I get text from a website via CURL however it has on the end on the original website, however when I return it back to mine, this is just a space(after looking at it in the source), however nothing seems to help even with str_replace, (string), strval() and so on.
Could anyone help?
Current code
$country = $s->fetchBetween('<dt>Country:</dt><dd>','</dd>', $result);
$country = strval($country);
$country = str_replace(" ", "", strval($country));
echo "start-{$country}-end";
exit;
The value on the website that I'm "Curling" appears as
India
Try the following instead.
$country = str_replace(" ", "", strval($country));
Try this out.
$string = 'x x ';
$pattern = '/ /';
echo preg_replace($pattern, '', $string);
Related
I have a strange problem with a simple preg_replace, if I use
$pattern = '/<div class="formula">(.*?)<\/div>/';
$str = preg_replace($pattern, "", $str);
not work correctly, nothing is replaced....if I put a static string instead of $str all work correctly.
string(2133) "Velocità: <div class="formulaTex">...</div><div class="formula">...</div>
why?there is some kind of encoding to use?
if I pass the var to preg_replace not work, if I pass the static string it work!
this is my code:
$db = new PDO('sqlite:ARGOMENTI_NEW.sqlite');;
$result = $db->query("SELECT * FROM Testi WHERE IDSezione = 100");
while($row = $result->fetchAll(PDO::FETCH_ASSOC)){
$pattern = '/<div class="formula">(.*?)<\/div>/';
$str = preg_replace($pattern, "", $row[0]["Testo"]);
echo $str . "<br/><br/><br/>";
}
thanks
I find the error, the string from sql query stamp encoded html entity, on the screen I see the correct string but real string have different characters....this is the problem! whit this I solve:
$str = preg_replace( "/\r|\n/", "", html_entity_decode($row[0]["Testo"]));
I want to replace a section of a string based that starts with one string and ends with another, and I want the section between also replaced. I think this is possible using regex but I cant' seem to find any decent examples showing this.
For Example:
I have "http://www.website.com" and I want to replace from "www" to "com" with "123xyz".
So"http://www.website.com/something" becomes "http://123xyz/something.
I am assuming I have to use preg_replace(), and I think the regex should start with "^www" and end with "com$", but I cant seem to get a grasp of the syntax of regex enough to create the desired effect.
please help
With reference to your example , you can try like this
$string = 'http://www.website.com/something';
$pattern = '/www(.*)com/';
$replacement = '123xyz';
echo preg_replace($pattern, $replacement, $string);
$phrase = "http://www.website.com";
$phraseWords = array("www", "com");
$replaceTo = array("123xyz", "something");
$result = str_replace($phraseWords, $replaceTo, $phrase);
echo $result;
Thanks so much to both #CodingAnt and #PHPWeblineindia for your great answers. Using #CodingAnt's answer (and some more research I did online) I wrote this function:
function replaceBetween(&$target, $from, $to, $with){
if(strpos($target, $from)===false)return false;
$regex = "'".$from."(.*?)".$to."'si";
preg_match_all($regex, $target, $match);
$match = $match[1];
foreach($match as $m) $target = str_replace($from.$m.$to, $with, $target);
return $target;
}
It seems to work pretty well. I hope someone finds this useful.
I want to ignore a specific character using php. So when a user adds this character in the textbox. the php scripts filters it out first. I tried something and came up with this:
<?php
$datetogoto = $_GET['datetogoto'];
$pattern = '-';
$replace = '';
preg_replace($pattern, $replace, $datetogoto);
header('Location: ../index.php?newsdate='.$datetogoto);
?>
So what it wrong with this code?
Can you try using str_replace
$datetogoto = $_GET['datetogoto'];
$datetogoto = str_replace("-","", $datetogoto);
Ref: http://us1.php.net/str_replace
Or , if you want get date format whatever you sent in query string, then use urlencode()
header('Location: ../index.php?newsdate='.urlencode($datetogoto));
PHP regex needs delimiters, so use it like this:
$pattern = '/-/';
OR else use str_replace:
str_replace('-', $replace, $datetogoto);
I have a small problem. I am tryng to convert a string like "1 234" to a number:1234
I cant't get there. The string is scraped fro a website. It is possible not to be a space there? Because I've tried methods like str_replace and preg_split for space and nothing. Also (int)$abc takes only the first digit(1).
If anyone has an ideea, I'd be greatefull! Thank you!
This is how I would handle it...
<?php
$string = "Here! is some text, and numbers 12 345, and symbols !£$%^&";
$new_string = preg_replace("/[^0-9]/", "", $string);
echo $new_string // Returns 12345
?>
intval(preg_replace('/[^0-9]/', '', $input))
Scraping websites always requires specific code, you know how you receive the input - and you write code that is required to make it usable.
That is why first answer is still str_replace.
$iInt = (int)str_replace(array(" ", ".", ","), "", $iInt);
$str = "1 234";
$int = intval(str_replace(' ', '', $str)); //1234
I've just came into the same issue, however the answer that was provided wasn't covering all the different cases I had...
So I made this function (the idea popped in my mind thanks to Dan) :
function customCastStringToNumber($stringContainingNumbers, $decimalSeparator = ".", $thousandsSeparator = " "){
$numericValues = $matches = $result = array();
$regExp = null;
$decimalSeparator = preg_quote($decimalSeparator);
$regExp = "/[^0-9$decimalSeparator]/";
preg_match_all("/[0-9]([0-9$thousandsSeparator]*)[0-9]($decimalSeparator)?([0-9]*)/", $stringContainingNumbers, $matches);
if(!empty($matches))
$matches = $matches[0];
foreach($matches as $match):
$numericValues[] = (float)str_replace(",", ".", preg_replace($regExp, "", $match));
endforeach;
$result = $numericValues;
if(count($numericValues) === 1)
$result = $numericValues[0];
return $result;
}
So, basically, this function extracts all the numbers contained inside of a string, no matter how many text there is, identifies the decimal separator and returns every extracted number as a float.
One can specify what decimal separator is used in one's country with the $decimalSeparator parameter.
Use this code for removing any other characters like .,:"'\/, !##$%^&*(), a-z, A-Z :
$string = "This string involves numbers like 12 3435 and 12.356 and other symbols like !## then the output will be just an integer number!";
$output = intval(preg_replace('/[^0-9]/', '', $string));
var_dump($output);
Hi all i know preg_replace can be used for formatting string but i need help in that concerned area my url will be like this
http://www.example.com/index.php/
also remove the http,https,ftp....sites also
what i want is to get
result as
example.com/index.php
echo preg_replace("~(([a-z]*[:](//))|(www.))~", '', "ftp://www.example.com");
$url = 'http://www.example.com/index.php/';
$strpos = strpos($url,'.');
$output = substr($url,$strpos+1);
$parts=parse_url($url);
unset($parts['scheme']);
//echo http_build_url($parts);
echo implode("",$parts);
EDIT
To use http_build_url you needs pecl_http you can use implode as alternate
Something like this
$url = "http://www.example.com/index.php";
$parts = parse_url($url);
unset($parts['scheme']);
echo preg_replace('/^((ww)[a-z\d][\x2E])/i', '', join('', $parts));
Output
example.com/index.php
Example #2
$url = "http://ww3.nysif.com/Workers_Compensation.aspx";
Output
nysif.com/Workers_Compensation.aspx