PHP Regex: remove div with class "image" - php

Question

I need to remove all images in a variable using the following pattern. (With PHP).
<div class="float-right image">
<img class="right" src="http://www.domain.com/media/images/image001.png" alt="">
</div>
All the div tags will have an image class, but the float-right might vary. I can't seem to get the regex working, please help me.

Answer 1

Use a DOM instead of regex. Example:
<?php
$doc = new DOMDocument();
$doc->loadHTML('<div class="float-right image">
<img class="right" src="http://www.domain.com/media/images/image001.png" alt="">
</div>');
foreach( $doc->getElementsByTagName("div") as $old_img ) {
$img = $doc->createElement("img");
$src = $doc->createAttribute('src');
$class = $doc->createAttribute('class');
$src->value = 'http://your.new.link';
$class->value = 'right';
$img->appendChild($src);
$img->appendChild($class);
$doc->replaceChild($img, $old_img);
}
echo $doc->saveHTML();
?>

Answer 2

This regex matches your pattern:
(?s)<div class="[^"]*">\W*<img\W*class="[^"]*"\W*src="[^"]*"\W*alt="[^"]*">\W*</div>
I have tested it against several strings. It will work on:
<div class="anything">
<img class="blah" src="anything" alt="blah">
</div>
, where you can replace the "blah" and "anything" strings with anything.
Also, the various \W* in the regex allow for different spacing from string to string.
You said you want to do this in PHP.
This will zap all the matched patterns from a page stored in the $my_html variable.
$my_html=preg_replace('%(?s)<div class="[^"]*">\W*<img\W*class="[^"]*"\W*src="[^"]*"\W*alt="[^"]*">\W*</div>%m', '', $my_html);
I think this is what you were looking for?