Foreach returning errors - php

Question

I'm working with the yahoo api - and pretty much going off their example. BUT I'm getting errors such as: Invalid argument supplied for foreach()
Here is the actual foreach statement:
foreach ($data->query->results->result as $r){
// do something with the data
}
The entire code i'm running is here:
$c =curl_init("http://query.yahooapis.com/v1/public/yql?q=select%20*%20from%20local.search%20where%20state%3D'delaware'%20and%20city%20%3D%20'smyrna'%20and%20query%3D'pizza'&format=json");
curl_setopt($c, CURLOPT_RETURNTRANSFER, true);
curl_setopt($c, CURLOPT_CONNECTTIMEOUT, 20); // query times out after 20 seconds
$data = curl_exec($c); // I asked for data format to be in json in the query it appears to be returned decoded
//print_r($data);
$data = curl_exec($c);
if ($data === FALSE) {
die("Curl failed with error: " . curl_error($c));
}
$data = json_decode($data);
if (is_null($data)) {
die("json_decode failed with error: " . json_last_error());
}
foreach ($data->query->results->result as $r){
// do something with the data
}
$data is a decoded json response - it's got the data and it appears that my structure is right - i just want to loop through and display business names for example - but no go.

Answer 1

It should be $data->query->results->Result. Notice, the Uppercase Result.
To help you with JSON. Paste the whole JSON string into this utility, and see the tree structure visually.

Answer 2

json_decode requires you pass an extra boolean parameter if you want it to return an ARRAY rather than an object.
$data = json_decode($data,TRUE);
if (is_null($data)) {
die("json_decode failed with error: " . json_last_error());
}
foreach ($data['query']['results]'['Result'] as $r){
// do something with the data
}