Using count(*) and mysql_fetch_object() at the same time? - php

Question

I want to count all the rows and at the same time list them as I usually do, using mysql_fetch_object. I thought I'd do something like this;
$total = mysql_query("SELECT *, COUNT(*) AS totalfound FROM img WHERE state='0'");
But I can't seem to wrap my head around how to get the values out - I just get the first item in the table when I run this;
while ($record = mysql_fetch_object($total)) { echo $record->id; }
If I want to get the totalfound I could do this;
$result = mysql_fetch_assoc($total);
$count = $result['totalfound'];
...but then I can't get the rest. I know I'm thinking wrong but can't seem to get it to work. Can you guys please help me out? Thanks!
Once thing I forgot to mention: mysql_num_rows is too slow, I was thinking of using count(*) instead. As an example, mysql_num_rows on the entire table takes everything from 3 to 9 seconds, and a count(*) always takes 0.6 seconds, getting the same results.

Answer 1

A count is an aggregate function, you cannot select both rows and aggregates without using group by. MySQL will let you do it without the group by, and will produce unpredictable results.
Just use the query without count to get the rows, and use mysql_num_rows() on the result.
Edit: If mysql_num_rows() is slow, you must be returning a lot of rows. You'd then better execute two queries, one simply select count(*) as numrows ..., and one to retreive your data.
Try to add proper indexes and the count(*) will execute within a few miliseconds.
You really don't want this in one query. Every row will then have a column that states how many rows there are, which is unrelated to that row.

Answer 2

Why not just list them normally and get the count by the inbuilt function?
$result = mysql_query("SELECT * FROM img WHERE state='0'");
$count = mysql_num_rows($result);
while ($row = mysql_fetch_array($result))
{
//do your thing here
}
Editing in response to your edit
In normal circumstances, where you only want the Count, a Count() would be far faster than mysql_num_rows() because Count() would only return the count. In your case, since you want the records anyway, mysql_num_rows() should be faster.

Answer 3

If I understand what you need, I think you could use:
$result = mysql_query("SELECT * FROM img WHERE state='0'");
$num_rows = mysql_num_rows($result);
With $result you can get all rows the way you're used to, while $num_rows has the number of returned rows from database.

Answer 4

Aside from the Marco's right answer,
why can't you make it the same way, echo $record->totalfound;?
As for the "mysql_num_rows being slow" - it is no more a delusion.
You have just heard something but didn't get the point.
mysql_num_rows itself isn't being slow by any means.
it is gathering data rows being slow, not getting them count.
mysql_num_rows indeed is slower than count(*) if you need only that number, not all the data
but if you are getting your data anyway, mysql_num_rows is exactly what you need

Answer 5

Use KISS theory and do the below
while ($record = mysql_fetch_object($total)) {$totalData[] = $record; }
count($totalData) // returns total number of rows
Count

Answer 6

My dear haven't you listen about mysql_num_rows
$total = mysql_query("SELECT * FROM img WHERE state='0'");
$total_found=mysql_num_rows($total);