Clicking a link display it in Different Div on Same Page - php

I would like to know if there is a way to be able to click a Link on the navigational Div tag and have it display on the content Div like if i had
<div id="nav">
a link </div>
<div id="content>show the stuff</div>
From the comments below - the OP stated the following :
I am trying to redo a website but my imagagination is getting the better of me. If I have three links like home, about author, and about our mission. I would like to be able to click about author and in the main_content div tag show the html file aboutauthor.html

Alt 1: Use jquery tabs:
See demo and code here: http://jqueryui.com/demos/tabs/
Alt 2: Hide/show div in same html file:
HTML:
<div id="nav">
Show content 1
Show content 2
Show content 3
</div>
<div id="content1" class="toggle" style="display:none">show the stuff1</div>
<div id="content2" class="toggle" style="display:none">show the stuff2</div>
<div id="content3" class="toggle" style="display:none">show the stuff3</div>
jQuery:
$("#nav a").click(function(e){
e.preventDefault();
$(".toggle").hide();
var toShow = $(this).attr('href');
$(toShow).show();
});
Demo: http://jsfiddle.net/5NEu3/3/
Alt 3: Load from server ondemand:
To load html into your main div you should use: http://api.jquery.com/load/
Follow examples on that site. And be aware that the html side you are loading must be in same domain as you are hosting the new page.
Html
Show content 1
Show content 2
jQuery
$("#nav a").click(function(e){
e.preventDefault();
$('#maindiv').load($(this).attr("href"));
});

Using jQuery, you could do something like this.
This will open the site <a href="example.html"> and put it inside of the <div id="content"> when you click it, and then disable changing the whole site.
<script src="//ajax.googleapis.com/ajax/libs/jquery/1.7.0/jquery.min.js" type="text/javascript"></script>
<script>
$(document).ready(function() {
$('#nav a').click(function(e) {
e.preventDefault();
$('#content').load($(this).attr('href'));
});
});
</script>
<div id="nav">
Some page
Some other page
My page
</div>
<div id="content">
show the stuff
</div>

Something like this:
function setContent(div, content)
{
getElementById(div).innerHtml = content;
return false; // return false to ignore the click
}
a link

to show a hidden div (i think this is what you wanted)
the javascript (using jQuery)
<script src="http://code.jquery.com/jquery-latest.js"></script>
<script type="text/javascript">
$(document).ready(function () {
$("#showdiv").click(function () {
$("#hiddendiv").show();
});
});
<script>
the html
Show the Div
<div id="hiddendiv" style="display:none;">Content here</div>
you can see it in action here

Related

Jquery mobile to add panels after loading file to populate a div

OK so I am using $_POST to submit a form in jquery mobile and it works like this:
if($_POST['i']){?>
<div id="info"></div>
<script>
$( "#info" ).load( "file.php?&information=<?=$_POST['i']?>");
</script>
<?}?>
file.php has something like this:
info 1
info 2
<div data-role="panel" id="panel1" data-display="overlay" data-position-fixed="true" class="panels">
Text 1
</div>
<div data-role="panel" id="panel2" data-display="overlay" data-position-fixed="true" class="panels">
Text 2
</div>
I want to load file.php to fill #info. Then I want to keep the links in that div and move the panels to after the footer of the containing page (#footer). My problem is that when I try to add something after the load like this:
<script>
$( "#info" ).load( "file.php?i=<?=$_POST['i']?>");
$("#footer").after(".panels");
</script>
Nothing appends. I can append other things after the footer like:
$("#footer").after("TEST");
So I guess the problem is that anything inside the loaded div is unavailable. How do I get at it?
You could try this
<script>
$( "#info" ).load( "file.php?i=<?=$_POST['i']?>", function() {
var p = $("#info").find( ".panels" ).detach();
$( "#footer" ).after(p);
});
</script>

I want to load 2nd div first and 1st div second

<div class="a">hello</div>
<div class="b">bye</div>
I have a one page website and I want a div to be loaded first and then the second one and... Can I do this just with html and css? Or it needs JavaScript or...
Just do it with Javascript:
Change your Body to <body onload="onloadFunction()">
Add style="display: none;" to your div Elements
Add following script:
<script language="javascript" type="text/javascript">
function onloadFunction(){
document.getElementsByClassName("a").style.display = "true";
document.getElementsByClassName("b").style.display = "true";
}
</script>
and change the order of the document. lines to which order you want to have it.
You can try this with something like.
$(document).ready(function() {
$(".b").delay(2000).fadeIn(500); //class b is on delay
});
Can't done with only HTML and CSS. Need to involve JavaScript or jQuery code too.
Yes you need javascript and I suggest jquery(javascript library).
More info at: http://www.w3schools.com/jquery/jquery_get_started.asp
And here is working example(just run with browser and click button):
<div class="a" style="display: none;">hello</div>
<div class="b" style="display: none;">bye</div>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.3/jquery.min.js"></script>
<script>
$(document).ready(function(){
$('.a').show();
setTimeout(function(){$('.b').show()}, 2000);
});
</script>

Side Menu without need for many pages

So I have a layout system that I am working on that allows users to click on links on a side menu to access some services.
So basically here is the simple html design
<div class="col-md-2" id="admin_menu">
<section class="list-group">
opt 1
opt 2
opt 3
Opt 4
</section>
</div>
<div class="col-md-10" id="admin_content">
<section class="">
Some content
</section>
</div>
The layout is working as i want it to. A small menu to the left and the main content to the right.
But I have a small issue with the design. As you can see the content is all on one page. When the user clicks on the opt2,3,4 links, he or she will be redirected to the respective page which will also contain the side menu.
So my questions are
What is the most convenient way/ways to create such a design whose
menu is needed in more than one interface.
How do i make the active link change color considering that most
likely the whole page will reload.
Here is the image for the design. The first link shows the style that the active link should have
include "menu.php";
And menu.php contains the menu.
Also works with
require_once "menu.php";
For question two, give each item a unique numbereid (listitem1, listitem2...) and on the page itself create a style tag:
<style>
#listitem1 {
whatever...
}
</style>
Depending on the page.
You can try this code i arranged for you:
1)first you can add some id in your code to identify in a unique way each link
2) second you just add some jquery code in the end of the body of the html code
the idea is that when you send the mouse over the link it changes color you can specify the color by yourself and when the mouse is out it changes color again try that i did it only for the first 3 links but you can do it for many link when you get the idea.
<div class="col-md-2" id="admin_menu">
<section class="list-group">
opt 1
opt 2
opt 3
Opt 4
</section>
</div>
<div class="col-md-10" id="admin_content">
<section class="">
Some content
</section>
</div>
<script>
$(document).ready(function(){
$("#first").mouseover(function () {
$("#first").css({
'color':'red'
});
});
$("#first").mouseout(function () {
$("#first").css({
'display':'lightgray'
});
});
});
$(document).ready(function(){
$("#second").mouseover(function () {
$("#second").css({
'color':'blue'
});
});
$("#second").mouseout(function () {
$("#second").css({
'display':'lightgray'
});
});
});
$(document).ready(function(){
$("#third").mouseover(function () {
$("#third").css({
'color':'yellow'
});
});
$("#third").mouseout(function () {
$("#third").css({
'display':'lightgray'
});
});
});
</script>
As #Faried said, you can include the menu into the main page.
And as for the second question you can use
<?php if(isset($_GET['page']) && $_GET['page']=="pageName")
{
//style for active link
} else
{
//non-active style
}

Load some PHP link within a specific div in HTML page?

I made a side menu with these links:
<div id="menu_lat">
Orçamentos
Relatórios
Próximos Eventos
Chat
</div>
When I open one of these, the content is opened in another div (which, in the first page, already has some content, which is an image):
<div id="conteudo">
<img src="img/foto_inicial.jpg">
</div>
How could I load the PHP file inside this layer when I click that link?
Use jQuery and the load() function
Update you links with a class
<div id="menu_lat">
<a class="loader" href="http://localhost:8080/sgf/form_proposta.php">Orçamentos</a>
<a class="loader" href="relatorios.html">Relatórios</a>
<a class="loader" href="proximos.html">Próximos Eventos</a>
<a class="loader" href="chat.html">Chat</a>
</div>
Then in your <script> tags add this to handle the click event on your links with the class loader.
<script src="//ajax.googleapis.com/ajax/libs/jquery/1.10.0/jquery.min.js"></script>
<script type="text/javascript">
$(function() {
$('.loader').click(function(event) {
event.preventDefault(); // stop the link loading the URL in href
$('#conteudo').load($(this).attr('href'));
});
});
</script>
DO the Ajax call on the DIV id conteudo

AJAX load PHP file

I am a newbie on AJAX, I have a link that loads table.php. Then it writes the code to the index.php. In that code, I have another link to
show the info.php. Is it possible to do this?
<!--This is index.php-->
<div id="link">my Info</div><!--it works here-->
<div id="link">My Table</div>
<div id="table"></div>
<div id="info"></div>
<!--My javascript-->
<script type="text/javascript">
$(document).ready(function() {
$('#link a').click(function(){
var page = $(this).attr('href');
if(page =='table')
$('#table').load('table.php');
else if(page =='info')
$('#info').load('info.php');
return false;
})
});
</script>
<!--This is table.php-->
<div id="link">my Info</div><!--it doesn't works here-->
<!--This is info.php-->
<h1>My info</h1>
Your three <div> (as pointed out by #scragar) have the same id link, most probably causing the issue. Make it a class like that :
<div class="link">
And in your JS :
$('.link a')
EDIT : As noted by dbf, you must as well declare your handler with live() or on() instead of click() :
$('.link a').live('click', function(){ ... });
in order for it to be binded after table.php is loaded in the page. ( http://api.jquery.com/live/ )

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