Whats wrong with my link? - php

Question

I am trying to echo a array value in a link, but it is coming up in dreamweaver as an error, but I cant work out what I have done wrong, can anyone tell me what is wrong with this line please ?.
thanks :-)
echo '';
EDIT >>>>>>>>>>>>>>>>>>>>>>>>
THIS IS THE FULL CODE :
$result = mysql_query("SELECT * FROM hqfjt_chronoforms_data_addemailtemplate");
while ($row = mysql_fetch_object($result)) {
echo '<div class="namerow">';
echo '<th>';
echo $row->emailformname;
echo '</th>';
echo '</div>';
echo '<div class="messagerow">';
echo '<th>';
echo $row->emailformmessage;
echo 'dssd';
echo '<tr></tr>';
echo '</div>';
}
echo '</th>';
mysql_free_result($result);
If I echo the cf_uid
echo $row->cf_uid;
this works fine and displays the unique id for each record next to it in the table, I just need to take that id thats is being echo'd and put in at the end of the link so that it looks like http://link&token=2626382837728 << (cf_uid)
FIXED !
Thanks for everyone's help on this work, I worked out what was wrong in the end, what I thought was an array didn't appear to be, this code worked in the end >>
$result = mysql_query("SELECT * FROM hqfjt_chronoforms_data_addemailtemplate");
while ($row = mysql_fetch_object($result)) {
echo '<div class="namerow">';
echo '<th>';
echo $row->emailformname;
echo '</th>';
echo '</div>';
echo '<div class="messagerow">';
echo '<th>';
echo $row->emailformmessage;
$id = $row->cf_uid;
echo 'LINK';
echo '<tr></tr>';
echo '</div>';
}
echo '</th>';
mysql_free_result($result);

Answer 1

Try to separate the strings and the variables.
echo '';
update: If you get an error in this line the problem could be the line before!

Answer 2

alternatively you can try this
echo '';
This way you can just concat the string

Answer 3

echo "SOME NAME FOR THE LINK";
[edit based on updated post]
Use this:
echo 'dssd';
However, I must ask... is there an array variable $detail which has a key 'cf_uid'? And what syntax error are you getting (after you tried this)?
[edit based on comment]
Since it's $row and since it's an object:
echo 'dssd';