I'm building a site using CodeIgniter. I have lots of experience using SQL with PHP but having some trouble working through CodeIgniter.
I'm using the following code to set userdata to hold a logo from my database.
Currently I only have 1 logo and it works fine but I need to edit it to handle multiple logos.
$query3 = $this->db->query('SELECT file FROM ohes_flyer_logos');
$row3 = $query3->row();
$data = array( 'userlogo' => $row3->file );
$this->session->set_userdata($data);
Where the Logos are listed...
echo $this->session->userdata('userlogo');
How can I edit this to pass through a full list of logos, and echo them all out?
Calling row() grabs only a single record. You probably want to use result() or result_array() and pass that to the view where you can loop through them. For example:
$query3 = $this->db
->query('SELECT file FROM ohes_flyer_logos')
->result();
$data = array('userlogo' => $query3);
$this->session->set_userdata($data);
Then in your view, you can do this:
foreach ($userlogo as $logo)
{
echo $logo->file; // do your processing here
}
Related
I'm trying to fetch certain values from and then pass it to another model in the same control.
However I'm only able to display the last row in the view.
I have shared my code below and I'm not sure where I'm going wrong.
Controller:
public function test($id){
$mapping_details = $this->queue_model->get_mapping_details($id);
foreach ($mapping_details as $value) {
$data['agent_details'] = array($this->agent_model->get_agent_details($value['user_id']));
}
$this->load->view('app/admin_console/agent_queue_mapping_view', $data);
}
Model:
public function get_agent_details($id) {
$query = "select * from user_table where id = ".$id." and company_id = ".$this->session->userdata('user_comp_id');
$res = $this->db->query($query);
return $res->result_array();
}
Welcome to StackOverflow. The problem is the iteration in your controller. You are iterating through the $mapping_details results and per every iteration you are re-assigning the value to $data['agent_details'] , thus losing the last stored information. What you need to do is push to an array, like this:
foreach ($mapping_details as $value) {
$data['agent_details'][] = $this->agent_model->get_agent_details($value['user_id']);
}
However, wouldn't it be best if you created a query that uses JOIN to get the related information from the database? This will be a more efficient way of creating your query, and will stop you from iterating and calling that get_agent_details() over and over again. Think of speed. To do this, you would create a model method that looks something like this (this is just an example):
public function get_mapping_details_with_users($id){
$this->db->select('*');
$this->db->from('mapping_details_table as m');
$this->db->join('user_table as u', 'u.id=m.user_id');
$this->db->where('m.id', $id);
$this->db->where('u.company_id', $this->session->userdata('user_comp_id'));
return $this->db->get()->result();
}
Then your controller will only need to get that model result and send it to the view:
public function test($id){
$data['details_w_users'] = $this->queue_model->get_mapping_details_with_users($id);
$this->load->view('app/admin_console/agent_queue_mapping_view', $data);
}
Hope this helps. :)
So I trying to build a notification system (CodeIgniter) and not store it in my database by this unique ID. Now I got some problem to using `SELECT query.
Also this is array stored in "value" row:
[{"id":0,"user_id":"1","comment":"That's a Nice Video.","posttime":1403523177,"status":1},{"id":1,"user_id":"4","comment":"Nice to see this..!!","posttime":1403590409,"status":1}]
And this is my (not work) query:
$query = $this->db->get_where('post_meta',array('status'=>1),in_array('user_id', $id));
Ideas?
Note: Notification will be sparated by "user_id".
You should not use in_array('user_id', $id) on that function because it returns boolean.
On the active record page: https://ellislab.com/codeigniter/user-guide/database/active_record.html you can take a look at parameter it takes for get_where() function
$query = $this->db->get_where('mytable', array('id' => $id), $limit, $offset);
Notice how the third parameter takes $limit which talks about the number of data you'll receive. (Leaving this blank will return you all data).
Some code examples:
If you just want to get the data with status = 1, use the following:
$query = $this->db->get_where('post_meta',array('status'=>1));
If you want to get the data with status = 1 and user_id = $id, use the following:
$this->db->like('value', '"user_id":"'.$id.'"');
$query = $this->db->get_where('post_meta',array('status'=>1));
The solution above is not the best, but it should work.
The $this->db->like() function will create rules to get data in value row which has "user_id":"$id" where $id is the value that you define.
What if I want to get all notifications and group them based on their ID?
I usually get all the data and then use PHP to group them into its own array. I think it's cheaper than relying on database to do that (Correct me if i'm wrong).
So use the first code:
$query = $this->db->get_where('post_meta',array('status'=>1));
Then iterate them using foreach() or whatever you find convenient.
$data = array();
foreach($query as $k=>$v) {
// Run a function to get User ID
$user_id = your_function_here($v->value);
if(!isset($data[$user_id]))
$data[$user_id] = array();
// This is just some example to group them together, you can optimize it to your own liking
array_push($data[$user_id],$v);
}
your_function_here() is your function to get the user_id from value row on your database.
I'm building a codeigniter site and I have a database table of books - one record for each book with title, author, etc etc fields. I know how to get the db table contents and pass an object to the view and then do a foreach loop to get the values. I could print a table of all the data. However I then get a bit muddled. The page has areas for each book and the data for a book will be one row of the data array. So what I want to do is, if the author is 'this' value, find the correct row in which the author appears and then get the other fields. How can I do a foreach loop that finds the one row with the author's name?
I can't think how to do it - I seem to go round and round in circles.
Help!
Edit: Code:
OK so here's the controller method:
public function index()
{
$books = $this->Books_model->getbooks();
$data = array(
'body_id'=>'home',
'main'=>'home_view',
'books'=>$books
);
$this->load->view('templates/template_main_view', $data);
}
and here's the model method:
function getbooks(){
$query = $this->db->get('books');
return $query->result();
}
so I end up with the variable $books (which is of course an object, not an array) in the view and a var_dump() shows that it has all the data. So far so good. I can then use a foreach loop to get values.
Now I want to extract a single row/record conditional on the fact that it has a given value for 'author' and assign each field of that row to a variable that I can use them in the view. And then I want to repeat that for the other rows. I can't seem to work out how to do that.
Afternote:
I found a way of doing this but not sure if it's the best or neatest:
I do this:
if(isset($books)){
foreach($books as $row){
if($row->author == 'authorname'){
$title = $row->title;
}
}
}
it works but seems a bit clumsy/overkill??
How about creating a specific function for getting the book/s that matches the author name?
For example:
In your controller you can do something like this:
public function index()
{
$data['books'] = $this->Books_model->get_each_book();
$data = array(
'body_id'=>'home',
'main'=>'home_view',
'books'=>$books
);
$this->load->view('templates/template_main_view', $data);
}
The in your model, do something like this:
function get_each_book(){
$this->db->where('author','authorname');
$query = $this->db->get('books');
return $query->result_array();
}
This way, you are gonna filter the results in the model already.
Then in your view, access the variable 'books' through a foreach loop:
Example:
foreach($books as $row)
{
$title = $row['title'];
echo $title;
}
I am new to CodeIgniter .Can some one please help me by telling how to pass $row['main_products_cat_id']; in model to 'id'=> 'my id here', in controller. I tried so many ways but I failed.
Thanks!!!
This is my model
function cart_product_records($id){
$this->db->from('tbl_sub_products');
$this->db->where('tbl_sub_products.sub_product_id', $id);
$query = $this->db->get();
foreach ($query->result_array() as $row){
echo $row['main_products_cat_id'];
echo $row['sub_product_id'];
echo $row['sub_product_name'];
echo $row['sub_product_description'];
echo $row['sub_product_image'];
echo $row['sub_product_price'];
}
return $query->result();
}
this is my controller
function shopping_cart(){
$id = $this->input->get('id');
if($query = $this->mod_products->cart_product_records($id)){
$data['result'] = array(
'id' => 'my id here',
'qty' => my qty here,
'price' => my price here,
'name' => 'my product name here'
);
}
}
First - you should not echo data in your model - you should really only echo data in your view file.
The way that your data is flowing is first you are passing $id from your controller to your cart_product_records function in the mod_products model. The model then runs a query and gets data from your database. This data is represented by $query->result_array() or $query->result() (you're using both of these but you should only use one, once).
So you then have return $query->result() which sends your data back to your controller. The data will be stored in the $query variable, because you have $query = $this->mod_products->cart_product_records($id).
If I were you I would add an !empty() check to the if statement, so it would look like this:
if( !empty($query = $this->mod_products->cart_product_records($id)) ){
Then, depending on what data you want to get from $query, you're either going to want to construct a loop (which would enable you to extract multiple ids, prices, etc), or you could retrieve specific values from $query, like $query[0][main_products_cat_id] (assuming $query is an array) or $query[0]->main_products_cat_id (if it's an object).
I hope that helps!
Your $query holds the database results object. So, you'll do this in your $data array in your controller.
$data['result'] = array(
'id' => $query->main_products_cat_id,
// carry on...
);
I dosen't make any sense to write
echo $row['main_products_cat_id'];
....
In your loop create array as
foreach ($query->result_array() as $row){
$return_array[] = $row;
}
return $return_array
and in controller, you can access as
$query['your_id'];
In my CodeIgniter project I'm getting the list of projects and successfully output them on a page. However, the data in one of the columns on that page should be retrieved from a different table in DB using the project ID. Could anybody help me to figure out how that can be done? Basically I need to make another query to that other table specifying the project id but don't actually know how to do that with CodeIgniter.
UPDATE
In the model I'm getting the list of projects with the following function:
function get_projects_list($page, $limit){
$sql = sprintf("SELECT * FROM Project WHERE deleted != 1 LIMIT %d, %d", ($page-1)*$limit, $limit);
$query = $this->db->query($sql);
return $query->result();
}
And in the controller I call the following function:
$projects_list = $this->Project_management_model->get_projects_list($curPage, self::$LIMIT_PER_PAGE);
$data['projects_list'] = $projects_list;
$data['cur_page'] = $curPage;
$data['page_count'] = $pageCount;
$this->load->view('project_management_view', $data);
And in the view I simply run on the $data with foreach and list the results in a table. In that table there's a column where I need to show a result from another table based on the ID of the project of that very row.
Thanks for helping.
You didn't mention whether you are using ActiveRecord or not. I am assuming that you are. I'll also guess that maybe what you need to do is use a JOIN.
If you were using straight SQL, you would do this using some SQL that might look something like this:
SELECT a.appointment_time, u.user_real_name FROM appointment a, site_user u WHERE u.site_user_id = a.user_id;
That would pull the user's name from the user table based on the user id in the appointment table and put it with the appointment time in the query results.
Using ActiveRecord, you would do something like this:
$this->db->select('appointment_time,user_real_name')->from('appointment')->join('site_user', 'site_user_id=appointment_user_id');
But why don't you tell us a little bit more about your question. Specifically, do you want this column in the other table to be related to the rows from the first table? If so, my JOIN suggestion is what you need.
I've actually found a way to do that with a custom helper. Creating a new helper and loading it in the controller gives an option to use the function from that helper in the view.
Thanks.
public function get data()
{
$this->db->flush_cache();
$query = $this->db->get('project_table');
$result = $query->result();
$data = array();
for ($i = 0;$i < count($result);$i++)
{
$data[$i] = $result[$i];
$data[$i]['project_data'] = temp($result[$i]->id);
}
return data;
}
private function temp($id = 0)
{
$this->db->flush_cache();
$this->where('id',$id);
$query = $this->db->get('project_table2');
$result = $query->result();
if (count($result) != 0)
return $result[0]->data;
}
you can do it by some thing like that,or you can use sub-query by query function of database.