I am echoing the data received from a blob column from mysql like this:
<?php
$con = mysql_connect("localhost","username","pass");
if (!$con)
{
die('Could not connect: ' . mysql_error());
}
mysql_select_db("mydb", $con);
if(isset($_GET['imageid'])){
$img=$_GET['imageid'];
$sql="SELECT image FROM vrzgallery WHERE id=$img";
$que=mysql_query($sql);
$ar=mysql_fetch_assoc($que);
echo $ar['image'];
header('Content-type: image/jpeg');
}
?>
QUESTION: How can i reduce my image to say like 500px X 500px
It is really the bad idea to store images in DB, because they are too big, harder to maintain, harder to work with and so on. You should store only path to it or file name.
To resize image you may use PHP's GD library. Create it using imagecreatefromstring() and manipulate using imagecopyresized() or imagecopyresampled(). Example from manual:
// File and new size
$filename = 'test.jpg';
$percent = 0.5;
// Content type
header('Content-Type: image/jpeg');
// Get new sizes
list($width, $height) = getimagesize($filename);
$newwidth = $width * $percent;
$newheight = $height * $percent;
// Load
$thumb = imagecreatetruecolor($newwidth, $newheight);
$source = imagecreatefromjpeg($filename);
// Resize
imagecopyresized($thumb, $source, 0, 0, 0, 0, $newwidth, $newheight, $width, $height);
// Output
imagejpeg($thumb);
Related
I have stored multiple images in base64 inside my database. I get images using php as image path. But I want to reduce size of my image when decoding it from base64, because it slows down my app if I load full size image. (Full size image I need just in backend).
/*
DB stuff getting base64 string from database
$img = base64 string (can be with 'data:image/jpg;base64,' in front, thats for the str_replace())
*/
if($img){
header("Content-Type: image/png");
echo base64_decode(str_replace("data:image/jpg;base64,","",$img));
}
Everything works nice this way. I use it like this:
<img src="http://example.com/getimg.php?id=4" />
or in css. I need this because of security reasons, I cant store any image on server, also in path I have access_token variable, so random person cant see images.
Is there a way to do this without storing the actual image in server?
You can use imagecreatefromstring and imagecopyresized.
Live example here
<?php
if ($img) {
$percent = 0.5;
// Content type
header('Content-Type: image/jpeg');
$data = base64_decode($img);
$im = imagecreatefromstring($data);
$width = imagesx($im);
$height = imagesy($im);
$newwidth = $width * $percent;
$newheight = $height * $percent;
$thumb = imagecreatetruecolor($newwidth, $newheight);
// Resize
imagecopyresized($thumb, $im, 0, 0, 0, 0, $newwidth, $newheight, $width, $height);
// Output
imagejpeg($thumb);
}
Is there something I am missing here? If I change imagejpeg($thumb, $newImage);
to imagejpeg($thumb); it echos a load of unreadable characters. The thumb image directory exists.
My ultimate aim is to copy an image at a lower quality.
$filename = $imageDirectory . '/1.jpg';
$percent = 0.5;
$newImage = $imageDirectory . '/thumbs/1.jpeg';
echo "image: <br>";
echo $filename;
list($width, $height) = getimagesize($filename);
$newwidth = $width * $percent;
$newheight = $height * $percent;
// Load
$thumb = imagecreatetruecolor($newwidth, $newheight);
$source = imagecreatefromjpeg($filename);
// Resize
imagecopyresized($thumb, $source, 0, 0, 0, 0, $newwidth, $newheight, $width, $height);
// Output
imagejpeg($thumb, $newImage);
UPDATE: I now realize that the second parameter must be an image location with the new name. So... I have redefined $newImage. The path is fine... if I upload an image named 1.jpg to that location manually it exists at that path.
You'll have to add the correct Content-Type header for the response if you want to output the image to the browser:
header('Content-Type: image/jpeg');
imagejpeg($yourimage);
Please check the first example in the documentation for more information. If you want to decrease the quality before outputting to your browser check the third example.
I found the following script from PHP site to half the size of the image. I use the database to fetch the link of the image. Other things are working correctly which means there isn't any kind of error anywhere except this one.
echo "<img src='".// File and new size
$filename = '$row["image"]';
$percent = 0.5;
// Content type
header('Content-Type: image/jpeg');
// Get new sizes
list($width, $height) = getimagesize($filename);
$newwidth = $width * $percent;
$newheight = $height * $percent;
// Load
$thumb = imagecreatetruecolor($newwidth, $newheight);
$source = imagecreatefromjpeg($filename);
// Resize
imagecopyresized($thumb, $source, 0, 0, 0, 0, $newwidth, $newheight, $width, $height);
// Output
imagejpeg($thumb);
"'>"
Error:
The whole page is destroyed and there is a broken link of an image.
Hope you guys will help me!
It works after you drop those lines:
echo "<img src='".// File and new size
"'>"
header does it for you, informs that there is jpg coming, no need to echo image tag.
The other solution is to remove this line:
header('Content-Type: image/jpeg');
And create new file, then use it as a source of an image:
// Output
$new_filename = 'new_image.jpg';
imagejpeg($thumb,$new_filename);//saves new image to a file, instead of outputting it to the screen
echo "<img src='$new_filename'>";
Try this it works
<?php
$filename = '$row["image"]';
$percent = 0.5;
// Content type
header('Content-Type: image/jpeg');
// Get new sizes
list($width, $height) = getimagesize($filename);
$newwidth = $width * $percent;
$newheight = $height * $percent;
// Load
$thumb = imagecreatetruecolor($newwidth, $newheight);
$source = imagecreatefromjpeg($filename);
// Resize
imagecopyresized($thumb, $source, 0, 0, 0, 0, $newwidth, $newheight, $width, $height);
// Output
echo "<img src='".imagejpeg($thumb)."'>";
?>
I used the code below to get an image:
$url = "http://maps.googleapis.com/maps/api/staticmap?size=800x600&zoom=12¢er=(10.763705518561297,106.64444580078126)";
$content = file_get_contents($url);
I received a 640px x 640px image meanwhile I expected a 800px x 600px one. How do I scale that image to 800px x 600px?
Try doing this:
<?php
// File and new size
$filename = 'test.jpg';
$percent = 0.5;
// Content type
header('Content-Type: image/jpeg');
// Get new sizes
list($width, $height) = getimagesize($filename);
$newwidth = $width * $percent;
$newheight = $height * $percent;
// Load
$thumb = imagecreatetruecolor($newwidth, $newheight);
$source = imagecreatefromjpeg($filename);
// Resize
imagecopyresized($thumb, $source, 0, 0, 0, 0, $newwidth, $newheight, $width, $height);
// Output
imagejpeg($thumb);
?>
Here, rescaling is done by 50%, you can change parameter as per your requirement. You can even use Imagick for image manipulation. See, if that helps.
Referred: PHP Manual
Sure this is a easy one for you experts, I`m trying to upload a image to the site and save the path to the database. If possible, how can i change the image size before saving?
Here is my script that handles to update query when updating:
<?php // Get Event ID
$update=$_GET['update'];
// Create Session
$event_name=$_POST['event_name'];
$event_description=$_POST['event_description'];
$event_date=$_POST['event_date'];
$event_time=$_POST['event_time'];
$event_cost=$_POST['event_cost'];
$event_image=$_POST['event_image'];
// Connection to MySQL Database.
include ('_includes/_dbconnection.php');
include ('_includes/_dbopen.php');
// Update Event using Event ID.
$sql="UPDATE b_events SET ename = '$event_name', edescription = '$event_description', edate = '$event_date', etime = '$event_time', ecost = '$event_cost', eimage = '$event_image' WHERE id = '$update'";
$result=mysql_query($sql);
if($result){
header('Location: _events.php');
}
else {
header('Location: _home.php');
}
?>
I have the following code in the update.html for the image:
<input name="event_image" type="file" />
Thanks!!!
To change the image size must resize. A function to create a copy with specific dimensions.
<?php
// File and new size
$filename = 'test.jpg';
$percent = 0.5;
// Content type
header('Content-Type: image/jpeg');
// Get new sizes
list($width, $height) = getimagesize($filename);
$newwidth = $width * $percent;
$newheight = $height * $percent;
// Load
$thumb = imagecreatetruecolor($newwidth, $newheight);
$source = imagecreatefromjpeg($filename);
// Resize
imagecopyresized($thumb, $source, 0, 0, 0, 0, $newwidth, $newheight, $width, $height);
// Output
imagejpeg($thumb);
?>
Source: http://php.net/manual/en/function.imagecopyresized.php
Php has GD library for working with images: function imagecopyresampled resize an image. Verify that GD is enalbed in you php config
http://us3.php.net/imagecopyresampled