add active class to menu links using php - php

Question

<div class="menu clearfix">
<ul>
<li>start</li>
<li>rating</li>
<li>upload</li>
</ul>
Was a while since i used php. Is there any smart way to do a foreach in php and render this menu + an "active" class to the clicked link. So if the active page is "rating", the html would render:
<div class="menu clearfix">
<ul>
<li>start</li>
<li>rating</li>
<li>upload</li>
</ul>
Thanks

Answer 1

Assuming the $_GET value of p would be rating (or any other link in the menu for that matter), one could do something like this:
<?php
echo "<div class=\"menu clearfix\">";
echo "<ul>";
$links = array('rating', 'upload', 'about');
foreach ($links as $link) {
$active = "";
if (!empty($_GET['p']) && $link == $_GET['p']){
$active = 'class="active"';
}
echo "<li><a href=\"./?p=$link\" $active>$link</a></li>";
}
echo "</ul></div>"
?>

Answer 2

As far as I understand you want to know which li is active after request.
If it is - you have to get $_GET parameter smth like $_GET['p'].
And do rendering, smth like:
foreach($ul as $li)
{
if ($_GET['p'] == $li->code)
echo 'class="active"';
}
For example:
<div class="menu clearfix">
<ul>
<?php foreach($ul as $li): ?>
<li><a href="<?php echo $li->url;?>" <?php echo $_GET['p']==$li->get ? class="active" : ''?>><?php echo $li->name;?></a></li>
<?php endforeach; ?>
</ul>

Answer 3

<ul class="sub-nav" >
<?php
$full_name = $_SERVER['PHP_SELF'];
$name_array = explode('/',$full_name);
$count = count($name_array);
$page_name = $name_array[$count-1];
?>
<li><a class="<?php echo ($page_name=='where-to-buy.php')?'active':'';?>" href="where-to-buy.php">WHERE TO BUY</a></li>
<li><a class="<?php echo ($page_name=='about.php')?'active':'';?>" href="about.php">ABOUT US</a></li>
<li><a class="<?php echo ($page_name=='contact.php')?'active':'';?>" href="contact.php">CONTACT US</a></li>
Please follow below URL to live demo...
https://webdesignerhut.com/active-class-navigation-menu/