insert statement post page to itself issue - php

Question

I am trying to submit the page to itself but some reason the following code is not working. Also How can I get the table1 primary key ID back after inserting the data successfully? I have a child table which needs this ID. Thanks for any suggestions.
<?php
include('db_login.php');
$connection = mysql_connect( $db_host, $db_username, $db_password );
if (!$connection){
die ("Could not connect to the database: <br />". mysql_error());
}
// Select the database
$db_select=mysql_select_db($db_database);
if (!$db_select){
die ("Could not select the database: <br />". mysql_error());
if ($_POST['Submit'])
{
$first = $_POST["first"];
$first = mysql_real_escape_string(get_magic_quotes_gpc() ? stripslashes($first): $first);
$last = $_POST["last"];
$last = mysql_real_escape_string(get_magic_quotes_gpc() ? stripslashes($last): $last);
$insertsql = "INSERT INTO table1(FirstName,LastName) VALUES ('".$first."', '" .$last. "')";
$result1 = mysql_query($insertsql) or die(mysql_error());
}
?>
<form name="hotlineForm" action="<?php echo htmlentities($_SERVER['PHP_SELF']); ?>"
method="post">
<input id="first" type="text">
<input id="last" type="text">
<input type="submit" value="Submit"></form></body>

Answer 1

What part isn't working on the post back? Are you not entering your if statement?
To get the ID of the last insert use the following after your $result1 = mysql_query(...):
$primary_id = mysql_insert_id()
http://php.net/manual/en/function.mysql-insert-id.php

Answer 2

Change your form inputs to include name attributes. Without them, your $_POST will be empty.
<input name='first' id="first" type="text">
<input name='last' id="last" type="text">
<input name='Submit' type="submit" value="Submit">
As mentioned in the comments, get_magic_quotes should not be used. You've correctly called mysql_real_escape_string() on your inputs already.
Following your insert, get the id from mysql_insert_id():
$result1 = mysql_query($insertsql) or die(mysql_error());
$new_id = myqsl_insert_id();

Answer 3

if ($_POST['Submit'])
I don't see a form element with this name.
try:
if (isset($_POST['first']) && isset($_POST['last']))
For getting inserted ID you can use:
mysql_insert_id();

Answer 4

You are missing a closing } here:
if (!$db_select){
die ("Could not select the database: <br />". mysql_error());
} <<---- Close your if statement here.
if ($_POST['Submit'])
Currently the code that does the actual work only gets called if the DB cannot be selected.
Not very useful.
This is why proper indentation is important.
If you are religious about your indentation, you will spot these kind of errors instantly.

Answer 5

Use a name for the input field and check if it was sents not the submit