I have the following test code:
<?php
$letter = 'A';
$letter++;
$letter++;
echo $letter.'<br>'; // C
$letter++;
$letter++;
$letter++;
echo $letter.'<br>'; // F
// how to add plus 3 letters
// so that
// $letter + 3 => I
As shown here by using $letter++ or $letter-- I can go up or down a character. Is there a way I can do something like $letter + 3 so it adds up 3 letters.
I know I can make a function with a loop which will add a char by char and at the end I will get the result. But is there a better way?
There might be better solutions but the fastest way I can think of is:
// get ASCII code of first letter
$ascii = ord('A');
// echo letter for +3
echo chr($ascii + 3);
keep in mind that you will get other symbols after Z
Try this...
$letter = ord('A')+3;
echo chr($letter);
Maybe this'll work:
$x = 'G';
$y = range('A','Z');
echo $y[array_search($x,$y)+3];
Old thread but in case someone searches. Create array of letters, needed letter as in spreadsheet.
$alphabet = array('A','B','C','D','E','F','G','H','I','J','K','L','M',..........'AY','AZ');
//add 36 to the letter A
$val = (array_search('A',$alphabet)) + 36;
echo $alphabet[$val]."<BR>";
I don't really like any of these answers as they don't replicate the function of PHP. Below is probably the easiest way to replicate it.
function addLetters($letter,$lettersToAdd){
for ($i=0;$i<$lettersToAdd;$i++){
$letter++;
}
return $letter;
}
echo addLetters('G',4);
echo "\n";
echo addLetters('Z',4);
Gives
K
AD
Related
I have a string formed up by numbers and sometimes by letters.
Example AF-1234 or 345ww.
I have to get the numeric part and increment it by one.
how can I do that? maybe with regex?
You can use preg_replace_callback as:
function inc($matches) {
return ++$matches[1];
}
$input = preg_replace_callback("|(\d+)|", "inc", $input);
Basically you match the numeric part of the string using the regex \d+ and replace it with the value returned by the callback function which returns the incremented value.
Ideone link
Alternatively this can be done using preg_replace() with the e modifier as:
$input = preg_replace("|(\d+)|e", "$1+1", $input);
Ideone link
If the string ends with numeric characters it is this simple...
$str = 'AF-1234';
echo $str++; //AF-1235
That works the same way with '345ww' though the result may not be what you expect.
$str = '345ww';
echo $str++; //345wx
#tampe125
This example is probably the best method for your needs if incrementing string that end with numbers.
$str = 'XXX-342';
echo $str++; //XXX-343
Here is an example that worked for me by doing a pre increment on the value
$admNo = HF0001;
$newAdmNo = ++$admNo;
The above code will output HF0002
If you are dealing with strings that have multiple number parts then it's not so easy to solve with regex, since you might have numbers overflowing from one numeric part to another.
For example if you have a number INV00-10-99 which should increment to INV00-11-00.
I ended up with the following:
for ($i = strlen($string) - 1; $i >= 0; $i--) {
if (is_numeric($string[$i])) {
$most_significant_number = $i;
if ($string[$i] < 9) {
$string[$i] = $string[$i] + 1;
break;
}
// The number was a 9, set it to zero and continue.
$string[$i] = 0;
}
}
// If the most significant number was set to a zero it has overflowed so we
// need to prefix it with a '1'.
if ($string[$most_significant_number] === '0') {
$string = substr_replace($string, '1', $most_significant_number, 0);
}
Here's some Python code that does what you ask. Not too great on my PHP, but I'll see if I can convert it for you.
>>> import re
>>> match = re.match(r'(\D*)(\d+)(\D*)', 'AF-1234')
>>> match.group(1) + str(int(match.group(2))+1) + match.group(3)
'AF-1235'
This is similar to the answer above, but contains the code inline and does a full check for the last character.
function replace_title($title) {
$pattern = '/(\d+)(?!.*\d)+/';
return preg_replace_callback($pattern, function($m) { return ++$m[0]; }, $title);
}
echo replace_title('test 123'); // test 124
echo replace_title('test 12 3'); // test 12 4
echo replace_title('test 123 - 2'); // test 123 - 3
echo replace_title('test 123 - 3 - 5'); // test 123 - 3 - 6
echo replace_title('123test'); // 124test
I have a string formed up by numbers and sometimes by letters.
Example AF-1234 or 345ww.
I have to get the numeric part and increment it by one.
how can I do that? maybe with regex?
You can use preg_replace_callback as:
function inc($matches) {
return ++$matches[1];
}
$input = preg_replace_callback("|(\d+)|", "inc", $input);
Basically you match the numeric part of the string using the regex \d+ and replace it with the value returned by the callback function which returns the incremented value.
Ideone link
Alternatively this can be done using preg_replace() with the e modifier as:
$input = preg_replace("|(\d+)|e", "$1+1", $input);
Ideone link
If the string ends with numeric characters it is this simple...
$str = 'AF-1234';
echo $str++; //AF-1235
That works the same way with '345ww' though the result may not be what you expect.
$str = '345ww';
echo $str++; //345wx
#tampe125
This example is probably the best method for your needs if incrementing string that end with numbers.
$str = 'XXX-342';
echo $str++; //XXX-343
Here is an example that worked for me by doing a pre increment on the value
$admNo = HF0001;
$newAdmNo = ++$admNo;
The above code will output HF0002
If you are dealing with strings that have multiple number parts then it's not so easy to solve with regex, since you might have numbers overflowing from one numeric part to another.
For example if you have a number INV00-10-99 which should increment to INV00-11-00.
I ended up with the following:
for ($i = strlen($string) - 1; $i >= 0; $i--) {
if (is_numeric($string[$i])) {
$most_significant_number = $i;
if ($string[$i] < 9) {
$string[$i] = $string[$i] + 1;
break;
}
// The number was a 9, set it to zero and continue.
$string[$i] = 0;
}
}
// If the most significant number was set to a zero it has overflowed so we
// need to prefix it with a '1'.
if ($string[$most_significant_number] === '0') {
$string = substr_replace($string, '1', $most_significant_number, 0);
}
Here's some Python code that does what you ask. Not too great on my PHP, but I'll see if I can convert it for you.
>>> import re
>>> match = re.match(r'(\D*)(\d+)(\D*)', 'AF-1234')
>>> match.group(1) + str(int(match.group(2))+1) + match.group(3)
'AF-1235'
This is similar to the answer above, but contains the code inline and does a full check for the last character.
function replace_title($title) {
$pattern = '/(\d+)(?!.*\d)+/';
return preg_replace_callback($pattern, function($m) { return ++$m[0]; }, $title);
}
echo replace_title('test 123'); // test 124
echo replace_title('test 12 3'); // test 12 4
echo replace_title('test 123 - 2'); // test 123 - 3
echo replace_title('test 123 - 3 - 5'); // test 123 - 3 - 6
echo replace_title('123test'); // 124test
I have this array which links numbers to letters at the moment like this:
1-26 = A-Z
But there is more, 27=AA and 28=AB etc...
so basically when I do this:
var_dump($array[2]); //shows B
var_dump($array[29]); //shows AC
Now this array I made myself but it's becoming way too long. Is there a way to actually get this going on till lets say 32? I know there is chr but I dont think I can use this.
Is there an easier way to actually get this without using this way too long of an array?
It's slower calculating it this way, but you can take advantage of the fact that PHP lets you increment letters in the same way as numbers, Perl style:
function excelColumnRange($number) {
$character = 'A';
while ($number > 1) {
++$character;
--$number;
}
return $character;
}
var_dump(excelColumnRange(2));
var_dump(excelColumnRange(29));
here is the code which you are looking for :
<?php
$start = "A";
$max = 50;
$result = array();
for($i=1; $i<=$max; $i++) {
$result[$i] = $start++;
}
print_r($result);
?>
Ref: http://www.xpertdeveloper.com/2011/01/php-strings-unusual-behaviour/
This should work for you:
Even without any loops. First I calculate how many times the alphabet (26) goes into the number. With this I define how many times it has to str_repleat() A. Then I simply subtract this number and calculate the number in the alphabet with the number which is left.
<?php
function numberToLetter($number) {
$fullSets = (($num = floor(($number-1) / 26)) < 0 ? 0 : $num);
return str_repeat("A", $fullSets) . (($v = ($number-$fullSets*26)) > 0 ? chr($v+64) : "");
}
echo numberToLetter(53);
?>
output:
AAA
I'm trying to achieve a loop over all possible 2 letter combinations.
Something like
foreach(range(aa,zz) as $i) {...}
My current solution is:
foreach (range(a, z) as $first) {
foreach (range(a, z) as $second) {
//all 2 letter combinations
echo $first.$second;
}
}
This makes me worry that if I needed all possible 10 letter combinations, there would be 10 loops involved.
Is there a better way to achieve this?
You could loop over letters using a simple for loop :
for ($letter = 'aa'; $letter != 'aaa'; ++$letter) {
echo $letter . '<br>';
}
Output :
aa
ab
...
zy
zz
$a = array(1,2,3,4,5,6,7,8,9,0);
$b = array('q','r','s','t','u','v','w','x','y','z');
for($i = 26;$i <= 1000;$i++)
echo str_replace($a,$b,base_convert ( $i, 10 , 26))."<br />";
just put in the right starting and end positions.
Since I am still new to PHP, I am looking for a way to find out how to get a specific character from a string.
Example:
$word = "master";
$length = strlen($word);
$random = rand(1,$length);
So let's say the $random value is 3, then I would like to find out what character the third one is, so in this case the character "s". If $random was 2 I would like to know that it's a "a".
I am sure this is really easy, but I tried some substr ideas for nearly an hour now and it always fails.
Your help would be greatly appreciated.
You can use substr() to grab a portion of a string starting from a point and going length. so example would be:
substr('abcde', 1, 1); //returns b
In your case:
$word = "master";
$length = strlen($word) - 1;
$random = rand(0,$length);
echo substr($word, $random, 1);//echos single char at random pos
See it in action here
You can use your string the same like 0-based index array:
$some_string = "apple";
echo $some_string[2];
It'll print 'p'.
or, in your case:
$word = "master";
$length = strlen($word);
$random = rand(0,$length-1);
echo $word[$random];
Try this simply:
$word = "master";
$length = strlen($word);
$random = rand(0,$length-1);
if($word[$random] == 's'){
echo $word[$random];
}
Here I used 0 because $word[0] is m so that we need to subtract one from strlen($word) for getting last character r
Use substr
$GetThis = substr($myStr, 5, 5);
Just use the same values for the same or different if you want multiple characters
$word = "master";
$length = strlen($word);
$random = rand(0,$length-1);
$GetThis = substr($word, $random, $random);
As noted in my comment (I overlooked as well) be sure to start your rand at 0 to include the beginning of your string since the m is at place 0. If we all overlooked that it wouldn't be random (as random?) now would it :)
You can simply use $myStr{$random} to obtain the nth character of the string.