contactlist mysql query - php

Im making a codeigniter webapp where users can add each other in a contactslist.
The table looks like this:
`id` int(11) NOT NULL AUTO_INCREMENT,
`user_1` int(11) NOT NULL,
`user_2` int(11) NOT NULL,
`accepted` tinyint(2) NOT NULL,
PRIMARY KEY (`id`)
The userid for the user that makes the request to add the contact is always stored in user_1 column. The other users userid is stored in user_2. user_2 then has to accept the request and the 'accepted' column gets updated to 1.
I want to list all contacts that are accepted (WHERE accepted = 1) in a html table, and the contact requests (accepted = 0) in another.
My question is: How can i make a mysql query that selects all the rows and just get the userid from the contact? Its a problem since they can be in either user_1 or user_2 (Depending on if they requested or accepted).
Should i change the db table in some way to achieve this. Or could i make a query (active rcords preferably) that accomplish this?
Any help is appreciated
Thanks in advance
George
Update:
So the final query looks like this:
SELECT DISTINCT users.id, users.username, contacts.accepted
FROM users
LEFT JOIN contacts ON users.id = contacts.user_1
WHERE contacts.user_2 = ' . $this->session->userdata('user_id') . '
UNION DISTINCT
SELECT DISTINCT users.id, users.username, contacts.accepted
FROM users
LEFT JOIN contacts ON users.id = contacts.user_2
WHERE user_1 = ' . $this->session->userdata('user_id')
And works exactly as i described :)

Use a UNION query. See the documentation.
SELECT DISTINCT user_1 userid FROM user WHERE accepted = 1
UNION DISTINCT
SELECT DISTINCT user_2 userid FROM user WHERE accepted = 1
About the join, you'd use something like below for each part of the UNION
SELECT DISTINCT users.userid, users.username, contacts.accepted
FROM users
LEFT JOIN contacts ON users.userid = contacts.user_1
WHERE contacts.user_2 = ?

Shouldn't the contactlist be owned by the user?
create table Contactlist (
OwnerID int, -- ID of the owning User
ContactID int, -- ID of the contact User
Accepted bool)
-- With composite primary key on OwnerID, ContactID
This way the query would be
select * from User
left outer join Contactlist on User.ID = Contactlist.OwnerID
left outer join User as Contact on Contactlist.ContactID = Contact.ID
Sorry... Overthunk the select ;)
select * from Contactlist
inner join User on Contactlist.ContactID = User.ID
where Contactlist.OwnerID = <the querying users ID>
(MSSQL syntax)

You can use queries but it will create problems later on I guess as I have also faced this problem before. You can insert new entries in the same table when a user accepts the request and mark the new record as accepted but this time the user_1 becomes user_2 and vice versa.

Alias with joins is waht I think you are asking.
Something like.
Select c.id, uRequest.UserName, uRequested.UserName From Contacts c
inner join Users As uRequest On c.User_1 = uRequest.id
inner join Users As uRequested On c.User_2 = URequested.id
Where accepted = 1
will give you all contacts where the request has been accepted.

Related

PHP mysql how to join two tables to link name from one table and post from other table

So I am very bad at this anyway right now I have this code
$test = "SELECT `status`,`pubdate` FROM `status` ORDER BY `pubdate` DESC";
$stmt = $db->prepare($test);
$stmt->execute();
while($row = $stmt->fetch(PDO::FETCH_ASSOC)){
echo "<section class='statusar'>"."<article>";
echo $row['status'];
echo $row['pubdate'];
echo "</article></section>";
}
and it shows the post but now I want to take users first name from another table and display it with the post. How do I do it?
The two tables I have look like this
This is the table with the post
Status_id int unsigned auto_increment primary
user_id int unsigned index
status varchar(600)
pubdate datetime
This is the other table
user_id int unsigned auto_increment primary index
firstname varchar(30)
surname varchar(30)
username varchar(30) unique
password varchar(90)
I have done so they have a relation between the user_ids
EDIT
I think I figured it out because now it works :D
So now when I use
SELECT status, pubdate,firstname,surname FROM status INNER JOIN user ON status.user_id = user.user_id ORDER BY status.pubdate DESC
It displays all the things I want and I also tried
SELECT * FROM status INNER JOIN user ON status.user_id = user.user_id ORDER BY status.pubdate DESC";
Which also works thanks for the help guys :D
Just use an inner join:
SELECT s.status, s.pubdate, u.firstname
FROM status s
INNER JOIN usertable u ON s.user_id = u.user_id
ORDER BY s.pubdate DESC
A Visual Explanation of SQL Joins
This assumes the user_id exists in the usertable. If that might not be the case, you'd want to use an outer join instead.

SQL select query

I have these tables currently:
assignments(assignment_id, module_id, year, semester, title, number, weighting)
module(module_id, code, name, crn, course_title)
usermodule(usermodule_id, user_id, module_id)
users(user_id, title, first_name, last_name)
I was wondering if anyone could give me guidance on how to get the lecturer name, based on the module_id?
So far I've come up with:
SELECT `first_name` FROM `users` WHERE `assignments.module_id` = '$module_id';
I think I may have to do some form of JOIN query...
try this query
SELECT u.first_name FROM users u
LEFT JOIN usermodule um ON um.user_id = u.user_id
WHERE um.module_id = '$module_id';
How about
SELECT `first_name`
FROM `users` u INNER JOIN
`usermodule` um ON u.user_id = um.user_id
WHERE `um.module_id` = '$module_id';
Try rhis:
SELECT `first_name` FROM
`users` INNER JOIN `usermodule` ON `users.user_id`=`usermodule.user_id`
INNER JOIN `assignments` ON `usermodule.module_id` =`assignments.module_id`
WHERE `assignments.module_id` = '$module_id';
Just try below sql
SELECT `first_name` FROM `users` WHERE user_id = (select user_id from usermodule where module_id = '$module_id' limit 1))
I see poor structuring of your database.
You do not necessarily need a table usermodule to create relationships between the other tables.
If there is a relationship between a user and a module.
make use of a foreign key.
You could have a user_id in the module to link a user to a given module, then have 'module_id' in assignment to link a given assignment to a module, that way in the end, the user, module and assignment are related.
It will then be easy to use JOIN or simple select query

mysql: linking 2 tables with 2 different fields

I have a user table, e.g.
userId
userName
and I have a message table, e.g.
messageId
messageToId
messageFromId
messageContent
I am trying to make a query to pull a message, but also get the user names from the user table based on the messageToId and messageFromId.
I have done this before with only 1 field between tables, e.g.
SELECT message.*, user.userName
FROM message, user
WHERE user.userId = message.messageToId
AND messageId = (whatever)
But I am having trouble with 2 links.
I want the result as follows:
messageId
messageToId
toUserName
messageFromId
fromUserName
messageContent
Any help would be much appreciated, or if someone had another way of attempting a private message system with PHP/MySQL.
You just have to use joins and different table aliases:
SELECT m.*, u1.userName AS toUserName, u2.username AS fromUserName
FROM message m INNER JOIN user u1 ON m.messageToId = u1.userId
INNER JOIN user u2 ON m.messageFromId = u2.userId
WHERE messageId = "XXX";
You need to use a join from to achieve this:
SELECT `m`.*,
`to`.`userName` AS `to`,
`from`.`userName` AS `from`,
FROM `message` `m`
JOIN `user` `to` ON `m`.`messageToId` = `to`.`userId`
JOIN `user` `from` ON `m`.`messageFromId` = `from`.`userId`
WHERE `m`.`messageId` = 1
So you join against the user table twice to get both users for a particular message. To do this you need to use table aliases as I have done with to and from so that you distinguish between them.
I have also used a field alias to get their usernames separately eg:
`to`.`username` AS `from`
Will this work?
SELECT b.userName AS author, c.userName AS reciever, a.messageId, a.messageContent FROM message a JOIN user b ON a.messageFromId = b.userId JOIN user c ON a.messageToId = c.userId

MySQL how to display data from two tables

I'm trying to display the username of the person who has submitted the most articles but I don't know how to do it using MySQL & PHP, can someone help me?
Here is the MySQL code.
CREATE TABLE users (
user_id INT UNSIGNED NOT NULL AUTO_INCREMENT,
username VARCHAR(255) DEFAULT NULL,
pass CHAR(40) NOT NULL,
PRIMARY KEY (user_id)
);
CREATE TABLE users_articles (
id INT UNSIGNED NOT NULL AUTO_INCREMENT,
user_id INT UNSIGNED mNOT NULL,
title TEXT NOT NULL,
acontent LONGTEXT NOT NULL,
PRIMARY KEY (id)
);
Here is the code I have so far.
$mysqli = mysqli_connect("localhost", "root", "", "sitename");
$dbc = mysqli_query($mysqli,"SELECT COUNT(*) as coun, user_id
FROM users_articles
GROUP BY user_id
ORDER BY coun DESC
LIMIT 1");
If you want to get the user's name, you should use the next query:
SELECT users.name, COUNT(users_articles.id) AS coun
FROM users_articles
LEFT JOIN users_articles ON users.id=users_articles.user_id
GROUP BY users_articles.user_id
ORDER BY coun DESC
LIMIT 1
select u.user_id, count(ua.id) as num_articles
from users u
left outer join users_articles ua
on u.user_id = ua.user_id
group by u.user_id
order by num_articles desc
The left outer join (as opposed to an inner join) ensures that all users are represented in the result, no matter if they have a record in users_articles or not.
EDIT: Since you only want the person who has submitted the most articles, you do not necessarily need the left outer join (as long as there is at least one user who has written any articles). For a complete list, it would be useful, however.
Whichever above queries given by geeks u use just DO NOT FORGET TO INCLUDE "username" field in select query as none of them has included the username field
What you want to do is a join.
The SQL query you need is this:
SELECT COUNT(*) as coun, users.user_id, username
FROM users_articles
INNER JOIN users
ON users_articles.user_id = users.user_id
GROUP BY user_id
ORDER BY coun DESC
LIMIT 1
I tested this and it works.
The result table contains the number of articles of the user, its user id and its username.
use like this,
SELECT COUNT(users_articles.*) as coun, users_articles.user_id, users.username
FROM users_articles, users
WHERE users_articles.user_id = users.user_id
GROUP BY users.user_id
ORDER BY coun DESC
SELECT COUNT(*) as coun, user_id, users.username
FROM users_articles, users
WHERE users_articles.user_id = users.user_id
GROUP BY user_id
ORDER BY coun DESC
LIMIT 1

Retrieving the latest note (by timestamp) in a single query from a 1:n table

Let's say I have two tables, users and notes. Let's say the schemas look like this:
users
id, name, field2, field3
notes
id, user_id, subject, heading, body, timestamp
What I want to do is select every user, and the LATEST (just 1) note posted by each user based on the timestamp to show in an overview report.
How would I go about doing this? Please note that the DB is MySQL.
Thanks!
select users.name, notes.subject, notes.heading, notes.body
from users, notes
where users.id = notes.user_id
and notes.timestamp = (select max(timestamp) from notes where user_id = users.id)
select u.id, u.name, n.id as note_id, n.subject, n.heading, n.body, n.timestamp
from users u
left outer join (
select user_id, max(timestamp) as timestamp
from notes
group by user_id
) nm
left outer join notes n on nm.user_id = n.user_id and nm.timestamp = n.timestamp
Note that this could potentially return duplicates if the user has two notes with the exact same timestamp. I have assumed this is not the case.
SELECT *
FROM `users`
LEFT JOIN `notes`
ON `user_id` = `users`.`id`
WHERE `notes`.`timestamp` = (
SELECT MAX(`timestamp`)
FROM `notes` AS `notes_1`
WHERE `notes_1`.`user_id` = `notes`.`user_id`
)

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