I'm really struggling with getting checkboxes to work, I've looked up tutorials
and have found no help... I'm not sure how to set up my table in MAMP for checkboxes and how to insert it...
If some one could help that would be just fantastic guys...
HTML:
<form action="mainpage2.php" method="POST">
Search : <input type="text" name="firstname" id="name" />
<input type="submit" name="confirm" value="Submit" />
<input type="checkbox" name="tick[]" value="male" />
<input type="checkbox" name="tick[]" value="female" />
<input type="checkbox" name="tick[]" value="alien" />
</form>
PHP:
if(isset($_POST['confirm'])) {
$subject = $_POST['firstname'];
$subjec = $_POST['tick'];
$result = mysql_query("INSERT INTO chipsticks (Name,sports) VALUES ('$subject'),('subjec');",$database);
You will need to flatten the array in order to store it in database.
if(isset($_POST['confirm']))
{
$subject = $_POST['firstname'];
$subjec = $_POST['tick'];
$sports = '';
if(is_array($subjec) && count($subjec)>0)
{
$sports = implode(',',$subjec);
}
$result = mysql_query("INSERT INTO chipsticks (Name,sports) VALUES ('$subject','$sports')",$database);
}
Instead of implode, you can also use serialize
Related
I want to find the group of checkbox that user tick the most to something else
please help me!
Thanks.
Here my HTML
<form method="post">
<input type="checkbox" name="group_1[]" value="V1"/>V1
<input type="checkbox" name="group_1[]" value="V2"/>V2
<input type="checkbox" name="group_1[]" value="V3"/>V3
<br>
<input type="checkbox" name="group_2[]" value="V4"/>V4
<input type="checkbox" name="group_2[]" value="V5"/>V5
<input type="checkbox" name="group_2[]" value="V6"/>V6
<br>
<input type="checkbox" name="group_3[]" value="V7"/>V7
<input type="checkbox" name="group_3[]" value="V8"/>V8
<input type="checkbox" name="group_3[]" value="V9"/>V9
<br><br>
<input type="submit" name="submit" />
</form>
PHP
<?php
if (isset($_POST['submit'])) {
$group_1 = count($_POST['group_1']);
$group_2 = count($_POST['group_2']);
$group_3 = count($_POST['group_3']);
if ($group_1 > $group_2 and $group_1 > $group_3) {
echo "Group 1 is highest ";
}
elseif ($group_2 > $group_1 and $group_2 > $group_3) {
echo "Group 2 is highest ";
}
elseif ($group_3 > $group_1 and $group_3 > $group_2) {
echo "Group 3 is highest ";
}
}
?>
i'm new in php so I code "If Else" but i don't want to use this. and one more i don't want to code specific like "$group_1 = count($_POST['group_1']);" i just want to define "name of checkbox" to get value.
all i want is get same result but different code.
I think you could use the max() function to get highest value
Please refer to http://php.net/max
Probably like this:
<?php
if (isset($_POST['submit'])) {
$group_1 = count($_POST['group_1']);
$group_2 = count($_POST['group_2']);
$group_3 = count($_POST['group_3']);
$array = array("Group 1"=>$group_1,"Group 2"=>$group_2,"Group 3"=>$group_3);
$maxIndex = array_search(max($array), $array);
echo $maxIndex;
}
?>
I have a form with multiple fields: Textinputs, Checkboxes, Radios.. and I want to submit it to a MySQL database. When I comment the checkboxes HTML, and the corresponding php code, everything is working fine, and everything is submitted and saved in the DB. If I try to submit the checkbox-form and I uncomment it, nothing get submitted, and clicking on the submit-button doesn't make any effect.
How can I submit the value of the checkbox-field to the MySQL-Database as a string, with the values separated with a semi-colon? For ex. if the checkbox fields are: Ab, Cd, De, Fg - and "Ab" and "De" are checked, the following string gets submitted: "Ab;Cd"
Here is a part of my HTML-form:
<div class="row">
<div class="col-sm-4">
<fieldset class="form-group">
<label for="plattform">Platform</label>
<form id="formId">
<input type="checkbox" name="check_list[]" value="Android">Android
<input type="checkbox" name="check_list[]" value="iPhone">iPhone
<input type="checkbox" name="check_list[]" value="iPad">iPad
<input type="checkbox" name="check_list[]" value="Windows Phone">Windows Phone
</form>
<!-- <input type="checkbox" name="check_list[]" value="Android">
<input type="checkbox" name="check_list[]" value="iPhone">
<input type="checkbox" name="check_list[]" value="iPad">
<input type="checkbox" name="check_list[]" value="Windows Phone"> -->
</fieldset>
</div>
<div class="col-sm-4">
<fieldset class="form-group">
<label for="featured">Featured</label>
<div>
<input type="radio" name="featured" required>True</input>
</div>
<div>
<input type="radio" name="featured" required checked>False</input>
</div>
</fieldset>
</div>
here is a sample of my php-file:
<?php /* Attempt MySQL server connection. Assuming you are running
MySQL server with default setting (user 'root' with no password) */
/* Database connection start */
$servername = "localhost";
$username = "serverName_Here";
$password = "password_Here";
$dbname = "dbName_Here";
$conn = mysqli_connect($servername, $username, $password, $dbname) or die("Connection failed: " . mysqli_connect_error());
// Check connection
if($conn === false){
die("ERROR: Could not connect. " . mysqli_connect_error());
}
// Escape user inputs for security
$stName = mysqli_real_escape_string($conn, $_POST['sName']);
$lgName = mysqli_real_escape_string($conn, $_POST['lName']);
$desc = mysqli_real_escape_string($conn, $_POST['desc']);
$Platform = '';
if(!empty($_POST['check_list'])) {
$counter = 0;
foreach($_POST['check_list'] as $check) {
if ($counter < 1) {
$Platform = $check;
} else {
$Platform = $excludePlatform + ';' + $check;
}
counter++;
}
}
$Platform = mysqli_real_escape_string($conn, $_POST['check_list']);
$sql = "INSERT INTO tableName_Here (stName, lgName, details_description, Platform) VALUES ('$stName', '$lgName', '$desc', '$Platform')";
if(mysqli_query($conn, $sql)){
echo "Records added successfully.";
} else {
echo "ERROR: Could not able to execute $sql. " . mysqli_error($conn);
} // close connection
mysqli_close($conn); ?>
You need to have the checkboxes within the form tags.
The easiest way is to put the form opening and closing tabs above and below the rest of the field code. The submit buttons should be within the form as well.
On the backend checkbox values will come through as an array. You can then do something like this if you want to save them comma separated.
$values = implode(', ', $_POST['check_list']);
First of all,Why you haven't used POST as method in form tag also you haven't used submit button.In that way you can access value of checkboxes in php like
$value=$_POST['check_list[]'];
Try this whole example,
Table Structure
CREATE TABLE IF NOT EXISTS `games` (
`id` int(12) NOT NULL AUTO_INCREMENT,
`game_name` varchar(255) NOT NULL,
PRIMARY KEY (`id`)
) ENGINE=InnoDB DEFAULT CHARSET=latin1 AUTO_INCREMENT=1;
<?php
include_once("yourconfig.php"); //include your db config file
extract($_POST);
$check_exist_qry="select * from games";
$run_qry=mysql_query($check_exist_qry);
$total_found=mysql_num_rows($run_qry);
if($total_found >0)
{
$my_value=mysql_fetch_assoc($run_qry);
$my_stored_game=explode(',',$my_value['game_name']);
}
if(isset($submit))
{
$all_game_value = implode(",",$_POST['games']);
if($total_found >0)
{
//update
$upd_qry="UPDATE games SET game_name='".$all_game_value."'";
mysql_query($upd_qry);
}
else
{
//insert
$ins_qry="INSERT INTO games(game_name) VALUES('".$all_game_value."')";
mysql_query($ins_qry);
}
}
?>
<form method="post" action="">
Games You Like: <br/>
<input type="checkbox" name="games[]" value="1" <?php if(in_array(1,$my_stored_game)){echo "checked";}?>><label>Football</label><br>
<input type="checkbox" name="games[]" value="2" <?php if(in_array(2,$my_stored_game)){echo "checked";}?>><label>Basket Ball</label><br>
<input type="checkbox" name="games[]" value="3" <?php if(in_array(3,$my_stored_game)){echo "checked";}?>><label>Pool</label><br>
<input type="checkbox" name="games[]" value="4" <?php if(in_array(4,$my_stored_game)){echo "checked";}?>><label>Rugby</label><br>
<input type="checkbox" name="games[]" value="5" <?php if(in_array(5,$my_stored_game)){echo "checked";}?>><label>Tennis</label><br>
<input type="checkbox" name="games[]" value="6" <?php if(in_array(6,$my_stored_game)){echo "checked";}?>><label>Cricket</label><br>
<input type="checkbox" name="games[]" value="7" <?php if(in_array(7,$my_stored_game)){echo "checked";}?>><label>Table Tennis</label><br>
<input type="checkbox" name="games[]" value="8" <?php if(in_array(8,$my_stored_game)){echo "checked";}?>><label>Hockey</label><br>
<input type="submit" name="submit" value="submit">
</form>
this is just basic example and query i have added in this example, you can learn from this basic example and i think this is very useful for you... if useful than give correct answer for this solution
I am trying to show specific data if two variables are set in a form.
$retired = "";
$stolen = "";
if(isset($_POST['submit'])){
$retired = $_GET['showretired'];
$stolen = $_GET['showstolen'];
}
I have tried the bellow:
<?php }elseif(isset($_GET['showretired']) && (isset($_GET['showstolen'])){ ?>
Which does not work
<?php }elseif(isset($retired, $stolen)){
Which works when not set
<?php }elseif(isset($_GET['showretired'], $_GET['showstolen'])) {
This one only shows the retired part.
I am unsure of the best way to do this.
Here is the form:
<form>
<label>Show Retired Column </label><input type="checkbox" name="showretired">
<label class="space">Show Stolen Column </label><input type="checkbox" name="showstolen">
<input class="space" type="submit" name="submit" value="Refine">
</form>
This is how I am using the variable in the same file.
<?php }elseif(isset($_GET['showretired'], $_GET['showstolen'])) {
?>
<tr>
<th>Retired</th>
<th>Stolen</th>
</tr>
<?php }else{ ?>
<?php
if(isset($_POST['submit'])){
if(isset($_POST['showretired'])) {
$retired = $_POST['showretired'];
}
if(isset($_POST['showstolen'])) {
$stolen = $_POST['showstolen'];
}
if(isset($retired)){
echo $retired;
}
if(isset($stolen)) {
echo $stolen;
}
}
?>
<form action="" method="POST">
<label>Show Retired Column </label><input type="checkbox" name="showretired" value="The retired field">
<label class="space">Show Stolen Column </label><input type="checkbox" name="showstolen" value="The showstolen field">
<input class="space" type="submit" name="submit" value="Refine">
</form>
No method on the form means it will default to GET. Change the conditional and check your checkboxes.
<?php
if(isset($_GET['submit'])){
$foo = isset($_GET['foo']) ? true : false;
$bar = isset($_GET['bar']) ? true : false;
var_dump($foo);
var_dump($bar);
}
?>
<form>
<input type="checkbox" name="foo">
<input type="checkbox" name="bar">
<input type="submit" name="submit">
</form>
if(isset($_GET['submit'])){
if(isset($_GET['showretired']) && $_GET['showretired'] !="" && isset($_GET['showstolen']) && $_GET['showstolen'] !="" )
{
echo $retired." ".$stolen;
}
}
and form
<form>
<label>Show Retired Column </label><input type="checkbox" name="showretired" value="showretired" checked="checked">
<label class="space">Show Stolen Column </label><input type="checkbox" name="showstolen" value="showstolen" checked="checked">
<input class="space" type="submit" name="submit" value="Refine">
</form>
Hope it will help
When my insert runs it will write the text in the text box but if I choose a radio button selection other than "other" nothing is inserted into the table.
If I remove the "other"code the radio button selected is written to the table.
here is the code
<input type="radio" name="job" value="PHP Programmer">PHP Programmer
<input type="radio" name="job" value="SQL Programmer">SQL Programmer<br>
<input type="radio" name="job">Other <input type="text" name="job" >
<h3>* If yes, check which ISO standard(s) you are accredited?</h3>
<input type="radio" name="iso_standard" value="17020">17020
<input type="radio" name="iso_standard" value="17025">17025
<br />
<input action="submit" type="submit" name="submit" value="Submit">
</form>
<?php
if(isset($_POST['job']) && isset($_POST['iso_standard']))
{
$job = mysqli_real_escape_string($db, $_POST['job']);
$iso_standard =mysqli_real_escape_string($db, $_POST['iso_standard']);
$sql="insert into tbl_test_insert(iso_cert, iso_standard)
values ('$job', '$iso_standard')";
if(!mysqli_query($db, $sql))
{
die('Error: ' .mysqli_error($db));
}
echo "1 record added";
}
else
{
echo "You didn't choose all the options!
}
?>
You are overwriting the value of job with the text input field. It does not mather if it has any value or not.
Please rename your <input type="text" name="job" > to for example otherJob and you should be fine
edit:
change <input type="radio" name="job">Other <input type="text" name="job" >
to <input type="radio" name="job" value="other">Other <input type="text" name="otherJob">
change $job = mysqli_real_escape_string($db, $_POST['job']);
to
$job = mysqli_real_escape_string($db, $_POST['job']);
$otherJob = mysqli_real_escape_string($db, $_POST['otherJob']);
if ($job == 'other') {
$jobField = $otherJob;
} else {
$jobField = $job;
}
and change $sql="insert into tbl_test_insert(iso_cert, iso_standard)
values ('$job', '$iso_standard')";
to $sql="insert into tbl_test_insert(iso_cert, iso_standard)
values ('$jobField', '$iso_standard')";
I have the following html code:
<form method="post" action="arrayplay.php">
<input type="checkbox" value="1" name="todelete[]"/>
<input type="checkbox" value="2" name="todelete[]"/>
<input type="checkbox" value="3" name="todelete[]"/>
<input type="checkbox" value="4" name="todelete[]"/>
<input type="submit" value="delete" name="delete"/>
</form>
And the following PHP script:
//arrayplay.php
foreach ($_POST['todelete'] as $id)
{
echo $id . "<br/>";
}
?>
It is supposed to echo out each element value but instead I get an error. I am getting really frustrated. If I use:
<form method="post" action="arrayplay.php">
<?php
$dbc= //connection
$query = "SELECT * FROM email_list";
$result = mysqli_query($dbc, $query);
while ($row = mysqli_fetch_array($result)) {
echo '<input type="checkbox" value="' . $row['id'] . '" name="todelete[]" />';
echo $row['first_name'];
echo ' ' . $row['last_name'];
echo ' ' . $row['email'];
echo '<br />';
}
mysqli_close($dbc);
?>
<input type="submit" name="submit" value="Remove" />
</form>
It works perfectly fine! Why? The first (hard coded html) holds the exact same value as the one that retrieves them from the database. I am having a real hard time understanding retrieving values from an array with $_POST. Why does name=foo[] create an array? Is it an associative or numeric array? I'm sorry for all of the questions, I'm just really ready to pull my hair out.
if you just named the input foo it would only get one value. because square brackets are commonly used for arrays, foo[] is how in the html form, you indicate an array. of course on the PHP side you just call it foo as you are aware from your working example.
I've tested this and it should work:
<?php
if ($_POST['delete']) {
foreach ($_POST['todelete'] as $id) {
echo $id.' selected<br />';
}
}
?>
<form method="post" action="arrayplay.php">
<input type="checkbox" value="1" name="todelete[]"/>
<input type="checkbox" value="2" name="todelete[]"/>
<input type="checkbox" value="3" name="todelete[]"/>
<input type="checkbox" value="4" name="todelete[]"/>
<input type="submit" value="delete" name="delete"/>
</form>
If you're still having troubles, you can try:
<?php
if ($_POST['delete']) {
for ($i = 0; $i < 4; $i++) {
if (isset($_POST['todelete'][$i])) {
echo $_POST['todelete'][$i].' selected<br />';
}
}
}
?>