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How do I get the complete line from a position gotten by strpos()?
Here is my code:
//$route_route sample: NAXOP UZ45 VIKIK
$route_waypoint = explode(" ", $route_route);
$file = "components/airways.txt";
$contents = file_get_contents($file);
foreach ($route_waypoint as $waypoint) {
//$waypoint sample: NAXOP
$pos = strpos($contents, $waypoint);
if ($pos === false) {
continue;
} else {
$line = fgets($contents, $pos); // Here is my problem
//line sample: MES,W714,005,NAXOP,38.804139,30.546833,149,000, ,L
list($fix, $lat, $lon, $sample_data1, $sample_data2) = explode(',', $line);
echo "$fix, $lat, $lon";
}
}
The main objective is localize "NAXOP", read his complete line, and echo some data. Any kind of help is welcome!
DISCLAIMER: if VIKIK comes before NAXOP in $contents. VIKIK Will not be found, if there are multiple occurrences of NAXOP || UZ45 || VIKIK only the first of each occurrence will be found.
$len = strlen($contents);
$pos = 0;
foreach ($route_waypoint as $waypoint) {
$pos = strpos($contents, $waypoint, $pos);
if ($pos === false) {
continue;
}
else {
// Here is the critical section for matching the entire line:
// First look backwards from where $waypoint was found for the
// beginning of the line
$startOfLine = strrpos($contents, "\n", ($pos - $len));
// Next look forwards from $waypoint to find the end of the line
$endOfLine = strpos($contents, "\n", $pos);
// we already have the file in memory, just read from that,
$line = substr($contents, $startOfLine, ($endOfLine - $startOfLine));
list($fix, $lat, $lon, $sample_data1, $sample_data2)
= explode(',', trim($line));
echo "$fix, $lat, $lon";
// IDK if you want to match the same line twice or not.
$pos = $endOfLine;
}
}
Here is a better program.
<?php
$str = "NAXOP UZ45 VIKIK";
$regex = "/" . preg_replace("/ /", "|", $str) . "/";
$fp = fopen("test.dat", "r");
while ($line = fgets($fp)) {
if (preg_match($regex, $line)) {
echo $line;
}
}
fclose($fp);
Here is test.dat
NAXOP
UZ45
VIKIK
UZ45 VIKIK
NAXOP
SILLYSTRING
Here is the output
NAXOP
UZ45
VIKIK
UZ45 VIKIK
NAXOP
I've used this library in soo many programs.. check it out I think it'll solve exactly the problem you are having. It works exactly like it says..
e.g
between ('#', '.', 'biohazard#online.ge');
//returns 'online'
//from the first occurrence of '#'
src: http://php.net/manual/en/function.substr.php
<?php
function after ($this, $inthat)
{
if (!is_bool(strpos($inthat, $this)))
return substr($inthat, strpos($inthat,$this)+strlen($this));
};
function after_last ($this, $inthat)
{
if (!is_bool(strrevpos($inthat, $this)))
return substr($inthat, strrevpos($inthat, $this)+strlen($this));
};
function before ($this, $inthat)
{
return substr($inthat, 0, strpos($inthat, $this));
};
function before_last ($this, $inthat)
{
return substr($inthat, 0, strrevpos($inthat, $this));
};
function between ($this, $that, $inthat)
{
return before ($that, after($this, $inthat));
};
function between_last ($this, $that, $inthat)
{
return after_last($this, before_last($that, $inthat));
};
// use strrevpos function in case your php version does not include it
function strrevpos($instr, $needle)
{
$rev_pos = strpos (strrev($instr), strrev($needle));
if ($rev_pos===false) return false;
else return strlen($instr) - $rev_pos - strlen($needle);
};
?>
How can I check if a sentence contains a word. I used names sentence and word instead of string and substring expressly. For example:
for sentence
$s = "Ala makota, a kot ma przesrane";
calling function
checkIfContains("kota",$s)
returns false.
But for
checkIfContains("makota",$s)
returns true.
If you're looking to match only full words, you'll need a regular expression to accomplish this. Try the following:
<?php
function checkIfContains( $needle, $haystack ) {
return preg_match( '#\b' . preg_quote( $needle, '#' ) . '\b#i', $haystack ) !== 0;
}
You need strpos.
if (strpos($s, 'kota') !== false) {
}
Or if you insist..
function checkIfContains($needle, $haystack) {
return (strpos($haystack, $needle) !== false);
}
For full words you could consider regex:
if (preg_match('/\bkota\b/i', $s)) { }
I'd use explode to separate the string into an array based on a character (" " in this case).
function checkIfContains($toTest, $toCheck)
{
// Check if length of either string is zero for validation purposes
if(strlen($toTest) == 0 || strlen($toCheck) == 0)
{
return false;
}
$exploded = explode(" ", $toCheck);
foreach($exploded as $word)
{
if($word == $toTest)
{
// Found a match, return true!
return true;
}
}
// None matched, return false
return false;
}
You can try :
function checkIfContains($needle, $haystack) {
// Remove punctuation marks
$haystack = preg_replace('/[^a-zA-Z 0-9]+/', '', $haystack);
// Explode sentence with space
$haystack = explode(' ', $haystack);
// Check if $needle exist
return in_array($needle, $haystack);
}
$string = "Ala makota, a kot ma przesrane";
checkIfInString("makota", $string);
function checkIfInString($needle, $haystack) {
$delimiters = ' ,.';
return in_array($needle, explode($haystack, $delimiters);
}
you can try like :
if(strpos($s,"kota") !== false){
echo true;
}
or :
function checkIfContains($string, $letter){
return strpos($string, $letter) !== false;
}
How do you use the strpos for an array of needles when searching a string? For example:
$find_letters = array('a', 'c', 'd');
$string = 'abcdefg';
if(strpos($string, $find_letters) !== false)
{
echo 'All the letters are found in the string!';
}
Because when using this, it wouldn't work, it would be good if there was something like this
#Dave an updated snippet from http://www.php.net/manual/en/function.strpos.php#107351
function strposa($haystack, $needles=array(), $offset=0) {
$chr = array();
foreach($needles as $needle) {
$res = strpos($haystack, $needle, $offset);
if ($res !== false) $chr[$needle] = $res;
}
if(empty($chr)) return false;
return min($chr);
}
How to use:
$string = 'Whis string contains word "cheese" and "tea".';
$array = array('burger', 'melon', 'cheese', 'milk');
if (strposa($string, $array, 1)) {
echo 'true';
} else {
echo 'false';
}
will return true, because of array "cheese".
Update: Improved code with stop when the first of the needles is found:
function strposa(string $haystack, array $needles, int $offset = 0): bool
{
foreach($needles as $needle) {
if(strpos($haystack, $needle, $offset) !== false) {
return true; // stop on first true result
}
}
return false;
}
$string = 'This string contains word "cheese" and "tea".';
$array = ['burger', 'melon', 'cheese', 'milk'];
var_dump(strposa($string, $array)); // will return true, since "cheese" has been found
str_replace is considerably faster.
$find_letters = array('a', 'c', 'd');
$string = 'abcdefg';
$match = (str_replace($find_letters, '', $string) != $string);
The below code not only shows how to do it, but also puts it in an easy to use function moving forward. It was written by "jesda". (I found it online)
PHP Code:
<?php
/* strpos that takes an array of values to match against a string
* note the stupid argument order (to match strpos)
*/
function strpos_arr($haystack, $needle) {
if(!is_array($needle)) $needle = array($needle);
foreach($needle as $what) {
if(($pos = strpos($haystack, $what))!==false) return $pos;
}
return false;
}
?>
Usage:
$needle = array('something','nothing');
$haystack = "This is something";
echo strpos_arr($haystack, $needle); // Will echo True
$haystack = "This isn't anything";
echo strpos_arr($haystack, $needle); // Will echo False
The question, is the provided example just an "example" or exact what you looking for? There are many mixed answers here, and I dont understand the complexibility of the accepted one.
To find out if ANY content of the array of needles exists in the string, and quickly return true or false:
$string = 'abcdefg';
if(str_replace(array('a', 'c', 'd'), '', $string) != $string){
echo 'at least one of the needles where found';
};
If, so, please give #Leon credit for that.
To find out if ALL values of the array of needles exists in the string, as in this case, all three 'a', 'b' and 'c' MUST be present, like you mention as your "for example"
echo 'All the letters are found in the string!';
Many answers here is out of that context, but I doubt that the intension of the question as you marked as resolved. E.g. The accepted answer is a needle of
$array = array('burger', 'melon', 'cheese', 'milk');
What if all those words MUST be found in the string?
Then you try out some "not accepted answers" on this page.
You can iterate through the array and set a "flag" value if strpos returns false.
$flag = false;
foreach ($find_letters as $letter)
{
if (strpos($string, $letter) !== false)
{
$flag = true;
}
}
Then check the value of $flag.
If you just want to check if certain characters are actually in the string or not, use strtok:
$string = 'abcdefg';
if (strtok($string, 'acd') === $string) {
// not found
} else {
// found
}
This expression searches for all letters:
count(array_filter(
array_map("strpos", array_fill(0, count($letters), $str), $letters),
"is_int")) == count($letters)
You can try this:
function in_array_strpos($word, $array){
foreach($array as $a){
if (strpos($word,$a) !== false) {
return true;
}
}
return false;
}
You can also try using strpbrk() for the negation (none of the letters have been found):
$find_letters = array('a', 'c', 'd');
$string = 'abcdefg';
if(strpbrk($string, implode($find_letters)) === false)
{
echo 'None of these letters are found in the string!';
}
This is my approach. Iterate over characters in the string until a match is found. On a larger array of needles this will outperform the accepted answer because it doesn't need to check every needle to determine that a match has been found.
function strpos_array($haystack, $needles = [], $offset = 0) {
for ($i = $offset, $len = strlen($haystack); $i < $len; $i++){
if (in_array($haystack[$i],$needles)) {
return $i;
}
}
return false;
}
I benchmarked this against the accepted answer and with an array of more than 7 $needles this was dramatically faster.
If i just want to find out if any of the needles exist in the haystack, i use
reusable function
function strposar($arrayOfNeedles, $haystack){
if (count(array_filter($arrayOfNeedles, function($needle) use($haystack){
return strpos($haystack, $needle) !== false;
})) > 0){
return true;
} else {
return false;
}
}
strposar($arrayOfNeedles, $haystack); //returns true/false
or lambda function
if (count(array_filter($arrayOfNeedles, function($needle) use($haystack){
return strpos($haystack, $needle) !== false;
})) > 0){
//found so do this
} else {
//not found do this instead
}
With the following code:
$flag = true;
foreach($find_letters as $letter)
if(false===strpos($string, $letter)) {
$flag = false;
break;
}
Then check the value of $flag. If it is true, all letters have been found. If not, it's false.
I'm writing a new answer which hopefully helps anyone looking for similar to what I am.
This works in the case of "I have multiple needles and I'm trying to use them to find a singled-out string". and this is the question I came across to find that.
$i = 0;
$found = array();
while ($i < count($needle)) {
$x = 0;
while ($x < count($haystack)) {
if (strpos($haystack[$x], $needle[$i]) !== false) {
array_push($found, $haystack[$x]);
}
$x++;
}
$i++;
}
$found = array_count_values($found);
The array $found will contain a list of all the matching needles, the item of the array with the highest count value will be the string(s) you're looking for, you can get this with:
print_r(array_search(max($found), $found));
Reply to #binyamin and #Timo.. (not enough points to add a comment..) but the result doesn't contain the position..
The code below will return the actual position of the first element which is what strpos is intended to do. This is useful if you're expecting to find exactly 1 match.. If you're expecting to find multiple matches, then position of first found may be meaningless.
function strposa($haystack, $needle, $offset=0) {
if(!is_array($needle)) $needle = array($needle);
foreach($needle as $query) {
$res=strpos($haystack, $query, $offset);
if($res !== false) return $res; // stop on first true result
}
return false;
}
Just an upgrade from above answers
function strsearch($findme, $source){
if(is_array($findme)){
if(str_replace($findme, '', $source) != $source){
return true;
}
}else{
if(strpos($source,$findme)){
return true;
}
}
return false;
}
<?php
$Words = array("hello","there","world");
$c = 0;
$message = 'Hi hello';
foreach ($Words as $word):
$trial = stripos($message,$word);
if($trial != true){
$c++;
echo 'Word '.$c.' didnt match <br> <br>';
}else{
$c++;
echo 'Word '.$c.' matched <br> <br>';
}
endforeach;
?>
I used this kind of code to check for hello, It also Has a numbering feature.
You can use this if you want to do content moderation practices in websites that need the user to type
The script below pulls a summary of the content in $description and if a period is found in the first 50 characters, it returns the first 50 characters and the period. However, the flaw is, when no period exists in the content, it just returns the first character.
function get_cat_desc($description){
$the_description = strip_tags($description);
if(strlen($the_description) > 50 )
return SUBSTR( $the_description,0,STRPOS( $the_description,".",50)+1);
else return $the_description;}
I'd like to make it so that if no period is found, it returns up until the first empty space after 50 characters (so it doesn't cut a word off) and appends "..."
Your best bet is to use regular expression. This will match your $description up to $maxLength (2nd argument in function) but will continue until it finds the next space.
function get_cat_desc($description, $max_length = 50) {
$the_description = strip_tags($description);
if(strlen($the_description) > $max_length && preg_match('#^\s*(.{'. $max_length .',}?)[,.\s]+.*$#s', $the_description, $matches)) {
return $matches[1] .'...';
} else {
return $the_description;
}
}
I think it just needs to be a little more complicated:
function get_cat_desc($description){
$the_description = strip_tags($description);
if(strlen($the_description) > 50 ) {
if (STRPOS( $the_description,".",50) !== false) {
return SUBSTR( $the_description,0,STRPOS( $the_description,".",50)+1);
} else {
return SUBSTR( $the_description,0,50) . '...';
}
} else {
return $the_description;
}
}
Try something like this:
$pos_period = strpos($the_description, '.');
if ($pos_period !== false && $pos_period <= 50) {
return substr($the_description, 0, 50);
} else {
$next_space = strpos($the_description, ' ', 50);
if ($next_space !== false) {
return substr($the_description, 0, $next_space) . '...';
} else {
return substr($the_description, 0, 50) . '...';
}
}
use substr_count to find it and then do substr(,0,50)
I have to test if a string begins with 00 or with +.
pseudocode:
Say I have the string **0090** or **+41**
if the string begins with **0090** return true,
elseif string begins with **+90** replace the **+** with **00**
else return false
The last two digits can be from 0-9.
How do I do that in php?
You can try:
function check(&$input) { // takes the input by reference.
if(preg_match('#^00\d{2}#',$input)) { // input begins with "00"
return true;
} elseif(preg_match('#^\+\d{2}#',$input)) { // input begins with "+"
$input = preg_replace('#^\+#','00',$input); // replace + with 00.
return true;
}else {
return false;
}
}
if (substr($str, 0, 2) === '00')
{
return true;
}
elseif ($str[0] === '+')
{
$str = '00'.substr($str, 1);
return true;
}
else
{
return false;
}
The middle condition won't do anything though, unless $str is a reference.
if (substr($theString, 0, 4) === '0090') {
return true;
} else if (substr($theString, 0, 3) === '+90') {
$theString = '00' . substr($theString, 1);
return true;
} else
return false;