data from few MySQL tables sorted by ASC - php

Question

In the dbase I 've few tables named as aaa_9xxx, aaa_9yyy, aaa_9zzz. I want to find all data with a specified DATE and show it with the TIME ASC.
First, I must find a tables in the dbase:
$STH_1a = $DBH->query("SELECT table_name
FROM information_schema.tables
WHERE table_name
LIKE 'aaa\_9%'
");
foreach($STH_1a as $row)
{
$table_name_s1[] = $row['table_name'];
}
Second, I must find a data wit a concrete date and show it with TIME ASC:
foreach($table_name_s1 as $table_name_1)
{
$STH_1a2 = $DBH->query("SELECT *
FROM `$table_name_1`
WHERE
date = '2011-11-11'
ORDER BY time ASC
");
while ($row = $STH_1a2->fetch(PDO::FETCH_ASSOC)) {
echo " ".$table_name_1."-".$row['time']."-".$row['ei_name']." <br>";
}
}
.. but it shows the data sorted by tables name, then by TIME ASC. I must to have all this data (from all tables) sorted by TIME ASC.
Thank You dev-null-dweller, Andrew Stubbs and Jaison Erick for your help.
I test the Erick solution :
foreach($STH_1a as $row) {
$stmts[] = sprintf('SELECT *
FROM %s
WHERE date="%s"', $row['table_name'], '2011-11-11');
}
$stmt = implode("\nUNION\n", $stmts);
$stmt .= "\nORDER BY time ASC";
$STH_1a2 = $DBH->query($stmt);
while ($row_1a2 = $STH_1a2->fetch(PDO::FETCH_ASSOC)) {
echo " ".$row['table_name']."-".$row_1a2['time']."-".$row_1a2['ei_name']." <br>";
}
it's working but I've problem with 'table_name' - it's always the LAST table name.
//----------------------------------------------------------------------
...and the ending solution with all fixes, thanks all for your help, :))
foreach($STH_1a as $row) {
$stmts[] = sprintf("SELECT *, '%s' AS table_name
FROM %s
WHERE date='%s'", $row['table_name'], $row['table_name'], '2011-11- 11');
}
$stmt = implode("\nUNION\n", $stmts);
$stmt .= "\nORDER BY time ASC";
$STH_1a2 = $DBH->query($stmt);
while ($row_1a2 = $STH_1a2->fetch(PDO::FETCH_ASSOC)) {
echo " ".$row_1a2['table_name']."-".$row_1a2['time']."-".$row_1a2['ei_name']." <br>";
}

Answer 1

Instead of printing the line as you fetch it from db, gather all data in one array taht you will be able to sort with usort and your own callback function.
Other option is to get it sorted directly from mysql, using UNION selects like this:
$SQL = "
(SELECT '$table_name_1' AS tbl_name, time, ei_name FROM `$table_name_1` WHERE date = '2011-11-11')
UNION
(SELECT '$table_name_2' AS tbl_name, time, ei_name FROM `$table_name_2` WHERE date = '2011-11-11')
UNION
(SELECT '$table_name_3' AS tbl_name, time, ei_name FROM `$table_name_3` WHERE date = '2011-11-11')
ORDER BY time ASC
";

Answer 2

You need to use the UNION sql directive:
<?php
$STH_1a = $DBH->query("SELECT table_name
FROM information_schema.tables
WHERE table_name
LIKE 'aaa\_9%'");
$stmts = array();
foreach($STH_1a as $row)
{
$stmts[] = sprintf('SELECT *, %s AS `table_name` FROM %s WHERE date="%s"', $row['table_name'], $row['table_name'], '2011-01-01');
}
$stmt = implode("\nUNION\n", $stmts);
$stmt .= "\nORDER BY time ASC";
$STH_1a2 = $DBH->query($stmt);
FIX: Included the table name as returned value.

Answer 3

The correct way to fix it will be to UNION your selection data as stated in other answers.
A quick fix would be to change your second code block to something like:
$Sorted = array();
foreach($table_name_s1 as $table_name_1)
{
$STH_1a2 = $DBH->query("SELECT *
FROM `$table_name_1`
WHERE date = '2011-11-11'
ORDER BY time ASC
");
while ($row = $STH_1a2->fetch(PDO::FETCH_ASSOC)) {
$Sorted[$row['time']] = " ".$table_name_1."-".$row['time']."-".$row['ei_name']." <br>";
}
}
ksort($Sorted);
foreach($Sorted as $Entry) {
echo $Entry;
}
Note: This will 'fail' for cases where there are multiple entries for one date.