drop-down navigation menu with HTML PHP MySQL - php

Question

EDIT FIXED by user #jeroen
You have to move the li and a tags inside the while loop.
Thank you for this, F4LLCON
So the final code (not so clean, but works now):
<?php
$query = mysql_query("SELECT * FROM `apps` ");
while ($query_row = mysql_fetch_assoc($query))
{
?>
<li>
<?php
$meer = $query_row['TITLE'];
$desc_inject = '';
$sub_string = substr($desc_inject, 0, 200);
echo $sub_string." " . '' . '' . $meer . '';
?>
</li>
<br />
<?php
}
?>
I want a drop-down menu that will show the TITLES out of my MySQL database.
I know how to do everything concerning the ID etc.
The only problem is that the PHP version of the drop-down menu will SELECT all the TITLES in my database and parse it as ONE link.
So instead of
Home
>About
>Contact
>Another
it will look like
Home
>About
Contact
Another
With other words
Home
>About Contact Another
It will not make multiple drop-down links but only one drop-down link
If you for example do:
<div>
<?php
echo $query_row['TITLE'];
?>
</div>
It will make a individual <div></div> for every TITLE in my database, so I thought this method would also work for the drop-down links..
Does anybody know how to fix it so it will make individual <li></li> for every TITLE?
Here is a normal drop-down menu:
<li id="media">
<ul>
<li id="1a">About</li>
<li id="1b">Contact</li>
<li id="1b">Another</li>
</ul>
</li>
And here is the PHP drop-down menu:
<li id="media">
<ul>
<li>
<a href="">
<?php
$query = mysql_query("SELECT * FROM `apps` ");
while ($query_row = mysql_fetch_assoc($query))
{
echo $query_row['TITLE'];
?>
<br />
<?php
}
?>
</a>
</li>
</ul>
</li>

Answer 1

You have to move the li and a tags inside the while loop.
echo '<li>' . $query_row['TITLE'] . '</li>';

Answer 2

<li id="media">
<ul>
<?php
$query = mysql_query("SELECT * FROM `apps` ");
while ($query_row = mysql_fetch_assoc($query))
{
echo "<li><a href=''>" . $query_row['TITLE'] ."</a></li>";
}
</ul>
</li>