Wrap an element for each set of elements with SimpleXML/DOMDocument - php

I have the code below to create a XML file
<?php
try
{
$dom = new domDocument;
$dom->formatOutput = true;
$root = $dom->appendChild($dom->createElement( "items" ));
$sxe = simplexml_import_dom( $dom );
$sxe->addChild("model", "HTC Desire");
$sxe->addChild("model", "Motorola Atrix");
echo $sxe->asXML();
}
catch( Exception $e )
{
echo $e->getMessage();
}
?>
While execute this code, it will generate the content likes:
<?xml version="1.0"?>
<items>
<model>HTC Desire</model>
<model>Motorola Atrix</model>
</items>
But, I would like to wrap an element called item for each model, the result should be:
<?xml version="1.0"?>
<items>
<item><model>HTC Desire</model></item>
<item><model>Motorola Atrix</model></item>
</items>
Anyone could suggest how to do this?

The addChild method returns a SimpleXMLElement object representing the child added to the XML node. This allows for method chaining like so:
try
{
$dom = new domDocument;
$dom->formatOutput = true;
$root = $dom->appendChild($dom->createElement( "items" ));
$sxe = simplexml_import_dom($dom);
$sxe->addChild("item")->addChild("model", "HTC Desire");
$sxe->addChild("item")->addChild("model", "Motorola Atrix");
echo $sxe->asXML();
}
catch( Exception $e )
{
echo $e->getMessage();
}

Related

Replace HTML tags with DOMdocument while keeping nested tags [duplicate]

I'm trying to figure out how to rename a node in XML using PHP?
I Have come this far:
$dom = new DOMDocument( '1.0' );
$dom->preserveWhiteSpace = false;
$dom->formatOutput = true;
// load the xml file
$dom->loadXML( '<?xml version="1.0" encoding="ISO-8859-1"?>
<library>
<data>
<invite>
<username>jmansa</username>
<userid>1</userid>
</invite>
<update>1</update>
</data>
</library>', LIBXML_NOBLANKS );
$xpath = new DOMXPath($dom);
//find all 'data' nodes.
$node = $xpath->query("//data");
// if found
if( $node->length ) {
foreach ($node as $n) {
// RENAME HERE? //
}
}
echo "<xmp>". $dom->saveXML() ."</xmp>";
Now, I want to rename <data> to <invites>. Can this be done and if yes, how?
A Node's name ("data" or "invites" respectively) cannot be renamed via the DOM because the Node::nodeName property is read-only.
You can create a new node named "invites", append it before the "data" node, move the children of "data" to the new "invites" node, remove the "data" node, and then output the tree to get your result.
Example:
<?php
// Create a test document.
$dom = new DOMDocument( '1.0' );
$dom->preserveWhiteSpace = false;
$dom->formatOutput = true;
// Load the xml file.
$dom->loadXML('<?xml version="1.0" encoding="ISO-8859-1"?'.'>
<library>
<data attr1="1" attr2="2">
<invite>
<username>jmansa</username>
<userid>1</userid>
</invite>
<update>1</update>
</data>
</library>', LIBXML_NOBLANKS );
$xpath = new DOMXPath($dom);
// Convert <data> to <invites>.
if ($dataNode = $xpath->query("/library/data")->item(0))
{
// Create the <invites> node.
$invitesNode = $dom->createElement('invites');
$dataAttrs = $dataNode->attributes;
foreach ($dataAttrs as $dataAttr)
{ $invitesNode->setAttributeNodeNS($dataAttr->cloneNode()); }
$dom->documentElement->appendChild($invitesNode);
// Move the <data> children over.
if ($childNodes = $xpath->query("/library/data/*"))
{
foreach ($childNodes as $childNode)
{ $invitesNode->appendChild($childNode); }
}
// Remove <data>.
$dataNode->parentNode->removeChild($dataNode);
}
// Test the result.
echo $dom->saveXML();
?>
My solution, with extended test case:
// Changes the name of element $element to $newName.
function renameElement($element, $newName) {
$newElement = $element->ownerDocument->createElement($newName);
$parentElement = $element->parentNode;
$parentElement->insertBefore($newElement, $element);
$childNodes = $element->childNodes;
while ($childNodes->length > 0) {
$newElement->appendChild($childNodes->item(0));
}
$attributes = $element->attributes;
while ($attributes->length > 0) {
$attribute = $attributes->item(0);
if (!is_null($attribute->namespaceURI)) {
$newElement->setAttributeNS('http://www.w3.org/2000/xmlns/',
'xmlns:'.$attribute->prefix,
$attribute->namespaceURI);
}
$newElement->setAttributeNode($attribute);
}
$parentElement->removeChild($element);
}
function prettyPrint($d) {
$d->formatOutput = true;
echo '<pre>'.htmlspecialchars($d->saveXML()).'</pre>';
}
$d = new DOMDocument( '1.0' );
$d->loadXML('<?xml version="1.0"?>
<library>
<data a:foo="1" x="bar" xmlns:a="http://example.com/a">
<invite>
<username>jmansa</username>
<userid>1</userid>
</invite>
<update>1</update>
</data>
</library>');
$xpath = new DOMXPath($d);
$elements = $xpath->query('/library/data');
if ($elements->length == 1) {
$element = $elements->item(0);
renameElement($element, 'invites');
}
prettyPrint($d);
By the way, I added this solution as a comment to the PHP documentation for DOMElement.

Rename an XML node using PHP

I'm trying to figure out how to rename a node in XML using PHP?
I Have come this far:
$dom = new DOMDocument( '1.0' );
$dom->preserveWhiteSpace = false;
$dom->formatOutput = true;
// load the xml file
$dom->loadXML( '<?xml version="1.0" encoding="ISO-8859-1"?>
<library>
<data>
<invite>
<username>jmansa</username>
<userid>1</userid>
</invite>
<update>1</update>
</data>
</library>', LIBXML_NOBLANKS );
$xpath = new DOMXPath($dom);
//find all 'data' nodes.
$node = $xpath->query("//data");
// if found
if( $node->length ) {
foreach ($node as $n) {
// RENAME HERE? //
}
}
echo "<xmp>". $dom->saveXML() ."</xmp>";
Now, I want to rename <data> to <invites>. Can this be done and if yes, how?
A Node's name ("data" or "invites" respectively) cannot be renamed via the DOM because the Node::nodeName property is read-only.
You can create a new node named "invites", append it before the "data" node, move the children of "data" to the new "invites" node, remove the "data" node, and then output the tree to get your result.
Example:
<?php
// Create a test document.
$dom = new DOMDocument( '1.0' );
$dom->preserveWhiteSpace = false;
$dom->formatOutput = true;
// Load the xml file.
$dom->loadXML('<?xml version="1.0" encoding="ISO-8859-1"?'.'>
<library>
<data attr1="1" attr2="2">
<invite>
<username>jmansa</username>
<userid>1</userid>
</invite>
<update>1</update>
</data>
</library>', LIBXML_NOBLANKS );
$xpath = new DOMXPath($dom);
// Convert <data> to <invites>.
if ($dataNode = $xpath->query("/library/data")->item(0))
{
// Create the <invites> node.
$invitesNode = $dom->createElement('invites');
$dataAttrs = $dataNode->attributes;
foreach ($dataAttrs as $dataAttr)
{ $invitesNode->setAttributeNodeNS($dataAttr->cloneNode()); }
$dom->documentElement->appendChild($invitesNode);
// Move the <data> children over.
if ($childNodes = $xpath->query("/library/data/*"))
{
foreach ($childNodes as $childNode)
{ $invitesNode->appendChild($childNode); }
}
// Remove <data>.
$dataNode->parentNode->removeChild($dataNode);
}
// Test the result.
echo $dom->saveXML();
?>
My solution, with extended test case:
// Changes the name of element $element to $newName.
function renameElement($element, $newName) {
$newElement = $element->ownerDocument->createElement($newName);
$parentElement = $element->parentNode;
$parentElement->insertBefore($newElement, $element);
$childNodes = $element->childNodes;
while ($childNodes->length > 0) {
$newElement->appendChild($childNodes->item(0));
}
$attributes = $element->attributes;
while ($attributes->length > 0) {
$attribute = $attributes->item(0);
if (!is_null($attribute->namespaceURI)) {
$newElement->setAttributeNS('http://www.w3.org/2000/xmlns/',
'xmlns:'.$attribute->prefix,
$attribute->namespaceURI);
}
$newElement->setAttributeNode($attribute);
}
$parentElement->removeChild($element);
}
function prettyPrint($d) {
$d->formatOutput = true;
echo '<pre>'.htmlspecialchars($d->saveXML()).'</pre>';
}
$d = new DOMDocument( '1.0' );
$d->loadXML('<?xml version="1.0"?>
<library>
<data a:foo="1" x="bar" xmlns:a="http://example.com/a">
<invite>
<username>jmansa</username>
<userid>1</userid>
</invite>
<update>1</update>
</data>
</library>');
$xpath = new DOMXPath($d);
$elements = $xpath->query('/library/data');
if ($elements->length == 1) {
$element = $elements->item(0);
renameElement($element, 'invites');
}
prettyPrint($d);
By the way, I added this solution as a comment to the PHP documentation for DOMElement.

How to delete a specific element from xml file

I want to delete:
<newWord>
<Heb>צהוב</Heb>
<Eng>yellow</Eng>
</newWord>
from:
<?xml version="1.0" encoding="UTF-8"?>
<xml>
<newWord>
<Heb>מילה ראשונה</Heb>
<Eng>first word</Eng>
</newWord>
<newWord>
<Heb>צהוב</Heb>
<Eng>yellow</Eng>
</newWord>
</xml>
so the output will be:
<?xml version="1.0" encoding="UTF-8"?>
<xml>
<newWord>
<Heb>מילה ראשונה</Heb>
<Eng>first word</Eng>
</newWord>
</xml>
I try to find the tag <newWord> and after this to go to child of it <Eng>yellow</Eng>
and if i found it by $searchString = 'yellow'; I should need to go to parrent of it and delete the element <newWord>.
I try to do it by the following code but I do not know ho to go to child of the <newWord>. many thx for helping.
this my code:
<?php
$del=true;
if ($del==TRUE){
$searchString = 'yellow';
header('Content-type: text/xml; charset=utf-8');
$xml = simplexml_load_file('./Dictionary_user.xml');
foreach($xml->children() as $child){
if($child->getName() == "newWord") {
if($searchString == $child['Eng']) {
$dom->parentNode->removeChild($xml);
} else {
echo('no match found resualt');
}
}
}
$dom = new DOMDocument;
$dom->preserveWhiteSpace = FALSE;
$dom->formatOutput = true;
$dom->load('Dictionary_user.xml');
$dom->save("Dictionary_user.xml");
$dom->saveXML();
header('Location: http://127.0.0.1/www/www1/ajax/ajax4/workwell/popus1.html');
}
?>
Try this:
$searchString = 'yellow';
$xml = simplexml_load_file('./Dictionary_user.xml');
foreach($xml->children() as $child){
if($child->getName() == "newWord") {
if($child->Eng == $searchString){
$dom = dom_import_simplexml($child);
$dom->parentNode->removeChild($dom);
}
}
}
echo $xml->asXML();
On this line
if($searchString == $child['Eng']) {
You're trying to compare the body of the child node, but it doesn't convert to a string automatically. It's still a SimpleXMLElement object, so the comparison fails.
Try explicitly casting it to a string to get the body of the tag.
if($searchString == (string)$child['Eng']) {

Need to show child data on parent id

i'm struggling with Xpath, i have an xml list and i need to get the child data based on the parent id ...
My xml file :
<projecten>
<project id="1">
<titel>Shop 1</titel>
<siteurl>http://test.be</siteurl>
<screenshot>test.jpg</screenshot>
<omschrijving>comment 1</omschrijving>
</project>
<project id="2">
<titel>Shop 2</titel>
<siteurl>http://test2.be</siteurl>
<screenshot>test2.jpg</screenshot>
<omschrijving>comment</omschrijving>
</project>
</projecten>
the code i use to get for example the project 1 data (does not work):
$xmlDoc = new DOMDocument();
$xmlDoc->load(data.xml);
$xpath = new DOMXPath($xmlDoc);
$projectId = '1';
$query = '//projecten/project[#id='.$projectId.']';
$details = $xpath->query($query);
foreach( $details as $detail )
{
echo $detail->titel;
echo $detail->siteurl;
echo $detail->screenshot;
echo $detail->omschrijving;
}
But this does not show anything, if someone can point me out ... thanks
In addition to the solution already given you can also use:
foreach ($xpath->query(sprintf('/projecten/project[#id="%d"]', $id)) as $projectNode) {
echo
$projectNode->getElementsByTagName('titel')->item(0)->nodeValue,
$projectNode->getElementsByTagName('siteurl')->item(0)->nodeValue,
$projectNode->getElementsByTagName('screenshot')->item(0)->nodeValue,
$projectNode->getElementsByTagName('omschrijving')->item(0)->nodeValue;
}
or fetch the DOMText node values directly with Xpath
foreach ($xpath->query(sprintf('/projecten/project[#id="%d"]', $id)) as $projectNode) {
echo
$xpath->evaluate('string(titel)', $projectNode),
$xpath->evaluate('string(siteurl)', $projectNode),
$xpath->evaluate('string(screenshot)', $projectNode),
$xpath->evaluate('string(omschrijving)', $projectNode);
}
or import the node to SimpleXml
foreach ($xpath->query(sprintf('/projecten/project[#id="%d"]', $id)) as $projectNode) {
$detail = simplexml_import_dom($projectNode);
echo
$detail->titel,
$detail->siteurl,
$detail->screenshot,
$detail->omschrijving;
}
or even concatenate all the values directly in the XPath:
$xpath = new DOMXPath($dom);
echo $xpath->evaluate(
sprintf(
'concat(
/projecten/project[#id = %1$d]/titel,
/projecten/project[#id = %1$d]/siteurl,
/projecten/project[#id = %1$d]/screenshot,
/projecten/project[#id = %1$d]/omschrijving
', $id
)
);
Accessing the child nodes as you do:
echo $detail->title;
Is not valid, if you use DOM* functions. This would probably work if you were using SimpleXML.
For DOM* try this:
$dom = new DOMDocument;
$dom->loadXml('<projecten>
<project id="1">
<titel>Shop 1</titel>
<siteurl>http://test.be</siteurl>
<screenshot>test.jpg</screenshot>
<omschrijving>comment 1</omschrijving>
</project>
<project id="2">
<titel>Shop 2</titel>
<siteurl>http://test2.be</siteurl>
<screenshot>test2.jpg</screenshot>
<omschrijving>comment</omschrijving>
</project>
</projecten>
');
$id = 2;
$xpath = new DOMXPath($dom);
foreach ($xpath->query(sprintf('/projecten/project[#id="%s"]', $id)) as $projectNode) {
// repeat this for every needed node
$titleNode = $xpath->query('titel', $projectNode)->item(0);
if ($titleNode instanceof DOMElement) {
echo $titleNode->nodeValue;
}
// or us a loop for all child nodes
foreach ($projectNode->childNodes as $childNode) {
echo $childNode->nodeValue;
}
}

php domdocument get node value where attribute value is

Say my XML looks like this:
<record>
<row name="title">this item</row>
<row name="url">this url</row>
</record>
Now I'm doing something like this:
$xml = new DOMDocument();
$xml->load('xmlfile.xml');
echo $xml->getElementByTagName('row')->item(0)->attributes->getNamedItem('title')->nodeValue;
But this just gives me:
NOTICE: Trying to get property of non-object id
Does anybody know how to get the node value where the "name" attribute has value "title"?
Try:
$xml = new DOMDocument();
$xml->loadXml('
<record>
<row name="title">this item</row>
<row name="url">this url</row>
</record>
');
$xpath = new DomXpath($xml);
// traverse all results
foreach ($xpath->query('//row[#name="title"]') as $rowNode) {
echo $rowNode->nodeValue; // will be 'this item'
}
// Or access the first result directly
$rowNode = $xpath->query('//row[#name="title"][1]')->item(0);
if ($rowNode instanceof DomElement) {
echo $rowNode->nodeValue;
}
foreach ($xml->getElementsByTagName('row') as $element)
{
if ($element->getAttribute('name') == "title")
{
echo $element->nodeValue;
}
}
$xpath = new DOMXPath( $xml );
$val = $xpath->query( '//row[#name="title"]' )->item(0)->nodeValue;

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