I'd like to check if to Zend_Date datetimes are on the same day. How can I do that?
$date1 = new Zend_Date('2011-11-14 10:45:00');
$date2 = new Zend_Date('2011-11-14 19:15:00');
$date1 = new Zend_Date('2011-11-14 10:45:00');
$date2 = new Zend_Date('2011-11-14 19:15:00');
if ($date1->compareDay($date2) === 0) {
echo 'same day';
}
Also see the chapter on Comparing Dates with Zend Date
On a sidenote, I strongly encourage you to verify if you have the need for Zend_Date. Do not use it just because it is part of ZF. Most of what Zend_Date does can be achieved faster and more comfortably with native DateTime as well:
$date1 = new DateTime('2011-11-14 10:45:00');
$date2 = new DateTime('2011-11-14 19:15:00');
if ($date1->diff($date2)->days === 0) {
echo 'same day';
}
EDIT after comments
If you want to compare whether it's the same date just do
$date1->compareDate($date2)
Related
Although my question seems can be found the solution on the internet easily. But I've already tried but it's not working.
I've already followed https://www.php.net/manual/en/datetime.diff.php Example #2 DateTime object comparison
or another solution like https://thevaluable.dev/php-datetime-create-compare-format/ Comparing DateTime Objects
But it is still not working.
Here is my code,
$end_time = new DateTime('2020-04-05 23:59:00');
$now = new DateTime('now');
if( $now > $end_time ){
echo 'expired!';
}
It throws the error
Object of class DateTime could not be converted to string.
Edited
I'm using PHP 7.1.23
Here is the solution for your problem. First you have to convert them into Strings then you can use them. I have changed the input date just to show you the result of if condition.
Select your City for time zone First
date_default_timezone_set('Asia/Karachi');
Your Inputs
$input_time = new DateTime('2020-04-01 23:59:00');
$now = new DateTime('now');
Convert them to string
$input_time = $input_time->format('Y-m-d H:i:s');
$now = $now->format('Y-m-d H:i:s');
The result
if( $now > $input_time )
{
echo 'expired!'. '<br>';
}
If it doesn't need to be an actual DateTime object, you could use times instead, which will then compare the same as an integer would.
Eg
$end_time = strtotime('2020-04-05 23:59:00');
$now = time();
if( $now > $end_time ) {
echo 'expired!';
}
I want to get the date of yesterday of the current date in a specifc time zone.
I tried like this, but it is not working:
$date = new DateTime(NULL, new DateTimeZone('Pacific/Wake'));
$yesterday = $date->modify( '-1 day' );
$yesterday = $yesterday->format('Y-m-d');
I am still getting today's date.
This problem, according to the documentation for the modify() method, seems to entirely depend on which version of php you're using. In this case, method chaining(which is what you're attempting to do is called), is only available on php version 5.3.0 and up, according to the changelog on the previously linked docs.
That in mind, it explains why your code didn't work, and #Deryck's did. If you ever do upgrade your php version, or get your host to upgrade it, you could likely reduce those three lines to two:
$date = new DateTime(NULL, new DateTimeZone('Pacific/Wake'));
$date = $date->modify( '-1 day' )->format('Y-m-d');
Not much of an improvement, I realize, but there's your reason for why it failed to work.
Below are two of the methods I see of getting around this; one is creation of a class.. which seems like overkill to me unless this is apart of something grander... the other is a creation of a function. Both shove the extra lines into something that takes up less space, in a sense.
class DT {
private $now; //can be null
private $timezone; //DateTimeZone object
public function __construct($tz_str, $now = NULL) {
$this->now = $now;
$this->timezone = new DateTimeZone($tz_str);;
}
public function mod($mod,$format) {
$dt = new DateTime($this->now, $this->timezone);
$dt->modify($mod);
return $dt->format($format);
}
}
function mod_formatted_zone($tz_str, $mod, $format, $now = NULL) {
$timezone = new DateTimeZone($tz_str);
$dt = new DateTime($now,$timezone);
$dt->modify($mod);
return $dt->format($format);
}
The use of either is simple; in the case of the class, it'd be something like..
$dt = new DT('Pacific/Wake');
echo $dt->mod('-1 day', 'Y-m-d');
While in the case of the function, it'd simply be..
echo mod_formatted_zone('Pacific/Wake', '-1 day', 'Y-m-d');
Seems to work once you don't re-assign the $date variable unnecessarily. See below:
<?php
$date = new DateTime(NULL, new DateTimeZone('Pacific/Wake'));
$date->modify("-1 day");
$date = $date->format("Y-m-d");
// echo $date; // just in case you wanna echo - ya dig
?>
View demo
FYI:
Wake Island Time Zone (UTC+12:00)
Which means 1 day before is actually today (for me at least, on the western hemisphere).
I want to get the date of yesterday of the current date in a specifc time zone.
You can specify relative dates in the DateTime constructor. This will work for you:-
$yesterday = new DateTime('- 1 day', new DateTimeZone('Pacific/Wake'));
var_dump($yesterday);
Proof!.
I'm trying to determine when a user has last logged on. My current method works but is there an easier way of determining this so that I could determine last X hours etc?
This is what I currently use:
$last_login_di = getdate($last_login);
$now = time();
$now_di = getdate($now);
$today = mktime(0,0,0,$now_di['mon'],$now_di['mday'], $now_di['year']);
if ($last_login > $today) {
return 'Online Today';
}
$yesterday = $now-86400;
$yesterday_di = getdate($yesterday);
$yesterday = mktime(0,0,0,$yesterday_di['mon'],$yesterday_di['mday'], $yesterday_di['year']);
if ($last_login > $yesterday) {
return 'Online Yesterday';
}
if (($now - $last_login < 604800) ) {
return 'Online This Week';
}
....
Try strtotime() (see relative formats it accepts) or better yet, the DateTime, DateInterval classes.
For example, the $yesterday variable creation is prone errors near datetime savings. strtotime() handles this properly with:
$yesterday = strtotime('-1 day');
While the $last_login check can be written like:
if (strtotime('-1 week') < $last_login) {
// ...
}
If you need to support different timezones you probably better of with the DateTime objects though.
Have a look at the DateTime and related classes DateTime Book on php.net. The DateInterval class may be of particular use to you.
How do you get the date? Using MySQL? Use UNIX_TIMESTAMP for dates, eg SELECT UNIX_TIMESTAMP(last_login) AS last_login_timestamp FROM ... Then you can better calculate in PHP (using date_diff)
I think your code's fine. But the $yesterday var is wrong.
It should be:
$yesterday = $today - 86400;
In your code $yesterday means $a_day_ago.
The same for the last week.
You should heavily use the date objects built-in with PHP.
$now = new DateTime();
$yesterday = new DateTime('yesterday');
$lastWeek = new DateTime('last week');
Now you are able to to any comparison logic you want, using the basic comparison operators:
if ($last_login > $now) {
...
} else if ($last_login > $yesterday) {
...
} else if ($last_login > $lastWeek) {
...
} else {
...
}
If you choose not to use the objects, try to avoid the time() function. That makes unit testing impossible. Tests should never depend on environment.
Use $_SERVER['REQUEST_TIME'] instead so you can mock it later.
I am trying to compare the current datetime, with a datetime from the database using string, as the following:
$today = new DateTime("now");
$todayString = $today->format('Y-m-d H:i:s');
if($todayString >= $rows["PrioritizationDueDate"])
{...}
$todayString keeps giving me the time 7 hours earlier (i.e now its 11:03pm, its giving me 16:04).
More, is it better to compare this way, or should i compare using datetime objects?
$todayString keeps giving me the time 7 hours earlier
you have to setup a timezone for the DateTime object I believe.
is it better to compare this way
I doubt so.
The general way is to compare in the query, using SQL to do all date calculations and return only matching rows.
Set a correct timezone in the constructor to DateTime.
$today = new DateTime("now", new DateTimeZone('TimezoneString'));
Where TimezoneString is a valid timezone string.
Edit: For a more complete example using DateTime objects, I would use DateTime::diff in conjunction with DateTime::createFromFormat.
$rows["PrioritizationDueDate"] = '2011-11-20 10:30:00';
$today = new DateTime("now", new DateTimeZone('America/New_York'));
$row_date = DateTime::createFromFormat( 'Y-m-d H:i:s', $rows["PrioritizationDueDate"], new DateTimeZone('America/New_York'));
if( $row_date->diff( $today)->format('%a') > 1)
{
echo 'The row timestamp is more than one day in the past from now.';
}
Demo
First set time zone using this function
date_default_timezone_set('UTC');
Then either you can use function strtotime() or get difference directly...
I have following
$var = "2010-01-21 00:00:00.0"
I'd like to compare this date against today's date (i.e. I'd like to know if this $var is before today or equals today or not)
What function would I need to use?
strtotime($var);
Turns it into a time value
time() - strtotime($var);
Gives you the seconds since $var
if((time()-(60*60*24)) < strtotime($var))
Will check if $var has been within the last day.
That format is perfectly appropriate for a standard string comparison e.g.
if ($date1 > $date2){
//Action
}
To get today's date in that format, simply use: date("Y-m-d H:i:s").
So:
$today = date("Y-m-d H:i:s");
$date = "2010-01-21 00:00:00";
if ($date < $today) {}
That's the beauty of that format: it orders nicely. Of course, that may be less efficient, depending on your exact circumstances, but it might also be a whole lot more convenient and lead to more maintainable code - we'd need to know more to truly make that judgement call.
For the correct timezone, you can use, for example,
date_default_timezone_set('America/New_York');
Click here to refer to the available PHP Timezones.
Here you go:
function isToday($time) // midnight second
{
return (strtotime($time) === strtotime('today'));
}
isToday('2010-01-22 00:00:00.0'); // true
Also, some more helper functions:
function isPast($time)
{
return (strtotime($time) < time());
}
function isFuture($time)
{
return (strtotime($time) > time());
}
You can use the DateTime class:
$past = new DateTime("2010-01-01 00:00:00");
$now = new DateTime();
$future = new DateTime("2021-01-01 00:00:00");
Comparison operators work*:
var_dump($past < $now); // bool(true)
var_dump($future < $now); // bool(false)
var_dump($now == $past); // bool(false)
var_dump($now == new DateTime()); // bool(true)
var_dump($now == $future); // bool(false)
var_dump($past > $now); // bool(false)
var_dump($future > $now); // bool(true)
It is also possible to grab the timestamp values from DateTime objects and compare them:
var_dump($past ->getTimestamp()); // int(1262286000)
var_dump($now ->getTimestamp()); // int(1431686228)
var_dump($future->getTimestamp()); // int(1577818800)
var_dump($past ->getTimestamp() < $now->getTimestamp()); // bool(true)
var_dump($future->getTimestamp() > $now->getTimestamp()); // bool(true)
* Note that === returns false when comparing two different DateTime objects even when they represent the same date.
To complete BoBby Jack, the use of DateTime OBject, if you have php 5.2.2+ :
if(new DateTime() > new DateTime($var)){
// $var is before today so use it
}
$toBeComparedDate = '2014-08-12';
$today = (new DateTime())->format('Y-m-d'); //use format whatever you are using
$expiry = (new DateTime($toBeComparedDate))->format('Y-m-d');
var_dump(strtotime($today) > strtotime($expiry)); //false or true
One caution based on my experience, if your purpose only involves date then be careful to include the timestamp. For example, say today is "2016-11-09". Comparison involving timestamp will nullify the logic here. Example,
// input
$var = "2016-11-09 00:00:00.0";
// check if date is today or in the future
if ( time() <= strtotime($var) )
{
// This seems right, but if it's ONLY date you are after
// then the code might treat $var as past depending on
// the time.
}
The code above seems right, but if it's ONLY the date you want to compare, then, the above code is not the right logic. Why? Because, time() and strtotime() will provide include timestamp. That is, even though both dates fall on the same day, but difference in time will matter. Consider the example below:
// plain date string
$input = "2016-11-09";
Because the input is plain date string, using strtotime() on $input will assume that it's the midnight of 2016-11-09. So, running time() anytime after midnight will always treat $input as past, even though they are on the same day.
To fix this, you can simply code, like this:
if (date("Y-m-d") <= $input)
{
echo "Input date is equal to or greater than today.";
}
Few years later, I second Bobby Jack's observation that last 24 hrs is not today!!! And I am surprised that the answer was so much upvoted...
To compare if a certain date is less, equal or greater than another, first you need to turn them "down" to beginning of the day. In other words, make sure that you're talking about same 00:00:00 time in both dates.
This can be simply and elegantly done as:
strtotime("today") <=> strtotime($var)
if $var has the time part on 00:00:00 like the OP specified.
Replace <=> with whatever you need (or keep it like this in php 7)
Also, obviously, we're talking about same timezone for both.
For list of supported TimeZones
$date1=date_create("2014-07-02");
$date2=date_create("2013-12-12");
$diff=date_diff($date1,$date2);
(the w3schools example, it works perfect)
Expanding on Josua's answer from w3schools:
//create objects for the dates to compare
$date1=date_create($someDate);
$date2=date_create(date("Y-m-d"));
$diff=date_diff($date1,$date2);
//now convert the $diff object to type integer
$intDiff = $diff->format("%R%a");
$intDiff = intval($intDiff);
//now compare the two dates
if ($intDiff > 0) {echo '$date1 is in the past';}
else {echo 'date1 is today or in the future';}
I hope this helps. My first post on stackoverflow!
Some given answers don't have in consideration the current day!
Here it is my proposal.
$var = "2010-01-21 00:00:00.0"
$given_date = new \DateTime($var);
if ($given_date == new \DateTime('today')) {
//today
}
if ($given_date < new \DateTime('today')) {
//past
}
if ($given_date > new \DateTime('today')) {
//future
}
Compare date time objects:
(I picked 10 days - Anything older than 10 days is "OLD", else "NEW")
$now = new DateTime();
$yourdate = new DateTime("2021-08-24");
$diff=date_diff($yourdate,$now);
$diff_days = $diff->format("%a");
if($diff_days > 10){
echo "OLD! " . $yourdate->format('m/d/Y');
}else{
echo "NEW! " . $yourdate->format('m/d/Y');
}
If you do things with time and dates Carbon is you best friend;
Install the package then:
$theDay = Carbon::make("2010-01-21 00:00:00.0");
$theDay->isToday();
$theDay->isPast();
$theDay->isFuture();
if($theDay->lt(Carbon::today()) || $theDay->gt(Carbon::today()))
lt = less than,
gt = greater than
As in the question:
$theDay->gt(Carbon::today()) ? true : false;
and much more;
Try this:
if (date("Y-m-d",strtotime($funding_dt)) >= date("Y-m-d",strtotime('31-01-2007')))
{
echo "ok";
} else {
echo "not";
}