I have a string that contains a lot of links and I would like to adjust them before they are printed to screen:
I have something like the following:
replace_this
and would like to end up with something like this
replace this
Normally I would just use something like:
echo str_replace("_"," ",$url);
In in this case I can't do that as the URL contains underscores so it breaks my links, the thought was that I could use regular expression to get around this.
Any ideas?
Here's the regex: <a(.+?)>.+?<\/a>.
What I'm doing is preserving the important dynamic stuff within the anchor tag, and and replacing it with the following function:
preg_replace('/<a(.+?)>.+?<\/a>/i',"<a$1>REPLACE</a>",$url);
This will cover most cases, but I suggest you review to make sure that nothing unexpected was missed or changed.
pattern = "/_(?=[^>]*<)/";
preg_replace($pattern,"",$url);
You can use this regular expression
(>(.*)<\s*/)
along with preg_replace_callback .
EDIT :
$replaced_text = preg_replace_callback('~(>(.*)<\s*/)~g','uscore_replace', $text);
function uscore_replace($matches){
return str_replace('_','',$matches[1]); //try this with 1 as index if it fails try 0, I am not entirely sure
}
Related
I think I need to use the preg_replace function but not sure exactly how to type in the patterns I want to find and replace. Basically, I want to replace this:
: u"x"x",
with this:
: u"x'x",
x means that any characters can go there. But I don't know how to write the x in PHP.
Thank you!
Edit: basically, I want to replace that middle double-quote with a single-quote. And I'll be searching through a big JSON file to do it. Probably should have said this at the start.
You could use this regular expression:
$result = preg_replace('#(: u".*?)"(.*?")#', "$1'$2", $string);
i'm searching for keywords in a string via a regular expression. It works fine for all keywords, exept one which contains a forward slash in it: "time/emit" .
Even using preg_quote($find,'/'), which escapes it, i still get the message:
Unknown modifier 't' in /frontend.functions.php on line 71
If i print the find pattern, it shows /time\\/emit/ . Without preg_quote, it shows /time/emit/ and both return the same error message.
Any bit of knowledge would be useful.
Try to begin and end your regular expression with different sign than /
I personally use `
I've seen people using #
I think most chars are good. You can read more about it here: http://pl.php.net/manual/en/regexp.reference.delimiters.php
Like this:
preg_match('#time/emit#', $subject); // instead of /time/emit/
To put it another way: Your $find variable should contain rather #time/emit# than /time/emit/
looks like you have something already escaping it..
preg_quote('time/emit') // returns time\/emit
preg_quote('time\/emit') // returns time\\/emit
as a hack you could simply do:
preg_quote(stripslashes($find)) // will return time\/emit
bit of code?
the the 'regex' for that particular term should look something like '/time/emit/'. With a set of keywords there may be a more efficient method so seeing what you are doing would be good.
this should work:
$a="Hello////////";
$b=str_replace($a,"//","/");
echo $b;
i have a following pattern, inside the html file, that i would like to parse in php to get a link but for now i dont see a solution as i am trying to use QueryPath and my case is simply not a common dom element:
<script>
to.addVariable("site_name","http://www.sitename.com");
</script>
I just would like to return a link part of that pattern in order to print it.
Hope someone could recommend how to.
Thank you.
UPDATE: I would like to get http://www.sitename.com as a value from the code above using php, maybe with phpQuery or QueryPath.
Something like this I guess will work
<?PHP
$text = '
<script>
to.addVariable("site_name","http://www.sitename.com");
</script>
';
preg_match('#to\.addVariable\("site_name","([^"]+)"\);#', $text, $matches);
echo $matches[1];
?>
You can also use preg_match_all if you have more than one to.addVariable(... strings in your <script> section.
Try this regular exp:
$regex = '#to\.addVariable\("(.+?)", "(.+?)"\)#';
Then, use preg_match_all to get the matches. If you want to check that the URL is an actual URL, the get any regular expression to match URLs and place it in the second .+?, these patterns will match anything between "", so you should check that you have what you need unless you trust the source.
NOTE: I'm not so sure that " doesn't needs to be escaped in regex, so check it out
Hope I can help!
If you don't understand something drop a comment!
I think I am right in asuming that RegEx can do this job, I'm just not sure how I would do it!
Basically I have a number of links on my website that are in the format of:
Example
I need some code that will transform the href value so that it gets outputed in lowercase, but that does not affect the anchor text . E.g:
Example
Is this possible? And if so, what would be the code to do this?
you can use preg_replace_callback
something like that
function replace($match){
return strtolower($matches[0])
}
...
preg_replace_callback('/(href="[^"]*")/i' 'replace',$str);
Using preg_match and strtolower functions
preg_match('/\<a(.*)\>(.*)\<\/a\>/i',$cadena, $a);
$a[1]=strtolower($a[1]);
$cadena = preg_replace('/\<a(.*)\>(.*)\<\/a\>/i',$a[1],$cadena);
echo $cadena;
Regards!
i'm searching for keywords in a string via a regular expression. It works fine for all keywords, exept one which contains a forward slash in it: "time/emit" .
Even using preg_quote($find,'/'), which escapes it, i still get the message:
Unknown modifier 't' in /frontend.functions.php on line 71
If i print the find pattern, it shows /time\\/emit/ . Without preg_quote, it shows /time/emit/ and both return the same error message.
Any bit of knowledge would be useful.
Try to begin and end your regular expression with different sign than /
I personally use `
I've seen people using #
I think most chars are good. You can read more about it here: http://pl.php.net/manual/en/regexp.reference.delimiters.php
Like this:
preg_match('#time/emit#', $subject); // instead of /time/emit/
To put it another way: Your $find variable should contain rather #time/emit# than /time/emit/
looks like you have something already escaping it..
preg_quote('time/emit') // returns time\/emit
preg_quote('time\/emit') // returns time\\/emit
as a hack you could simply do:
preg_quote(stripslashes($find)) // will return time\/emit
bit of code?
the the 'regex' for that particular term should look something like '/time/emit/'. With a set of keywords there may be a more efficient method so seeing what you are doing would be good.
this should work:
$a="Hello////////";
$b=str_replace($a,"//","/");
echo $b;