Reading REST API Response in PHP - php

I am trying to read Raven SEO Tools API. It is a REST API and currently it is serving the data backup as an XML (or JSON if I choose) when I just request the URL through a web browser. What is the best method to get the response from their server into my own PHP script for me to then play around with.
Any help much appreciated
Cheers

If you only needs to retrieve a URL and parse its info. The easiest way is curl/JSON combination. Note that parsing JSON is faster than parsing XML.
http://www.php.net/manual/en/function.curl-exec.php
http://www.php.net/manual/en/function.json-decode.php
Something simple as:
$url = "http://api.raventools.com/api?key=B1DFC59CA6EC76FF&method=domains&format=json";
$ch = curl_init();
curl_setopt($ch,CURLOPT_URL,$url);
curl_setopt($ch,CURLOPT_RETURNTRANSFER,1);
curl_setopt($ch,CURLOPT_CONNECTTIMEOUT, 4);
$json = curl_exec($ch);
if(!$json) {
echo curl_error($ch);
}
curl_close($ch);
print_r(json_decode($json));
But if you need to call other methods from this API such as DELETE/PUT, etc. Then to have a REST client in PHP is more elegant solution. A comparison on those clients can be found in PHP REST Clients
I founded this code specifically for Raven API https://github.com/stephenyeargin/raventools-api-php
Sample code:
require 'path/to/raventools-api-php/raventools-api-php.class.php';
$Raven = new RavenTools( 'B1DFC59CA6EC76FF' );
$method = 'domains';
$options = array('format'=> 'json');
$responseString = $Raven->getJSON($method, $options);
print_r(json_decode($responseString));

cUrl
cUrl is a command line tool for getting or sending files using URL syntax.
curl -o example.html www.example.com
file_get_contents
<?php
$homepage = file_get_contents('http://www.example.com/api/parameters');
echo $homepage;
?>

Pecl's HTTPRequest class is a very nice client, I've been using it for a couple of Projects. http://pecl.php.net/package/pecl_http
Another pretty cool client is the Buzz client https://github.com/kriswallsmith/Buzz
It also plays nice with Symfony2 if that's of interest to you :)

You can use either one of them, but I think JSON is the easiest and more hassle-free, unless you use SimpleXML. The decision depends on the complexity of your data.
Given that the JSON returned by the API is valid you can convert it to an array or object by using PHP's json_decode() function.
<?php
# retrieve JSON from API here...
# i.e. it is stored in $data as a string
$object = json_decode($data);
$array = json_decode($data, true);
?>
In SimpleXML, it would be as follows:
<?php
$object = simplexml_load_string($data);
?>

Related

HOW TO USE API's in PHP LARAVEL [duplicate]

I'm planning to use PHP for a simple requirement. I need to download a XML content from a URL, for which I need to send HTTP GET request to that URL.
How do I do it in PHP?
Unless you need more than just the contents of the file, you could use file_get_contents.
$xml = file_get_contents("http://www.example.com/file.xml");
For anything more complex, I'd use cURL.
For more advanced GET/POST requests, you can install the CURL library (http://us3.php.net/curl):
$ch = curl_init("REMOTE XML FILE URL GOES HERE"); // such as http://example.com/example.xml
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
curl_setopt($ch, CURLOPT_HEADER, 0);
$data = curl_exec($ch);
curl_close($ch);
http_get should do the trick. The advantages of http_get over file_get_contents include the ability to view HTTP headers, access request details, and control the connection timeout.
$response = http_get("http://www.example.com/file.xml");
Remember that if you are using a proxy you need to do a little trick in your php code:
(PROXY WITHOUT AUTENTICATION EXAMPLE)
<?php
$aContext = array(
'http' => array(
'proxy' => 'proxy:8080',
'request_fulluri' => true,
),
);
$cxContext = stream_context_create($aContext);
$sFile = file_get_contents("http://www.google.com", False, $cxContext);
echo $sFile;
?>
Guzzle is a very well known library which makes it extremely easy to do all sorts of HTTP calls. See https://github.com/guzzle/guzzle. Install with composer require guzzlehttp/guzzle and run composer install. Now code below is enough for a http get call.
$client = new \GuzzleHttp\Client();
$response = $client->get('https://example.com/path/to/resource');
echo $response->getStatusCode();
echo $response->getBody();
Depending on whether your php setup allows fopen on URLs, you could also simply fopen the url with the get arguments in the string (such as http://example.com?variable=value )
Edit: Re-reading the question I'm not certain whether you're looking to pass variables or not - if you're not you can simply send the fopen request containg http://example.com/filename.xml - feel free to ignore the variable=value part
I like using fsockopen open for this.
On the other hand, using the REST API of servers is very popular in PHP. You can suppose all URLs are parts of a REST API and use many well-designed PHP packages.
Actually, REST API is a way to use services from a site.
So, there are many PHP packages developed to simplify REST API call. For example here is a very nice one:
https://github.com/romanpitak/PHP-REST-Client
Using such packages helps you to fetch resources easily.
So, getting the xml file (that you mentioned about) is as easy as:
$client = new Client('http://example.com');
$request = $client->newRequest('/filename.xml');
$response = $request->getResponse();
echo $response->getParsedResponse();

Any idea how to connect to this API?

I tried to find any widget to show Tinkoof's bank currency rate, because it changes every 60sec., but nothing.
Finally I found this API, but there is no any documentation for it.
I tried to find any articles about parsing, but I guess there's no use in that because of absence of any tag.
I need to show the currency rate on my website via this API. Any idea?
Big thanks!
You just need to fetch the content You can use cURL or file_get_contents()
cURL version:
<?php
$url = "https://www.tinkoff.ru/api/v1/currency_rates";
$curl = curl_init($url);
curl_setopt($curl, CURLOPT_RETURNTRANSFER, TRUE);
$r = curl_exec($curl);
curl_close($curl);
$array = json_decode($r, true);
echo "<pre>";
print_r($array);
echo "</pre>";
?>
file_get_contents version:
<?php
$r = file_get_contents('https://www.tinkoff.ru/api/v1/currency_rates');
echo "<pre>";
echo print_r(json_decode($r, true));
echo "</pre>";
?>
Both of them will work unless the remote website requires you to be human (has extra verifications to stop robot requests). cURL would be a better way if that were the case because you can fake a user agent using a header array.
Once you have the array build it's just a matter of accessing the required data. using $r as an array result of the remote json structure.
It looks pretty straightforward to me. For someone with a decent knowledge of PHP will do this, provided the output is:
Now with the above information, I would:
Get the result to PHP using file_get_contents().
Parse the result as an array using json_decode($contents, $true).
Using the above result, I would get display the value using: $output["payload"]["rates"][0]["buy"] or something similar.
At this time of writing, the above will get me 58:

Not able to read aliexpress.com via php

I'm trying to read aliexpress.com deals page via php. I'm not able to get the details of the page in output.
Is there a way I can get the details.
Below is the code.
<?php
include('simple_html_dom.php');
$url = 'http://activities.aliexpress.com/superdeals.php';
$xml = file_get_html($url);
//$file = 'output1.txt';
$element = $xml;
echo $element;
?>
This website used AJAX
There are two solutions :
- Make the same request as Javascript
- Using a tool like Phantomjs
If you look at requests, you will find easily that a GET request is made and return all information in JSON.
So you need to find by yourself the link or use third party library + tools.
EDIT:
You can use your web browser to get the link (I don't give you it because i think stackoverflow is not for that) with firebug or if you're using chrome, in network tab search for the JSON.
$url = "....";
$str = file_get_contents($url);
if($str) {
$json = json_decode($str, true); // json is an array
// ... do what you need
}
I recommend to use curl instead of file_get_contents for many reasons.
Or you can use Phantomjs (it's really more difficult) and get a "HTML snapshot" and then use DOM or XPATH to get what you need, but you must run Phantomjs and use a third party library for communicate with it.

PHP REST client API call

I'm wondering, is there an easy way to perform a REST API GET call? I've been reading about cURL, but is that a good way to do it?
I also came across php://input but I have no idea how to use it. Does anyone have an example for me?
I don't need advanced API client stuff, I just need to perform a GET call to a certain URL to get some JSON data that will be parsed by the client.
Thanks!
There are multiple ways to make REST client API call:
Use CURL
CURL is the simplest and good way to go. Here is a simple call
$ch = curl_init();
curl_setopt($ch, CURLOPT_URL, $url);
curl_setopt($ch, CURLOPT_POST, 1);
curl_setopt($ch, CURLOPT_POSTFIELDS, POST DATA);
$result = curl_exec($ch);
print_r($result);
curl_close($ch);
Use Guzzle
It's a "PHP HTTP client that makes it easy to work with HTTP/1.1 and takes the pain out of consuming web services". Working with Guzzle is much easier than working with cURL.
Here's an example from the Web site:
$client = new GuzzleHttp\Client();
$res = $client->get('https://api.github.com/user', [
'auth' => ['user', 'pass']
]);
echo $res->getStatusCode(); // 200
echo $res->getHeader('content-type'); // 'application/json; charset=utf8'
echo $res->getBody(); // {"type":"User"...'
var_export($res->json()); // Outputs the JSON decoded data
Use file_get_contents
If you have a url and your php supports it, you could just call file_get_contents:
$response = file_get_contents('http://example.com/path/to/api/call?param1=5');
if $response is JSON, use json_decode to turn it into php array:
$response = json_decode($response);
Use Symfony's RestClient
If you are using Symfony there's a great rest client bundle that even includes all of the ~100 exceptions and throws them instead of returning some meaningless error code + message.
try {
$restClient = new RestClient();
$response = $restClient->get('http://www.someUrl.com');
$statusCode = $response->getStatusCode();
$content = $response->getContent();
} catch(OperationTimedOutException $e) {
// do something
}
Use HTTPFUL
Httpful is a simple, chainable, readable PHP library intended to make speaking HTTP sane. It lets the developer focus on interacting with APIs instead of sifting through curl set_opt pages and is an ideal PHP REST client.
Httpful includes...
Readable HTTP Method Support (GET, PUT, POST, DELETE, HEAD, and OPTIONS)
Custom Headers
Automatic "Smart" Parsing
Automatic Payload Serialization
Basic Auth
Client Side Certificate Auth
Request "Templates"
Ex.
Send off a GET request. Get automatically parsed JSON response.
The library notices the JSON Content-Type in the response and automatically parses the response into a native PHP object.
$uri = "https://www.googleapis.com/freebase/v1/mqlread?query=%7B%22type%22:%22/music/artist%22%2C%22name%22:%22The%20Dead%20Weather%22%2C%22album%22:%5B%5D%7D";
$response = \Httpful\Request::get($uri)->send();
echo 'The Dead Weather has ' . count($response->body->result->album) . " albums.\n";
You can use file_get_contents if the fopen wrappers are enabled. See: http://php.net/manual/en/function.file-get-contents.php
If they are not, and you cannot fix that because your host doesn't allow it, cURL is a good method to use.
You can use:
$result = file_get_contents( $url );
http://php.net/manual/en/function.file-get-contents.php

How to send a GET request from PHP?

I'm planning to use PHP for a simple requirement. I need to download a XML content from a URL, for which I need to send HTTP GET request to that URL.
How do I do it in PHP?
Unless you need more than just the contents of the file, you could use file_get_contents.
$xml = file_get_contents("http://www.example.com/file.xml");
For anything more complex, I'd use cURL.
For more advanced GET/POST requests, you can install the CURL library (http://us3.php.net/curl):
$ch = curl_init("REMOTE XML FILE URL GOES HERE"); // such as http://example.com/example.xml
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
curl_setopt($ch, CURLOPT_HEADER, 0);
$data = curl_exec($ch);
curl_close($ch);
http_get should do the trick. The advantages of http_get over file_get_contents include the ability to view HTTP headers, access request details, and control the connection timeout.
$response = http_get("http://www.example.com/file.xml");
Remember that if you are using a proxy you need to do a little trick in your php code:
(PROXY WITHOUT AUTENTICATION EXAMPLE)
<?php
$aContext = array(
'http' => array(
'proxy' => 'proxy:8080',
'request_fulluri' => true,
),
);
$cxContext = stream_context_create($aContext);
$sFile = file_get_contents("http://www.google.com", False, $cxContext);
echo $sFile;
?>
Guzzle is a very well known library which makes it extremely easy to do all sorts of HTTP calls. See https://github.com/guzzle/guzzle. Install with composer require guzzlehttp/guzzle and run composer install. Now code below is enough for a http get call.
$client = new \GuzzleHttp\Client();
$response = $client->get('https://example.com/path/to/resource');
echo $response->getStatusCode();
echo $response->getBody();
Depending on whether your php setup allows fopen on URLs, you could also simply fopen the url with the get arguments in the string (such as http://example.com?variable=value )
Edit: Re-reading the question I'm not certain whether you're looking to pass variables or not - if you're not you can simply send the fopen request containg http://example.com/filename.xml - feel free to ignore the variable=value part
I like using fsockopen open for this.
On the other hand, using the REST API of servers is very popular in PHP. You can suppose all URLs are parts of a REST API and use many well-designed PHP packages.
Actually, REST API is a way to use services from a site.
So, there are many PHP packages developed to simplify REST API call. For example here is a very nice one:
https://github.com/romanpitak/PHP-REST-Client
Using such packages helps you to fetch resources easily.
So, getting the xml file (that you mentioned about) is as easy as:
$client = new Client('http://example.com');
$request = $client->newRequest('/filename.xml');
$response = $request->getResponse();
echo $response->getParsedResponse();

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