I have a date 2015-12-16
i want to get the date of the first day's date for the current week of my date
here 2015-12-16 is in the week 51 of the year then i want to get the first day's date of the week 51 ( 2015-12-14 here)
how could i do it ?
thank you
EDIT: it must work when there are 53 weeks in the year (like in 2015 for example)
You can do the following:
$dateTime = new DateTime("2015-12-16");
$weekNo = $dateTime->format("W");
$newDate = new DateTime();
$newDate->setISODate($dateTime->format("Y"), $weekNo);
Example:
http://sandbox.onlinephpfunctions.com/code/281a1ac298bfee8be421e333e4b7e92c6bb44d65
Since the above is a bit off in some cases here's something more reliable:
$dateTime = new DateTime("2016-01-01");
$dateTime->sub(new DateInterval("P".($dateTime->format("w")-1)."D")); //Since the weekdays are 1-based.
Example:
http://sandbox.onlinephpfunctions.com/code/c5cb0f077fa77974d977ddbffa6bc0b61f9d7851
$date = new \DateTime('2015-12-16');
echo $date->modify('last sunday +1 day')->format('Y-m-d');
This gets start of this week if you count monday to sunday.
Try this:
date('Y-m-d', strtotime('This week', strtotime('2015-12-16')));
I need to get the DATE of this week's Thursday (or any other day) OR next week's Thursday (or any other day)
The scenario is that there are 3 tours happening every week.. I need to find out next tour date
If today is tuesday and date is 21/01/2014 and tours happen on tuesday, friday and sunday.. then I need to find out next tour date which will be on friday on friday
Similarly, if today is Friday, I'll need to find out date on next week's tuesday.
So far, I tried using strtotime("next tuesday") but it doesn't seem to work well
echo strtotime("next Thursday");
Example straight from PHP.net, should work. And for the Thursday after that one you can do
$nextThursday= strtotime("next Thursday");
$secondThursday=strtotime("next Thursday",$nextThursday); // And so on
Demo
Try this,
<?php
$next_thursday = strtotime("next Thursday");
$this_thurday = strtotime('thursday this week');
if($next_thursday==$this_thurday)
{
$numberOfWeeks = 1;
$next_thursday = $next_thursday + ($numberOfWeeks * 60 * 60 * 24 * 7);
}
echo date("Y/m/d", $this_thurday);
echo date("Y/m/d", $next_thursday);
?>
I was looking for something like this and found the following in a comment here from deceze:
(new DateTime('now'))->modify('+5 days')
I used this in the follow way:
$date = DateTime('15 apr 15');
$date->modify('next thursday');
var_dump($date);
This worked for me so I am putting this out there as another possibility for those looking.
I am trying to get the second thursday from a datetime.
Code
$test = new DateTime('2013-08-02 10:00');
echo $test->modify('second thursday'.$test->format('H:i'))->format('Y-m-d H:i');
The above code returns 2013-08-15 10:00 instead of 2013-08-08 10:00
But it works correctly when I use the following code
$test = new DateTime('2013-08-02 10:00');
echo $test->modify('second wednesday'.$test->format('H:i'))->format('Y-m-d H:i');
First day of month of 2013-August is Thursday.
And there is bug in the code that if if the first day is Thursday , first Thursday will come in the next week i.e 8-August and like wise 2nd second Thursday will come on 15-August
this code will help
echo date('Y-m-d', strtotime('second thursday of august 2013'));
updated code
$test = new DateTime('2013-08-02 10:00');
echo date('Y-m-d', strtotime("second thursday of august 2013")).' '.$test->format('H:i');
Added By RC
From PHP strtotime manual page
In PHP 5 prior to 5.2.7, requesting a given occurrence of a given
weekday in a month where that weekday was the first day of the month
would incorrectly add one week to the returned timestamp. This has
been corrected in 5.2.7 and later versions.
try this,
echo date('Y-m-d', strtotime('second thursday of august 2013'));
try this one. i have already check and it shows the result you want.
$test = new DateTime('2013-08-00 10:00');
echo $test->modify('second thursday'.$test->format('H:i'))->format('Y-m-d H:i');
$test = new DateTime('2013-08-02 10:00');
echo $test->modify('second thursday'.$test->format('H:i'))->format('Y-m-d H:i');
'second Thursday' means the second Thursday after the current date. So the expected outcome is 2013-08-15. If you want the second Thursday of the given month, you could specify it like this:
$test = new DateTime('2013-08-02 10:00');
echo $test->modify('second thursday of this month '.$test->format('H:i'))->format('Y-m-d H:i');
Note that 'this month' refers to the date currently stored in the DateTime object, not on the date the code is executed.
I need to get previous month and year, relative to current date.
However, see following example.
// Today is 2011-03-30
echo date('Y-m-d', strtotime('last month'));
// Output:
2011-03-02
This behavior is understandable (to a certain point), due to different number of days in february and march, and code in example above is what I need, but works only 100% correctly for between 1st and 28th of each month.
So, how to get last month AND year (think of date("Y-m")) in the most elegant manner as possible, which works for every day of the year? Optimal solution will be based on strtotime argument parsing.
Update. To clarify requirements a bit.
I have a piece of code that gets some statistics of last couple of months, but I first show stats from last month, and then load other months when needed. That's intended purpose. So, during THIS month, I want to find out which month-year should I pull in order to load PREVIOUS month stats.
I also have a code that is timezone-aware (not really important right now), and that accepts strtotime-compatible string as input (to initialize internal date), and then allows date/time to be adjusted, also using strtotime-compatible strings.
I know it can be done with few conditionals and basic math, but that's really messy, compared to this, for example (if it worked correctly, of course):
echo tz::date('last month')->format('Y-d')
So, I ONLY need previous month and year, in a strtotime-compatible fashion.
Answer (thanks, #dnagirl):
// Today is 2011-03-30
echo date('Y-m-d', strtotime('first day of last month')); // Output: 2011-02-01
Have a look at the DateTime class. It should do the calculations correctly and the date formats are compatible with strttotime. Something like:
$datestring='2011-03-30 first day of last month';
$dt=date_create($datestring);
echo $dt->format('Y-m'); //2011-02
if the day itself doesn't matter do this:
echo date('Y-m-d', strtotime(date('Y-m')." -1 month"));
I found an answer as I had the same issue today which is a 31st. It's not a bug in php as some would suggest, but is the expected functionality (in some since). According to this post what strtotime actually does is set the month back by one and does not modify the number of days. So in the event of today, May 31st, it's looking for April-31st which is an invalid date. So it then takes April 30 an then adds 1 day past it and yields May 1st.
In your example 2011-03-30, it would go back one month to February 30th, which is invalid since February only has 28 days. It then takes difference of those days (30-28 = 2) and then moves two days past February 28th which is March 2nd.
As others have pointed out, the best way to get "last month" is to add in either "first day of" or "last day of" using either strtotime or the DateTime object:
// Today being 2012-05-31
//All the following return 2012-04-30
echo date('Y-m-d', strtotime("last day of -1 month"));
echo date('Y-m-d', strtotime("last day of last month"));
echo date_create("last day of -1 month")->format('Y-m-d');
// All the following return 2012-04-01
echo date('Y-m-d', strtotime("first day of -1 month"));
echo date('Y-m-d', strtotime("first day of last month"));
echo date_create("first day of -1 month")->format('Y-m-d');
So using these it's possible to create a date range if your making a query etc.
If you want the previous year and month relative to a specific date and have DateTime available then you can do this:
$d = new \DateTimeImmutable('2013-01-01', new \DateTimeZone('UTC'));
$firstDay = $d->modify('first day of previous month');
$year = $firstDay->format('Y'); //2012
$month = $firstDay->format('m'); //12
date('Y-m', strtotime('first day of last month'));
strtotime have second timestamp parameter that make the first parameter relative to second parameter. So you can do this:
date('Y-m', strtotime('-1 month', time()))
if i understand the question correctly you just want last month and the year it is in:
<?php
$month = date('m');
$year = date('Y');
$last_month = $month-1%12;
echo ($last_month==0?($year-1):$year)."-".($last_month==0?'12':$last_month);
?>
Here is the example: http://codepad.org/c99nVKG8
ehh, its not a bug as one person mentioned. that is the expected behavior as the number of days in a month is often different. The easiest way to get the previous month using strtotime would probably be to use -1 month from the first of this month.
$date_string = date('Y-m', strtotime('-1 month', strtotime(date('Y-m-01'))));
I think you've found a bug in the strtotime function. Whenever I have to work around this, I always find myself doing math on the month/year values. Try something like this:
$LastMonth = (date('n') - 1) % 12;
$Year = date('Y') - !$LastMonth;
date("m-Y", strtotime("-1 months"));
would solve this
Perhaps slightly more long winded than you want, but i've used more code than maybe nescessary in order for it to be more readable.
That said, it comes out with the same result as you are getting - what is it you want/expect it to come out with?
//Today is whenever I want it to be.
$today = mktime(0,0,0,3,31,2011);
$hour = date("H",$today);
$minute = date("i",$today);
$second = date("s",$today);
$month = date("m",$today);
$day = date("d",$today);
$year = date("Y",$today);
echo "Today: ".date('Y-m-d', $today)."<br/>";
echo "Recalulated: ".date("Y-m-d",mktime($hour,$minute,$second,$month-1,$day,$year));
If you just want the month and year, then just set the day to be '01' rather than taking 'todays' day:
$day = 1;
That should give you what you need. You can just set the hour, minute and second to zero as well as you aren't interested in using those.
date("Y-m",mktime(0,0,0,$month-1,1,$year);
Cuts it down quite a bit ;-)
This is because the previous month has less days than the current month. I've fixed this by first checking if the previous month has less days that the current and changing the calculation based on it.
If it has less days get the last day of -1 month else get the current day -1 month:
if (date('d') > date('d', strtotime('last day of -1 month')))
{
$first_end = date('Y-m-d', strtotime('last day of -1 month'));
}
else
{
$first_end = date('Y-m-d', strtotime('-1 month'));
}
If a DateTime solution is acceptable this snippet returns the year of last month and month of last month avoiding the possible trap when you run this in January.
function fn_LastMonthYearNumber()
{
$now = new DateTime();
$lastMonth = $now->sub(new DateInterval('P1M'));
$lm= $lastMonth->format('m');
$ly= $lastMonth->format('Y');
return array($lm,$ly);
}
//return timestamp, use to format month, year as per requirement
function getMonthYear($beforeMonth = '') {
if($beforeMonth !="" && $beforeMonth >= 1) {
$date = date('Y')."-".date('m')."-15";
$timestamp_before = strtotime( $date . ' -'.$beforeMonth.' month' );
return $timestamp_before;
} else {
$time= time();
return $time;
}
}
//call function
$month_year = date("Y-m",getMonthYear(1));// last month before current month
$month_year = date("Y-m",getMonthYear(2)); // second last month before current month
function getOnemonthBefore($date){
$day = intval(date("t", strtotime("$date")));//get the last day of the month
$month_date = date("y-m-d",strtotime("$date -$day days"));//get the day 1 month before
return $month_date;
}
The resulting date is dependent to the number of days the input month is consist of. If input month is february (28 days), 28 days before february 5 is january 8. If input is may 17, 31 days before is april 16. Likewise, if input is may 31, resulting date will be april 30.
NOTE: the input takes complete date ('y-m-d') and outputs ('y-m-d') you can modify this code to suit your needs.
I have week number of current year and week day generated by date() like this.
$week_number = date('W');
$week_day = date('w');
I need to format this. How can I get starting date of this week? Or day of month with $week_number and $week_day?
Update:
Maybe this article helps you. It describes how to get the start and end date of a given week.
<?php
// Monday
echo date(
datetime::ISO8601,
strtotime("2006W37"));
// Sunday
echo date(
datetime::ISO8601,
strtotime("2006W377"));
?>
Where the format is <year>W<week-number><daynumber> and Monday is 1.
Update 2:
Maybe another possibility is to use strtotime() this way:
echo strtotime("last Monday");
echo strtotime("next Sunday");
You can combine this with date() to get the date in the desired format.
You can get the day of the month with date('d') directly.
date() documentation.