I am working on a project that involves a type of caching to be performed. Multiple caches can be done for situations based on different cache names. In the files I am storying a cache like so:
{cache:2011-12-11 02:01:47}
And when I search for it, I am trying to preg_match it like this:
$match = "{cache:/\d{4}\-\d{2}\-\d{2} \d{2}:\d{2}:\d{2}/}";
$str = 'FIND ME! {cache:2011-12-11 02:01:47}';
if (preg_match($match, $str, $matches)) {
print "it's a match";
print_r($match);
}
The problem is, it never finds it. But this will work if I do:
$match = "/\d{4}\-\d{2}\-\d{2} \d{2}:\d{2}:\d{2}/";
What am I doing wrong with my preg_match statement? And is there something type of string search I could use that is faster than preg_match?
Your in-code regex will not work, because you copy&pasted the delimiters where they don't belong:
$match = "{cache:/\d{4}\-\d{2}\-\d{2} \d{2}:\d{2}:\d{2}/}";
^ ^
Eeek! Eeek!
This way your { and } became the regex delimiters, and the inner slashes were interpreted as literal characters to search for.
It rather should have been:
$match = "/\{cache:\d{4}\-\d{2}\-\d{2} \d{2}:\d{2}:\d{2}}/";
Note also the escaped leading \{ curly.
Related
I try to make system that can detect date in some string, here is the code :
$string = "02/04/16 10:08:42";
$pattern = "/\<(0?[1-9]|[12][0-9]|3[01])\/\.- \/\.- \d{2}\>/";
$found = preg_match($pattern, $string);
if ($found) {
echo ('The pattern matches the string');
} else {
echo ('No match');
}
The result i found is "No Match", i don't think that i used correct regex for the pattern. Can somebody tell me what i must to do to fix this code
First of all, remove all gibberish from the pattern. This is the part you'll need to work on:
(/0?[1-9]|[12][0-9]|3[01]/)
(As you said, you need the date only, not the datetime).
The main problem with the pattern, that you are using the logical OR operators (|) at the delimiters. If the delimiters are slashes, then you need to replace the tube characters with escaped slashes (/). Note that you need to escape them, because the parser will not take them as control characters. Like this: \/.
Now, you need to solve some logical tasks here, to match the numbers correctly and you're good to go.
(I'm not gonna solve the homework for you :) )
These articles will help you to solve the problem tough:
Character classes
Repetition opetors
Special characters
Pipe character (alternation operator)
Good luck!
In your comment you say you are looking for yyyy, but the example says yy.
I made a code for yy because that is what you gave us, you can easily change the 2 to a 4 and it's for yyyy.
preg_match("/((0|1|2|3)[0-9])\/\d{2}\/\d{2}/", $string, $output_array);
Echo $output_array[1]; // date
Edit:
If you use this pattern it will match the time too, thus make it harder to match wrong.
((0|1|2|3)[0-9])/\d{2}/\d{2}\s+\d{2}:\d{2}:\d{2}
http://www.phpliveregex.com/p/fjP
Edit2:
Also, you can skip one line of code.
You first preg_match to $found and then do an if $found.
This works too:
If(preg_match($pattern, $string, $found))}{
Echo $found[1];
}Else{
Echo "nothing found";
}
With pattern and string as refered to above.
As you can see the found variable is in the preg_match as the output, thus if there is a match the if will be true.
I have a string that looks like this
../Clean_Smarty_Projekt/tpl/templates_c\.
../Clean_Smarty_Projekt/tpl/templates_c\..
I want to replace ../, \. and \.. with a regulare expression.
Before, I did this like this:
$result = str_replace(array("../","\..","\."),"",$str);
And there it (pattern) has to be in this order because changing it makes the output a little buggy. So I decided to use a regular expression.
Now I came up with this pattern
$result = preg_replace('/(\.\.\/)|(\\[\.]{1,2})/',"",$str);
What actually returns only empty strings...
Reason: (\\[\.]{1,2})
In Regex101 its all ok. (Took me a couple of minutes to realize that I don't need the /g in preg_replace)
If I use this pattern in preg_replace I have to do (\\\\[\.]{1,2}) to get it to work. But that's obviously wrong because im not searching for two slashes.
Of course I know the escaping rulse (escaping slashes).
Why doesn't this match correctly ?
I suggest you to use a different php delimiter. Within the / delimiter, you need to use three \\\ or four \\\\ backslashes to match a single backslash.
$string = '../Clean_Smarty_Projekt/tpl/templates_c\.'."\n".'../Clean_Smarty_Projekt/tpl/templates_c\..';
echo preg_replace('~\.\./|\\\.{1,2}~', '', $string)
Output:
Clean_Smarty_Projekt/tpl/templates_c
Clean_Smarty_Projekt/tpl/templates_c
I’m trying to write a regular expression to change mm3 to mL:
<?php
$match = 'mm<sup>3</sup>';
if(preg_match('/\b(mm<sup>3</sup>)\b/', $match))
{
$replacement = 'ml';
$replac = preg_replace('/\b(mm<sup>3</sup>)\b/', $replacement, $match);
echo $replac;
}
?>
But my regular expression doesn't capture the content in $match variable, and the $replac value isn't output. What am I doing wrong?
Change:
if(preg_match('/\b(mm<sup>3</sup>)\b/',$match))
to:
if(preg_match('#\bmm<sup>3</sup>\b#',$match))
and similarly in the preg_replace call.
Since your regular expression contains /, you need to either escape it or use a different delimiter around the regular expression.
There's also no need for the parentheses, since you're not doing anything with the groups.
You need to either use preg_quote to get rid of that / in your regexp, or use a different delimiter (usually # is used).
Also, the \b separator after the > is not necessary, nor are parentheses since you don't seem to be doing capture; you're basically doing a more expensive str_replace.
Finally, you can do everything in one move. If there's no match, nothing will happen.
<?php
$match = 'mm<sup>3</sup>';
$replacement='ML';
$replac = preg_replace('#\\bmm<sup>3</sup>#',
$replacement,
$match);
echo $replac;
?>
If you want to be picky, I guess you should also replace with 'ml', not 'ML' :-)
(for replacement of multiple strings, preg_replace supports arrays).
Note: unless you're sure that is the correct HTML you want replaces, maybe you ought to try
$match = 'mm\\s*<sup>\\s*3\\s*</sup>';
in order to catch mm 3 and similar, in addition to mm3 (in some circumstances they may look alike, and some editors might use or automatically "correct" either form into the other).
<?php
$data='123
[test=abc]cba[/test]
321';
$test = preg_replace("(\[test=(.+?)\](.+?)\[\/test\])is","$1",$data);
echo $test;
?>
I expect the above code to return
abc
but instead of returning abc it returns
123 abc 321
Please tell me what I am doing wrong.
You're only replacing the matched part (the BBcode section). You're leaving the rest of the string untouched.
If you also want to remove the leading/trailing text, include those in the expression:
$test = preg_replace("(.*\[test=(.+?)\](.+?)\[\/test\].*)is","$1",$data);
I don't know if you're aware of this, but the outermost set of parentheses in your regex does not form a group (capturing or otherwise). PHP is interpreting them as regex delimiters. If you are aware of that, and you're using them as delimiters on purpose, please don't. It's usually best to use a non-bracketing character that never has any special meaning in regexes (~, %, #, etc.).
I agree with Casimir that preg_match() is the tool you should be using, not preg_replace(). But his solution is trickier than it needs to be. Your original regex works fine; all you have to do is grab the contents of the first capturing group, like so:
if (preg_match('%\[test=(.+?)\](.+?)\[/test\]%si', $data, $match)) {
$test = $match[1];
}
You don't need to use a replace here, all that you need is to take something in the string. To do that preg_match is more useful:
$data='123
[test=abc]cba[/test]
321';
$test = preg_match('~\[test=\K[^\]]++~', $data, $match);
echo $match[0];
Hi i want to retrieve certain information from a website.
This is what is display on the website with html tags.
<a href="ProductDisplay?catalogId=10051&storeId=90001&productId=258033&langId=-1" id="WC_CatalogSearchResultDisplay_Link_6_3" class="s_result_name">
SALT - Fine
</a>
What i want to extract is "SALT - FINE" using preg match however i do not know why i cant use it. isit because they are all on different line? cos i realise if they are on a single line i can actually retrieve what i want.
This is my code -
$pattern = '/id="WC_CatalogSearchResultDisplay_Link_6_3.*<\/a>/';
preg_match_all($pattern, $response, $match);
print_r($match);
I do not get anything in my array. if they are on a single line it works?.why is that so?
Have a look at:
http://www.php.net/manual/en/reference.pcre.pattern.modifiers.php
especially the m and s modifiers.
Also, I would recommend, changing the pattern to something like:
$pattern = '/id="WC_CatalogSearchResultDisplay_Link_6_3"[^>]*>(.*)<\/a>/ims';
Otherwise, you'll match the end of your a-tag.
And on a side note, don't use regex to parse html/xml.
Something like this:
<?php
$dom = DOMDocument::loadHtml($response);
$xpath = new DOMXPath($dom);
$node = $xpath->query('//*[#id="WC_CatalogSearchResultDisplay_Link_6_3"]/text()')->item(0);
if ($node instanceof DOMText) {
echo trim($node->nodeValue);
}
will also work, and will be a lot more robust.
You should encapsulate what you want to match by (). So i guess your pattern would then become
$pattern = '/id="WC_CatalogSearchResultDisplay_Link_6_3(.*)<\/a>/';
I however don't fully see how you arrived at this pattern, since it would be simpler to just match everything enclosed by a-tags.
Edit:
You also need the s modifier as mentioned by Yoshi so the . matches a newline. I would thus suggest you use this code:
$pattern = '/<a[^>]*>(.+)<\/a>/si';
preg_match_all($pattern, $response, $match);
print_r($match);
You're right, it's because it's a multi-line input string.
You need to add the m and s modifiers to the regex pattern to match multiline strings:
$pattern = '/id="WC_CatalogSearchResultDisplay_Link_6_3.*<\/a>/ms';
The m modifier makes it multi-line.
The s modifier makes the . dot match newline characters as well as all others (by default it doesn't match newlines)