How to count the unchecked checkboxes in a while loop - php

Question

$query = mysql_query("SELECT DISTINCT status, vendor FROM tbl_softwareinstalled WHERE vendor NOT LIKE ''");
$nums = mysql_num_rows($query);
echo "<form name = 'filter' action='softwarefilter.php' method='POST'>
$nums<br>
<table border = 1><tr><td> </td>
<td><strong>Software Vendor</strong></td></tr>";
$ctr1 = 1;
while($fetch = mysql_fetch_array($query)) {
$vendor = $fetch['vendor'];
$status = $fetch['status'];
if(($ctr1 % 2)==1)
{ print "<tr bgcolor = 'white'>";}
else
{ print "<tr bgcolor = '#EEEEEE'>"; }
print "<td><input name= 'chk[]' type='hidden' value='0'>
<input type = 'checkbox' name = 'chk[]' value = '$vendor' ";
if ($status == 'Enabled') {
print "checked = 'checked'></td><td>$vendor</td></tr>"; }
else {
print "></td><td>$vendor</td></tr>"; }
$ctr1++;
}
print "</table>";
print "<input type = 'submit' name = 'submit' value = 'Update Filter'>
</form> ";
$submit = $_POST['submit'];
if(isset($submit))
{
$chk = $_POST['chk'];
$count = count($chk);
if (empty($chk)) {
echo "qweqwe<br>";
}
for ($i=0; $i<$count; $i++) {
$abc = $chk[$i];
$query = mysql_query("UPDATE tbl_softwareinstalled SET status = 'Enabled' WHERE vendor = '$abc'");
}
echo '<meta http-equiv="refresh" content="0.5;url=/assets/softwarefilter.php">
<script language="javascript">
alert("Software filter updated.");
</script>';
}
Hi, how can I count the UNCHECKED CHECKBOXES in a while loop with this block of code?
Let's say for example I have 10 checkboxes with 10 values, the user checked 3 checkboxes (with values: 'abc', 'def', 'ghi'), after submitting it. It will count all the UNCHECKED checkboxes and echoes the value of it. The values of 3 checked checkboxes SHOULD NOT be echoed.

Answer 1

The browser will only tell you which have been checked. Pull all the possible boxes from your database, and then remove those that the browser has told you are checked.

Answer 2

I had worked on a similar thing for counting unchecked boxes.
place two input fields of input type checkbox and input type hidden with different names
<input type="hidden" class="" name="test[]" value="0">
<input type="checkbox" class="" name="checkbox[]" value="1">
then on submit
if (isset($_POST['submit'])) {
$cnt = array();
$counter =0;
$testcnt = 0;
$cnt = 0;
if (isset($_POST['test'])) {
$testcnt = count($_POST['test']);
}
if (isset($_POST['checkbox'])) {
$cnt = count($_POST['checkbox']);
}
echo 'the count of unchecked boxes is ';
print_r($testcnt-$cnt);
}
For your case change this to:
<input name= 'unchecked[]' type='hidden' value='0'>
then on submit when your checking for isset(submit) you can add the following an d change accordingly
$unchecked_input = count($_POST['unchecked']);
$chk = $_POST['chk'];
$count = count($chk);
echo $unchecked_input-$count; //will output the count of unchecked boxes