mysql_fetch_row not returning full array - php

Question

I am attempting to loop through rows in MySQL with the following code. Unfortunately, the mysql_fetch_row function is only returning the first row of my query (I confirmed this with print_r). When I use mysql_num_rowsit returns the correct number of rows for that query(2). Any idea why mysql_fetch_row is returning only the first row?
$query = 'SELECT firstName FROM profiles WHERE city="Phoenix" and lastName ="Smith"';
$result = mysql_query($query);
$row = mysql_fetch_row($result);
print_r($row); //This returns only 1 array item: Array ( [0] => John)
$a=mysql_num_rows($result);
print_r($a); //This returns 2
I have also run the same query in MySQL and it returns both rows ("John" and "Jim").
Thanks for the help.

Answer 1

Just perform mysql_fetch_row twice (or in a loop). By definition (if you read the documentation) it returns only one row at once. So:
while ($row = mysql_fetch_row($result)) {
var_dump($row);
}

Answer 2

You want to put it in a while loop:
while ($row = mysql_fetch_array($result)) {
$firstName = $row['firstName'];
echo("$firstName<br />");
}
What this does is for each result (row) it finds, it fetches the data you want and displays it. So it gets the first result, displays the name, loops back to the top, fetches the second result, displays that name and so on, then once you have no more results that match the query criteria, the while loop is ended.

Answer 3

PHP accesses the SQL Results in order of how they're buffered. You'll need to run a loop to access all the contents.
If you wish to load everything into an array:
$allRows=array();
while($row=mysql_fetch_assoc($result) {
$allRows[]=$row;
}

Answer 4

You can use any of the following one:
while ($row = mysql_fetch_array($result))
{
echo $row['firstName'];
}
or
while ($row = mysql_fetch_assoc($result))
{
echo $row['firstName'];
}
or
while ($row = mysql_fetch_object($result))
{
echo $row->firstName;
}