I am trying to create videos from images sequence. I tried all the below code given in $ff_command variable.
$path = dirname(__FILE__);
$ff_command = "ffmpeg -f image2 -i {$path}/img%03d.jpg video.mpg";
$ff_command = "ffmpeg -r 10 -b 1800 -i {$path}/img%03d.jpg test1800.mpg";
$ff_command = "ffmpeg -i {$path}/img%03d.jpg -s 1280x720 -aspect 16:9 -r 24 -vb 20M teste.mp4";
$ff_command = "ffmpeg -f image2 -i {$path}/img%03d.jpg -vcodec mpeg4 -b 800k video.avi";
$ff_command = "ffmpeg -f image2 -i {$path}/img%03d.jpg -vcodec libx264 -b 800k video.avi";
Most of these commands are creating a video file. But when I open that video nothing comes or first image is coming for a split second and nothing after that
Please let me know what I am doing wrong here
I noticed that video is too short to see. Is it possible to increase the video duration so that we can see all the images?
Related
FFmpeg version 0.6.5 is installed on my web server.
In my website mp4 videos allowed to upload, that part is done.
Now i am working on create a thumbnail of the video and then resize it.
The following links are I referred.
https://trac.ffmpeg.org/wiki/Create%20a%20thumbnail%20image%20every%20X%20seconds%20of%20the%20video
https://trac.ffmpeg.org/wiki/Scaling%20(resizing)%20with%20ffmpeg
This is the command i used to create a thumbnail from video, this command is working.
$cmd = "ffmpeg -i test.mp4 -ss 0 -vframes 1 out.png";
After creating the thumbnail, I tried the following the command to resize it, but this is not working.
$cmd = 'ffmpeg -i out.png -vf scale=210:-1 output_320x240.png';
And Some other commands i have tried
$cmd = "ffmpeg -ss 10 -i test.mp4 -vframes 1 -filter scale=-1:150,crop=200:150 output.jpg";
$cmd = "ffmpeg -itsoffset -1 -i test.mp4 -vframes 1 -filter:v scale=280:-1 output.jpg";
In my localhost I used the following command to create thumbnail and resize in a single command, but this is also not working in the server.
$ffmpeg = 'C:\\ffmpeg\\bin\\ffmpeg';
$video = 'test.mp4';
$cmd = "$ffmpeg -itsoffset -1 -i $video -vframes 1 -filter:v scale=\"210:-1\" thumbnail.png";
Thanks to all
I'm generating thumbnails like so:
exec(ffmpeg -itsoffset -4 -i '.$path.' -vcodec mjpeg -vframes 1 -an -f rawvideo -s 300x300 '.$other_path);
Is it possible to not specify the exact size of output image and set it to 100%?
You can simply remove the -s 300x300 option, and it will note resize.
I am using this code for my thumbnail image
<?php
$ffmpeg = '/usr/bin/ffmpeg';
$second = 2;
$video = 'video/123.mp4';
$image = 'thumb/123.jpg';
$command = "$ffmpeg -itsoffset -$second -i $video -vcodec mjpeg -vframes 1 -an -f rawvideo -s 175x150 $image";
its giving me the thumbnail image BUT i want to rotate that thumbnail image. I already tried transpose and rotate but nothing happen even i lost the thumbnail image also.
Tried solutions but nothing happen :-
$command ="$ffmpeg -itsoffset -$second -i $video -vcodec mjpeg -vframes 1 -vf 'transpose=1' -an -f rawvideo -s 175x150 $image";
and
$command ="$ffmpeg -itsoffset -$second -i $video -vcodec mjpeg -vframes 1 -vf 'rotate=PI/2' -an -f rawvideo -s 175x150 $image";
Please help me.....
So this command works for generating a thumbnail 5 seconds into the video, with a size of 300x300:
$cmd = '/usr/local/bin/ffmpeg -i '.$this->getUploadRootDir().'/'.$fname.' -ss 00:00:05 -f image2 -vframes 1 -s 300x300 '.$this->getUploadRootDir().'/thumb_'.$output;
However, I want to keep the aspect ratio so I changed my code to this:
$cmd = "/usr/local/bin/ffmpeg -i ".$this->getUploadRootDir()."/".$fname." -ss 00:00:5 -f image2 scale='min(300\, iw):-1' ".$this->getUploadRootDir()."/thumb_".$output;
The above code correctly sizes the image, however it's of the first frame in the video.. I need the thumbnail to be 5 seconds in. Any help would be much appreciated.
You can do that with a command line similar to:
ffmpeg -i inputVideo -vf scale='min(300,iw)':-1 -ss 00:00:05 -f image2 -vframes 1 thumbnail.jpg
So in your script, add -vf (video filter) before scale and reorder input and output parameters like below:
$cmd = "/usr/local/bin/ffmpeg -i ".$this->getUploadRootDir()."/".$fname." -vf scale='min(300\, iw):-1' -ss 00:00:5 -f image2 -vframes 1 ".$this->getUploadRootDir()."/thumb_".$output;
#alexbuisson has the correct answer, but just to confirm as I'm playing with ffmpeg today:
This works for me:
ffmpeg -i "my_video.mp4" -ss 00:00:05 -f image2 -vf scale="min(300\, iw):-1" -vframes 1 "capture.jpg"
I get one Jpeg 300 px wide with the correct image ratio.
So adapted to your code this becomes:
$cmd = "/usr/local/bin/ffmpeg -i ".$this->getUploadRootDir()."/".$fname." -ss 00:00:05 -f image2 -vf scale='min(300\, iw):-1' ".$this->getUploadRootDir()."/thumb_".$output;
i have a simple site on which people upload videos, so i want to generate a simple thumbnail from an uploaded video. i have tried every trick and way to do this from a number of websites but i am failing to make the command run without problems.
$video = $_FILES['vpopupdropin']["tmp_name"];
$ffmpeg = "C:\\Ffmpeg\\ffmpeg-20130605-git-3289670-win64-static\\bin";
$image = "manu.jpg";
$second = 12;
$size = "150x90";
$command = "$ffmpeg -i $video -an -ss $second -s $size -vcodec mjpeg $image";
echo $command;
shell_exec($command);
if(shell_exec($command)){
echo 'okay';
echo '<img src="'.$image.'"/ >';
}
else{
echo ' Problem';
}
i Echoed the the command from PHP and this is what i got:
C:\Ffmpeg\ffmpeg-20130605-git-3289670-win64-static\bin -i C:\xampp\tmp\php27F1.tmp -an -ss 12 -s 150x90 -vcodec mjpeg manu.jpg Problem
so i took the Command above and entered it in Cmd and got this error
[image2 # 00000000000000003d87580] Could not open file : manu.jpg
av_interleaved_write_frame(): Input/output error. the uploaded file transfers well to where iam saving it and plays well on the site meaning the file is not corrupt. but the thumbnail command seems to fail, i have even checked the other questions on this site but i seem to fail to get the right solution. the paths in the Command are correct and i have verified that at least
You did not give ffmpeg a name :-) So you tried to execute a \\bin folder !
$ffmpeg = "C:\\Ffmpeg\\ffmpeg-20130605-git-3289670-win64-static\\bin";
you forget ffmpeg.exe
$ffmpeg = "C:\\Ffmpeg\\ffmpeg-20130605-git-3289670-win64-static\\bin\\ffmpeg";
I do it for a .avi with following command
ffmpeg -i Echo2012.avi -r 1 -s 1024x576 -f image2 -vframes 1 foo-001.jpg
Don't execute your command twice !
$command = "$ffmpeg -i $video -an -ss $second -s $size -vcodec mjpeg $image";
echo $command;
shell_exec($command);
if(shell_exec($command)){
EDIT :
your command string :
ffmpeg -i upload.tmp -an -ss 12 -s 150x90 -vcodec mjpeg manu.jpg
-vcodec codec (output) : Set the video output codec. It's a switch for a output video. You want as output an image.
-an : You can disable Audio stream. You don't need Audio for an image.
-ss : position (input/output) When used as an input option (before -i), seeks in this input file to position.
my command string :
ffmpeg -i Echo2012.avi -r 1 -s 1024x576 -f image2 -vframes 1 foo-001.jpg
-r : fps (input/output,per-stream) . Set frame rate (Hz value, fraction or abbreviation).
As an input option, ignore any timestamps stored in the file and instead generate timestamps assuming constant frame rate fps.
-f image2 : Force output file format image2. The format is normally auto detected guessed from the file extension for output files.
-vframes number (output) : Set the number of video frames to record.