Probably simple php regex - php

Question

Sorry for the simple question that I could research, but i crashed a database today, been here 12 hours, and want to go home.
I am rotating recursively through files trying to extract city, phone number, and email address so that I can match the city and phone to my database entries and update the users email address. In theory, they could just login with their email and request to reset their password.
heres what i need. my file contents look like this:
> Address : 123 main street City : somecity State/Province : somestate
> Zip/Postal Code : 12345 Country : United States Phone : [phone] Fax
> : E-Mail : example#example.com ==== CUSTOMER SHIPPING INFORMATION ===
I should note that there is other info before and after the snippet I showed. Can someone please help me with a regex to remove the 3 items? Thanks.

Answer 1

Try something like this, without regex..
$string = 'Address : 123 main street City : somecity State/Province : somestate Zip/Postal Code : 12345 Country : United States Phone : [phone] Fax : E-Mail : example#example.com ==== CUSTOMER SHIPPING INFORMATION ===';
$string = str_replace(
array(
' ==== CUSTOMER SHIPPING INFORMATION ===',
'Address',
'City',
'State/Province',
'Zip/Postal Code',
'Country',
'Phone',
'Fax',
'E-Mail'
)
, '', $string);
$string = explode(' : ', $string);
unset($string[0]);
print_r($string);
Result...
Array
(
[0] =>
[1] => 123 main street
[2] => somecity
[3] => somestate
[4] => 12345
[5] => United States
[6] => 1231231234
[7] =>
[8] => example#example.com
)
If there are linebreaks, something like this...
$string = explode("\n", $string);
foreach($string as $value){
list(, $info) = explode(' : ', $value);
echo $info . '<br />';
}
Solution with regex..
$fields = array('City', 'Phone', 'E-mail');
foreach($fields as $field){
preg_match("#$field : (.*?) #is", $string, $matches);
echo "$field : $matches[1]";
echo '<br />';
}
Result:
City : somecity
Phone : [phone]
E-mail : example#example.com

Answer 2

Something like this:
Address\s*:\s*(.*?)\s*City\s*:\s*(.*?)\s*State/Province\s*:\s*(.*?)\s*Zip/Postal Code\s*:\s*(.*?)\s*Country\s*:\s*(.*?)\s*Phone\s*:\s*(.*?)\s*Fax\s*:\s*(.*?)\s*E-Mail\s*:\s*(.*?)\s
Will work if you rip out the > at the start of each line first.
proof
If you print_r that, you'll see the different components.
Note the "dot matches all" modifier. Might be even easier if you rip out newlines too (after you take out the >).

Answer 3

What about this
$test =
'
> Address : 123 main street City : somecity State/Province : somestate
> Zip/Postal Code : 12345 Country : United States Phone : [phone] Fax
> : E-Mail : example#example.com ==== CUSTOMER SHIPPING INFORMATION ===
';
preg_match('#.*City : (.+?) .*? Country : (.+?) Phone : (.+?) .*#si',$test,$res);
var_dump($res);
result
array
0 => string '
> Address : 123 main street City : somecity State/Province : somestate
> Zip/Postal Code : 12345 Country : United States Phone : [phone] Fax
> : E-Mail : example#example.com ==== CUSTOMER SHIPPING INFORMATION ===
' (length=217)
1 => string 'somecity' (length=8)
2 => string 'United States' (length=13)
3 => string '1231231234' (length=10)