How do I display only match keyword in array - php

Question

This is my array output
Array
(
[0] => Array
(
[tweet_text] => Fedora 16 "Verne" released! http://t.co/lECbdzE0 #Fedora #Linux
)
[1] => Array
(
[tweet_text] => Ubuntu 11.10 "Oneiric Ocelot" released! #Ubuntu #Linux
)
)
Example to find Ubuntu keyword. From the current array how do I filter to show only
Array ( [1] => Array (
[tweet_text] => Ubuntu 11.10 "Oneiric Ocelot" released! #Ubuntu #Linux
)
)
The code
$keywords = array('Ubuntu');
foreach ($keywords as &$keyword) {
$keyword = preg_quote($keyword);
}
$regex = "/(" . implode('|', $keywords) . ")/";
$check = preg_match($regex, $anArray);
if($check == 1) {
// here I want to display only Ubuntu
}
Let me know

Answer 1

preg_grep — Return array entries that match the pattern
example:-
$arr = array('k'=>'ubuntu', 'j'=>'ubuntu1', 'n'=>'fedorra');
$matches = preg_grep('/ubuntu/i', $arr);
if you original source is an multi-dimensional array,
you can try :-
$cmp = array();
foreach ($src as $key=>$arr)
{
$cmp[$key] = $arr['tweet_text'];
}
$matches = preg_grep('/ubuntu/i', $cmp);
// $matches will be an associate array contains the matches
// and $matches and $src are using same index key

Answer 2

There are a few approaches here, basically you could look at your current function: preg_match. By the way i don't think you can put a array into the subject parameter if it requires a string. For now i will guess you are putting a string there with the wrong name.
You could use it also to save the matches found like so:
$check = preg_match($regex, $string, $matches);
print_r($matches);
If it is an array you should approach it like a single result and loop trough it (there are betters ways, but this is an approach you are using and i try to teach you this better.
// Your code ....
foreach($anArray as $rule) {
$check = preg_match($regex, $anArray, $matches);
if($check == 1) {
echo print_r($matches);
}
}