Currently, trying to get this to work with Opencart, but I think my knowledge of the file structure needs some help.
I have added an additional field into the DB for Opencart, which I added to provide data based on the person logging in with an affiliate code.
After I query that file, I would like the fields echo'ed in the header.tpl output to the screen for every page.
If I query the database in the Index.php file, for the tracking number in the DB, it returns the right information the first time and displays it in the header, but then when I click on the products, the next screen there will be an error, because it looks like the Index.php file is constantly being re-run for every page on Opencart, even when the URL link changes ? Is there another file I am missing which I should put the query into, and also where do I place variables to display on each header file.
Thanks in advance.
It's hard to know what exactly you are wanting to do based on your question. If you are wanting to display affiliate data in the header, you should be using the file /catalog/controller/common/header.php to assign the data to the header view. You should then be adding the data in the /catalog/view/theme/your-theme-name/template/common/header.tpl file.
Really speaking, you should be using
if($this->affiliate->isLogged()) {
// Code here
}
To make sure that the affiliate is actually logged in before showing the data. To pull the data from the database, you are probably going to want to edit /system/library/affiliate.php and pull the data that way rather than in a controller file, so you can get any of the information across the store files
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I just wanted to say I got all my information from this document for the most part. Making modifications as I learn. https://developers.google.com/maps/documentation/javascript/mysql-to-maps
Now I echo'd my information from sql database.. and read the file as a myfile.php.. Problem is.. if I go to www.mywebsite.com/myfile.php.. I can see all the results of my sql database.
How do I hide this information from view, but can call upon it?
fairly new to PHP and webdesign.... I have a website which has a bunch of products for vehicles - all of this is stored in a database.
In order to narrow down what products are available, I want to take the user through 2-3 pages where they firstly select what categorey of product they want, then what make of car they have, then the model, then I want to run a mysql query with that information and return the answerson a page.
I already have the code to request the info from a database and then display it on the page, but The way the current website is setup, they are hard coded mysql queries (meaning the user didnt input any data to get there).
So how can I transfer variable between php pages? Page 1 (contains Categorey) - then pass to Page 2 (contains Make) then page to Page 3 (contains Model) then compile the three variavles collections, and pass them to results.php (a standard results page which Gets variables and then searches).
I know this might seem basic, but I am really stumped as to how to get it coded.
If someone can give me an a newbie explanation about how to achieve this? Thank you
You can pass PHP variables through URLs for example
Your HTML code,
<a href='yourPage.php?yourVariable=someValue'>TEST!</a>
Your PHP code,
if (isset($_GET['yourVariable'])) {
$yourVariable = $_GET['yourVariable'];
// Your code here.
}
Now using this you can create what you want with a little bit of tinkering.
Remember
You need to use $_GET because parameters are being passed using the URL and not a POST request.
Don't forget to clean all input.
I have a piece of code that counts the lines of code within a wordpress site. I have successfully managed to send that number to the wordpress database so I can call on it in a different location in my theme files (this is because the script needs to be in the root of the install to count the lines of code).
Whilst this works really nicely, the BIG issue I have is that the number won't update itself automatically. i.e. the code for counting lines is www.mysite.com/loc.php and I mus go to this page and let it load before it updates the value in the database.
Is there a way to make it so that the value just automatically updates, so I don't have to navigate to the page for this to happen? i.e. when I add more lines of code, the value in the database updates itself.
Code for sending value to the db is as follows:
$num_of_lines = $folder -> count_lines();
update_option('line_count', $num_of_lines);
look into jquery and ajax call
Wordpress provides for you the framework to call backend functions on the frontend
http://wptheming.com/2013/07/simple-ajax-example/
another example:
http://premium.wpmudev.org/blog/how-to-use-ajax-with-php-on-your-wp-site-without-a-plugin/
You need to create a trigger, in order to update automatically MYSQL database
Look at this, i hope it will help
How to automatically update a MYSQL column value using formula and data from other columns in same row?
I'm looking at neatening my file structures and code. At the moment I'm making an image gallery, it has a management page which allows the user to upload, edit and delete images/information.
To upload an image, the user would select their files, sumbit the form and arrive at uploaded.php.
To delete an image, the user would click a link taking them to delete.php?id=IMAGEID.
To edit an image, the user would be taken to a page with an editor. Upon making any revisions they'd then be taken to edit.php?id=IMAGEID.
Each page runs either a function. I feel it's unecessary to have three different pages to run three different functions. Is there any way I could neaten this process?
Well, it just depends on how you like to manage your files and how you are using your IDE when you've to edit something.
If you're working alone, it's clearly up to you. If you know someone will, maybe, have to rework your code someday, having three files could be a plus, somehow.
I guess you're not concerned about SEO for these pages, but just in case the problem appears again, it could be better to have actions in parameters, rather than in files name.
/manage.php?edit or /manage.php?delete or /manage.php?upload
But, if your code is really really big, using three files could still result in a lower use of memory (Well, very slight improvement, but still)
Exactly you don't need 3 pages for each function
1)Delete ,instead of redirection the user to a different page and delete it ,you can add an image button which delete icon and when user click on it ,it call a specific function in your php and delete it then refresh your page.
2)Edit and Insert : these are 1 page ,like make your insert page if it doesnt have a query string with the Image ID then it's insert function ,else it contains and ID then load the content of this Image inside your inputs and while saving check if there is ID then update else insert new record
So,you moved from 3 pages to 1 page only.Hope this helped you.
I have a database of different stores.
When a user clicks on a store name, I want an Ajax function to run displaying information about the store in a different div.
Information categories for all stores wll be the same: products carried, location, general information, etc.
I could easily make it so that each different store uses a different file name as an argument to the ajax function, and all files would have the same layout/format but with different data.
However i feel like this is bad form. How can i make it so that i have one fixed template and all that changes is the information specifics imputed into the template?
Please note that the store information display pages will also need to be able to have clickable links of their own (i.e. click on location and a google map pops up).
Is it something to do with XML? I dont know much about it.
Instead of returning a template, return the data.
So it says getstore.php?id=2 which returns a json string
{"name":"my store", "info" :"blah"}
Then you use java script to insert a new div, populated with that data.