I have the following route:
Router::connect('/admin/login/:to',
array('admin'=>true,'controller'=>'users','action'=>'login'),
array(
'to' => '[A-Za-z0-9\._-]+',
'pass' => array('to')
));
Which basically passes a string/int with the login url. But it no longer uses the named parameter of to. So for example instead of getting: /admin/login/to:1AB I get /admin/login/1AB
How do I keep the named parameter but still alter the routing to remove the users bit from the url? I've tried: '/admin/login/to::to' but that seems rather sloppy...
you could find passed parameter's name in "$this->data" in your controller.
in your example: $this->data->to has the same value you put in your url.
Remove that route. Why do you have that route when you want the named parameter?
Edit: if so:
Router::connect(
'/admin/login/*',
array(
'admin' => true,
'controller' => 'users',
'action' => 'login'
)
);
Related
I am making small project in cakePHP v3.5, i am not able to use parametrized in appropriate way. Also in some cases if we want to pass optional parameter in url then how can i do?
CakePHP v3.5
$routes->get('test/testfn/:param1/:param2', ['controller' => 'Pages', 'action' => 'testfn']);
where
test: Controller,
testfn: Method of TestController,
param1: Parameter 1,
param2: Parameter 2
All i did to get params from url to TestController,
$this->request->getParam(param1)
$this->request->getParam(param2)
How can i list all parameters that i passed from routes to My Controller instead of single param step by step.
OR anyone have better options to do routing in cakePHP v3.5
Also I am confused about the paramterized routing principle of cakePHP3.4
so, in that case if anyone has some solution to cakePHP v3.4.
Please Help me.
Thanks
In config/routes.php
$routes->get(
'/api/test/*', ['controller' => 'Api', 'action' => 'check']
);
In controller
public function check($first=null, $sec=null) {
pr($params);
pr($sec);
die;
}
In Routes.php
$routes->connect('/users/:id/edit/:type', ['controller' => 'Users', 'action' => 'edit', ['id' => '\d+', 'pass' => ['id', 'type'], '_name' => 'edit-client']);
In this route in ID is user id and Type is user type two parameter pass in this route
if this route method is POST then ex - $this->request->getData('id'); and if this route method GET then ex - $this->request->getParam('id')
I obviously have a fundamental misunderstanding of how pagination works in CakePHP.
I have the following route set up which shows all posts in a category:
Router::connect('/:parent/:category',
array('controller' => 'posts', 'action' => 'viewCategory'),
array('parent' => '[a-z0-9-]+', 'category' => '[a-z0-9-]+'));
The pages work fine, however the pagination helper is outputting the wrong links for pagination.
I'm using $this->Paginator->numbers().
It's outputting links in this format: mysite.com/posts/viewCategory?page=2
rather than like this: mysite.com/parent-category/sub-category?page=2.
I've tried adding the following route after the first one and it still doesn't work:
Router::connect('/:parent/:category/:page',
array('controller' => 'posts', 'action' => 'viewCategory'),
array('parent' => '[a-z0-9-]+',
'category' => '[a-z0-9-]+',
'page' => '[0-9]+'));
For reference, my pagination options set in my view are as so:
<?php $this->Paginator->options(
array('url' =>
array('controller' => 'posts', 'action' => 'viewCategory')
)); ?>
What am I doing wrong here?
You are setting the url yourself
This is your paginator options call:
<?php
$this->Paginator->options(array(
'url' => array(
'controller' => 'posts',
'action' => 'viewCategory'
)
));
?>
Where you are overriding the current url - and explicitly requesting that the paginator uses the the '/posts/viewCategory' url (with no arguments) as it's base url.
Just don't define the url
Simply don't call options and the helper will use the current url - that should mean that if the current url is:
/parent-category/sub-category
Then page 2 will be (assuming you are using the paramType option to use GET arguments rather than named parameters):
/parent-category/sub-category?page=2
If that's not the case there's information missing from the question; it's important to distinguish between "vanity routes not being used" and "the url is not equivalent (the current situation).
Just had a battle fixing something similar and came across this post. Though old, but I think my answer might save someone the time I had to spend fixing it.
Basically, what you need to do is call the Paginator->options() before Paginator->numbers(), thus:
$this->Paginator->options(
array(
'controller' => 'parent-category',
'action' => 'sub-category'
)
);
Though the controller and action do not exist, it just tricks CakePHP to use them "AS IS", since the reverse routing isn't working!
And for those (like me), who want have set up a route similar to
Router::connect(
'/go/page:id',
array(
'controller' => 'blog',
'action' => 'paginated'
)
);
There might be difficulty setting up the Paginator options. This, however, worked for me:
$this->Paginator->options(
array(
'controller' => 'go',
'action' => '/'
)
);
I guess you know why it worked ;)
I'm using Zend Framework 1.12 and have this route:
$router->addRoute('item_start',
new Zend_Controller_Router_Route_Regex(
'(foo|bar|baz)',
array(
'module' => 'default',
'controller' => 'item',
'action' => 'start'
),
array(
1 => 'area'
),
'%s'
)
);
Problem is, when I call '/foo' and use the Url Helper in the View, it doesn't give me any parameters:
$this->url(array("page"=>1));
// returns '/foo' (expected '/foo/page/1')
$this->url(array("page"=>1), "item_start", true);
// also returns '/foo'
Any idea how to get the page-parameter into the URL? I can't use the wildcard like in the standard route, can't I?
In addition to David's suggestions, you could change this route to use the standard route class, and then keep the wildcard option:
$router->addRoute('item_start',
new Zend_Controller_Router_Route(
':area/*',
array(
'module' => 'default',
'controller' => 'item',
'action' => 'start'
),
array(
'area' => '(foo|bar|baz)'
)
)
);
// in your view:
echo $this->url(array('area' => 'foo', 'page' => 1), 'item_start');
Your Regex route doesn't have a page parameter, so when the url view-helper ends up calling Route::assemble() with the parameters you feed it, it ignores your page value.
The two choices that come to mind are:
Modify your regex to include a (probably optional with default value) page parameter
Manage the page parameter outside of your route in the query string.
Having a bit of trouble getting my URLs to work properly.
The URL looks like this: /messages/from/1/page/5
My route looks like this
$router->addRoute('messages-from',
new Zend_Controller_Router_Route('messages/from/:user_id/:page', array(
'controller' => 'messages',
'action' => 'from',
'page' => 1
))
);
Which works fine. But the URL is missing the /page/ part. If I add it in:
'messages/from/:user_id/page/:page'
then it breaks and the user_id param is always null.
How can I fix this?
Thanks!
Since you want to be able to leave off the /page/ part from the URL, you would have to define two separate routes, one that matches the user ID and page parameters and one that only matches the user ID without the page so the router can find route matches in both cases.
Alternatively, this regex based route works in both cases.
$route = new Zend_Controller_Router_Route_Regex(
'messages/from/(\d+)(?:/page/(\d+)/?)?',
array(
'controller' => 'messages',
'action' => 'from',
'page' => 1,
),
array(
1 => 'from',
2 => 'page',
)
);
$router->addRoute('messages-from', $route);
Based on the URL you supplied, I assumed in the regex that the from parameter is an integer. If you can have strings passed, you will need to change the (\d+) pattern to something more suitable like ([\w\d_-\.]+).
I have one route that looks like this:
Router::connect('/Album/:slug/:id',array('controller' => 'albums', 'action' => 'photo'),array('pass' => array('slug','id'),'id' => '[0-9]+'));
and another like this:
Router::connect('/Album/:slug/*',array('controller' => 'albums','action' => 'contents'),array('pass' => array('slug')));
for what doesn't match the first. In the 'contents' action of the 'albums' controller, I take care of pagination myself - meaning I retrieve the named parameter 'page'.
A URL for the second route would look like this:
http://somesite.com/Album/foo-bar/page:2
The Above URL indeed works, but when I try to use the HTML Helper (url,link) to output a url like this, it appends the controller and action to the beginning, like this:
http://somesite.com/albums/contents/Album/foo-bar/page:2
Which i don't like.
The code that uses the HtmlHelper is as such:
$html->url(array('/Album/' . $album['Album']['slug'] . '/page:' . $next))
See below url it is very help full to you
http://book.cakephp.org/2.0/en/development/routing.html
Or read it
Passing parameters to action
When connecting routes using Route elements you may want to have routed elements be passed arguments instead. By using the 3rd argument of Router::connect() you can define which route elements should also be made available as passed arguments:
<?php
// SomeController.php
public function view($articleId = null, $slug = null) {
// some code here...
}
// routes.php
Router::connect(
'/blog/:id-:slug', // E.g. /blog/3-CakePHP_Rocks
array('controller' => 'blog', 'action' => 'view'),
array(
// order matters since this will simply map ":id" to $articleId in your action
'pass' => array('id', 'slug'),
'id' => '[0-9]+'
)
);
And now, thanks to the reverse routing capabilities, you can pass in the url array like below and Cake will know how to form the URL as defined in the routes:
// view.ctp
// this will return a link to /blog/3-CakePHP_Rocks
<?php
echo $this->Html->link('CakePHP Rocks', array(
'controller' => 'blog',
'action' => 'view',
'id' => 3,
'slug' => 'CakePHP_Rocks'
));