Output:
Hey check this cool site <img src="https://stackoverflow.com/img/myimage.png" /> its dope!
Hey check this cool site https://stackoverflow.com/ its dope!
The basic idea is that since image url is also a link, such check must be done first. Then if it's effective (input and return is different), then do <img> convertion. Otherwise do <a> convertion.
In my code I am trying to extract url only from my string using preg_match() function but its not working properly I tried all possible references but nothing works for me.
Here is the string example
FileID = "http://downloader.example.com/myfile/Josh.mp4";
My Expectation
http://downloader.example.com/myfile/Josh.mp4
Here is my php code
<?php
$stringURL = "FileID = \"http://downloader.example.com/myfile/Josh.mp4\";";
preg_match('/FileID(.*)=(.*)"(.*)"/U', $stringURL,$matches);
if (isset($matches[0])) {
$myurl = $matches[0];
} else {
$myurl = "http://";
}
echo $myurl;
?>
Why not it like this?
preg_match('/https?\:\/\/[^\" ]+/i', $stringURL,$matches);
I'll start by saying I'm fairly new to coding so I'm probably going about this the wrong way.
Basically I've got the below php function that changes urls to the page title of the url instead of a plain web address. So instead of www.google.com it would appear as Google.
<?php
function get_title($url){
$str = file_get_contents($url);
if(strlen($str)>0){
$str = trim(preg_replace('/\s+/', ' ', $str)); // supports line breaks inside <title>
preg_match("/\<title\>(.*)\<\/title\>/i",$str,$title); // ignore case
return $title[1];
}
}
?>
This is great but to implement this I have to use the below code.
echo get_title("http://www.google.com/");
However this just works on a predefined URL. What I have set up on my site at the moment is a shortcode in a html widget.
<a href='[rwmb_meta meta_key="link_1"]'>[rwmb_meta meta_key="link_1"]</a>
This shortcode displays a url/link that is input by the user in the backend of Wordpress and displays it on the frontend as a link. However I want to apply the get_title function to the above shortcode so instead of the web address it shows the page title.
Is this possible?
Thanks in advance.
for name of a url from a link you can use parse_url($url, PHP_URL_HOST);
easier way would be to have an array of links for example
$links[] = 'some1 url here';
$links[] = 'some2 url here';
then just loop your $links array with the function.
foreach($links as $link)get_title($link);
https://metabox.io/docs/get-meta-value/
try:
$files = rwmb_meta( 'info' ); // Since 4.8.0
$files = rwmb_meta( 'info', 'type=file' ); // Prior to 4.8.0
if ( !empty( $files ) ) {
foreach ( $files as $file ) {
echo $file['url'];
}
}
I use the following to find all URL´s inside $content
$content = preg_match_all( '/(http[s]?:[^\s]*)/i', $content, $links );
But this will depend on the http:// part in http://www.google.com/some/path .
My questions are :
1 - How can I modify it in order to hit also the links that are start with only www , e.g. www.google.com?
2 - The main aim is to find the links, and replace them with a value that is returned from another function. I tried preg_match_callback() , but it is not working (probably using it wrong ..
$content = preg_replace_callback(
"/(http[s]?:[^\s]*)/i",
"my_callback",
$content);
function my_callback(){
// do a lot of stuff independently of preg_replace
// adding to =.output...
return $output;
}
Now , in my logic (which is probably wrong ) all matches from the $content would be replaced by $output. what am I doing wrong ?
(please no anonymous functions - i am testing on an old server)
EDIT I - after comments , trying to clarify with more details
function o99_simple_parse($content){
$content = preg_replace_callback( '/(http[s]?:[^\s]*)/i', 'o99_simple_callback', $content );
return $content;
}
callback :
function o99_simple_callback($url){
// how to get the URL which is actually the match? and width ??
$url = esc_url_raw( $link );
$url_name = parse_url($url);
$url_name = $description = $url_name['host'];// get rid of http://..
$url = 'http://something' . urlencode($url) . '?w=' . $width ;
return $url; // what i really need to replace
}
To modify the regex you already have to allow URLs that begin with www, you'd simply write this:
/((http[s]?:|www[.])[^\s]*)/i
+ ++++++++
I use PHP.
I have an URL that looks like this
http://www.mydomain.com/mydir/mydir2/?something=hello
I want this:
http://www.mydomain.com
I did it like this but it feels like the wrong way to do it
To long and ugly.
$url = 'http://www.mydomain.com/mydir/mydir2/?something=hello';
$root_url_a = explode('/', $url);
$root_url = $root_url_a[0] . '//' . $root_url_a[2];
$root_url_clean = $root_url_a[2];
Suggestions
Regex?
Xpath?
Some for me unknown PHP function?
The shortest most correct way of doing it will get my vote.
Ok here is an example:
$url = parse_url('http://www.mydomain.com/mydir/mydir2/?something=hello');
echo $url->scheme.'://'.$url->host;
Is along the right lines.
Though technically this is not even right since depending on whether you send in a scheme or not for a url parse_url can actually change the way it assigns variables, so I wrote:
function return_url($url){
$parsed_url = parse_url($url);
if(!$parsed_url){
return false;
}
if(isset($parsed_url['scheme'])){
if(!isset($parsed_url['host'])){
return false;
}else{
return $parsed_url['scheme'].'://'.$parsed_url['host'];
}
}
if(isset($parsed_url['path'])){
return 'http://'.$parsed_url['path'];
}
return false;
}
I would do it like this:
$url = "http://www.mydomain.com/mydir/mydir2/?something=hello";
echo parse_url($url, PHP_URL_HOST);
// Would echo:
http://www.mydomain.com
I would say RTM ;)
http://php.net/manual/en/function.parse-url.php
<?php
$url = 'http://username:password#hostname/path?arg=value#anchor';
print_r(parse_url($url));
echo parse_url($url, PHP_URL_HOST);
?>