pass values from 2 tables to a view codeigniter - php

Question

im having function that will display both buy and sell listings. Im trying to display both of these in one page.
im getting the values from 2 different tables and i wanr to pass both the values into the same template
Can someone please suggest how to do it?
controller
function leads(){
$this->load->model('listings');
$data['mylists']=$this->member_functions->mine();
$data['mylists2']=$this->member_functions->mine();
$data['heading']='headings/heading_view';
$data['body']='listbody';
$data['nav']='right';
$this->load->view('includes/template',$data);
}
Model
function mine(){
$mylists=$this->db->get('buy');
if ($mylists->num_rows()>0){
foreach ($mylists->result() as $a)
{
$data[]=$a;
}
return $data;
}
$mylists2=$this->db->get('sell');
if ($mylists2->num_rows>0)
{
foreach ($mylists->result() as $b)
{
$data[]=$b;
}
return $data;
}
}
View
<h2>Buy leads</h2>
<?php foreach ($mylists as $mylist):?>
<p><?php echo "$mylist->type1 in $mylist->country as $mylist->buyid" ?></p>
<?php endforeach;?>
</div>
<br />
<h2>Sell leads</h2>
<?php foreach ($mylists2 as $mylist2):?>
<p><?php echo "$mylist2->type1 in $mylist2->country" ?></p>
<?php endforeach;?>

Answer 1

You cannot use 2 return statements within the same function, since whenever the first is encountered...well, the function returns, and stops there. Try returning a single array with the 2 results instead, such as:
Model:
function mine(){
$mylists=$this->db->get('buy');
if ($mylists->num_rows()>0){
foreach ($mylists->result() as $a)
{
$data['res1'][]=$a;
}
}
$mylists2=$this->db->get('sell');
if ($mylists2->num_rows>0)
{
foreach ($mylists->result() as $b)
{
$data['res2'][]=$b;
}
}
return $data;
}
Controller:
$data['lists']=$this->member_functions->mine();
In your view, this array should be called like $lists['res1'] adn $lists['res2']