For some reason, I keep getting XMLDoc is null, in firebug. I think that perhaps my program isn't parsing the XML that I am trying to generate (and that means I am likely not doing it correctly).
NOTE: I DO NOT WANT TO USE JQUERY HERE!
Here's my code that is supposed to generate the XML code:
<?php
$con = mysql_connect("localhost", "root", "");
if (!$con)
{
die('Could not connect: ' . mysql_error());
}
mysql_select_db("generic");
$rescult = mysql_query("SELECT * FROM culture order by cult_id");
if (!$rescult) {
die('Invalid query: ' . mysql());
}
$row = mysql_fetch_row($rescult);
ECHO "<item>";
ECHO "<item1>" . $row[0] . "</item1>" . "<br />";
ECHO "<item2>" . $row[1] . "</item2>" . "<br />";
ECHO "</item>";
?>
And here's my code that is supposed to parse it:
<html>
<header>
<script type="text/javascript">
if (window.XMLHttpRequest)
{ // Code for IE7+, Firefox, Chrome, Opera, Safari
xmlhttp = new XMLHttpRequest();
}
else
{
// Code for IE6, IE5
xmlhttp = new ActiveXObject("Microsoft.XMLHTTP");
}
xmlhttp.open("GET","testitout2.php",false);
xmlhttp.send();
xmlDoc = xmlhttp.responseXML;
document.getElementById("item1").value =
xmlDoc.getElementsByTagName("item1")[0].childNodes[0].nodeValue;
document.getElementById("item2").value =
xmlDoc.getElementsByTagName("item2")[0].childNodes[0].nodeValue;
</script>
</header>
<body>
<input type="text" id="item1">
<input type="text" id="item2">
</body>
</html>
Edit: I didn't notice the async flag. Guess my answer is irrelevant then.
You are trying to access XML before it was even loaded.
Set property onreadystatechange to xmlhttp:
xmlhttp.onreadystatechange = onStateChange;
function onStateChange() {
if (xmlhttp.readyState != 4) return; //4 means doc is ready
var xmlDoc = xmlhttp.responseXML;
}
You are using a wrong HTML tag: <header>...</header>.
Try replacing it with <head>...</head>, otherwise your script might be simply skipped by the browser.
Related
I want to refresh two variables named profittext and sumtext which will be refreshed and echoed in the following places every few seconds. I know AJAX is needed to do this but how do i actually make it work ? The only way i found out was to refresh the content of the whole file. is there any way to refresh specific variables? Any answers will be greatly appreciated . Thank you very very much.
<table>
if($profitandloss<$zero) {
$profitText = "<div style=\"color: red;\">$profitandloss</div>";
} elseif ($profitandloss>$zero) {
$profitText = "<div style=\"color: green;\">$profitandloss</div>";
}
// for profit and loss counting
$sum+= $profitandloss;
//
echo "<tr><td>" . $row['trade_id'] .
"</td><td>" . $row['selection'] .
"</td><td>" . $row['date'] .
"</td><td>" . $row['type'] .
"</td><td>" . $row['size'] .
"</td><td>" . $row['bidprice'] .
"</td><td>" . $row['offerprice'] .
"</td><td>" . $row['stoploss'] .
"</td><td>" . $row['takeprofit'] .
"</td><td>" . $profitText .
"</td><td><a href ='delete.php?id=".
$row['trade_id']."'>X</a>
</td></tr>";
$profitandloss=0;
if($sum<$zero) {
$sumText = "<div style=\"color: red;\">$sum</div>";
} elseif ($sum>$zero) {
$sumText = "<div style=\"color: green;\">$sum</div>";
}
}
echo "</table><br>";
?>
<!DOCTYPE html>
<html>
<table style="border:1px solid black;">
<tr>
<th style="border:1px solid black;">Profit/Loss</th>
</tr>
<tr>
<td style="border:1px solid black;"><?php echo $sumText ;?></td>
</tr>
</table>
</html>
I struggled with the concept of how to structure such code when I first started too. Although it's not specific to your particular variables, here's a quick example for how to update a var through AJAX with jQuery/PHP.
Prologue: If this is something you're going to be doing often, you'll want to learn jQuery, rather than using normal javascript alone. There are lots of great, free, resources on how to learn jQuery. Alternatively, if you're not satisfied with the free tutorials online, this is an excellent book. I'll write the example in jQuery.
Design: Okay, so the way it works is this:
Set a timer in javascript to execute a particular function every X seconds (you DO NOT want to do it every second).
That function makes an AJAX call (with jQuery) to a .PHP file on the server, sending it the data necessary so that the .PHP code knows what to send back.
The .PHP code grabs the data required (e.g., with MySQL) encodes it in a JSON format, and exits.
A promise on the AJAX call is fired and the data sent from PHP is received. Process it as you will.
Repeat from step 2.
If you have any questions about what the code is doing, please ask.
AJAX.PHP
<?php
$mysqli = new mysqli("localhost", "my_user", "my_password", "world");
$return_obj = array();
$request_obj = NULL;
// our AJAX call used "POST" as it's 'type', so we look in that
// variable.
if ( array_key_exists("func",$_POST) ) {
if ( $_POST['func'] === "get_update" ) {
if ( array_key_exists("which_var",$_POST) ) {
$which_var = $_POST['which_var'];
$which_var = $mysqli->real_escape_string($which_var); // should use prepared statements
// we sent 'num_people_logged_in' as our value here, so we'll be looking for a column/field
// with that value. this assumes that some other code, somewhere else,
// is regularly updating the table. it also assumes that there will only
// be a single row returned, which will hold the value.
$query = "SELECT '$which_var' FROM site_stats ";
if ( $result = $mysqli->query($query) ) {
if ( $row = $result->fetch_assoc() ) {
$request_obj[$which_var] = $row[$which_var];
}
}
}
}
}
$return_obj['request'] = $request_obj;
echo json_encode($return_obj);
die();
?>
MYCODE.JS
// this actually sends the AJAX request to the server.
function getUpdate() {
var jqXHR = $.ajax({
url : "ajax.php",
data : {
'func' : 'get_update',
'which_var' : 'num_people_logged_in'
},
dataType : 'json',
type : 'POST',
timeout : 10000
});
// attach 'promises' to the jqXHR object, which represents
// the AJAX call itself. 'promises' are, in this context,
// just events.
jqXHR.done(function(data,textStatus,jqXHR) {
// this executes if the AJAX call succeeded.
// the variable 'data' holds what the server
// sent us.
if ( ( data ) && ( data.request ) ) {
receiveUpdate(data.request);
}
});
jqXHR.fail(function(jqXHR,textStatus,errorThrown) {
// this executes if it failed
console.log("Fail: " + textStatus + " (" + errorThrown + ")");
});
jqXHR.always(function(a,textStatus,c){
// this executes either way, after .done or .fail
});
}
// this is called from jqXHR.done, on success
function receiveUpdate(request_obj) {
if ( request_obj.num_people_logged_in ) {
updateDOM(request_obj.num_people_logged_in);
}
}
function updateDOM(num_people_logged_in) {
if ( num_people_logged_in ) {
$("#mydiv > p.update").html("The updated value is: " + num_people_logged_in);
}
}
var timeoutID = null;
// setup our timer, to periodically make an
// AJAX call
function init() {
timeOutID = setInterval(function(){
getUpdate();
},5000);
}
// stop the timer
function cleanup() {
clearTimeout(timeoutID);
}
INDEX.HTML
<!DOCTYPE html>
<html>
<head>
<meta charset='utf-8'>
<title>AJAX practice</title>
<!-- <link href="mycss.css" rel='stylesheet'> if needed -->
<script src="http://code.jquery.com/jquery-1.9.1.js"></script>
<script src="mycode.js"></script>
<script>
$(document).ready(function() {
init();
$("#cleanup").on("click",function(){
cleanup();
});
}); // end ready
</script>
</head>
<body>
<div id='mydiv'>
<p>
How many people are online?
</p>
<p class='update'>
</p>
</div>
<button id='cleanup'>Stop updating!</button>
</div>
</body>
</html>
You will needd two PHP pages:
- one with HTML and JS, which periodicly makes ajax calls and puts the result to the HTML
- second with json (or even plain text) output of your dynamic data piece
Unfortunately, writing the full code in the answer is not someting that people do at stackoverflow, so just look at small example below, and try to figure out the missing parts.
http://jsfiddle.net/AMEqz/
var xhr = new XMLHttpRequest();
xhr.onload = function(r) {
// your render logic HERE
setTimeout(send, 1000);
}
function send() {
xhr.open("GET", "/", true);
xhr.send();
}
send();
p.s.: keep in mind that each ajax request will mean extra connection to your server, so make sure it can deal with the load ;)
Use a timer : https://developer.mozilla.org/en/docs/DOM/window.setInterval
setInterval(function(){
//update your var here
},1000);
This question already has answers here:
Error on IE 9 - 'SCRIPT600: Invalid target element for this operation
(3 answers)
Closed 9 years ago.
I am using a combination of PHP, AJAX, and MYSQLI to load suggestions of what a user is typing (fires off to load at each keypress). This is all working nicely in chrome, ie10, firefox, safari, etc. Then I tried it on IE9, and it just displayed "No Suggestions" (which I coded to do if it found no matches). My only thought was that it could be a caching issue that I read about on google, but on trying all the suggestions.. I ended up where I started.. "No Suggestions". So, I'm stumped. Here's the code for my AJAX:
function activelyLoad(passedInfo, insertInto, urlInLib)
{
if (passedInfo.length==0)
{
document.getElementById(insertInto).innerHTML="";
return;
}
if (window.XMLHttpRequest)
{// code for IE7+, Firefox, Chrome, Opera, Safari
xmlhttp=new XMLHttpRequest();
}
else
{// code for IE6, IE5
xmlhttp=new ActiveXObject("Microsoft.XMLHTTP");
}
xmlhttp.onreadystatechange=function()
{
if (xmlhttp.readyState==4 && xmlhttp.status==200)
{
document.getElementById(insertInto).innerHTML=xmlhttp.responseText;
}
}
xmlhttp.open("GET","../lib/"+urlInLib+"?q="+passedInfo,true);
xmlhttp.send();
}
And here's one of the PHP files I'm loading in:
<?php
include('config.inc.php');
header( 'Cache-Control: no-store, no-cache, must-revalidate' );
header( 'Pragma: no-cache' );
$full = $_GET['q'];
$fullAr = explode(" ", $full);
$count = count($fullAr);
$var = $fullAr[0];
$query = "SELECT * FROM StudentInfo WHERE (StudentFirstName LIKE '%$var%' OR StudentPrefferedName LIKE '%$var%' OR StudentLastName LIKE '%$var%')";
$response = "";
if ($count >= 2) {
$var2 = $fullAr[1];
$query = "SELECT * FROM StudentInfo WHERE ((StudentFirstName LIKE '%$var%' OR StudentPrefferedName LIKE '%$var%') AND StudentLastName LIKE '%$var2%') OR ((StudentFirstName LIKE '%$var2%' OR StudentPrefferedName LIKE '%$var2%') AND StudentLastName LIKE '%$var%')";
}
$result = mysqli_query($connection, $query);
$num_results = mysqli_num_rows($result);
if ($num_results > 0) {
while ($row = mysqli_fetch_array($result)) {
$id = $row['StudentID'];
$functionList = "\"activelyLoad($id, 'detDiv', 'addtable.php'),showElem('#details')\"";
$functionList2 = "\"logLoad($id), showElem('#contactDets')\"";
if(strcmp($row['StudentPrefferedName'], '') != 0){
$response .= ("<tr><td>" . $row['StudentFirstName'] . " \"" . $row['StudentPrefferedName'] . "\" " . $row['StudentLastName'] . "</td><td><button type='button' onmousedown=" . $functionList . " onclick=" . $functionList2 . ">Get details</button></td></tr>");
}
else{
$response .= ("<tr><td>" . $row['StudentFirstName'] . " " . $row['StudentLastName'] . "</td><td><button type='button' onmousedown=" . $functionList . " onclick=" . $functionList2 . ">Get details</button></td></tr>");
}
}
}
else $response = "No suggestions";
echo($response);
mysqli_close($connection);
?>
Here is the relevant HTML output of this page in IE9:
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<META HTTP-EQUIV=”Pragma” CONTENT=”no-cache”>
<title>XXXXXXX</title>
<script src="//ajax.googleapis.com/ajax/libs/jquery/1.10.1/jquery.min.js"></script>
<script src="../lib/searchScripts.js"></script>
</head>
<body>
<h1>XXXXXXXX</h1>
<p>Please select one of the following options:</p>
<ul>
<li><a id="searchLink" href="#" onclick="showElem('#search')">Search for a student</a></li>
<div id="search">
<p><b>To find a student, start typing a name in the input field below:</b></p>
<form>
Student Name: <input type="text" onkeyup="activelyLoad(this.value, 'txtHint', 'gethint.php'), showElem('#suggestions')">
</form>
<div id="suggestions"><h2>Suggestions:</h2> <div id="suggestionsBox"><table id="txtHint"><tr><td>No Suggestions</td></tr></table></div></div>
The only thing that makes me think it has to be a cache issue is that this WORKS on all modern up to date browsers. Any help is greatly appreciated.
EDIT IE9's console returns
SCRIPT600: Invalid target element for this operation. for 'document.getElementById(insertInto).innerHTML=xmlhttp.responseText;'
Is this my issue? How is it invalid? How is the browser able to get to the AJAX to load the "No Suggestions" if it errors out here?
Among many other issues you are trying to dump the AJAX results into a <table> element as the .innerHTML property.
Internet Explorer has a bug that won't let you set the content of a table tag via .innerHTML until the bug is fixed in IE10
Bug report: http://webbugtrack.blogspot.ca/2007/12/bug-210-no-innerhtml-support-on-tables.html
You would be better off to create a <div> and set the .innerHTML of that instead.
this is something I've been stuck on for around 7 hours total over the last 3 days, and it is driving me absolutely insane. Any assistance you could lend me with be greatly appreciated.
Basically I want to:
Call a PHP function on pageload which randomly selects a record from
my MySQL database
Dynamically display that record in a HTML page
(Once I've got that down, I also want to be able to trigger that this process on the click of a button.)
Before tackling this task, I put together a prototype which dynamically displays a specific record via a HTML dropdown menu: http://lrdondmt.com/week13/ajaxprototype1.html
I've been trying to modifications to this code to achieve the above.
My PHP looks like this:
<?php
// connect to database
$username= "**withheld**"'
$password="**withheld**";
$database="**withheld**";
$table="banddb";
mysql_connect(localhost,$username,$password);
#mysql_select_db($database) or die( "Unable to select database");
// the query itself, selects random record from database
$sql="SELECT * FROM banddb WHERE id >= (SELECT FLOOR( MAX(id) * RAND()) FROM quotes ) ORDER BY id LIMIT 1";
$result = mysql_query($sql);
// echo result
while($row = mysql_fetch_array($result))
{
echo '<b>Band name:</b> ' . $row['bandname'] . '</br></br>';
echo '<b>Location:</b> ' . $row['city'] . ', ' . $row['state'] . '</br></br>';
echo '<b>Image:</b> </br></br>' . '<img src="http://lrdondmt.com/discovermusic/images/' . $row['imgpath'] . '" />' . '</br></br>';
echo '<b>About the band: </b>' . $row['abouttheband'] . '</br></br>';
echo '<img src="http://www.lrdondmt.com/discovermusic/images/bandcamp-icon.png" alt="Find on the band on Bandcamp" />' . '</br></br>';
echo '<img src="http://www.lrdondmt.com/discovermusic/images/facebook-icon.png" alt="Find on the band on Facebook" />' . '</br></br>';
echo '<b>Bandcamp player:</b> </br></br>' . '<iframe width="300" height="100" id=bandcampplayer src="http://bandcamp.com/EmbeddedPlayer/v=2/album=' . $row['bandcampid'] . '/size=grande/bgcol=e9e9e9/linkcol=890101/" allowtransparency="true" frameborder="0" >' . '</br></br>';
}
echo "</table>";
// close connection
mysql_close();
?>
My HTML document looks like this:
<!DOCTYPE html>
<html>
<head>
<title>AJAX prototype 2</title>
<script type="text/javascript" >
function showRecord()
{
{
document.getElementById("txtHint").innerHTML="";
return;
}
if (window.XMLHttpRequest)
{// code for IE7+, Firefox, Chrome, Opera, Safari
xmlhttp=new XMLHttpRequest();
}
else
{// code for IE6, IE5
xmlhttp=new ActiveXObject("Microsoft.XMLHTTP");
}
if (xmlhttp.readyState==4 && xmlhttp.status==200)
{
document.getElementById("txtHint").innerHTML=xmlhttp.responseText;
}
xmlhttp.open("GET","getmusic2.php",true);
xmlhttp.send();
}
</script>
<script type="text/javascript" >
$(document).ready(function(showRecord))
</script>
</head>
<body>
<div id="txtHint">
<em>Your content should appear here.</em>
</div>
</body>
</html>
If you need any further info, please just ask.
Since you are already using jQuery, you could replace your whole showRecord() function with this more simple jQuery function :
$.ajax({
url: 'getmusic2.php',
success: function(data) {
$('#txtHint').html(data);
}
});
Also, your on load call should look like that :
$(document).ready(function() {
showRecord();
});
Your closure looks wrong when calling your ajax function, fix this line
$(document).ready(function(showRecord))
to look like this
$(document).ready(function(){showRecord()})
I have two dropdowns and I want the second dropdown to get populated on the basis of the data selected from the 1st dropdown
Here is my main.php:
<?php
include('connection.php');
$query_religion="SELECT DISTINCT religion FROM religion_caste_table";
$result_religion = mysql_query($query_religion, $con);
?>
<html>
<body>
<select name="religion" id="religion" style="width: 100px" onChange="showcaste(this.value)">
<?php
while($q_rel_data = mysql_fetch_array($result_religion))
{?>
<option value="<?php echo $q_rel_data[0]; ?>">
<?php echo $q_rel_data[0]; ?>
</option>
<?php }?>
</select>
<div id="view"></div>
<select name="caste" id="caste" style="width: 100px"></select>
</body>
</html>
And this is getcaste.php:
<?php
include('connection.php');
$string=$_GET["religion"];
$sql="SELECT caste FROM religion_caste_table WHERE religion = '".$string."'";
$result = mysql_query($sql,$con);
$myarray=array();
$str="";
while($result_caste=mysql_fetch_array($result))
{
$str=$str . "\"$result_caste[caste]\"".",";
}
$str=substr($str,0,(strLen($str)-1)); // Removing the last char , from the string
echo $str;/*Stop hiding from IE Mac */
//echo $string;
mysql_close($con);
?>
<html>
</html>
now for the javascript ajax file,(religion_caste.js)
function showcaste(string)
{
if (string=="")
{
document.getElementById("caste").innerHTML="";
return;
}
alert(string);
if (window.XMLHttpRequest)
{// code for IE7+, Firefox, Chrome, Opera, Safari
xmlhttp=new XMLHttpRequest();
}
else
{// code for IE6, IE5
xmlhttp=new ActiveXObject("Microsoft.XMLHTTP");
}
xmlhttp.onreadystatechange=function()
{
if (xmlhttp.readyState==4 && xmlhttp.status==200)
{
document.getElementById("view").innerHTML=xmlhttp.responseText;
//now how to catch the string from (getcaste.php), split it and save it into array
// and to populate the second dropdwn by the array;
}
}
xmlhttp.open("GET","getcaste.php?religion="+string,true);
xmlhttp.send();
}
For more better assistance, the database table contains two fields, religion and caste, where the first attribute is religion, and caste being the second.
If somehow I can catch the string str, then it could have solved the matter.
document.getElementById("view").InnerHTML=xmlhttp.responseText provides the string "str1","str2",... to be viewed in <div id="view">
But if I write the following code:
var string=(document.getElementById("view").InnerHTML);
alert(string);
Then a msgbox pops up with such view:
<meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1">
<title>Untitled Document</title>
"Catholic","Protestant"
If I could just get the string, I would be happy.
So in your place a would do a little remake in getcaste.php first - place all results from your query into an array and then use implode to get a string using delimiter - ;. (Optionaly you could use a json and decode it in js). In religion_caste.js use split to get an array back from it (; as delimiter);
Now use for cycle to cycle through all values, and every cycle add one option into select
example:
var select = document.getElementById("caste");
for (var key in values)
{
var OptNew = document.createElement('option');
OptNew.text = values[key];
OptNew.value = key;
try
{
select.add(OptNew, null); // doesn't work in IE
}
catch(ex)
{
select.add(OptNew); // IE only
}
}
Edit:
so json in php is easy - json_encode
json in js is a little bit more difficult. New browsers should support JSON.parse, for old ones you have to use this code(Not 100% sure here since I always use jQuery). Alternatively you could use jQuery and jQuery.parseJSON
This question already has answers here:
Closed 10 years ago.
Possible Duplicate:
mysql_fetch_array() expects parameter 1 to be resource, boolean given in select
I'm trying to learn how to use AJAX correctly with PHP and MySQL. I've seen other people's posts on this site regarding the same example I'm working with, but I haven't seen anything about the same issues I'm having.
The site holding the source code is PHP - AJAX and PHP.The site I have hosting my code is here.
The first link has a working example and the second link shows you the error I'm trying to figure out.
I tried to use mysqli, but it said something about expecting two parameters, so I changed it back. If anyone has suggestions on how to get it to work, I'd greatly appreciate it.
Error: mysql_fetch_array() expects parameter 1 to be resource, null given in /data/multiserv/users/748953/projects/1801445/www/test/getuser.php on line 24
The html code:
<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN">
<html>
<head>
<meta http-equiv="content-type" content="text/html; charset=utf-8">
<title>Ajax-PHP/MySQL Cooperation Test</title>
<script type="text/javascript">
function showUser(str)
{
if (str=="")
{
document.getElementById("txtHint").innerHTML="";
return;
}
if (window.XMLHttpRequest)
{// code for IE7+, Firefox, Chrome, Opera, Safari
xmlhttp=new XMLHttpRequest();
}
else
{// code for IE6, IE5
xmlhttp=new ActiveXObject("Microsoft.XMLHTTP");
}
xmlhttp.onreadystatechange=function()
{
if (xmlhttp.readyState==4 && xmlhttp.status==200)
{
document.getElementById("txtHint").innerHTML=xmlhttp.responseText;
}
}
xmlhttp.open("GET","getuser.php?q="+str,true);
xmlhttp.send();
}
</script>
</head>
<body>
<form>
<select name="users" onchange="showUser(this.value)">
<option value="">Select a person:</option>
<option value="1">Peter Griffin</option>
<option value="2">Lois Griffin</option>
<option value="3">Glenn Quagmire</option>
<option value="4">Joseph Swanson</option>
</select>
</form>
<br />
<div id="txtHint">Person info will be listed here.</div>
</body>
</html>
PHP:
<?php
$q=$_GET["q"];
include("dbinfo.inc.php");
$con = mysql_connect(localhost, $username, $password);
if (!$con)
{
die('Could not connect: ' . mysql_error());
}
mysql_select_db($database, $con);
$resul1 = mysql_query('SELECT * FROM `ajax_demo` WHERE id = \'\".$q.\"\'') or die(mysql_error());
echo "<table border='1'>
<tr>
<th>Firstname</th>
<th>Lastname</th>
<th>Age</th>
<th>Hometown</th>
<th>Job</th>
</tr>";
while($row = mysql_fetch_array($result))
{
echo "<tr>";
echo "<td>" . $row['FirstName'] . "</td>";
echo "<td>" . $row['LastName'] . "</td>";
echo "<td>" . $row['Age'] . "</td>";
echo "<td>" . $row['Hometown'] . "</td>";
echo "<td>" . $row['Job'] . "</td>";
echo "</tr>";
}
echo "</table>";
mysql_close($con);
?>
You have a spelling mistake you are assigning value in $resul1 and using mysql_fetch_array($result) notice $result
first try to check the data of $q
and after that try with this query:
mysql_query("SELECT * FROM `ajax_demo`
WHERE id = '" . mysql_real_escape_string($q) ."'");
You have a spelling mistake you are assigning value in $resul1 and using mysql_fetch_array($result) notice $result.
change your while statement into this:
while($row = mysql_fetch_array($result1))
Edit:
Make sure to always review your code and always use a consistent naming convention, the error indicated by the server is already enough to detect to which part of the program the issue is occuring (no need to run any other function if you want to have a complete debugging settings for you development server set it up on the configuration files instead of doing it on the application itself but turn it off for the live server for security purposes).
"Error: mysql_fetch_array() expects parameter 1 to be resource, null given in /data/multiserv/users/748953/projects/1801445/www/test/getuser.php on line 24"
which means that the error is happening on line 24 of the file "/data/multiserv/users/748953/projects/1801445/www/test/getuser.php" and that the variable on the first parameter you have used on the function "mysql_fetch_array" is the one causing the problem because of the statement "expects parameter 1 to be resource" so you should go directly to which part of the program this error is pointing which is helpful for any programmer. ;)
Change $resul1 to $result1, you did wrote wrong there.