I can't figure out for the life of my to select from a collection with the or parameter. It's not working at all for me and I can't really find any documentation on it for php.
Here is my example code that doesn't return anything even though they exist in the collection:
$cursor = $products->find(
array(
'$or' => array(
"brand" => "anti-clothes",
"allSizes" => "small"
)
)
);
The $or operator lets you use boolean or in a query.
You give $or an array of expressions, any of which can satisfy the query.
You provided only one element in the array. Use:
find(array('$or' => array(
array("brand" => "anti-clothes"),
array("allSizes" => "small")
)));
Related
Hello i want to use an array as condition.
For example i have services with a zip as combination
12345 => cleaning,
54321 => cleaning
now i build my array together in a foreach loop
$searcharray = [];
foreach($services as $key => $val){
searcharray[] = array('service' => $val['service'], 'zip' => $val['zip']);
}
My search array lookes like this:
[
(int) 0 => [
'service' => 'cleaning',
'zip' => '12345'
],
(int) 1 => [
'service' => 'cleaning',
'zip' => '54321'
]
]
Then i try to get the data from my request table
$this->loadModel('Requests');
$openrequests = $this->Requests->find('all', array(
'conditions' => array(
'OR' => array(
$searcharray
)
)
));
It didnt work maybe of the keys in the array, because i set after the $searcharray for example [1] and then it works. I dont want to write the condition as string, but how can i solve it?
You have nested the conditions one level too deep.
Your $searcharray is already nested correctly, if you nest it again as in your example, then you're basically creating an OR node with only one child (which in turn has children itself), which is interpreted as basically "nothing", as you need at least two children for an operator to be used. The children in the array nested one level deeper will then be interpreted as AND, as that is the default when no operator is specified.
Long story short, just pass $searcharray as is:
'conditions' => [
'OR' => $searcharray,
]
See also
Cookbook > Database Access & ORM > Query Builder > Advanced Conditions
I'm trying to write a simple Mongo query to return all documents where the value of a field is null (or an empty array, I'm not sure what you call it).
Here is my query;
db.getCollection('contact').find({'poco.name.email':false})
Here is a screenshot of my collection using RoboMongo;
Ultimately, I need to transfer this to some PHP. So far I have this working;
$conditions = array_merge($conditions, [
'owner.$id' => $this->getId(),
'poco.name.familyName' => "Smith",
//not sure what goes here.. something like
//'poco.emails' => null,
]);
return Model_Mongo_Contact::getContacts($conditions, $sort, $fields, $limit, $skip);
That's probably going to be harder to answer without more access to the methods.. Or maybe not I am very new to Mongo it might be really obvious.
I'm not PHP expert but I'll be doing in mongo shell as:
db.collection.find({
$and: [
{"poco.email":{$exists: true}},
{"poco.email":{$ne: []}}
]})
Query above will list all documents where poco.name.email is not missing and is not empty.
The basic concept when looking for an "empty" array or even "non-existent" is to use a property of "dot notation" and search where the 0 index of the array does not exist. This can be achieved with using the $exists operator:
$conditions = array_merge($conditions, [
'owner.$id' => $this->getId(),
'poco.name.familyName' => "Smith",
'poco.emails.0' => array( '$exists' => FALSE )
]);
That condition is true when either there is no property at all, or if it is something other than an array ( therefore no "0" field property ) or indeed an "empty" array ( since there is no content at the first index ).
This works best when the field is actually "indexed". So if in your "normal" structure you have "sub-documents" inside the array element with say a consistent field named "address" which is indexed as "poco.emails.address", then you are best of pointing to that specific indexed property to see if it $exists or not:
$conditions = array_merge($conditions, [
'owner.$id' => $this->getId(),
'poco.name.familyName' => "Smith",
'poco.emails.0.address' => array( '$exists' => FALSE )
]);
But if the array consists purely of "values" only and no "sub-documents", then simply testing for the 0 index position of the array as initially demonstrated will be enough.
Example of a Mongo Entry:
array(
'name' => 'blog one',
'blogCategory' => array(
'displayAndLightMeasurement' => '1',
'LEDAndDisplayTestInstrument' => '0'
)
);
A Query like this works fine:
$blogInfoRaw = $collection->find(array('blogCategory' => array('displayAndLightMeasurement' => '1')));
When I try to '$or' query like this:
$blogInfoRaw = $collection->find(array('$or' => array('blogCategory' => array('displayAndLightMeasurement' => '1')),array('blogCategory' => array('LEDAndDisplayTestInstrument' => '1'))));
I get this error:
$or requires nonempty array
What am I doing wrong?
You really meant to use "dot notation" to reference the embedded fields:
$blogInfoRaw = $collection->find(
array(
'$or' => array(
array( 'blogCategory.displayAndLightMeasurement' => '1' ),
array( 'blogCategory.LEDAndDisplayTestInstrument' => '1')
)
)
);
Otherwise the notation you are using implies that the "only" elements present in the embedded level are those that you specify. This is not true since there are multiple keys. So "dot notation" solves this problem by referencing the distinct keys.
PHP array notation does not help here, but the $or needs to be a wrapping "real" array as in [] also.
Issuing a json_encode often helps when comparing to the official MongoDB examples.
we're often dealing with a code that looks like the following:
return $this->find(
'all', [
'fields' => ['DISTINCT Tag.tag', 'COUNT(Tag.tag) as count'],
'group' => ['Tag.tag'],
'order' => ['count' => 'DESC']
]);
This query leads us to the following output:
[0] => Array
(
[Tag] => Array
(
[tag] => walls.io
)
[0] => Array
(
[count] => 15
)
)
As you can see, the query returns the results in a "somehow wrong" nesting. The "count" field is unfortunately put into a pseudo [0]-array.
IIRC, CakePHP uses internally a syntax like Tag__field for correctly nesting virtual fields.
When changing the code to the Model__-syntax, the problem stays the same:
return $this->find(
'all', [
'fields' => ['DISTINCT Tag.tag', 'COUNT(Tag.tag) as Tag__count'],
'group' => ['Tag.tag'],
'order' => ['COUNT(Tag.tag)' => 'DESC']
]);
Output:
[0] => Array
(
[Tag] => Array
(
[tag] => walls.io
)
[0] => Array
(
[Tag__count] => 15
)
)
Workaround 1: array_map
CakePHP pros: Is there a better/more elegant solution than manually mapping the array after the select statement?
$tags = array_map(function($tag) {
$tag['Tag']['count'] = $tag[0]['count'];
unset($tag[0]);
return $tag;
}, $tags);
Workaround 2: virtual field
As described above, the usage of a virtual field might solve this problem:
$this->virtualFields = ['count' => 'COUNT(Tag.Tag)'];
return $this->find(
'all', [
'group' => ['Tag.tag'],
'order' => [$this->getVirtualField('count') => 'DESC']
]);
Unfortunately, with this solution, it's not possible to specify ANY fields at all. only by completely leaving the "fields"-key, the nesting of the array works as expected. when selecting $fields = ['Tag.tag', $this->getVirtualField('count')] the nesting is wrong again.
CakePHP pros: Do you know a method, where the nesting is done right, even if you specify your own fields?
Looking at the CakePHP code, such a method does not exist.
Have a look at the file lib/Cake/Model/Datasource/Database/Mysql.php.
Find the method called: Mysql::resultSet( $results ); (around line 240).
That method maps the result to an array. To determine if a column is part of a table or not it uses PDOStatement::getColumnMeta(). For your "virtual column" that method will return an empty table and so the CakePHP code will put it separately, see the else branch
$this->map[$index++] = array(0, $column['name'], $type);
In order to avoid that else branch you would have to use Virtual fields, but then you run into the other problems that you have noticed.
So you are left with the array_map solution or you could try to overload that Mysql class and add your custom logic at how to identify where a column fits.
I need to perform a query based on the value of some boolean fields. These fields may not exist in some documents, as they were added at a later stage.
I tested the query in the shell and worked ok:
db.product.find({$or: [{approved:true},{$and: [{approved:{$exists:false}}, {sold:{$ne:true}}]}]})
But trying to do the same with the PHP driver doesn't seem to work:
$condA = array('approved' => true);
$condB = array('approved' => array('$exists' => false), 'sold' => array('$ne' => true));
$query = array('pid' => $prodId, '$or' => array($condA, array('$and' => $condB)));
I tested some variants but I'm always getting this error in the log:
assertion 13086 $and/$or/$nor must be a nonempty array
Any hint on what I might be doing wrong? Thanks in advance.
Since multiple "clauses" of a query are interpreted as "and" you don't need the $and in your query. If you take out $and:[ ] you end up with a simpler
{ $or : [ { approved : true }, { approved : {$exists:false}, sold : {$ne:true} } ] }
When you convert that into corresponding PHP that should work for you.