I use PHP and Imagick to change the color of a transparent PNG. The image in the PNG is a simple shape with a transparent background.
I use the colorizeImage function to change the color.
$img = new Imagick("shape.png");
$img->colorizeImage("#99ccff",0.0);
The problem is that Imagick show a dark version of my HEX code (#99ccff)?
Is there a way to get the exact color (#99ccff)?
(my PNG is PNG 32 - and the shape is black)
I thought I would answer this question despite that it is old. This is for anyone else having this problem.
I solved this for a project I am working on by simply using "Clut" instead, like so:
$img = new Imagick("shape.png");
$clut = new Imagick();
$clut->newImage(1, 1, new ImagickPixel('#99ccff'));
$img->clutImage($clut);
$clut->destroy();
Hope it helps anyone else having this issue.
$img = new Imagick("shape.png");
$img->colorizeImage("#99ccff",0.0);
That second parameter is opacity. If you set it to 1.0, it will match #99ccff 100%. You can set it to 0.5 to meet 50% over the original layer, etc:
$img = new Imagick("shape.png");
$img->colorizeImage("#99ccff", 1.0);
You must provide opacity, and opacity value MUST be integer 1,
$img->colorizeImage('#99ccff', 1);
or it does not work, i have tested a bit and i think to work with transparency you need to provide alpha channel.
Related
I want to convert a given color to transparency with iMagick. I have found one way to do this, but it behaves like a paint bucket rather than examining the entire image.
For the following example, I'm using this:
$transparentColor = new ImagickPixel('transparent');
$image->floodFillPaintImage($transparentColor, 20000, "#0009c5", 0, 0, false, Imagick::CHANNEL_ALPHA);
This is the input image
This is the output image
The result I'd like to see is all the blue areas turned to transparency. Unfortunately, it seems that "fill" is the key point in this function and hence stops when confronted with non-"target" colors.
Does anyone know how to accomplish turning all the blue areas to transparent using iMagick (not command line imageMagick)?
Thanks in advance!
Try:
$image->transparentPaintImage($targetColor, $alphaLevel, $fuzz, false);
If the transparent areas are "messy", it may help to despeckle:
$image->despeckleimage();
Doc: http://php.net/manual/en/imagick.transparentpaintimage.php
I would like to know and find out, how I can colorize/replace any pixel of an image, that is not (fully) transparent with an opaque pixel.
For example, having a multicolored Logo with transparent pixels, I would like to convert it in to a logo with only the color #ff0000, and not change the transparent background.
I want to achieve this with the PHP Imagick Library. I cannot find any good documentation.
I thought that Imagick::thresholdImage would be a helper, but there is no documentation about the threshold parameter.
Best results are achieved with this fragment of code. But still not working perfectly. Some pixels - i guess those with alpha > 0 and < 1 are not replaced.
$image = new \Imagick($source);
$image->setImageFormat('png');
$fill = new \ImagickPixel('#ff0000');
$image->thresholdImage(0);
$image->paintOpaqueImage('#ffffff', $fill, 1);
$image->writeImage($destination);
I would like to know and find out, how I can colorize/replace any pixel of an image, that is not (fully) transparent with an opaque pixel.
You almost certainly don't.
The code below does what you are asking (I think) and the output looks terrible. Perhaps you should give an example input image, and a hoped for example output image, that you have edited in Photoshop, to show what you were hoping for.
Input image:
Output image:
$imagick = new Imagick("fnord.png");
// Get the alpha channel of the original image.
$imagick->separateImageChannel(\Imagick::CHANNEL_ALPHA);
// Make all the colors above this pure white.
$imagick->whiteThresholdImage("rgb(254, 254, 254)");
// Make all the colors below this pure black.
$imagick->blackThresholdImage("rgb(254, 254, 254)");
// We want the mask the other way round
$imagick->negateImage(false);
$imagickCanvas = new \Imagick();
$imagickCanvas->newPseudoImage(
$imagick->getImageWidth(),
$imagick->getImageHeight(),
"xc:rgb(255, 0, 0)"
);
// Copy the mask back as the alpha channel.
$imagickCanvas->compositeImage($imagick, \Imagick::COMPOSITE_COPYOPACITY, 0, 0);
// Write out the image.
$imagickCanvas->setImageFormat('png');
$imagickCanvas->writeImage("./output.png");
I was trying to perform a crop on a image using imagemagick. It did not give the results I expected.
I decided to set the crop value to 0 to try and find the error.
With a crop value of 0 the image was still being cropped.
Here is the code:
$img = new Imagick();
$img->readImage("{german-grammar.pdf}[17]");
$img->trimImage(10);
$width = $img->getImageWidth();
$height= $img->getImageHeight();
$img->setImagePage($width,$height, 0, 0); //Solution
$img->cropImage($width, $height,0,0); //Original Problem lime
$img->setImagePage(0,0,0,0);
$img->writeImage($ImagesPath.$ImageName);
The input is a PDF file.
I would appreciate if anyone could tell me what I am doing wrong.
Surely a crop value of 0 should not crop at all.
Thanks!
Cymro
I think you need to repage your image immediately after the trimImage() and before the cropImage(). It is generally a good idea to repage an image after any changes to its geometry (such as trimming and resizing) if you want the image to forget that it was once part of a larger image and go forth in the world happy and content with its own new shape and size.
I have pieced together a PHP class to perform various image related functions using GD functions of PHP.
It works great for all image types. Rotate, flip, resize, crop and to a lesser extent, watermark.
All but the latter work perfectly. For example after a few changes, rotated PNG images retained their transparency whereas before they were losing that and the background turning black. Common problem, it appears. But all working now.
Where I'm still getting stuck is watermarking a PNG image with another PNG image. It appears to work fine with JPG and other images. This is the code (simplified):
public function writeWatermarkSimple()
{
$watermarkFile = 'watermark.png';
$watermarkImage = imagecreatefrompng($watermarkFile);
imagealphablending($watermarkImage, false);
imagesavealpha($watermarkImage, true);
$imageFile = 'image.png';
$baseImage = imagecreatefrompng($imageFile);
imagealphablending($baseImage, false);
imagesavealpha($baseImage, true);
$marginH = imagesx($baseImage) - imagesx($watermarkImage);
$marginV = imagesy($baseImage) - imagesy($watermarkImage);
$cut = imagecreatetruecolor(imagesx($watermarkImage), imagesy($watermarkImage));
imagecopy($cut, $baseImage, 0, 0, $marginH, $marginV, imagesx($watermarkImage), imagesy($watermarkImage));
imagecopy($cut, $watermarkImage, 0, 0, 0, 0, imagesx($watermarkImage), imagesy($watermarkImage));
imagecopymerge($baseImage, $cut, $marginH, $marginV, 0, 0, imagesx($watermarkImage), imagesy($watermarkImage), 80);
if (!imagepng($baseImage, 'watermarked_image.png'))
{
return false;
}
return true;
}
This has been pieced together with various guides and advice people have given based on a similar issue. Again, working perfectly with JPG images and PNG watermarks, but not PNG & PNG.
Some example images:
http://i.imgur.com/hHRWinj.png - This is the watermark I'm using.
http://i.imgur.com/6sy8Ncs.png - This is the image I'm applying the watermark to.
http://i.imgur.com/ghovYLm.png - This is the end result.
The bit I find interesting is that any part of the watermark that is overlaid on a non-transparent portion of the image is working fine. Just the rest of it has the black background.
This leads me to believe I'm close, and I hope that the expertise of you fine people may lead me to the solution.
Thanks ever so for reading.
So, I'm not giving up on finding the correct answer to do this using GD. However, I was overjoyed to find that what needed up to 30 lines of code with GD can be achieved using much less with ImageMagick:
$image = new Imagick();
$image->readimage($this->_image);
$watermark = new Imagick();
$watermark->readimage($this->_watermark->_getImage());
$watermark->evaluateImage(Imagick::EVALUATE_DIVIDE, 2, Imagick::CHANNEL_ALPHA);
$image->compositeImage($watermark, imagick::COMPOSITE_OVER, $marginH, $marginV);
So this is before (with GD):
http://i.imgur.com/AlS0TcO.png
And after (with ImageMagick and the code above):
http://i.imgur.com/zBxlC3R.png
If anyone has an answer that is purely GD then I'd be immensely grateful.
Ran into some similar issues recently and while this may not exactly solve your problem, these were some useful discoveries that I made.
In my case, I have an original .jpg image and a watermark .png image. The watermark image has a fully transparent background. I wanted to specify the opacity in my script and have it change the watermark opacity before placing it on top of the origina image. Most posts out there regarding PHP watermarking assume that the original watermark .png file already has the solid watermark portion set to the correct opacity rather than changing it via the script.
gd didn't like a 24 bit .png and caused some goofy issues. Switching to 8 bit resolved that with gd. On the other hand, imagick works very well with a 24 bit .png and the final result seems to be better.
For me, using gd worked just fine if I was opening the original watermark .png and using imagecopymerge() to set the watermark transparency. If however I tried to scale the original watermark .png (which has transparent background) first, then I would get similar results as you with black or white background portion of where watermark image is. See How do I resize pngs with transparency in PHP? for a partial solution by filling the new wm image with transparent rectangle first. For me this still produced an opaque white background on the final result no matter what I tried.
I switched to imagick and was using setImageOpacity() to change the transparency of my watermark .png before applying it on top of my original image and I was still getting the same effect with a black background. Finally read in the PHP doc for setImageOpacity() that if the original .png has any transparent pixels and you try to lower the opacity, those pixels become opaque (black) with the new transparency applied. Instead, need to use the evaluateImage() function. This will instead evaluate each pixel's alpha channel only and divide by the specifid number.
I assume the black / white background issue with gd is likely due to similar ways that it treats alpha channels when scaling / combining as compared to imagick and if you want to do it all in gd you just need to find some similar way to evaluate and manipulate the alpha channel per-pixel because the "easy" ways seem to take an already transparent background and make it opaque.
So, the solution:
Assuming you want to apply your watermark at an opacity of 45% and you're using imagick, then instead of this:
$watermark->setImageOpacity(.45);
do this
$watermark->evaluateImage(Imagick::EVALUATE_DIVIDE, (1/.45), Imagick::CHANNEL_ALPHA);
You need to divide 1 by your opacity to get the demoninator by which the function will divide the alpha channel value for each pixel. In this case, 1/.45 = 2.2222, so then the function will divide the alpha channel of each pixel by 2.2222. This means a solid pixel (alpha of 1) would result in 1/2.2222 or .45 alpha or transparency when finished. Any pixels that were already transparent (alpha 0) would stay transparent because 0 divided by anything is always what? Zero!
After you change the watermark transparency then you can use compositeImage() to merge the watermark onto the original image.
I'm writing code this week to dynamically change the color of images. As long as the image is square or rectangle, the code below works perfectly. However, I have an image that has rounded corners (filled with a spot color and the background outside the corners is white.)
Can someone tell me if there's a simple way to color an image that has rounded corners using the imagecolorset function (or any other php method)?
I only want the non white areas of the image to be colored (In case you're wondering, I'm disallowing the color white to be applied to the image).
Note, perhaps a better way to do this would be to use a PNG image that has transparent background (rather than my gif image). If you think that's a better approach, please advise.
Here's the function that I'm working with...
function set_theme_color_header($hex)
{
$info = hexToRGB($hex); //calls a helper function which translates the hex to RGB
$img = imagecreatefromgif('header-template.gif'); //again, this could be a PNG image, but we always start with this image, then create a color copy
$color = imagecolorallocate($img, $info["red"], $info["green"], $info["blue"]);
imagecolorset($img, 0, $info["red"], $info["green"], $info["blue"]);
imagegif($img, 'header.gif'); //only problem is that the imagecolorset function creates a messy fill at the corners
}
GD does not handle gif's very well. I recommend creating a png image with your rounded corners, then use GD's imagefilter($img, IMG_FILTER_COLORIZE, $info["red"], $info["green"], $info["blue"], $alpha) function. Then save the image as a gif.
Alternatively, use php's imagick library to literally draw the image. imagick is about a billion times better than GD. Poorly documented, but...the basic stuff isnnt too hard. See the tut link below.
Search php.net for "imagick" to see all the functions.
imagick tutorial
i really do not not why you are doing this, but maybe have a look at phpTumb (and its demos here).