Trouble using percent sign operator (%) (PHP) - php

Question

I'm attempting to convert 7500 seconds to minutes, and then the minutes to hours. If it comes out to 2 hours and 5 minutes, as in this example, I'd like to display it as "2 hours and 5 minutes". If its 2 hours even, I just want it to display "2 hours".
7500 divided by 60 divided by 60 comes out to 2.083 (3 repeated). Why does the % return 0? How can I determine if its hours exactly, or if there are minutes to display?
die("Test: " . ((7500 / 60) / 60) % 1);

Answer 1

For conversion, you can use:
function secondsToWords($seconds)
{
/*** return value ***/
$ret = "";
/*** get the hours ***/
$hours = intval(intval($seconds) / 3600);
if($hours > 0)
{
$ret .= "$hours hours ";
}
/*** get the minutes ***/
$minutes = bcmod((intval($seconds) / 60),60);
if($hours > 0 || $minutes > 0)
{
$ret .= "$minutes minutes ";
}
/*** get the seconds ***/
$seconds = bcmod(intval($seconds),60);
$ret .= "$seconds seconds";
return $ret;
}
echo secondsToWords(7500);

Answer 2

Because that is the modulus operator, which gives the remainder of the division.
You want to use /, the division operator, that returns a float. See here

Answer 3

I've created a nice function for that a while ago. It also does years and months (and anything you'd like) if you want.
Source + examples: http://hotblocks.nl/tests/time_ago.php
Function:
<?php
function time_ago( $f_seconds, $f_size = 2, $f_factor = 1.6 ) {
$units = array(
86400*365.25 => array(' year', ' years'),
86400*30 => array(' month', ' months'),
86400*7 => array(' week', ' weeks'),
86400 => array(' day', ' days'),
3600 => array(' hour', ' hours'),
60 => array(' minute', ' minutes'),
1 => array(' second', ' seconds'),
);
if ( isset($GLOBALS['g_units']) && is_array($GLOBALS['g_units']) ) {
$units = $GLOBALS['g_units'];
}
$timeAgo = array();
$seconds = (int)$f_seconds;
foreach ( $units AS $range => $unit ) {
if ( 1 == $range || $seconds >= $range * $f_factor ) {
is_array($unit) || $unit = array($unit, $unit);
$last = count($timeAgo) == $f_size-1;
$round = $last ? 'round' : 'floor';
$num = $round($seconds / $range);
$timeAgo[] = $num . $unit[(int)(1 != $num)];
if ( $last ) {
break;
}
$seconds -= $num * $range;
}
}
$separator = isset($GLOBALS['g_separator']) ? $GLOBALS['g_separator'] : ', ';
return implode($separator, $timeAgo);
}
?>

Answer 4

That's the way the mod (%) operator works. Every integer is divisible by 1, so
n % 1 = 0
for all integral n.
What are you trying to do with the % operator?
Whatever it is, you probably want to apply it on an integral value, like the number of seconds. It doesn't work for non-integral values; they are promoted to int values before the operator is applied.