I have a simple html form and some php that input the POST variables into a mysql database. However, I noticed that the form would not input the data when
if (isset($_POST['submit'])){
insert stuff in here
}
was included. I then removed the if statement above and ran the code. All of the variables were imputed except the ones from the form using POST (ex $_POST['var1']). It seems like the POST variables are not being recognized and I dont know what's wrong.
ALL CODE:
<?php session_start(); ?>
<!DOCTYPE html>
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<title></title>
<script type='text/javascript' src='http://code.jquery.com/jquery-1.7.1.min.js'></script>
<script type='text/javascript' src='http://twitter.github.com/bootstrap/1.4.0/bootstrap-modal.js'></script>
<link rel="stylesheet" href="../css/bootstrap.css" type="text/css" media="screen" />
<link rel="stylesheet" href="../css/basic.css" type="text/css" media="screen" />
</head>
<body>
<?php include '../css/bar.php'; ?>
<div id='content'>
<?php include '../nav.php';
?>
<?php
if (isset($_POST['submit'])){
include '../connect.php';
$question=mysql_real_escape_string($_POST['question']);
$detail=mysql_real_escape_string($_POST['detail']);
$date=date("d M Y");
$time=time();
$user=$_SESSION['id'];
$put=mysql_query("INSERT INTO questions VALUES ('','$question','$detail','$date','$time','$user','subject','0')");
$result=mysql_query("SELECT * FROM questions WHERE user='$user' AND time='$time'");
while ($row = mysql_fetch_assoc($result)){
$q=$row['id'];
}
}
?>
<form method='POST' action='question.php?q=<?php echo $q ?>'>
<p>Question:</p>
<p><input type='text' name='question' id='question' maxlength='200'></p>
<p>Add some detail (optional):</p>
<p><textarea id='detail' name='detail' ></textarea></p>
<p>Tags:</p>
<p><input type='submit' value='submit' name='submit'></p>
</form>
</div>
<?php include '../footer.php'; ?>
</body>
</html>
TESTPAGE:
<?php
include 'connect.php';
if (isset($_POST['submit'])){
$hhh=mysql_real_escape_string($_POST['hhh']);
$put=mysql_query("INSERT INTO questions VALUES ('','$hhh','','','','','','')");
}
?>
<form action='test.php' method='post'>
<input type='text' name='hhh'>
<input type='submit' name='submit' value='submit'>
</form>
You have two PHP pages - ask.php and question.php. I (guess)think the ask.php is used to store questions and other details and you want to open a question.php with question id.
ask.php
<?php session_start(); ?>
<!DOCTYPE html>
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<title></title>
<script type='text/javascript' src='http://code.jquery.com/jquery-1.7.1.min.js'></script>
<script type='text/javascript' src='http://twitter.github.com/bootstrap/1.4.0/bootstrap-modal.js'></script>
<link rel="stylesheet" href="../css/bootstrap.css" type="text/css" media="screen" />
<link rel="stylesheet" href="../css/basic.css" type="text/css" media="screen" />
</head>
<body>
<?php include '../css/bar.php'; ?>
<div id='content'>
<?php
include '../nav.php';
/*--- If submit button is pressed ---- */
if (isset($_POST['submit']))
{
include '../connect.php';
$question=mysql_real_escape_string($_POST['question']);
$detail=mysql_real_escape_string($_POST['detail']);
$date=date("d M Y");
$time=time();
$user=$_SESSION['id'];
/* SELECT column names you want to use with INSERT statement */
$put=mysql_query("INSERT INTO questions
(`question`,`detail`,`date`,`time`,`user`,`subject`,`name_of_last_col` )
VALUES
('$question','$detail','$date','$time','$user','subject','0')");
//for debug purpose
if($put)
{
echo "Record added";
}
else
{
echo "Can't add record " . mysql_error();
}
}
/*----- End submit block -----------*/
/*----List the questions and select it----------*/
$time=time();
$user=$_SESSION['id'];
//I think this wont work. Try to remove time comparison from the SELECT statement.
$result=mysql_query("SELECT * FROM questions WHERE `user`='$user' AND `time`='$time'");
//$result=mysql_query("SELECT * FROM questions WHERE `user`='$user'");
if($result)
{
echo "<table>";
while($row = mysql_fetch_assoc($result))
{
echo "<tr>";
echo "<td>$row[question]</td>";
echo "<td><a href='question.php?qid=$row[id]'>Show a question</a></td>";
echo "</tr>";
}
echo "</table>";
}
else
{
echo "No questions!!!";
}
?>
<form method='POST' action="ask.php">
<p>Question:</p>
<p><input type='text' name='question' id='question' maxlength='200'></p>
<p>Add some detail (optional):</p>
<p><textarea id='detail' name='detail' ></textarea></p>
<p>Tags:</p>
<p><input type='submit' value='submit' name='submit'></p>
</form>
question.php should be:
<?php
$qid=$_GET["qid"];
echo "$qid is selected...";
?>
You may split code into two PHP pages - one for save records and another to list and select rows.
addquestion.php
<?php
session_start();
if(isset($_POST['submit']))
{
mysql_connect("localhost","user","password") or die(mysql_error());
mysql_select_db("your_db_name") or die(mysql_error());
$question=mysql_real_escape_string($_POST['question']);
$detail=mysql_real_escape_string($_POST['detail']);
$date=date("d M Y");
$time=time();
$user=$_SESSION['id'];
$put=mysql_query("INSERT INTO questions
(`question`,`detail`,`date`,`time`,`user`,`subject`,`name_of_last_col` )
VALUES
('$question','$detail','$date','$time','$user','subject','0')");
//for debug purpose
if($put)
{
echo "Record added";
}
else
{
echo "Can't add record " . mysql_error();
}
}
?>
<form method='post' action="addquestion.php">
<p>Question:</p>
<p><input type='text' name='question' id='question' maxlength='200'></p>
<p>Add some detail (optional):</p>
<p><textarea id='detail' name='detail' ></textarea></p>
<p>Tags:</p>
<p><input type='submit' value='submit' name='submit'></p>
</form>
questionlist.php
<?php
session_start();
$user=$_SESSION['id'];
mysql_connect("localhost","user","password") or die(mysql_error());
mysql_select_db("your_db_name") or die(mysql_error());
$result=mysql_query("SELECT * FROM questions WHERE `user`='$user'");
if($result)
{
echo "<table>";
while($row = mysql_fetch_assoc($result))
{
echo "<tr>";
echo "<td>$row[question]</td>";
echo "<td><a href='question.php?qid=$row[id]'>Show a question</a></td>";
echo "</tr>";
}
echo "</table>";
}
else
{
echo "No questions!!!";
}
?>
Related
I was creating a page which will create a number of html forms in it's body using a php for loop and each form will submit the response to the page itself. But after creating it the webpage is looking fine, but none of the forms are working. Here is a picture of the page.
Webpage is looking completely fine.
And the code is here.
<?php
session_start();
date_default_timezone_set("Asia/Dhaka");
if(!isset($_SESSION["user"])||$_SESSION["user"]!="shihan04"){
echo "<script> location.href=\"https://sgtcmc.000webhostapp.com/contests/index.php\";</script>";
}
if($_SERVER["REQUEST_METHOD"] == "POST"){
$pp = $_POST["pp"];
$rep = test_input($_POST["rep"]);
$dn = test_input($_POST["dn"]);
$dir=getcwd()."/clarifications/";
$fa=fopen($dir.$dn,"r");
$unm=fgets($fa);$ppb=fgets($fa);$tm=fgets($fa);$sub=fgets($fa);$qs=fgets($fa);$repb=fgets ($fa);
fclose($fa);
$fa=fopen($dir.$dn,"w");
fwrite($fa,$unm.$pp."\n".$tm.$sub.$qs.$rep);
fclose($fa);
}
function test_input($data) {
$data = trim($data);
$data = stripslashes($data);
$data = htmlspecialchars($data);
return $data;
}
?>
<!DOCTYPE HTML>
<html>
<head>
<title>Clarification Response</title>
<meta charset="utf-8">
<meta name="viewport" content="width=device-width, initial-scale=1">
<link rel="stylesheet" href="https://maxcdn.bootstrapcdn.com/bootstrap/4.5.2/css/bootstrap.min.css">
<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.5.1/jquery.min.js"></script>
<script src="https://cdnjs.cloudflare.com/ajax/libs/popper.js/1.16.0/umd/popper.min.js"></script>
<script src="https://maxcdn.bootstrapcdn.com/bootstrap/4.5.2/js/bootstrap.min.js"></script>
<link rel="stylesheet" href="styles.css">
<script>MathJax = {tex: {inlineMath: [['$', '$'], ['\\(', '\\)']]},svg: {fontCache: 'global'}};</script>
<script id="MathJax-script" async src="https://cdn.jsdelivr.net/npm/mathjax#3/es5/tex-svg.js"></script>
</head>
<body>
<?php
$ad=getcwd()."/clarifications/";
$af=scandir($ad,1);
$ac=count($af)-2;
for($i=0;$i<$ac;$i++){
$fa=fopen($ad.$af[$i],"r");
$unm=fgets($fa);$pp=fgets($fa);$tm=fgets($fa);$sub=fgets($fa);$qs=fgets($fa);$rep=fgets($fa);
fclose($fa);
echo "<table class=\"table-sm table-bordered\">
<tr><th>Username</th><td>".$unm."</td></tr>
<tr><th>Time</th><td>".$tm."</td></tr>
<tr><th>Subject</th><td>".$sub."</td></tr>
<tr><th>Question</th><td>".$qs."</td></tr>
</table>";
echo "<div class=\"container-sm\">
<form method=\"post\" action=\"".htmlspecialchars($_SERVER["PHP_SELF"])."\">
<div class=\"form-group\">";
if($pp=="1\n"){
echo "<select class=\"form-control\" id=\"pp\" name=\"pp\">
<option value=\"1\">Public</option>
<option value=\"0\">Private</option>";
}
else{
echo "<select class=\"form-control\" id=\"pp\" name=\"pp\">
<option value=\"0\">Private</option>
<option value=\"1\">Public</option>";
}
echo "</select>
</div>";
echo "<div class=\"form-group\">
<input type=\"text\" class=\"form-control\" name=\"dn\" value=\"".$af[$i]."\" disabled>
</div>
<div class=\"form-group\">
<input type=\"text\" class=\"form-control\" placeholder=\"Reply\" name=\"rep\" value=\"".$rep."\">
</div>
<input type=\"submit\" name=\"submit\" value=\"Submit\" class=\"btn btn-outline-primary\">
</form></div><br>";
}
?>
</body>
I can't find the solution for this and I need to fix this in next 2-3 days. I'm a complete noob. So please help me with this.
I displayed a set of questions.
On selecting one of those questions for which I required the answers to be posted on the same page, but the problem is I am not getting id parameter from url which I am passing on selectiong the question.
Now when I am trying to answer the question which is selected, I will need the id of question to post the answer of that perticular question which I already have in url as a parameter for Example: id=1.
Here is the body section of html page:
<?php
include("menu/menu.php");
$sqli = "SELECT * FROM forum_question where id='$id'";
$result=mysqli_query($conn,$sqli);
?>
<form action="submit_answer.php" method="post" name="answers">
<br> <br> <br>
<?php
while($row = mysqli_fetch_array($result))
echo "Q".$row['detail'];
?>
<br>
answers:<br>
<textarea class="tinymce" name="answers"></textarea>
<input type="hidden" name="id" value="<?php echo $id;?>">
<br> <br>
<input type="submit" value="submit" name="submit">
After submit the page "submit_answer.php", Code is:
<?php
include'config.php';
if($conn){
if ($_SERVER["REQUEST_METHOD"] == "POST") {
$answers = $_REQUEST['answers'];
$id= $_GET ['id'];
}
$sqli= "INSERT INTO answers (answers)
VALUES ('$answers')";
if (mysqli_query( $conn,$sqli))
{
echo "New record created successfully";
header("location:answer.php?id='$id'");
} else {
echo "Error: " . $sqli . "<br>" . $conn->error;
}
}else{
}
mysqli_close($conn);
?>
Basically I am very much fresher in Php I just want to know how should I get the id of question and submit it to the "submit_answer.php" with the answer content.
just take a hidden field below the answer field and get the url parameter to that hidden field on page load, as said by user buivankim2020 and submit submit_answer.php,
after submit get the value of that field in variable like what you do for getting the answer..
You should change it (add hidden input for id in markup html)
<?php
include'config.php';
//session_start();
$id= $_GET ['id'];
?>
<html>
<head>
<link rel="stylesheet" type="text/css" href="css/style.css">
<script type="text/javascript" src="tinymce/js/jquery.min.js"></script>
<script type="text/javascript" src="tinymce/plugin/tinymce/tinymce.min.js"></script>
<script type="text/javascript" src="tinymce/plugin/tinymce/init-tinymce.js"></script>
</head>
<body>
<div id="container">
<div id="main">
<?php
include("menu/menu.php");
$sqli = "SELECT * FROM forum_question where id='$id'";
$result=mysqli_query($conn,$sqli);
?>
<form action="submit_answer.php" method="post" name="answers">
<br> <br> <br>
<?php
while($row = mysqli_fetch_array($result))
echo "Q".$row['detail'];
?>
<br>answers:<br>
<textarea class="tinymce" name="answers"></textarea>
<input type="hidden" name="id" value="<?php echo $id;?>">
<br> <br>
<input type="submit" value="submit" name="submit">
</form>
</body>
</html>
submit_answer.php
<?php
include'config.php';
if($conn){
if (isset($_POST['answers']) && isset($_POST['id'])) {
$answers = $_POST['answers'];
$id= $_POST['id'];
$sqli= "INSERT INTO answers (answers) VALUES ('$answers')";
if (mysqli_query( $conn,$sqli))
{
echo "New record created successfully";
header("location:answer.php?id='$id'");
} else {
echo "Error: " . $sqli . "<br>" . $conn->error;
}
}
mysqli_close($conn);
}
?>
update
Can anyone explain to me why I am getting duplicate messages instead of one?
how can I change my code so that when I type a comment and press "Comment" button, it will only display one message instead of duplicates! When I have one comment boxes it doesn't show duplicate comments, but if I have more than one then it starts duplicating!
COMMENT.INC.PHP
include 'cdbh.inc.php';
function setComments($con)
{
if (isset($_POST['commentSubmit'])) {
$uid = mysqli_real_escape_string($con,$_POST['uid']);
$date = mysqli_real_escape_string($con,$_POST['date']);
$message = mysqli_real_escape_string($con,$_POST['message']);
$sql = "INSERT INTO comments (uid, date, message) VALUES ('$uid','$date','$message')";
$result = mysqli_query($con,$sql);
}
}
function getComments($con)
{
$sql = "SELECT * FROM comments";
$result = mysqli_query($con,$sql);
while ($row=mysqli_fetch_assoc($result)) {
echo $row['uid'];
echo ":";
echo $row['message']."<br><br>";
}
}
page code
<?php
date_default_timezone_set('America/Los_Angeles');
include 'comment.inc.php';
include("connection.php");
?>
<!DOCTYPE html>
<html>
<head>
<meta charset="UTF-8">
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>
<link href="comment.css" rel ="stylesheet">
</head>
<body>
<?php
$sql="Select * from tbl_images";
$result=mysqli_query($connection,$sql);
while ($row=mysqli_fetch_array($result)) {
?>
<img src="images/<?php echo $row['images_name'] ?>" width="200px" height="200px">
<?php
echo "<form method ='POST' action ='".setComments($con)."'>
<input type ='hidden' name ='uid' value='unknown'>
<input type ='hidden' name ='date' value='".date('Y-m-d H:i:s')."'>
<textarea name='message'></textarea>
<button type ='submit' name='commentSubmit'>Comment</button>
</form>";
}
getComments($con);
?>
</body>
</html>
Maybe you are submiting all your forms instead of one..
check your database in order to know from what img comes each message.
If you have other code like javascript, you should post it.
I am trying to make a html or php page (for some own learning process) which can input 3 selection and then display there results in next page.
1- input Start Date
2- input End Date
3- Show Service Name in drop down menu via mysql query to get services names from the table
So far I have managed to get the start and end table and drop down menu which successfully query the services table and shows the name, but the problem is that when i click submit i can see the results of start and end date but i am unable to see how can i add services selection in the posting.
This is my code.
<!DOCTYPE html>
<html>
<head>
<link href="http://ajax.googleapis.com/ajax/libs/jqueryui/1.8/themes/base/jquery-ui.css" rel="stylesheet" type="text/css"/>
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.5/jquery.min.js"></script>
<script src="http://ajax.googleapis.com/ajax/libs/jqueryui/1.8/jquery-ui.min.js"></script>
<script>
$(document).ready(function() {
$("#start_datepicker").datepicker();
$("#end_datepicker").datepicker();
});
</script>
</head>
<body style="font-size:62.5%;">
<form action="test.php" method="post">
Start Date: <input type="text" name="startdate" id="start_datepicker"> <br />
End Date: <input type="text" name="enddate" id="end_datepicker"><br />
<select name="srvname">
<?php
$conn = new mysqli('localhost', 'root', 'SQLPASS', 'radius')
or die ('Cannot connect to db');
$result = $conn->query("select srvname name from rm_services");
while ($row = $result->fetch_assoc()) {
echo "<option value=\"" . $row["id"] . "\">" . $row["name"] . "</option>";
}
?>
</select>
<input type="submit" value="Submit:">
</form>
</body>
</html>
and this is test.php which will per form action shows the date
<?php
$STARTDATE = $_POST['startdate'];
$ENDDATE = $_POST['enddate'];
$SRVNAME = $_POST['srvname']; //gets the value -> $row["id"]
echo "<h2>You have entered the following information:</h2>";
echo "<pre>$STARTDATE</pre> ";
echo "<pre>$ENDDATE</pre>";
echo "<pre>$SRVNAME</pre>";
?>
This one should work, and for the future: if you post something on stackoverflow, please post formatted code, it's way easier to edit and especially to read it...
your index.php or whatever...
<!DOCTYPE html>
<html>
<head>
<link href="http://ajax.googleapis.com/ajax/libs/jqueryui/1.8/themes/base/jquery-ui.css" rel="stylesheet" type="text/css"/>
<script src="http://ajax.googleapis.com/ajax/libs/jquery/1.5/jquery.min.js"></script>
<script src="http://ajax.googleapis.com/ajax/libs/jqueryui/1.8/jquery-ui.min.js"></script>
<script>
$(document).ready(function() {
$("#start_datepicker").datepicker();
$("#end_datepicker").datepicker();
});
</script>
</head>
<body style="font-size:62.5%;">
<form action="test.php" method="post">
Start Date: <input type="text" name="startdate" id="start_datepicker"> <br />
End Date: <input type="text" name="enddate" id="end_datepicker"><br />
<select name="srvname">
<?php
$conn = new mysqli('localhost', 'root', 'SQLPASS', 'radius')
or die ('Cannot connect to db');
$result = $conn->query("select id, name from rm_services");
while ($row = $result->fetch_assoc()) {
echo "<option value=\"" . $row["id"] . "\">" . $row["name"] . "</option>";
}
?>
</select>
<input type="submit" value="Submit:">
</form>
</body>
</html>
your test.php
<?php
$STARTDATE = $_POST['startdate'];
$ENDDATE = $_POST['enddate'];
$SRVNAME = $_POST['srvname']; //gets the value -> $row["id"]
echo "<h2>You have entered the following information:</h2>";
echo "<pre>$STARTDATE</pre> ";
echo "<pre>$ENDDATE</pre>";
echo "<pre>$SRVNAME</pre>";
?>
I didn't test it, but actually it should work...
My aim to is to Update Value in Database By using Update Query . On my first page i have just displayed database table in webpage. Then by using hyperlink i have to click on Edit to second page "edit.php".While on first page i have to get the value of id and send it to second page. Where a input form is displayed which gets Value casually but Id through hidden tag. On third page getting the values query is implented but the value of id is missing.
First Page
<html>
<head>
<title>Assignment</title>
</head>
<body>
<?php
$con=mysql_connect("localhost","root","");
// Check connection
if (!mysql_connect()) {
echo "Failed to connect to MySQL: " . mysql_connect_error();
}
$db=mysql_select_db("assignment",$con);
$result = mysql_query("SELECT * FROM teacher ",$con);
?><table cellpadding="2px" border="2px"><?php
while($row = mysql_fetch_array($result)) {
?> <tr>
<td><a href="edit.php?id=<?php
echo $row['id']; ?>">Edit</a > Delete
</td><td>
<?php
echo $row['id']; ?></td><td> <?php echo $row['name'];?></td><td><?php echo $row['program']; ?></td>
<?php }
?></table><?php
mysql_close($con);
?>
</body>
</html>
Secnod Page edit.php
<html>
<head>
<title>Assignment Edit</title>
</head>
<body>
<?php
$id = $_GET['id'];
?>
<form action="update.php" method="get">
Address <input type="text" name="program"><br>
<input type="hidden" name="id" value='<?php $id?>'>
<input type="submit" name="submit">
</form>
</body>
</html>
Third Page update.php
<html>
<head>
<title>Update Page</title>
</head>
<body>
<?php
$add=$_GET['program'];
$id=$_GET['id'];
$con=mysql_connect("localhost","root","");
// Check connection
if (!mysql_connect()) {
echo "Failed to connect to MySQL: " . mysql_connect_error();
}
$db=mysql_select_db("assignment",$con);
$query = "UPDATE teacher SET program='$add' WHERE id =".$id;
echo $query;
$result = mysql_query($query,$con);
/* while($row = mysql_fetch_array($result)) {
echo $row['id'] ." " . $row['name']." ". $row['address']."<br>";
}
mysql_close($con);
*/
?>
</body>
</html>
output
UPDATE teacher SET program='openSource' WHERE id =
you need to change this
<input type="hidden" name="id" value='<?php $id?>'>
to
<input type="hidden" name="id" value='<?php echo $id?>'>
(or)
<input type="hidden" name="id" value='<?=$id?>'>